Excel create table with all combinations












6















Let's assume I have 3 columns with labels




  1. A B C D

  2. a b c d e

  3. 1 2 3 4 5 6 7 8 9 10


Is there a quick and easy way to create an empty table with all permutations? i.e.




  • A - a - 1

  • A - a - 2

  • ....

  • D - e - 10










share|improve this question




















  • 2





    Why does this look to me like a school homework assignment?

    – Jeff Zeitlin
    Mar 31 '17 at 15:49











  • No worries, it's for work and I'm trying to automatize cumbersome copy paste tasks as I might be required to redo this several times in the future

    – SuperMartingale
    Apr 3 '17 at 7:04











  • Clearly worded question that solved my exact problem. Thank you. Well asked questions don't get enough upvotes.

    – Myrddin Emrys
    Nov 21 '17 at 14:11
















6















Let's assume I have 3 columns with labels




  1. A B C D

  2. a b c d e

  3. 1 2 3 4 5 6 7 8 9 10


Is there a quick and easy way to create an empty table with all permutations? i.e.




  • A - a - 1

  • A - a - 2

  • ....

  • D - e - 10










share|improve this question




















  • 2





    Why does this look to me like a school homework assignment?

    – Jeff Zeitlin
    Mar 31 '17 at 15:49











  • No worries, it's for work and I'm trying to automatize cumbersome copy paste tasks as I might be required to redo this several times in the future

    – SuperMartingale
    Apr 3 '17 at 7:04











  • Clearly worded question that solved my exact problem. Thank you. Well asked questions don't get enough upvotes.

    – Myrddin Emrys
    Nov 21 '17 at 14:11














6












6








6


3






Let's assume I have 3 columns with labels




  1. A B C D

  2. a b c d e

  3. 1 2 3 4 5 6 7 8 9 10


Is there a quick and easy way to create an empty table with all permutations? i.e.




  • A - a - 1

  • A - a - 2

  • ....

  • D - e - 10










share|improve this question
















Let's assume I have 3 columns with labels




  1. A B C D

  2. a b c d e

  3. 1 2 3 4 5 6 7 8 9 10


Is there a quick and easy way to create an empty table with all permutations? i.e.




  • A - a - 1

  • A - a - 2

  • ....

  • D - e - 10







microsoft-excel






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 20 at 0:50









fixer1234

18.9k144982




18.9k144982










asked Mar 31 '17 at 15:36









SuperMartingaleSuperMartingale

33113




33113








  • 2





    Why does this look to me like a school homework assignment?

    – Jeff Zeitlin
    Mar 31 '17 at 15:49











  • No worries, it's for work and I'm trying to automatize cumbersome copy paste tasks as I might be required to redo this several times in the future

    – SuperMartingale
    Apr 3 '17 at 7:04











  • Clearly worded question that solved my exact problem. Thank you. Well asked questions don't get enough upvotes.

    – Myrddin Emrys
    Nov 21 '17 at 14:11














  • 2





    Why does this look to me like a school homework assignment?

    – Jeff Zeitlin
    Mar 31 '17 at 15:49











  • No worries, it's for work and I'm trying to automatize cumbersome copy paste tasks as I might be required to redo this several times in the future

    – SuperMartingale
    Apr 3 '17 at 7:04











  • Clearly worded question that solved my exact problem. Thank you. Well asked questions don't get enough upvotes.

    – Myrddin Emrys
    Nov 21 '17 at 14:11








2




2





Why does this look to me like a school homework assignment?

– Jeff Zeitlin
Mar 31 '17 at 15:49





Why does this look to me like a school homework assignment?

– Jeff Zeitlin
Mar 31 '17 at 15:49













No worries, it's for work and I'm trying to automatize cumbersome copy paste tasks as I might be required to redo this several times in the future

– SuperMartingale
Apr 3 '17 at 7:04





No worries, it's for work and I'm trying to automatize cumbersome copy paste tasks as I might be required to redo this several times in the future

– SuperMartingale
Apr 3 '17 at 7:04













Clearly worded question that solved my exact problem. Thank you. Well asked questions don't get enough upvotes.

– Myrddin Emrys
Nov 21 '17 at 14:11





Clearly worded question that solved my exact problem. Thank you. Well asked questions don't get enough upvotes.

– Myrddin Emrys
Nov 21 '17 at 14:11










2 Answers
2






active

oldest

votes


















4














Running this short macro:



Sub marine()
Dim i As Long, j As Long, k As Long, N As Long

N = 1
For i = 1 To 4
For j = 1 To 5
For k = 1 To 10
Cells(N, 4) = Cells(i, 1) & "-" & Cells(j, 2) & "-" & Cells(k, 3)
N = N + 1
Next k
Next j
Next i
End Sub


will produce a column of the desired 200 combinations:



enter image description here






share|improve this answer
























  • after long search your way is the easiest if the person can write code

    – shady sherif
    Jun 12 '18 at 12:34











  • @shadysherif Thank you, I also like Scott's answer

    – Gary's Student
    Jun 12 '18 at 12:36











  • In my case I have data in different sheets.that's why this answer is the best for me.

    – shady sherif
    Jun 12 '18 at 15:07






  • 1





    Exactly! These are COMBINATIONS, not permutations. If they were permutations, you would include A-a-1, A-1-a, a-A-1, etc...

    – richard1941
    Aug 11 '18 at 19:08





















6














You can do this with a formula:



=IFERROR(INDEX($A$1:$A$4,INT((ROW(1:1)-1)/((COUNTA(B:B)*(COUNTA(C:C)))))+1)&" - "&INDEX(B:B,MOD(INT((ROW(1:1)-1)/COUNTA(C:C)),COUNTA(B:B))+1)&" - "&INDEX(C:C,MOD((ROW(1:1)-1),COUNTA(C:C))+1),"")


enter image description here






share|improve this answer























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    4














    Running this short macro:



    Sub marine()
    Dim i As Long, j As Long, k As Long, N As Long

    N = 1
    For i = 1 To 4
    For j = 1 To 5
    For k = 1 To 10
    Cells(N, 4) = Cells(i, 1) & "-" & Cells(j, 2) & "-" & Cells(k, 3)
    N = N + 1
    Next k
    Next j
    Next i
    End Sub


    will produce a column of the desired 200 combinations:



    enter image description here






    share|improve this answer
























    • after long search your way is the easiest if the person can write code

      – shady sherif
      Jun 12 '18 at 12:34











    • @shadysherif Thank you, I also like Scott's answer

      – Gary's Student
      Jun 12 '18 at 12:36











    • In my case I have data in different sheets.that's why this answer is the best for me.

      – shady sherif
      Jun 12 '18 at 15:07






    • 1





      Exactly! These are COMBINATIONS, not permutations. If they were permutations, you would include A-a-1, A-1-a, a-A-1, etc...

      – richard1941
      Aug 11 '18 at 19:08


















    4














    Running this short macro:



    Sub marine()
    Dim i As Long, j As Long, k As Long, N As Long

    N = 1
    For i = 1 To 4
    For j = 1 To 5
    For k = 1 To 10
    Cells(N, 4) = Cells(i, 1) & "-" & Cells(j, 2) & "-" & Cells(k, 3)
    N = N + 1
    Next k
    Next j
    Next i
    End Sub


    will produce a column of the desired 200 combinations:



    enter image description here






    share|improve this answer
























    • after long search your way is the easiest if the person can write code

      – shady sherif
      Jun 12 '18 at 12:34











    • @shadysherif Thank you, I also like Scott's answer

      – Gary's Student
      Jun 12 '18 at 12:36











    • In my case I have data in different sheets.that's why this answer is the best for me.

      – shady sherif
      Jun 12 '18 at 15:07






    • 1





      Exactly! These are COMBINATIONS, not permutations. If they were permutations, you would include A-a-1, A-1-a, a-A-1, etc...

      – richard1941
      Aug 11 '18 at 19:08
















    4












    4








    4







    Running this short macro:



    Sub marine()
    Dim i As Long, j As Long, k As Long, N As Long

    N = 1
    For i = 1 To 4
    For j = 1 To 5
    For k = 1 To 10
    Cells(N, 4) = Cells(i, 1) & "-" & Cells(j, 2) & "-" & Cells(k, 3)
    N = N + 1
    Next k
    Next j
    Next i
    End Sub


    will produce a column of the desired 200 combinations:



    enter image description here






    share|improve this answer













    Running this short macro:



    Sub marine()
    Dim i As Long, j As Long, k As Long, N As Long

    N = 1
    For i = 1 To 4
    For j = 1 To 5
    For k = 1 To 10
    Cells(N, 4) = Cells(i, 1) & "-" & Cells(j, 2) & "-" & Cells(k, 3)
    N = N + 1
    Next k
    Next j
    Next i
    End Sub


    will produce a column of the desired 200 combinations:



    enter image description here







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Mar 31 '17 at 17:33









    Gary's StudentGary's Student

    13.8k31730




    13.8k31730













    • after long search your way is the easiest if the person can write code

      – shady sherif
      Jun 12 '18 at 12:34











    • @shadysherif Thank you, I also like Scott's answer

      – Gary's Student
      Jun 12 '18 at 12:36











    • In my case I have data in different sheets.that's why this answer is the best for me.

      – shady sherif
      Jun 12 '18 at 15:07






    • 1





      Exactly! These are COMBINATIONS, not permutations. If they were permutations, you would include A-a-1, A-1-a, a-A-1, etc...

      – richard1941
      Aug 11 '18 at 19:08





















    • after long search your way is the easiest if the person can write code

      – shady sherif
      Jun 12 '18 at 12:34











    • @shadysherif Thank you, I also like Scott's answer

      – Gary's Student
      Jun 12 '18 at 12:36











    • In my case I have data in different sheets.that's why this answer is the best for me.

      – shady sherif
      Jun 12 '18 at 15:07






    • 1





      Exactly! These are COMBINATIONS, not permutations. If they were permutations, you would include A-a-1, A-1-a, a-A-1, etc...

      – richard1941
      Aug 11 '18 at 19:08



















    after long search your way is the easiest if the person can write code

    – shady sherif
    Jun 12 '18 at 12:34





    after long search your way is the easiest if the person can write code

    – shady sherif
    Jun 12 '18 at 12:34













    @shadysherif Thank you, I also like Scott's answer

    – Gary's Student
    Jun 12 '18 at 12:36





    @shadysherif Thank you, I also like Scott's answer

    – Gary's Student
    Jun 12 '18 at 12:36













    In my case I have data in different sheets.that's why this answer is the best for me.

    – shady sherif
    Jun 12 '18 at 15:07





    In my case I have data in different sheets.that's why this answer is the best for me.

    – shady sherif
    Jun 12 '18 at 15:07




    1




    1





    Exactly! These are COMBINATIONS, not permutations. If they were permutations, you would include A-a-1, A-1-a, a-A-1, etc...

    – richard1941
    Aug 11 '18 at 19:08







    Exactly! These are COMBINATIONS, not permutations. If they were permutations, you would include A-a-1, A-1-a, a-A-1, etc...

    – richard1941
    Aug 11 '18 at 19:08















    6














    You can do this with a formula:



    =IFERROR(INDEX($A$1:$A$4,INT((ROW(1:1)-1)/((COUNTA(B:B)*(COUNTA(C:C)))))+1)&" - "&INDEX(B:B,MOD(INT((ROW(1:1)-1)/COUNTA(C:C)),COUNTA(B:B))+1)&" - "&INDEX(C:C,MOD((ROW(1:1)-1),COUNTA(C:C))+1),"")


    enter image description here






    share|improve this answer




























      6














      You can do this with a formula:



      =IFERROR(INDEX($A$1:$A$4,INT((ROW(1:1)-1)/((COUNTA(B:B)*(COUNTA(C:C)))))+1)&" - "&INDEX(B:B,MOD(INT((ROW(1:1)-1)/COUNTA(C:C)),COUNTA(B:B))+1)&" - "&INDEX(C:C,MOD((ROW(1:1)-1),COUNTA(C:C))+1),"")


      enter image description here






      share|improve this answer


























        6












        6








        6







        You can do this with a formula:



        =IFERROR(INDEX($A$1:$A$4,INT((ROW(1:1)-1)/((COUNTA(B:B)*(COUNTA(C:C)))))+1)&" - "&INDEX(B:B,MOD(INT((ROW(1:1)-1)/COUNTA(C:C)),COUNTA(B:B))+1)&" - "&INDEX(C:C,MOD((ROW(1:1)-1),COUNTA(C:C))+1),"")


        enter image description here






        share|improve this answer













        You can do this with a formula:



        =IFERROR(INDEX($A$1:$A$4,INT((ROW(1:1)-1)/((COUNTA(B:B)*(COUNTA(C:C)))))+1)&" - "&INDEX(B:B,MOD(INT((ROW(1:1)-1)/COUNTA(C:C)),COUNTA(B:B))+1)&" - "&INDEX(C:C,MOD((ROW(1:1)-1),COUNTA(C:C))+1),"")


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 31 '17 at 19:08









        Scott CranerScott Craner

        12.2k11218




        12.2k11218






























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