A C method that gets a string from the user input
Multi tool use
0
$begingroup$
I'm new to C (and English), so don't kill me yet...
I've made a simple function that gets a string from the user and returns a char* array with said input. I would like to know how to better utilize the C tools to adapt this piece of code to the C standards.
char *getstr()
{
unsigned char buffer[128];
char counter = -1;
for(;;)
{
unsigned char c;
buffer[++counter] = (c = (unsigned char)getchar()) == 'n' ? '' : c;
if(buffer[counter] == (unsigned char)'' || counter == 127)
{
buffer[++counter] = (unsigned char)'';
break;
}
}
unsigned char str[counter];
return strncpy(str, buffer, counter + 1);
}
c reinventing-the-wheel
asked 4 mins ago
StacklysmStacklysm
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add a comment |
0
$begingroup$
I'm new to C (and English), so don't kill me yet...
I've made a simple function that gets a string from the user and returns a char* array with said input. I would like to know how to better utilize the C tools to adapt this piece of code to the C standards.
char *getstr()
{
unsigned char buffer[128];
char counter = -1;
for(;;)
{
unsigned char c;
buffer[++counter] = (c = (unsigned char)getchar()) == 'n' ? '' : c;
if(buffer[counter] == (unsigned char)'' || counter == 127)
{
buffer[++counter] = (unsigned char)'';
break;
}
}
unsigned char str[counter];
return strncpy(str, buffer, counter + 1);
}
c reinventing-the-wheel
asked 4 mins ago
StacklysmStacklysm
11
New contributor
Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
0
0
$begingroup$
I'm new to C (and English), so don't kill me yet...
I've made a simple function that gets a string from the user and returns a char* array with said input. I would like to know how to better utilize the C tools to adapt this piece of code to the C standards.
char *getstr()
{
unsigned char buffer[128];
char counter = -1;
for(;;)
{
unsigned char c;
buffer[++counter] = (c = (unsigned char)getchar()) == 'n' ? '' : c;
if(buffer[counter] == (unsigned char)'' || counter == 127)
{
buffer[++counter] = (unsigned char)'';
break;
}
}
unsigned char str[counter];
return strncpy(str, buffer, counter + 1);
}
c reinventing-the-wheel
asked 4 mins ago
StacklysmStacklysm
11
New contributor
Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I'm new to C (and English), so don't kill me yet...
I've made a simple function that gets a string from the user and returns a char* array with said input. I would like to know how to better utilize the C tools to adapt this piece of code to the C standards.
char *getstr()
{
unsigned char buffer[128];
char counter = -1;
for(;;)
{
unsigned char c;
buffer[++counter] = (c = (unsigned char)getchar()) == 'n' ? '' : c;
if(buffer[counter] == (unsigned char)'' || counter == 127)
{
buffer[++counter] = (unsigned char)'';
break;
}
}
unsigned char str[counter];
return strncpy(str, buffer, counter + 1);
}
c reinventing-the-wheel
c reinventing-the-wheel
asked 4 mins ago
StacklysmStacklysm
11
New contributor
Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
StacklysmStacklysm
11
New contributor
Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
StacklysmStacklysm
11
New contributor
Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
StacklysmStacklysm
11
asked 4 mins ago
StacklysmStacklysm
11
11
New contributor
Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Stacklysm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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