Divide an array into two parts
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I am trying to divide an array into 2 equal parts. below code is working fine as given input ->> int arr = {1,2,3,4,5,6,7,8,9,10};
for even number of array elements but in odd number of input elements.
Q1 - One index is missing when inputs are odd (Size of array is odd).
Q2 - I want to improve complexity of this program
public class DivideArray {
public static void main(String args) {
int arr = {1,2,3,4,5,6,7,8,9,10};
int len = arr.length;
int arr1= new int[(len/2)+1];
int arr2 = new int[(len/2)+1];
for(int i=0;i<arr.length;i++){
if(((len/2))>i){
arr1[i] = arr[i];
}
else{
arr2[(arr.length-i)-1] = arr[i];
}
}
//First half array
System.out.println("First half array");
for(int i=0;i<arr.length/2;i++){
System.out.print(" " + arr1[i]);
}
//Second half array
System.out.println();
System.out.println("Second half array");
for(int i=arr.length/2-1;i>=0;i--){
System.out.print(" " + arr2[i]);
}
}
}
java array
New contributor
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add a comment |
$begingroup$
I am trying to divide an array into 2 equal parts. below code is working fine as given input ->> int arr = {1,2,3,4,5,6,7,8,9,10};
for even number of array elements but in odd number of input elements.
Q1 - One index is missing when inputs are odd (Size of array is odd).
Q2 - I want to improve complexity of this program
public class DivideArray {
public static void main(String args) {
int arr = {1,2,3,4,5,6,7,8,9,10};
int len = arr.length;
int arr1= new int[(len/2)+1];
int arr2 = new int[(len/2)+1];
for(int i=0;i<arr.length;i++){
if(((len/2))>i){
arr1[i] = arr[i];
}
else{
arr2[(arr.length-i)-1] = arr[i];
}
}
//First half array
System.out.println("First half array");
for(int i=0;i<arr.length/2;i++){
System.out.print(" " + arr1[i]);
}
//Second half array
System.out.println();
System.out.println("Second half array");
for(int i=arr.length/2-1;i>=0;i--){
System.out.print(" " + arr2[i]);
}
}
}
java array
New contributor
$endgroup$
add a comment |
$begingroup$
I am trying to divide an array into 2 equal parts. below code is working fine as given input ->> int arr = {1,2,3,4,5,6,7,8,9,10};
for even number of array elements but in odd number of input elements.
Q1 - One index is missing when inputs are odd (Size of array is odd).
Q2 - I want to improve complexity of this program
public class DivideArray {
public static void main(String args) {
int arr = {1,2,3,4,5,6,7,8,9,10};
int len = arr.length;
int arr1= new int[(len/2)+1];
int arr2 = new int[(len/2)+1];
for(int i=0;i<arr.length;i++){
if(((len/2))>i){
arr1[i] = arr[i];
}
else{
arr2[(arr.length-i)-1] = arr[i];
}
}
//First half array
System.out.println("First half array");
for(int i=0;i<arr.length/2;i++){
System.out.print(" " + arr1[i]);
}
//Second half array
System.out.println();
System.out.println("Second half array");
for(int i=arr.length/2-1;i>=0;i--){
System.out.print(" " + arr2[i]);
}
}
}
java array
New contributor
$endgroup$
I am trying to divide an array into 2 equal parts. below code is working fine as given input ->> int arr = {1,2,3,4,5,6,7,8,9,10};
for even number of array elements but in odd number of input elements.
Q1 - One index is missing when inputs are odd (Size of array is odd).
Q2 - I want to improve complexity of this program
public class DivideArray {
public static void main(String args) {
int arr = {1,2,3,4,5,6,7,8,9,10};
int len = arr.length;
int arr1= new int[(len/2)+1];
int arr2 = new int[(len/2)+1];
for(int i=0;i<arr.length;i++){
if(((len/2))>i){
arr1[i] = arr[i];
}
else{
arr2[(arr.length-i)-1] = arr[i];
}
}
//First half array
System.out.println("First half array");
for(int i=0;i<arr.length/2;i++){
System.out.print(" " + arr1[i]);
}
//Second half array
System.out.println();
System.out.println("Second half array");
for(int i=arr.length/2-1;i>=0;i--){
System.out.print(" " + arr2[i]);
}
}
}
java array
java array
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asked 5 mins ago
Ved PrakashVed Prakash
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