Plotting the arctanh
5
I've been trying to plot the arctanh function for a while now
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*ln(1+x)/ln(1-x);}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
but it doesn't look right, what am I doing wrong?
tikz-pgf
asked Dec 19 at 9:47
Three Diag
20727
add a comment |
5
I've been trying to plot the arctanh function for a while now
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*ln(1+x)/ln(1-x);}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
but it doesn't look right, what am I doing wrong?
tikz-pgf
asked Dec 19 at 9:47
Three Diag
20727
add a comment |
5
5
5
I've been trying to plot the arctanh function for a while now
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*ln(1+x)/ln(1-x);}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
but it doesn't look right, what am I doing wrong?
tikz-pgf
asked Dec 19 at 9:47
Three Diag
20727
I've been trying to plot the arctanh function for a while now
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*ln(1+x)/ln(1-x);}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
but it doesn't look right, what am I doing wrong?
tikz-pgf
tikz-pgf
asked Dec 19 at 9:47
Three Diag
20727
asked Dec 19 at 9:47
Three Diag
20727
asked Dec 19 at 9:47
Three Diag
20727
asked Dec 19 at 9:47
Three Diag
20727
asked Dec 19 at 9:47
Three Diag
20727
20727
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
6
It does not look right because there is a small mistake in the definition of arctanh.
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*(ln(1+x)-ln(1-x));}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
Or, a somewhat closer representations to yours and a domain that avoids the warnings.
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*(ln((1+x)/(1-x)));}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick,domain=-0.99:0.99] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
answered Dec 19 at 12:25
marmot
85.9k499183
add a comment |
4
For comparism purpose: run with xelatex
documentclass{article}
usepackage{pstricks,pst-math,pst-plot}
begin{document}
begin{pspicture}[algebraic](-5,-4)(5,4)
psaxes{->}(0,0)(-5,-4)(5,4)
psplot[linewidth=1.5pt,linecolor=blue]{1}{5}{ACOSH(x)}
psplot[linewidth=1.5pt,linecolor=red]{-5}{5}{ASINH(x)}
psplot[linewidth=1.5pt,linecolor=green]{-.999}{.999}{ATANH(x)}
end{pspicture}
end{document}
answered Dec 19 at 12:47
Herbert
269k24407717
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
6
It does not look right because there is a small mistake in the definition of arctanh.
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*(ln(1+x)-ln(1-x));}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
Or, a somewhat closer representations to yours and a domain that avoids the warnings.
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*(ln((1+x)/(1-x)));}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick,domain=-0.99:0.99] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
answered Dec 19 at 12:25
marmot
85.9k499183
add a comment |
6
It does not look right because there is a small mistake in the definition of arctanh.
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*(ln(1+x)-ln(1-x));}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
Or, a somewhat closer representations to yours and a domain that avoids the warnings.
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*(ln((1+x)/(1-x)));}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick,domain=-0.99:0.99] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
answered Dec 19 at 12:25
marmot
85.9k499183
add a comment |
6
6
6
It does not look right because there is a small mistake in the definition of arctanh.
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*(ln(1+x)-ln(1-x));}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
Or, a somewhat closer representations to yours and a domain that avoids the warnings.
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*(ln((1+x)/(1-x)));}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick,domain=-0.99:0.99] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
answered Dec 19 at 12:25
marmot
85.9k499183
It does not look right because there is a small mistake in the definition of arctanh.
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*(ln(1+x)-ln(1-x));}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
Or, a somewhat closer representations to yours and a domain that avoids the warnings.
documentclass{article}
usepackage{tikz}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
pgfkeys{/pgf/declare function={arctanh(x) = 0.5*(ln((1+x)/(1-x)));}}
vspace{1cm}
begin{tikzpicture}[trim axis left]
begin{axis}[
xmin=-1, xmax=1,
ymin=-1, ymax=1,
samples=100,
enlarge x limits=false,
grid=both,
no markers,
axis equal]
addplot +[thick,domain=-0.99:0.99] {arctanh(x)};
end{axis}
end{tikzpicture}
end{document}
answered Dec 19 at 12:25
marmot
85.9k499183
answered Dec 19 at 12:25
marmot
85.9k499183
answered Dec 19 at 12:25
marmot
85.9k499183
answered Dec 19 at 12:25
marmot
85.9k499183
85.9k499183
add a comment |
add a comment |
4
For comparism purpose: run with xelatex
documentclass{article}
usepackage{pstricks,pst-math,pst-plot}
begin{document}
begin{pspicture}[algebraic](-5,-4)(5,4)
psaxes{->}(0,0)(-5,-4)(5,4)
psplot[linewidth=1.5pt,linecolor=blue]{1}{5}{ACOSH(x)}
psplot[linewidth=1.5pt,linecolor=red]{-5}{5}{ASINH(x)}
psplot[linewidth=1.5pt,linecolor=green]{-.999}{.999}{ATANH(x)}
end{pspicture}
end{document}
answered Dec 19 at 12:47
Herbert
269k24407717
add a comment |
4
For comparism purpose: run with xelatex
documentclass{article}
usepackage{pstricks,pst-math,pst-plot}
begin{document}
begin{pspicture}[algebraic](-5,-4)(5,4)
psaxes{->}(0,0)(-5,-4)(5,4)
psplot[linewidth=1.5pt,linecolor=blue]{1}{5}{ACOSH(x)}
psplot[linewidth=1.5pt,linecolor=red]{-5}{5}{ASINH(x)}
psplot[linewidth=1.5pt,linecolor=green]{-.999}{.999}{ATANH(x)}
end{pspicture}
end{document}
answered Dec 19 at 12:47
Herbert
269k24407717
add a comment |
4
4
4
For comparism purpose: run with xelatex
documentclass{article}
usepackage{pstricks,pst-math,pst-plot}
begin{document}
begin{pspicture}[algebraic](-5,-4)(5,4)
psaxes{->}(0,0)(-5,-4)(5,4)
psplot[linewidth=1.5pt,linecolor=blue]{1}{5}{ACOSH(x)}
psplot[linewidth=1.5pt,linecolor=red]{-5}{5}{ASINH(x)}
psplot[linewidth=1.5pt,linecolor=green]{-.999}{.999}{ATANH(x)}
end{pspicture}
end{document}
answered Dec 19 at 12:47
Herbert
269k24407717
For comparism purpose: run with xelatex
documentclass{article}
usepackage{pstricks,pst-math,pst-plot}
begin{document}
begin{pspicture}[algebraic](-5,-4)(5,4)
psaxes{->}(0,0)(-5,-4)(5,4)
psplot[linewidth=1.5pt,linecolor=blue]{1}{5}{ACOSH(x)}
psplot[linewidth=1.5pt,linecolor=red]{-5}{5}{ASINH(x)}
psplot[linewidth=1.5pt,linecolor=green]{-.999}{.999}{ATANH(x)}
end{pspicture}
end{document}
answered Dec 19 at 12:47
Herbert
269k24407717
answered Dec 19 at 12:47
Herbert
269k24407717
answered Dec 19 at 12:47
Herbert
269k24407717
answered Dec 19 at 12:47
Herbert
269k24407717
269k24407717
add a comment |
add a comment |
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