Active filter with series inductor and resistor - do these exist?





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I have seen (online) and in books basic active filters (involving an op-amp) with a series R C branch at the input side. This series R C branch at the input side would make the circuit a high-pass filter. Series RC configuration at the input is quite commonly seen online. However, there appear to be no circuit diagrams seen online involving series R and L (resistor and inductor in series) for the input branch, as shown below in the drawing. enter image description here



There is likely some reasons for no diagrams like this seen online - anywhere. I don't know those reasons, and definitely interested to know why. Anyone know if op-amp configurations with series RL inputs are not seen? Thanks in advance for any comments!










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    $begingroup$


    I have seen (online) and in books basic active filters (involving an op-amp) with a series R C branch at the input side. This series R C branch at the input side would make the circuit a high-pass filter. Series RC configuration at the input is quite commonly seen online. However, there appear to be no circuit diagrams seen online involving series R and L (resistor and inductor in series) for the input branch, as shown below in the drawing. enter image description here



    There is likely some reasons for no diagrams like this seen online - anywhere. I don't know those reasons, and definitely interested to know why. Anyone know if op-amp configurations with series RL inputs are not seen? Thanks in advance for any comments!










    share|improve this question









    New contributor




    Kenny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      2












      2








      2





      $begingroup$


      I have seen (online) and in books basic active filters (involving an op-amp) with a series R C branch at the input side. This series R C branch at the input side would make the circuit a high-pass filter. Series RC configuration at the input is quite commonly seen online. However, there appear to be no circuit diagrams seen online involving series R and L (resistor and inductor in series) for the input branch, as shown below in the drawing. enter image description here



      There is likely some reasons for no diagrams like this seen online - anywhere. I don't know those reasons, and definitely interested to know why. Anyone know if op-amp configurations with series RL inputs are not seen? Thanks in advance for any comments!










      share|improve this question









      New contributor




      Kenny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I have seen (online) and in books basic active filters (involving an op-amp) with a series R C branch at the input side. This series R C branch at the input side would make the circuit a high-pass filter. Series RC configuration at the input is quite commonly seen online. However, there appear to be no circuit diagrams seen online involving series R and L (resistor and inductor in series) for the input branch, as shown below in the drawing. enter image description here



      There is likely some reasons for no diagrams like this seen online - anywhere. I don't know those reasons, and definitely interested to know why. Anyone know if op-amp configurations with series RL inputs are not seen? Thanks in advance for any comments!







      active-filter






      share|improve this question









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      Kenny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









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      Kenny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      edited 4 hours ago







      Kenny













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      asked 4 hours ago









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      New contributor




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      New contributor





      Kenny is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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          1 Answer
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          $begingroup$

          Inductors are generally more expensive, more bulky and less ideal than capacitors so you'll usually see a strong preference for capacitors over inductors.



          However, series inductance is frequently used where conductors enter a shielded enclosure or signals enter a PCB. Sometimes as inductors, sometimes as ferrite beads (which are inductive over a range of frequencies) and sometimes as common-mode chokes.






          share|improve this answer









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          • 1




            $begingroup$
            Thanks very much for your help Spehro! Really appreciated that a lot. I attempted to add +1 to your reply, but getting a popup message that says users with less than some number of reputation points can't do the +1 (or something like that!). Thanks again!
            $endgroup$
            – Kenny
            4 hours ago








          • 1




            $begingroup$
            You won't be able to upvote comments until you get more reputation, but you can accept answers or not. It's recommended to wait some time before accepting a given answer because a better answer may come along.
            $endgroup$
            – Spehro Pefhany
            4 hours ago












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          1 Answer
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          1 Answer
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          active

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          active

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          3












          $begingroup$

          Inductors are generally more expensive, more bulky and less ideal than capacitors so you'll usually see a strong preference for capacitors over inductors.



          However, series inductance is frequently used where conductors enter a shielded enclosure or signals enter a PCB. Sometimes as inductors, sometimes as ferrite beads (which are inductive over a range of frequencies) and sometimes as common-mode chokes.






          share|improve this answer









          $endgroup$









          • 1




            $begingroup$
            Thanks very much for your help Spehro! Really appreciated that a lot. I attempted to add +1 to your reply, but getting a popup message that says users with less than some number of reputation points can't do the +1 (or something like that!). Thanks again!
            $endgroup$
            – Kenny
            4 hours ago








          • 1




            $begingroup$
            You won't be able to upvote comments until you get more reputation, but you can accept answers or not. It's recommended to wait some time before accepting a given answer because a better answer may come along.
            $endgroup$
            – Spehro Pefhany
            4 hours ago
















          3












          $begingroup$

          Inductors are generally more expensive, more bulky and less ideal than capacitors so you'll usually see a strong preference for capacitors over inductors.



          However, series inductance is frequently used where conductors enter a shielded enclosure or signals enter a PCB. Sometimes as inductors, sometimes as ferrite beads (which are inductive over a range of frequencies) and sometimes as common-mode chokes.






          share|improve this answer









          $endgroup$









          • 1




            $begingroup$
            Thanks very much for your help Spehro! Really appreciated that a lot. I attempted to add +1 to your reply, but getting a popup message that says users with less than some number of reputation points can't do the +1 (or something like that!). Thanks again!
            $endgroup$
            – Kenny
            4 hours ago








          • 1




            $begingroup$
            You won't be able to upvote comments until you get more reputation, but you can accept answers or not. It's recommended to wait some time before accepting a given answer because a better answer may come along.
            $endgroup$
            – Spehro Pefhany
            4 hours ago














          3












          3








          3





          $begingroup$

          Inductors are generally more expensive, more bulky and less ideal than capacitors so you'll usually see a strong preference for capacitors over inductors.



          However, series inductance is frequently used where conductors enter a shielded enclosure or signals enter a PCB. Sometimes as inductors, sometimes as ferrite beads (which are inductive over a range of frequencies) and sometimes as common-mode chokes.






          share|improve this answer









          $endgroup$



          Inductors are generally more expensive, more bulky and less ideal than capacitors so you'll usually see a strong preference for capacitors over inductors.



          However, series inductance is frequently used where conductors enter a shielded enclosure or signals enter a PCB. Sometimes as inductors, sometimes as ferrite beads (which are inductive over a range of frequencies) and sometimes as common-mode chokes.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 4 hours ago









          Spehro PefhanySpehro Pefhany

          214k5162432




          214k5162432








          • 1




            $begingroup$
            Thanks very much for your help Spehro! Really appreciated that a lot. I attempted to add +1 to your reply, but getting a popup message that says users with less than some number of reputation points can't do the +1 (or something like that!). Thanks again!
            $endgroup$
            – Kenny
            4 hours ago








          • 1




            $begingroup$
            You won't be able to upvote comments until you get more reputation, but you can accept answers or not. It's recommended to wait some time before accepting a given answer because a better answer may come along.
            $endgroup$
            – Spehro Pefhany
            4 hours ago














          • 1




            $begingroup$
            Thanks very much for your help Spehro! Really appreciated that a lot. I attempted to add +1 to your reply, but getting a popup message that says users with less than some number of reputation points can't do the +1 (or something like that!). Thanks again!
            $endgroup$
            – Kenny
            4 hours ago








          • 1




            $begingroup$
            You won't be able to upvote comments until you get more reputation, but you can accept answers or not. It's recommended to wait some time before accepting a given answer because a better answer may come along.
            $endgroup$
            – Spehro Pefhany
            4 hours ago








          1




          1




          $begingroup$
          Thanks very much for your help Spehro! Really appreciated that a lot. I attempted to add +1 to your reply, but getting a popup message that says users with less than some number of reputation points can't do the +1 (or something like that!). Thanks again!
          $endgroup$
          – Kenny
          4 hours ago






          $begingroup$
          Thanks very much for your help Spehro! Really appreciated that a lot. I attempted to add +1 to your reply, but getting a popup message that says users with less than some number of reputation points can't do the +1 (or something like that!). Thanks again!
          $endgroup$
          – Kenny
          4 hours ago






          1




          1




          $begingroup$
          You won't be able to upvote comments until you get more reputation, but you can accept answers or not. It's recommended to wait some time before accepting a given answer because a better answer may come along.
          $endgroup$
          – Spehro Pefhany
          4 hours ago




          $begingroup$
          You won't be able to upvote comments until you get more reputation, but you can accept answers or not. It's recommended to wait some time before accepting a given answer because a better answer may come along.
          $endgroup$
          – Spehro Pefhany
          4 hours ago










          Kenny is a new contributor. Be nice, and check out our Code of Conduct.










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