square the elements of a sorted list and give the output in sorted order
$begingroup$
Given a sorted list of integers, square the elements and give the
output in sorted order.
For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].
My solution 1:
const square = el => el * el;
const sortAsc = (a, b) => a - b;
const sortSquare = list => list
.map(square)
.sort(sortAsc);
console.log(sortSquare([-9, -2, 0, 2, 3]));
My solution 2:
const sortSquare2 = list => {
const result = ;
list.sort((a, b) => Math.abs(a) - Math.abs(b));
for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
return result;
};
console.log(sortSquare2([-9, -2, 0, 2, 3]));
Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 2 mins ago
thadeuszlaythadeuszlay
548214
$endgroup$
add a comment |
$begingroup$
Given a sorted list of integers, square the elements and give the
output in sorted order.
For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].
My solution 1:
const square = el => el * el;
const sortAsc = (a, b) => a - b;
const sortSquare = list => list
.map(square)
.sort(sortAsc);
console.log(sortSquare([-9, -2, 0, 2, 3]));
My solution 2:
const sortSquare2 = list => {
const result = ;
list.sort((a, b) => Math.abs(a) - Math.abs(b));
for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
return result;
};
console.log(sortSquare2([-9, -2, 0, 2, 3]));
Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 2 mins ago
thadeuszlaythadeuszlay
548214
$endgroup$
add a comment |
$begingroup$
Given a sorted list of integers, square the elements and give the
output in sorted order.
For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].
My solution 1:
const square = el => el * el;
const sortAsc = (a, b) => a - b;
const sortSquare = list => list
.map(square)
.sort(sortAsc);
console.log(sortSquare([-9, -2, 0, 2, 3]));
My solution 2:
const sortSquare2 = list => {
const result = ;
list.sort((a, b) => Math.abs(a) - Math.abs(b));
for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
return result;
};
console.log(sortSquare2([-9, -2, 0, 2, 3]));
Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 2 mins ago
thadeuszlaythadeuszlay
548214
$endgroup$
Given a sorted list of integers, square the elements and give the
output in sorted order.
For example, given [-9, -2, 0, 2, 3], return [0, 4, 4, 9, 81].
My solution 1:
const square = el => el * el;
const sortAsc = (a, b) => a - b;
const sortSquare = list => list
.map(square)
.sort(sortAsc);
console.log(sortSquare([-9, -2, 0, 2, 3]));
My solution 2:
const sortSquare2 = list => {
const result = ;
list.sort((a, b) => Math.abs(a) - Math.abs(b));
for (let i = 0; i < list.length; i++) { result.push(Math.pow(list[i], 2)); }
return result;
};
console.log(sortSquare2([-9, -2, 0, 2, 3]));
Is there a faster solution? I have the feeling you can do something with the fact that the list is sorted to begin with. But I can't think of a good one.
javascript algorithm programming-challenge functional-programming ecmascript-6
javascript algorithm programming-challenge functional-programming ecmascript-6
asked 2 mins ago
thadeuszlaythadeuszlay
548214
asked 2 mins ago
thadeuszlaythadeuszlay
548214
asked 2 mins ago
thadeuszlaythadeuszlay
548214
asked 2 mins ago
thadeuszlaythadeuszlay
548214
asked 2 mins ago
thadeuszlaythadeuszlay
548214
548214
add a comment |
add a comment |
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