What's the radius?
I have a book of puzzles from 1972 with the pretentious title, "Games for the Superintelligent" by James Fixx. One puzzle had me thinking for a couple of days:
I drew it out, thought about different ways of attacking it, and eventually gave up and looked up the answer in the back of the book.
See if you can do better than me and figure out the answer on your own!
geometry
edited Dec 23 at 20:57
ABcDexter
5,00133173
asked Dec 23 at 19:31
WhiteHotLoveTiger
1815
New contributor
WhiteHotLoveTiger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I have a book of puzzles from 1972 with the pretentious title, "Games for the Superintelligent" by James Fixx. One puzzle had me thinking for a couple of days:
I drew it out, thought about different ways of attacking it, and eventually gave up and looked up the answer in the back of the book.
See if you can do better than me and figure out the answer on your own!
geometry
edited Dec 23 at 20:57
ABcDexter
5,00133173
asked Dec 23 at 19:31
WhiteHotLoveTiger
1815
New contributor
WhiteHotLoveTiger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Welcome to Puzzling :D
– ABcDexter
Dec 23 at 20:50
1
I feel like this should go on Math.SE. It's just elementary math, rather than a "puzzle".
– Hugh
Dec 23 at 21:24
2
Fun trivia*: Richard Feynman was stumped by a similar problem! (*source: It's a bit of telephone game, as the source is Walter Bender’s webpage which shares a story told by Oliver Selfridge: web.media.mit.edu/~walter/MAS-A12/week11.html)
– Presh
Dec 24 at 9:19
1
This was a lot of fun. I sat down with my wife for ten minutes trying to crack this. We ended up trying to rewrite things in terms of the usual polar coordinates and facepalmed when the answer spilled out.
– user1717828
Dec 24 at 18:04
That was a great puzzle! (Are the other puzzles in the book just as fun? I am going to look for it)
– BruceWayne
Dec 24 at 23:31
add a comment |
I have a book of puzzles from 1972 with the pretentious title, "Games for the Superintelligent" by James Fixx. One puzzle had me thinking for a couple of days:
I drew it out, thought about different ways of attacking it, and eventually gave up and looked up the answer in the back of the book.
See if you can do better than me and figure out the answer on your own!
geometry
edited Dec 23 at 20:57
ABcDexter
5,00133173
asked Dec 23 at 19:31
WhiteHotLoveTiger
1815
New contributor
WhiteHotLoveTiger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have a book of puzzles from 1972 with the pretentious title, "Games for the Superintelligent" by James Fixx. One puzzle had me thinking for a couple of days:
I drew it out, thought about different ways of attacking it, and eventually gave up and looked up the answer in the back of the book.
See if you can do better than me and figure out the answer on your own!
geometry
geometry
edited Dec 23 at 20:57
ABcDexter
5,00133173
asked Dec 23 at 19:31
WhiteHotLoveTiger
1815
New contributor
WhiteHotLoveTiger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 23 at 20:57
ABcDexter
5,00133173
asked Dec 23 at 19:31
WhiteHotLoveTiger
1815
New contributor
WhiteHotLoveTiger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 23 at 20:57
ABcDexter
5,00133173
edited Dec 23 at 20:57
ABcDexter
5,00133173
edited Dec 23 at 20:57
ABcDexter
5,00133173
5,00133173
asked Dec 23 at 19:31
WhiteHotLoveTiger
1815
New contributor
WhiteHotLoveTiger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 23 at 19:31
WhiteHotLoveTiger
1815
asked Dec 23 at 19:31
WhiteHotLoveTiger
1815
1815
New contributor
WhiteHotLoveTiger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
WhiteHotLoveTiger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
WhiteHotLoveTiger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Welcome to Puzzling :D
– ABcDexter
Dec 23 at 20:50
1
I feel like this should go on Math.SE. It's just elementary math, rather than a "puzzle".
– Hugh
Dec 23 at 21:24
2
Fun trivia*: Richard Feynman was stumped by a similar problem! (*source: It's a bit of telephone game, as the source is Walter Bender’s webpage which shares a story told by Oliver Selfridge: web.media.mit.edu/~walter/MAS-A12/week11.html)
– Presh
Dec 24 at 9:19
1
This was a lot of fun. I sat down with my wife for ten minutes trying to crack this. We ended up trying to rewrite things in terms of the usual polar coordinates and facepalmed when the answer spilled out.
– user1717828
Dec 24 at 18:04
That was a great puzzle! (Are the other puzzles in the book just as fun? I am going to look for it)
– BruceWayne
Dec 24 at 23:31
add a comment |
Welcome to Puzzling :D
– ABcDexter
Dec 23 at 20:50
1
I feel like this should go on Math.SE. It's just elementary math, rather than a "puzzle".
– Hugh
Dec 23 at 21:24
2
Fun trivia*: Richard Feynman was stumped by a similar problem! (*source: It's a bit of telephone game, as the source is Walter Bender’s webpage which shares a story told by Oliver Selfridge: web.media.mit.edu/~walter/MAS-A12/week11.html)
– Presh
Dec 24 at 9:19
1
This was a lot of fun. I sat down with my wife for ten minutes trying to crack this. We ended up trying to rewrite things in terms of the usual polar coordinates and facepalmed when the answer spilled out.
– user1717828
Dec 24 at 18:04
That was a great puzzle! (Are the other puzzles in the book just as fun? I am going to look for it)
– BruceWayne
Dec 24 at 23:31
Welcome to Puzzling :D
– ABcDexter
Dec 23 at 20:50
Welcome to Puzzling :D
– ABcDexter
Dec 23 at 20:50
1
1
I feel like this should go on Math.SE. It's just elementary math, rather than a "puzzle".
– Hugh
Dec 23 at 21:24
I feel like this should go on Math.SE. It's just elementary math, rather than a "puzzle".
– Hugh
Dec 23 at 21:24
2
2
Fun trivia*: Richard Feynman was stumped by a similar problem! (*source: It's a bit of telephone game, as the source is Walter Bender’s webpage which shares a story told by Oliver Selfridge: web.media.mit.edu/~walter/MAS-A12/week11.html)
– Presh
Dec 24 at 9:19
Fun trivia*: Richard Feynman was stumped by a similar problem! (*source: It's a bit of telephone game, as the source is Walter Bender’s webpage which shares a story told by Oliver Selfridge: web.media.mit.edu/~walter/MAS-A12/week11.html)
– Presh
Dec 24 at 9:19
1
1
This was a lot of fun. I sat down with my wife for ten minutes trying to crack this. We ended up trying to rewrite things in terms of the usual polar coordinates and facepalmed when the answer spilled out.
– user1717828
Dec 24 at 18:04
This was a lot of fun. I sat down with my wife for ten minutes trying to crack this. We ended up trying to rewrite things in terms of the usual polar coordinates and facepalmed when the answer spilled out.
– user1717828
Dec 24 at 18:04
That was a great puzzle! (Are the other puzzles in the book just as fun? I am going to look for it)
– BruceWayne
Dec 24 at 23:31
That was a great puzzle! (Are the other puzzles in the book just as fun? I am going to look for it)
– BruceWayne
Dec 24 at 23:31
add a comment |
4 Answers
4
active
oldest
votes
Is it:
8 inches. Because the other diagonal of the same rectangle is also $8^"$, which coincidentally, is also the radius of the circle.
edited 2 days ago
Benjamin Lee
33
answered Dec 23 at 19:43
JonMark Perry
17.4k63483
2
"the rectangle with the 8′′ marked other diagonal is the radius", so basically "the rectangle ... is the radius"? That seem ungrammatical to me.
– hkBst
Dec 25 at 9:50
add a comment |
Lol! If you're using Pythagorus you're doing it wrong :-)
8" Draw a diagonal line between the other 2 corners of the rectangle. You'll immediately see the answer and then you'll be kicking yourself!
answered Dec 24 at 10:25
Gazzer
1411
New contributor
Gazzer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
So,
A right-angled square rests plumb atop the diameter of a circle. The distance from the square edge to the circle’s edge is 3”, so then the radius of the circle would be the 5” of the square arm, which is at right angles at two arms spread from opposite the hypotenuse in a meeting of two mirrored triangles; added to the 3” of extension to the circle’s edge -resulting in a radius measurement of a combined(square arm+extension to circle edge) 8”.
I solved this visually first, but then challenged myself to articulate. I still feel rocky about the explanation and should have drawn it out to clarify as I have been taught instinctual to “show my work.”
answered yesterday
Adam Borchardt
1
New contributor
Adam Borchardt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
Radius.......
From the word we can understood that it means that half of any object...
But your subject is geometry so:
If we consider a circle it is the half of the diameter of the circle...
So, according to your question...
Your answer is 8 inches. Because the rectangle with the 8′′ marked other diagonal is the radius, and this is also 8′′ long
edited Dec 24 at 17:51
Ahmed Ashour
948212
answered Dec 24 at 14:08
arka
1
New contributor
arka is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
The first three fourths of your question is just regurgitating definitions (and not even the correct one, at first: I'm not aware of any definition of "radius" being "half of any object), and the rest is just repeating what other answers have said.
– Acccumulation
Dec 24 at 16:10
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "559"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
WhiteHotLoveTiger is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f77733%2fwhats-the-radius%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Is it:
8 inches. Because the other diagonal of the same rectangle is also $8^"$, which coincidentally, is also the radius of the circle.
edited 2 days ago
Benjamin Lee
33
answered Dec 23 at 19:43
JonMark Perry
17.4k63483
2
"the rectangle with the 8′′ marked other diagonal is the radius", so basically "the rectangle ... is the radius"? That seem ungrammatical to me.
– hkBst
Dec 25 at 9:50
add a comment |
Is it:
8 inches. Because the other diagonal of the same rectangle is also $8^"$, which coincidentally, is also the radius of the circle.
edited 2 days ago
Benjamin Lee
33
answered Dec 23 at 19:43
JonMark Perry
17.4k63483
2
"the rectangle with the 8′′ marked other diagonal is the radius", so basically "the rectangle ... is the radius"? That seem ungrammatical to me.
– hkBst
Dec 25 at 9:50
add a comment |
Is it:
8 inches. Because the other diagonal of the same rectangle is also $8^"$, which coincidentally, is also the radius of the circle.
edited 2 days ago
Benjamin Lee
33
answered Dec 23 at 19:43
JonMark Perry
17.4k63483
Is it:
8 inches. Because the other diagonal of the same rectangle is also $8^"$, which coincidentally, is also the radius of the circle.
edited 2 days ago
Benjamin Lee
33
answered Dec 23 at 19:43
JonMark Perry
17.4k63483
edited 2 days ago
Benjamin Lee
33
edited 2 days ago
Benjamin Lee
33
edited 2 days ago
Benjamin Lee
33
33
answered Dec 23 at 19:43
JonMark Perry
17.4k63483
answered Dec 23 at 19:43
JonMark Perry
17.4k63483
answered Dec 23 at 19:43
JonMark Perry
17.4k63483
17.4k63483
2
"the rectangle with the 8′′ marked other diagonal is the radius", so basically "the rectangle ... is the radius"? That seem ungrammatical to me.
– hkBst
Dec 25 at 9:50
add a comment |
2
"the rectangle with the 8′′ marked other diagonal is the radius", so basically "the rectangle ... is the radius"? That seem ungrammatical to me.
– hkBst
Dec 25 at 9:50
2
2
"the rectangle with the 8′′ marked other diagonal is the radius", so basically "the rectangle ... is the radius"? That seem ungrammatical to me.
– hkBst
Dec 25 at 9:50
"the rectangle with the 8′′ marked other diagonal is the radius", so basically "the rectangle ... is the radius"? That seem ungrammatical to me.
– hkBst
Dec 25 at 9:50
add a comment |
Lol! If you're using Pythagorus you're doing it wrong :-)
8" Draw a diagonal line between the other 2 corners of the rectangle. You'll immediately see the answer and then you'll be kicking yourself!
answered Dec 24 at 10:25
Gazzer
1411
New contributor
Gazzer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
Lol! If you're using Pythagorus you're doing it wrong :-)
8" Draw a diagonal line between the other 2 corners of the rectangle. You'll immediately see the answer and then you'll be kicking yourself!
answered Dec 24 at 10:25
Gazzer
1411
New contributor
Gazzer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
Lol! If you're using Pythagorus you're doing it wrong :-)
8" Draw a diagonal line between the other 2 corners of the rectangle. You'll immediately see the answer and then you'll be kicking yourself!
answered Dec 24 at 10:25
Gazzer
1411
New contributor
Gazzer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Lol! If you're using Pythagorus you're doing it wrong :-)
8" Draw a diagonal line between the other 2 corners of the rectangle. You'll immediately see the answer and then you'll be kicking yourself!
answered Dec 24 at 10:25
Gazzer
1411
New contributor
Gazzer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Dec 24 at 10:25
Gazzer
1411
New contributor
Gazzer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Dec 24 at 10:25
Gazzer
1411
answered Dec 24 at 10:25
Gazzer
1411
1411
New contributor
Gazzer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Gazzer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Gazzer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
So,
A right-angled square rests plumb atop the diameter of a circle. The distance from the square edge to the circle’s edge is 3”, so then the radius of the circle would be the 5” of the square arm, which is at right angles at two arms spread from opposite the hypotenuse in a meeting of two mirrored triangles; added to the 3” of extension to the circle’s edge -resulting in a radius measurement of a combined(square arm+extension to circle edge) 8”.
I solved this visually first, but then challenged myself to articulate. I still feel rocky about the explanation and should have drawn it out to clarify as I have been taught instinctual to “show my work.”
answered yesterday
Adam Borchardt
1
New contributor
Adam Borchardt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
So,
A right-angled square rests plumb atop the diameter of a circle. The distance from the square edge to the circle’s edge is 3”, so then the radius of the circle would be the 5” of the square arm, which is at right angles at two arms spread from opposite the hypotenuse in a meeting of two mirrored triangles; added to the 3” of extension to the circle’s edge -resulting in a radius measurement of a combined(square arm+extension to circle edge) 8”.
I solved this visually first, but then challenged myself to articulate. I still feel rocky about the explanation and should have drawn it out to clarify as I have been taught instinctual to “show my work.”
answered yesterday
Adam Borchardt
1
New contributor
Adam Borchardt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
So,
A right-angled square rests plumb atop the diameter of a circle. The distance from the square edge to the circle’s edge is 3”, so then the radius of the circle would be the 5” of the square arm, which is at right angles at two arms spread from opposite the hypotenuse in a meeting of two mirrored triangles; added to the 3” of extension to the circle’s edge -resulting in a radius measurement of a combined(square arm+extension to circle edge) 8”.
I solved this visually first, but then challenged myself to articulate. I still feel rocky about the explanation and should have drawn it out to clarify as I have been taught instinctual to “show my work.”
answered yesterday
Adam Borchardt
1
New contributor
Adam Borchardt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
So,
A right-angled square rests plumb atop the diameter of a circle. The distance from the square edge to the circle’s edge is 3”, so then the radius of the circle would be the 5” of the square arm, which is at right angles at two arms spread from opposite the hypotenuse in a meeting of two mirrored triangles; added to the 3” of extension to the circle’s edge -resulting in a radius measurement of a combined(square arm+extension to circle edge) 8”.
I solved this visually first, but then challenged myself to articulate. I still feel rocky about the explanation and should have drawn it out to clarify as I have been taught instinctual to “show my work.”
answered yesterday
Adam Borchardt
1
New contributor
Adam Borchardt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
Adam Borchardt
1
New contributor
Adam Borchardt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
Adam Borchardt
1
answered yesterday
Adam Borchardt
1
1
New contributor
Adam Borchardt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Adam Borchardt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Adam Borchardt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
Radius.......
From the word we can understood that it means that half of any object...
But your subject is geometry so:
If we consider a circle it is the half of the diameter of the circle...
So, according to your question...
Your answer is 8 inches. Because the rectangle with the 8′′ marked other diagonal is the radius, and this is also 8′′ long
edited Dec 24 at 17:51
Ahmed Ashour
948212
answered Dec 24 at 14:08
arka
1
New contributor
arka is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
The first three fourths of your question is just regurgitating definitions (and not even the correct one, at first: I'm not aware of any definition of "radius" being "half of any object), and the rest is just repeating what other answers have said.
– Acccumulation
Dec 24 at 16:10
add a comment |
Radius.......
From the word we can understood that it means that half of any object...
But your subject is geometry so:
If we consider a circle it is the half of the diameter of the circle...
So, according to your question...
Your answer is 8 inches. Because the rectangle with the 8′′ marked other diagonal is the radius, and this is also 8′′ long
edited Dec 24 at 17:51
Ahmed Ashour
948212
answered Dec 24 at 14:08
arka
1
New contributor
arka is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
The first three fourths of your question is just regurgitating definitions (and not even the correct one, at first: I'm not aware of any definition of "radius" being "half of any object), and the rest is just repeating what other answers have said.
– Acccumulation
Dec 24 at 16:10
add a comment |
Radius.......
From the word we can understood that it means that half of any object...
But your subject is geometry so:
If we consider a circle it is the half of the diameter of the circle...
So, according to your question...
Your answer is 8 inches. Because the rectangle with the 8′′ marked other diagonal is the radius, and this is also 8′′ long
edited Dec 24 at 17:51
Ahmed Ashour
948212
answered Dec 24 at 14:08
arka
1
New contributor
arka is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Radius.......
From the word we can understood that it means that half of any object...
But your subject is geometry so:
If we consider a circle it is the half of the diameter of the circle...
So, according to your question...
Your answer is 8 inches. Because the rectangle with the 8′′ marked other diagonal is the radius, and this is also 8′′ long
edited Dec 24 at 17:51
Ahmed Ashour
948212
answered Dec 24 at 14:08
arka
1
New contributor
arka is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 24 at 17:51
Ahmed Ashour
948212
edited Dec 24 at 17:51
Ahmed Ashour
948212
edited Dec 24 at 17:51
Ahmed Ashour
948212
948212
answered Dec 24 at 14:08
arka
1
New contributor
arka is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Dec 24 at 14:08
arka
1
answered Dec 24 at 14:08
arka
1
1
New contributor
arka is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
arka is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
arka is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
The first three fourths of your question is just regurgitating definitions (and not even the correct one, at first: I'm not aware of any definition of "radius" being "half of any object), and the rest is just repeating what other answers have said.
– Acccumulation
Dec 24 at 16:10
add a comment |
2
The first three fourths of your question is just regurgitating definitions (and not even the correct one, at first: I'm not aware of any definition of "radius" being "half of any object), and the rest is just repeating what other answers have said.
– Acccumulation
Dec 24 at 16:10
2
2
The first three fourths of your question is just regurgitating definitions (and not even the correct one, at first: I'm not aware of any definition of "radius" being "half of any object), and the rest is just repeating what other answers have said.
– Acccumulation
Dec 24 at 16:10
The first three fourths of your question is just regurgitating definitions (and not even the correct one, at first: I'm not aware of any definition of "radius" being "half of any object), and the rest is just repeating what other answers have said.
– Acccumulation
Dec 24 at 16:10
add a comment |
WhiteHotLoveTiger is a new contributor. Be nice, and check out our Code of Conduct.
WhiteHotLoveTiger is a new contributor. Be nice, and check out our Code of Conduct.
WhiteHotLoveTiger is a new contributor. Be nice, and check out our Code of Conduct.
WhiteHotLoveTiger is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f77733%2fwhats-the-radius%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Welcome to Puzzling :D
– ABcDexter
Dec 23 at 20:50
1
I feel like this should go on Math.SE. It's just elementary math, rather than a "puzzle".
– Hugh
Dec 23 at 21:24
2
Fun trivia*: Richard Feynman was stumped by a similar problem! (*source: It's a bit of telephone game, as the source is Walter Bender’s webpage which shares a story told by Oliver Selfridge: web.media.mit.edu/~walter/MAS-A12/week11.html)
– Presh
Dec 24 at 9:19
1
This was a lot of fun. I sat down with my wife for ten minutes trying to crack this. We ended up trying to rewrite things in terms of the usual polar coordinates and facepalmed when the answer spilled out.
– user1717828
Dec 24 at 18:04
That was a great puzzle! (Are the other puzzles in the book just as fun? I am going to look for it)
– BruceWayne
Dec 24 at 23:31