Plotting an Equation Using ParametricNDSolve












4














I'm trying to plot the solution of a set of differential equations and see how the solution changes when the value of a certain variable de is changed. The equations have solutions to the values of de which I have gotten individually using NDSolve but I am unable to replicate the result for all required values of de in one single program. I code I have written is:



om = 1;
k = 1;
L = 0.001;
P = 1.3;
eqns = {
a'[t] == I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t]
-1/2) - (k/(2*om))*a[t],
b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
b[0] == 0, a[0] == 0};
s = ParametricNDSolve[eqns, {a[t], b[t]}, {t, 0, 100}, de,
MaxSteps -> [Infinity]]
x[de] = b[de] + Conjugate[b[de]]
Manipulate[Plot[Evaluate[x[de][t] ], {t, 0, 99}, PlotRange
-> All], {de, 0.1, 1}]


I have tried everything that I knew in my limited knowledge of Mathematica but I couldn't get a solution. I hope someone can help me with this.



Thank you very much for your help!










share|improve this question







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    4














    I'm trying to plot the solution of a set of differential equations and see how the solution changes when the value of a certain variable de is changed. The equations have solutions to the values of de which I have gotten individually using NDSolve but I am unable to replicate the result for all required values of de in one single program. I code I have written is:



    om = 1;
    k = 1;
    L = 0.001;
    P = 1.3;
    eqns = {
    a'[t] == I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t]
    -1/2) - (k/(2*om))*a[t],
    b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
    b[0] == 0, a[0] == 0};
    s = ParametricNDSolve[eqns, {a[t], b[t]}, {t, 0, 100}, de,
    MaxSteps -> [Infinity]]
    x[de] = b[de] + Conjugate[b[de]]
    Manipulate[Plot[Evaluate[x[de][t] ], {t, 0, 99}, PlotRange
    -> All], {de, 0.1, 1}]


    I have tried everything that I knew in my limited knowledge of Mathematica but I couldn't get a solution. I hope someone can help me with this.



    Thank you very much for your help!










    share|improve this question







    New contributor




    Manik Kapil is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      4












      4








      4


      2





      I'm trying to plot the solution of a set of differential equations and see how the solution changes when the value of a certain variable de is changed. The equations have solutions to the values of de which I have gotten individually using NDSolve but I am unable to replicate the result for all required values of de in one single program. I code I have written is:



      om = 1;
      k = 1;
      L = 0.001;
      P = 1.3;
      eqns = {
      a'[t] == I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t]
      -1/2) - (k/(2*om))*a[t],
      b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
      b[0] == 0, a[0] == 0};
      s = ParametricNDSolve[eqns, {a[t], b[t]}, {t, 0, 100}, de,
      MaxSteps -> [Infinity]]
      x[de] = b[de] + Conjugate[b[de]]
      Manipulate[Plot[Evaluate[x[de][t] ], {t, 0, 99}, PlotRange
      -> All], {de, 0.1, 1}]


      I have tried everything that I knew in my limited knowledge of Mathematica but I couldn't get a solution. I hope someone can help me with this.



      Thank you very much for your help!










      share|improve this question







      New contributor




      Manik Kapil is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I'm trying to plot the solution of a set of differential equations and see how the solution changes when the value of a certain variable de is changed. The equations have solutions to the values of de which I have gotten individually using NDSolve but I am unable to replicate the result for all required values of de in one single program. I code I have written is:



      om = 1;
      k = 1;
      L = 0.001;
      P = 1.3;
      eqns = {
      a'[t] == I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t]
      -1/2) - (k/(2*om))*a[t],
      b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
      b[0] == 0, a[0] == 0};
      s = ParametricNDSolve[eqns, {a[t], b[t]}, {t, 0, 100}, de,
      MaxSteps -> [Infinity]]
      x[de] = b[de] + Conjugate[b[de]]
      Manipulate[Plot[Evaluate[x[de][t] ], {t, 0, 99}, PlotRange
      -> All], {de, 0.1, 1}]


      I have tried everything that I knew in my limited knowledge of Mathematica but I couldn't get a solution. I hope someone can help me with this.



      Thank you very much for your help!







      differential-equations physics parametric-functions






      share|improve this question







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      asked Dec 23 at 17:50









      Manik Kapil

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          3 Answers
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          active

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          4














          Clear["Global`*"]

          om = 1;
          k = 1;
          L = 1/1000;
          P = 13/10;

          eqns = {a'[t] ==
          I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t] - 1/2) -
          (k/(2*om))*a[t],
          b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
          b[0] == 0, a[0] == 0};

          s = ParametricNDSolve[eqns, {a, b}, {t, 0, 100}, de, MaxSteps -> ∞];

          x[de_?NumericQ][t_?NumericQ] = (b[de][t] + Conjugate[b[de][t]]) /. s;

          Manipulate[
          Plot[x[de][t], {t, 0, 99}, PlotRange -> {-4, 4}], {de, 0.1, 1,
          Appearance -> "Labeled"}]


          enter image description here






          share|improve this answer































            2














            om = 1;
            k = 1;
            L = 0.001;
            P = 1.3;
            eqns = {a'[t] ==
            I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t] -
            1/2) - (k/(2*om))*a[t],
            b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
            b[0] == 0, a[0] == 0};
            s = ParametricNDSolve[eqns, {a[t], b[t]}, {t, 0, 100}, de,
            MaxSteps -> [Infinity]];
            x = b[t]/. s;
            Manipulate[
            Plot[x[de]+Conjugate[x[de]], {t, 0, 99}, PlotRange -> All], {de,
            0.1, 1}]


            When solving equations, Mathematica always returns solutions as substitution rules, then you have to use the /. operator to get a working function.



            Also, there is no need to write [t] when calling x[de] in the Plot command, as x[*some value*] returns PInterpolatingFunction[{{0., 100.}}, <>][t], which already has the [t] argument.






            share|improve this answer








            New contributor




            Mat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.


























              1














              Here is another variation that is somewhat more succinct than the other solutions.



              m = 1;
              k = 1;
              L = 0.001;
              P = 1.3;

              pF = ParametricNDSolveValue[eqns, {a, b}, {t, 0, 100}, de];

              Manipulate[
              With[{bF = pF[de][[2]]}, Plot[2 Re[bF[t]], {t, 0, 99}, PlotRange -> 4.1]],
              {de, .1, 1., .1, Appearance -> "Labeled"}]


              demo



              Notes





              • Reduce[z + Conjugate[z] == 2 Re[z], z]




                True




              • Specifying 4.1 for the plot range, fixes the y-axis scale and better demonstrates the growth of the curve as the parameter de varies.







              share|improve this answer























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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

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                active

                oldest

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                4














                Clear["Global`*"]

                om = 1;
                k = 1;
                L = 1/1000;
                P = 13/10;

                eqns = {a'[t] ==
                I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t] - 1/2) -
                (k/(2*om))*a[t],
                b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
                b[0] == 0, a[0] == 0};

                s = ParametricNDSolve[eqns, {a, b}, {t, 0, 100}, de, MaxSteps -> ∞];

                x[de_?NumericQ][t_?NumericQ] = (b[de][t] + Conjugate[b[de][t]]) /. s;

                Manipulate[
                Plot[x[de][t], {t, 0, 99}, PlotRange -> {-4, 4}], {de, 0.1, 1,
                Appearance -> "Labeled"}]


                enter image description here






                share|improve this answer




























                  4














                  Clear["Global`*"]

                  om = 1;
                  k = 1;
                  L = 1/1000;
                  P = 13/10;

                  eqns = {a'[t] ==
                  I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t] - 1/2) -
                  (k/(2*om))*a[t],
                  b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
                  b[0] == 0, a[0] == 0};

                  s = ParametricNDSolve[eqns, {a, b}, {t, 0, 100}, de, MaxSteps -> ∞];

                  x[de_?NumericQ][t_?NumericQ] = (b[de][t] + Conjugate[b[de][t]]) /. s;

                  Manipulate[
                  Plot[x[de][t], {t, 0, 99}, PlotRange -> {-4, 4}], {de, 0.1, 1,
                  Appearance -> "Labeled"}]


                  enter image description here






                  share|improve this answer


























                    4












                    4








                    4






                    Clear["Global`*"]

                    om = 1;
                    k = 1;
                    L = 1/1000;
                    P = 13/10;

                    eqns = {a'[t] ==
                    I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t] - 1/2) -
                    (k/(2*om))*a[t],
                    b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
                    b[0] == 0, a[0] == 0};

                    s = ParametricNDSolve[eqns, {a, b}, {t, 0, 100}, de, MaxSteps -> ∞];

                    x[de_?NumericQ][t_?NumericQ] = (b[de][t] + Conjugate[b[de][t]]) /. s;

                    Manipulate[
                    Plot[x[de][t], {t, 0, 99}, PlotRange -> {-4, 4}], {de, 0.1, 1,
                    Appearance -> "Labeled"}]


                    enter image description here






                    share|improve this answer














                    Clear["Global`*"]

                    om = 1;
                    k = 1;
                    L = 1/1000;
                    P = 13/10;

                    eqns = {a'[t] ==
                    I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t] - 1/2) -
                    (k/(2*om))*a[t],
                    b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
                    b[0] == 0, a[0] == 0};

                    s = ParametricNDSolve[eqns, {a, b}, {t, 0, 100}, de, MaxSteps -> ∞];

                    x[de_?NumericQ][t_?NumericQ] = (b[de][t] + Conjugate[b[de][t]]) /. s;

                    Manipulate[
                    Plot[x[de][t], {t, 0, 99}, PlotRange -> {-4, 4}], {de, 0.1, 1,
                    Appearance -> "Labeled"}]


                    enter image description here







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Dec 23 at 18:52

























                    answered Dec 23 at 18:46









                    Bob Hanlon

                    58.7k23595




                    58.7k23595























                        2














                        om = 1;
                        k = 1;
                        L = 0.001;
                        P = 1.3;
                        eqns = {a'[t] ==
                        I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t] -
                        1/2) - (k/(2*om))*a[t],
                        b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
                        b[0] == 0, a[0] == 0};
                        s = ParametricNDSolve[eqns, {a[t], b[t]}, {t, 0, 100}, de,
                        MaxSteps -> [Infinity]];
                        x = b[t]/. s;
                        Manipulate[
                        Plot[x[de]+Conjugate[x[de]], {t, 0, 99}, PlotRange -> All], {de,
                        0.1, 1}]


                        When solving equations, Mathematica always returns solutions as substitution rules, then you have to use the /. operator to get a working function.



                        Also, there is no need to write [t] when calling x[de] in the Plot command, as x[*some value*] returns PInterpolatingFunction[{{0., 100.}}, <>][t], which already has the [t] argument.






                        share|improve this answer








                        New contributor




                        Mat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                        Check out our Code of Conduct.























                          2














                          om = 1;
                          k = 1;
                          L = 0.001;
                          P = 1.3;
                          eqns = {a'[t] ==
                          I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t] -
                          1/2) - (k/(2*om))*a[t],
                          b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
                          b[0] == 0, a[0] == 0};
                          s = ParametricNDSolve[eqns, {a[t], b[t]}, {t, 0, 100}, de,
                          MaxSteps -> [Infinity]];
                          x = b[t]/. s;
                          Manipulate[
                          Plot[x[de]+Conjugate[x[de]], {t, 0, 99}, PlotRange -> All], {de,
                          0.1, 1}]


                          When solving equations, Mathematica always returns solutions as substitution rules, then you have to use the /. operator to get a working function.



                          Also, there is no need to write [t] when calling x[de] in the Plot command, as x[*some value*] returns PInterpolatingFunction[{{0., 100.}}, <>][t], which already has the [t] argument.






                          share|improve this answer








                          New contributor




                          Mat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.





















                            2












                            2








                            2






                            om = 1;
                            k = 1;
                            L = 0.001;
                            P = 1.3;
                            eqns = {a'[t] ==
                            I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t] -
                            1/2) - (k/(2*om))*a[t],
                            b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
                            b[0] == 0, a[0] == 0};
                            s = ParametricNDSolve[eqns, {a[t], b[t]}, {t, 0, 100}, de,
                            MaxSteps -> [Infinity]];
                            x = b[t]/. s;
                            Manipulate[
                            Plot[x[de]+Conjugate[x[de]], {t, 0, 99}, PlotRange -> All], {de,
                            0.1, 1}]


                            When solving equations, Mathematica always returns solutions as substitution rules, then you have to use the /. operator to get a working function.



                            Also, there is no need to write [t] when calling x[de] in the Plot command, as x[*some value*] returns PInterpolatingFunction[{{0., 100.}}, <>][t], which already has the [t] argument.






                            share|improve this answer








                            New contributor




                            Mat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.









                            om = 1;
                            k = 1;
                            L = 0.001;
                            P = 1.3;
                            eqns = {a'[t] ==
                            I*((de/om)*a[t] - (b[t] + Conjugate[b[t]])*a[t] -
                            1/2) - (k/(2*om))*a[t],
                            b'[t] == -I*((P*(Abs[a[t]])^2)/2 + b[t]) - (L/(2*om))*b[t],
                            b[0] == 0, a[0] == 0};
                            s = ParametricNDSolve[eqns, {a[t], b[t]}, {t, 0, 100}, de,
                            MaxSteps -> [Infinity]];
                            x = b[t]/. s;
                            Manipulate[
                            Plot[x[de]+Conjugate[x[de]], {t, 0, 99}, PlotRange -> All], {de,
                            0.1, 1}]


                            When solving equations, Mathematica always returns solutions as substitution rules, then you have to use the /. operator to get a working function.



                            Also, there is no need to write [t] when calling x[de] in the Plot command, as x[*some value*] returns PInterpolatingFunction[{{0., 100.}}, <>][t], which already has the [t] argument.







                            share|improve this answer








                            New contributor




                            Mat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.









                            share|improve this answer



                            share|improve this answer






                            New contributor




                            Mat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                            Check out our Code of Conduct.









                            answered Dec 23 at 19:11









                            Mat

                            312




                            312




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                            New contributor





                            Mat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                            Mat is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                                1














                                Here is another variation that is somewhat more succinct than the other solutions.



                                m = 1;
                                k = 1;
                                L = 0.001;
                                P = 1.3;

                                pF = ParametricNDSolveValue[eqns, {a, b}, {t, 0, 100}, de];

                                Manipulate[
                                With[{bF = pF[de][[2]]}, Plot[2 Re[bF[t]], {t, 0, 99}, PlotRange -> 4.1]],
                                {de, .1, 1., .1, Appearance -> "Labeled"}]


                                demo



                                Notes





                                • Reduce[z + Conjugate[z] == 2 Re[z], z]




                                  True




                                • Specifying 4.1 for the plot range, fixes the y-axis scale and better demonstrates the growth of the curve as the parameter de varies.







                                share|improve this answer




























                                  1














                                  Here is another variation that is somewhat more succinct than the other solutions.



                                  m = 1;
                                  k = 1;
                                  L = 0.001;
                                  P = 1.3;

                                  pF = ParametricNDSolveValue[eqns, {a, b}, {t, 0, 100}, de];

                                  Manipulate[
                                  With[{bF = pF[de][[2]]}, Plot[2 Re[bF[t]], {t, 0, 99}, PlotRange -> 4.1]],
                                  {de, .1, 1., .1, Appearance -> "Labeled"}]


                                  demo



                                  Notes





                                  • Reduce[z + Conjugate[z] == 2 Re[z], z]




                                    True




                                  • Specifying 4.1 for the plot range, fixes the y-axis scale and better demonstrates the growth of the curve as the parameter de varies.







                                  share|improve this answer


























                                    1












                                    1








                                    1






                                    Here is another variation that is somewhat more succinct than the other solutions.



                                    m = 1;
                                    k = 1;
                                    L = 0.001;
                                    P = 1.3;

                                    pF = ParametricNDSolveValue[eqns, {a, b}, {t, 0, 100}, de];

                                    Manipulate[
                                    With[{bF = pF[de][[2]]}, Plot[2 Re[bF[t]], {t, 0, 99}, PlotRange -> 4.1]],
                                    {de, .1, 1., .1, Appearance -> "Labeled"}]


                                    demo



                                    Notes





                                    • Reduce[z + Conjugate[z] == 2 Re[z], z]




                                      True




                                    • Specifying 4.1 for the plot range, fixes the y-axis scale and better demonstrates the growth of the curve as the parameter de varies.







                                    share|improve this answer














                                    Here is another variation that is somewhat more succinct than the other solutions.



                                    m = 1;
                                    k = 1;
                                    L = 0.001;
                                    P = 1.3;

                                    pF = ParametricNDSolveValue[eqns, {a, b}, {t, 0, 100}, de];

                                    Manipulate[
                                    With[{bF = pF[de][[2]]}, Plot[2 Re[bF[t]], {t, 0, 99}, PlotRange -> 4.1]],
                                    {de, .1, 1., .1, Appearance -> "Labeled"}]


                                    demo



                                    Notes





                                    • Reduce[z + Conjugate[z] == 2 Re[z], z]




                                      True




                                    • Specifying 4.1 for the plot range, fixes the y-axis scale and better demonstrates the growth of the curve as the parameter de varies.








                                    share|improve this answer














                                    share|improve this answer



                                    share|improve this answer








                                    edited Dec 23 at 21:41

























                                    answered Dec 23 at 21:32









                                    m_goldberg

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