How to align equations to the left
3
I have this equation on Overleaf that aligns to the right instead of the left. I have followed instructions on other questions found here but it doesn't work.
{setlength{abovedisplayskip}{0pt}%
begin{flalign}
-frac{tau}{2} sum (x_n - mu)^2 -b_0tau -frac{lambda_0tau}{2} (mu - mu_0)^2 \
= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
= -frac{tau}{2}(sum x_n^2 + Nmu^2 - 2musum x_n) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)
end{flalign}%
}%
How can I align to the left?
overleaf
asked Dec 23 at 17:15
Sahand
1184
add a comment |
3
I have this equation on Overleaf that aligns to the right instead of the left. I have followed instructions on other questions found here but it doesn't work.
{setlength{abovedisplayskip}{0pt}%
begin{flalign}
-frac{tau}{2} sum (x_n - mu)^2 -b_0tau -frac{lambda_0tau}{2} (mu - mu_0)^2 \
= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
= -frac{tau}{2}(sum x_n^2 + Nmu^2 - 2musum x_n) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)
end{flalign}%
}%
How can I align to the left?
overleaf
asked Dec 23 at 17:15
Sahand
1184
2
Please make your given code snippet compilable ...
– Kurt
Dec 23 at 17:17
add a comment |
3
3
3
0
I have this equation on Overleaf that aligns to the right instead of the left. I have followed instructions on other questions found here but it doesn't work.
{setlength{abovedisplayskip}{0pt}%
begin{flalign}
-frac{tau}{2} sum (x_n - mu)^2 -b_0tau -frac{lambda_0tau}{2} (mu - mu_0)^2 \
= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
= -frac{tau}{2}(sum x_n^2 + Nmu^2 - 2musum x_n) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)
end{flalign}%
}%
How can I align to the left?
overleaf
asked Dec 23 at 17:15
Sahand
1184
I have this equation on Overleaf that aligns to the right instead of the left. I have followed instructions on other questions found here but it doesn't work.
{setlength{abovedisplayskip}{0pt}%
begin{flalign}
-frac{tau}{2} sum (x_n - mu)^2 -b_0tau -frac{lambda_0tau}{2} (mu - mu_0)^2 \
= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
= -frac{tau}{2}(sum x_n^2 + Nmu^2 - 2musum x_n) - b_0tau - frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)
end{flalign}%
}%
How can I align to the left?
overleaf
overleaf
asked Dec 23 at 17:15
Sahand
1184
asked Dec 23 at 17:15
Sahand
1184
asked Dec 23 at 17:15
Sahand
1184
asked Dec 23 at 17:15
Sahand
1184
asked Dec 23 at 17:15
Sahand
1184
1184
2
Please make your given code snippet compilable ...
– Kurt
Dec 23 at 17:17
add a comment |
2
Please make your given code snippet compilable ...
– Kurt
Dec 23 at 17:17
2
2
Please make your given code snippet compilable ...
– Kurt
Dec 23 at 17:17
Please make your given code snippet compilable ...
– Kurt
Dec 23 at 17:17
add a comment |
2 Answers
2
active
oldest
votes
4
i guess that you are looking for the following:
documentclass{article}
usepackage{mathtools}
begin{document}
begin{equation}
begin{split}
MoveEqLeft
-frac{tau}{2}sum (x_n-mu)^2-b_0tau
-frac{lambda_0tau}{2}(mu-mu_0)^2 \
& = - frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
& = -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0))
end{split}
end{equation}
end{document}
edited Dec 23 at 18:19
Mico
273k30369756
answered Dec 23 at 17:30
Zarko
120k865156
@Mico, thank you very much. i consider your suggestion.
– Zarko
Dec 23 at 17:38
Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.
– Mico
Dec 23 at 18:20
@Mico, thank you very much. i should see, which parenthesis are in pair.
– Zarko
Dec 23 at 18:47
add a comment |
1
documentclass{article}
usepackage{amsmath}
begin{document}
begin{flalign}
-& frac{tau}{2}sum (x_n-mu)^2-b_0tau -frac{lambda_0tau}{2}(mu-mu_0)^2 notag \
&= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0) \
&= -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)) notag
end{flalign}
end{document}
answered Dec 23 at 18:46
AboAmmar
32.9k22882
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
4
i guess that you are looking for the following:
documentclass{article}
usepackage{mathtools}
begin{document}
begin{equation}
begin{split}
MoveEqLeft
-frac{tau}{2}sum (x_n-mu)^2-b_0tau
-frac{lambda_0tau}{2}(mu-mu_0)^2 \
& = - frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
& = -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0))
end{split}
end{equation}
end{document}
edited Dec 23 at 18:19
Mico
273k30369756
answered Dec 23 at 17:30
Zarko
120k865156
@Mico, thank you very much. i consider your suggestion.
– Zarko
Dec 23 at 17:38
Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.
– Mico
Dec 23 at 18:20
@Mico, thank you very much. i should see, which parenthesis are in pair.
– Zarko
Dec 23 at 18:47
add a comment |
4
i guess that you are looking for the following:
documentclass{article}
usepackage{mathtools}
begin{document}
begin{equation}
begin{split}
MoveEqLeft
-frac{tau}{2}sum (x_n-mu)^2-b_0tau
-frac{lambda_0tau}{2}(mu-mu_0)^2 \
& = - frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
& = -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0))
end{split}
end{equation}
end{document}
edited Dec 23 at 18:19
Mico
273k30369756
answered Dec 23 at 17:30
Zarko
120k865156
@Mico, thank you very much. i consider your suggestion.
– Zarko
Dec 23 at 17:38
Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.
– Mico
Dec 23 at 18:20
@Mico, thank you very much. i should see, which parenthesis are in pair.
– Zarko
Dec 23 at 18:47
add a comment |
4
4
4
i guess that you are looking for the following:
documentclass{article}
usepackage{mathtools}
begin{document}
begin{equation}
begin{split}
MoveEqLeft
-frac{tau}{2}sum (x_n-mu)^2-b_0tau
-frac{lambda_0tau}{2}(mu-mu_0)^2 \
& = - frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
& = -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0))
end{split}
end{equation}
end{document}
edited Dec 23 at 18:19
Mico
273k30369756
answered Dec 23 at 17:30
Zarko
120k865156
i guess that you are looking for the following:
documentclass{article}
usepackage{mathtools}
begin{document}
begin{equation}
begin{split}
MoveEqLeft
-frac{tau}{2}sum (x_n-mu)^2-b_0tau
-frac{lambda_0tau}{2}(mu-mu_0)^2 \
& = - frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)\
& = -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0))
end{split}
end{equation}
end{document}
edited Dec 23 at 18:19
Mico
273k30369756
answered Dec 23 at 17:30
Zarko
120k865156
edited Dec 23 at 18:19
Mico
273k30369756
edited Dec 23 at 18:19
Mico
273k30369756
edited Dec 23 at 18:19
Mico
273k30369756
273k30369756
answered Dec 23 at 17:30
Zarko
120k865156
answered Dec 23 at 17:30
Zarko
120k865156
answered Dec 23 at 17:30
Zarko
120k865156
120k865156
@Mico, thank you very much. i consider your suggestion.
– Zarko
Dec 23 at 17:38
Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.
– Mico
Dec 23 at 18:20
@Mico, thank you very much. i should see, which parenthesis are in pair.
– Zarko
Dec 23 at 18:47
add a comment |
@Mico, thank you very much. i consider your suggestion.
– Zarko
Dec 23 at 17:38
Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.
– Mico
Dec 23 at 18:20
@Mico, thank you very much. i should see, which parenthesis are in pair.
– Zarko
Dec 23 at 18:47
@Mico, thank you very much. i consider your suggestion.
– Zarko
Dec 23 at 17:38
@Mico, thank you very much. i consider your suggestion.
– Zarko
Dec 23 at 17:38
Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.
– Mico
Dec 23 at 18:20
Sorry for not being sufficiently clear earlier about where the large parentheses should go. I've taken the liberty of providing an update.
– Mico
Dec 23 at 18:20
@Mico, thank you very much. i should see, which parenthesis are in pair.
– Zarko
Dec 23 at 18:47
@Mico, thank you very much. i should see, which parenthesis are in pair.
– Zarko
Dec 23 at 18:47
add a comment |
1
documentclass{article}
usepackage{amsmath}
begin{document}
begin{flalign}
-& frac{tau}{2}sum (x_n-mu)^2-b_0tau -frac{lambda_0tau}{2}(mu-mu_0)^2 notag \
&= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0) \
&= -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)) notag
end{flalign}
end{document}
answered Dec 23 at 18:46
AboAmmar
32.9k22882
add a comment |
1
documentclass{article}
usepackage{amsmath}
begin{document}
begin{flalign}
-& frac{tau}{2}sum (x_n-mu)^2-b_0tau -frac{lambda_0tau}{2}(mu-mu_0)^2 notag \
&= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0) \
&= -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)) notag
end{flalign}
end{document}
answered Dec 23 at 18:46
AboAmmar
32.9k22882
add a comment |
1
1
1
documentclass{article}
usepackage{amsmath}
begin{document}
begin{flalign}
-& frac{tau}{2}sum (x_n-mu)^2-b_0tau -frac{lambda_0tau}{2}(mu-mu_0)^2 notag \
&= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0) \
&= -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)) notag
end{flalign}
end{document}
answered Dec 23 at 18:46
AboAmmar
32.9k22882
documentclass{article}
usepackage{amsmath}
begin{document}
begin{flalign}
-& frac{tau}{2}sum (x_n-mu)^2-b_0tau -frac{lambda_0tau}{2}(mu-mu_0)^2 notag \
&= -frac{tau}{2}sum(x_n^2 + mu^2 - 2x_nmu) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0) \
&= -frac{tau}{2}Bigl(sum x_n^2 + Nmu^2 - 2musum x_nBigr) - b_0tau -
frac{lambda_0tau}{2}(mu^2 + mu_0^2 - 2mumu_0)) notag
end{flalign}
end{document}
answered Dec 23 at 18:46
AboAmmar
32.9k22882
answered Dec 23 at 18:46
AboAmmar
32.9k22882
answered Dec 23 at 18:46
AboAmmar
32.9k22882
answered Dec 23 at 18:46
AboAmmar
32.9k22882
32.9k22882
add a comment |
add a comment |
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2
Please make your given code snippet compilable ...
– Kurt
Dec 23 at 17:17