Searching a nested data structure for 2 attributes
0
$begingroup$
So I have the following data structures
export class BudgetGroupInfo {
name: string;
bcInfo: BudgetCatInfo = ;
}
export class BudgetCatInfo {
name: string;
description: string;
bcAccounts: BCAccountInfo = ;
}
export class BCAccountInfo {
name: string;
description: string;
}
What I need to be able to do is find which BudgetGroupInfo contains both BudgetCatInfo.name and BCAccountInfo.name
This is what I have so far and it works, but I feel like this isn't the most efficient want to do this.
getGroupInfo(budCat: string, account: string, budgetGroupInfo: BudgetGroupInfo): BudgetGroupInfo {
let groupInfo = null;
budgetGroupInfo.forEach(infoGroup => {
infoGroup.bcInfo.filter(bcInfo => bcInfo.name == budCat)
.map(bcInfo => bcInfo.bcAccounts)
.forEach(accounts => {
const acctInfo: BCAccountInfo = accounts.find(acct => acct.name == account);
if(acctInfo) {
groupInfo = infoGroup;
}
});
})
return groupInfo;
}
- First I go through the groups and find which ones have the specific
budCat
- I take the valid
BudgetCatInfoandmapthebcAccountarray - I search that array and look for the specified
account
- If I find it then I set it for return.
Just a note that there won't always be a result and there will never be multiple matches.
javascript typescript
asked 12 mins ago
Raymond HolguinRaymond Holguin
101
New contributor
Raymond Holguin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
$begingroup$
So I have the following data structures
export class BudgetGroupInfo {
name: string;
bcInfo: BudgetCatInfo = ;
}
export class BudgetCatInfo {
name: string;
description: string;
bcAccounts: BCAccountInfo = ;
}
export class BCAccountInfo {
name: string;
description: string;
}
What I need to be able to do is find which BudgetGroupInfo contains both BudgetCatInfo.name and BCAccountInfo.name
This is what I have so far and it works, but I feel like this isn't the most efficient want to do this.
getGroupInfo(budCat: string, account: string, budgetGroupInfo: BudgetGroupInfo): BudgetGroupInfo {
let groupInfo = null;
budgetGroupInfo.forEach(infoGroup => {
infoGroup.bcInfo.filter(bcInfo => bcInfo.name == budCat)
.map(bcInfo => bcInfo.bcAccounts)
.forEach(accounts => {
const acctInfo: BCAccountInfo = accounts.find(acct => acct.name == account);
if(acctInfo) {
groupInfo = infoGroup;
}
});
})
return groupInfo;
}
- First I go through the groups and find which ones have the specific
budCat
- I take the valid
BudgetCatInfoandmapthebcAccountarray - I search that array and look for the specified
account
- If I find it then I set it for return.
Just a note that there won't always be a result and there will never be multiple matches.
javascript typescript
asked 12 mins ago
Raymond HolguinRaymond Holguin
101
New contributor
Raymond Holguin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
0
0
$begingroup$
So I have the following data structures
export class BudgetGroupInfo {
name: string;
bcInfo: BudgetCatInfo = ;
}
export class BudgetCatInfo {
name: string;
description: string;
bcAccounts: BCAccountInfo = ;
}
export class BCAccountInfo {
name: string;
description: string;
}
What I need to be able to do is find which BudgetGroupInfo contains both BudgetCatInfo.name and BCAccountInfo.name
This is what I have so far and it works, but I feel like this isn't the most efficient want to do this.
getGroupInfo(budCat: string, account: string, budgetGroupInfo: BudgetGroupInfo): BudgetGroupInfo {
let groupInfo = null;
budgetGroupInfo.forEach(infoGroup => {
infoGroup.bcInfo.filter(bcInfo => bcInfo.name == budCat)
.map(bcInfo => bcInfo.bcAccounts)
.forEach(accounts => {
const acctInfo: BCAccountInfo = accounts.find(acct => acct.name == account);
if(acctInfo) {
groupInfo = infoGroup;
}
});
})
return groupInfo;
}
- First I go through the groups and find which ones have the specific
budCat
- I take the valid
BudgetCatInfoandmapthebcAccountarray - I search that array and look for the specified
account
- If I find it then I set it for return.
Just a note that there won't always be a result and there will never be multiple matches.
javascript typescript
asked 12 mins ago
Raymond HolguinRaymond Holguin
101
New contributor
Raymond Holguin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
So I have the following data structures
export class BudgetGroupInfo {
name: string;
bcInfo: BudgetCatInfo = ;
}
export class BudgetCatInfo {
name: string;
description: string;
bcAccounts: BCAccountInfo = ;
}
export class BCAccountInfo {
name: string;
description: string;
}
What I need to be able to do is find which BudgetGroupInfo contains both BudgetCatInfo.name and BCAccountInfo.name
This is what I have so far and it works, but I feel like this isn't the most efficient want to do this.
getGroupInfo(budCat: string, account: string, budgetGroupInfo: BudgetGroupInfo): BudgetGroupInfo {
let groupInfo = null;
budgetGroupInfo.forEach(infoGroup => {
infoGroup.bcInfo.filter(bcInfo => bcInfo.name == budCat)
.map(bcInfo => bcInfo.bcAccounts)
.forEach(accounts => {
const acctInfo: BCAccountInfo = accounts.find(acct => acct.name == account);
if(acctInfo) {
groupInfo = infoGroup;
}
});
})
return groupInfo;
}
- First I go through the groups and find which ones have the specific
budCat
- I take the valid
BudgetCatInfoandmapthebcAccountarray - I search that array and look for the specified
account
- If I find it then I set it for return.
Just a note that there won't always be a result and there will never be multiple matches.
javascript typescript
javascript typescript
asked 12 mins ago
Raymond HolguinRaymond Holguin
101
New contributor
Raymond Holguin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 12 mins ago
Raymond HolguinRaymond Holguin
101
New contributor
Raymond Holguin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 12 mins ago
Raymond HolguinRaymond Holguin
101
New contributor
Raymond Holguin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 12 mins ago
Raymond HolguinRaymond Holguin
101
asked 12 mins ago
Raymond HolguinRaymond Holguin
101
101
New contributor
Raymond Holguin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Raymond Holguin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Raymond Holguin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
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