Using stream API to set strings all lowercase but capitalize first letter

I have a List<String> and through only using the stream API I was settings all strings to lowercase, sorting them from smallest string to largest and printing them. The issue I'm having is capitalizing the first letter of the string.

Is that something I do through .stream().map()?

public class Main {



    public static void main(String args) {



        List<String> list = Arrays.asList("SOmE", "StriNgs", "fRom", "mE", "To", "yOU");

        list.stream()

            .map(n -> n.toLowerCase())

            .sorted((a, b) -> a.length() - b.length())

            .forEach(n -> System.out.println(n));;



    }



}

Output:

me

to

you

some

from

strings

Desired output:

Me

To

You

Some

From

Strings

edited Dec 12 '18 at 9:19

Andrew Tobilko

26.8k104284

asked Dec 11 '18 at 23:14

Devin

1368

add a comment |

Is that something I do through .stream().map()?

public class Main {



    public static void main(String args) {



        List<String> list = Arrays.asList("SOmE", "StriNgs", "fRom", "mE", "To", "yOU");

        list.stream()

            .map(n -> n.toLowerCase())

            .sorted((a, b) -> a.length() - b.length())

            .forEach(n -> System.out.println(n));;



    }



}

Output:

me

to

you

some

from

strings

Desired output:

Me

To

You

Some

From

Strings

edited Dec 12 '18 at 9:19

Andrew Tobilko

26.8k104284

asked Dec 11 '18 at 23:14

Devin

1368

add a comment |

Is that something I do through .stream().map()?

public class Main {



    public static void main(String args) {



        List<String> list = Arrays.asList("SOmE", "StriNgs", "fRom", "mE", "To", "yOU");

        list.stream()

            .map(n -> n.toLowerCase())

            .sorted((a, b) -> a.length() - b.length())

            .forEach(n -> System.out.println(n));;



    }



}

Output:

me

to

you

some

from

strings

Desired output:

Me

To

You

Some

From

Strings

edited Dec 12 '18 at 9:19

Andrew Tobilko

26.8k104284

asked Dec 11 '18 at 23:14

Devin

1368

Is that something I do through .stream().map()?

public class Main {



    public static void main(String args) {



        List<String> list = Arrays.asList("SOmE", "StriNgs", "fRom", "mE", "To", "yOU");

        list.stream()

            .map(n -> n.toLowerCase())

            .sorted((a, b) -> a.length() - b.length())

            .forEach(n -> System.out.println(n));;



    }



}

Output:

me

to

you

some

from

strings

Desired output:

Me

To

You

Some

From

Strings

java java-8 mapping java-stream capitalization

edited Dec 12 '18 at 9:19

Andrew Tobilko

26.8k104284

asked Dec 11 '18 at 23:14

Devin

1368

edited Dec 12 '18 at 9:19

Andrew Tobilko

26.8k104284

asked Dec 11 '18 at 23:14

Devin

1368

edited Dec 12 '18 at 9:19

Andrew Tobilko

26.8k104284

edited Dec 12 '18 at 9:19

Andrew Tobilko

26.8k104284

edited Dec 12 '18 at 9:19

Andrew Tobilko

26.8k104284

asked Dec 11 '18 at 23:14

Devin

1368

asked Dec 11 '18 at 23:14

Devin

1368

asked Dec 11 '18 at 23:14

Devin

1368

add a comment |

3 Answers
3

active

oldest

votes

Something like this should suffice:

 list.stream()

     .map(n -> n.toLowerCase())

     .sorted(Comparator.comparingInt(String::length))

     .map(s -> Character.toUpperCase(s.charAt(0)) + s.substring(1))

     .forEachOrdered(n -> System.out.println(n));

note that I've changed the comparator, which is essentially the idiomatic approach to do it.

I've added a map operation after sorting to uppercase the first letter.

edited Dec 12 '18 at 7:48

answered Dec 11 '18 at 23:16

Aomine

41.6k74071

Yes that works, thank you! I was unaware I could use Map multiple times for the same stream.
– Devin
Dec 11 '18 at 23:19

2

@Devin you can chain as many intermediate operations as you like.
– Aomine
Dec 11 '18 at 23:19

3

Keep in mind that forEach makes no ordering guaranties, so to be sure to see the elements in the sorted order, you have to use forEachOrdered.
– Holger
Dec 12 '18 at 7:47

@Devin, use as many intermediate operations (filter/map/distinct/sorted/peek) as you need. After you have applied a terminal method (reduce/collect/foreach) you have "ended" the stream.
– Viktor Mellgren
Dec 12 '18 at 8:58

Will fail for empty strings. Use .map(s -> s.isEmpty() ? "" : Character.toUpperCase(s.charAt(0)) + s.substring(1))
– ssz
Jan 6 at 21:28

|
show 4 more comments

list.stream()

    .map(s -> s.substring(0, 1).toUpperCase() + s.substring(1).toLowerCase())

    .sorted(Comparator.comparingInt(String::length))

    .forEach(System.out::println);

For readability, the line performing capitalisation should be moved into a method,

public class StringUtils {

    public static String capitalise(String s) {

        return s.substring(0, 1).toUpperCase() + s.substring(1).toLowerCase();

    }

}

so you can refer to it via an eloquent method reference:

list.stream()

    .map(StringUtils::capitalise)

    .sorted(Comparator.comparingInt(String::length))

    .forEach(System.out::println);

edited Dec 11 '18 at 23:44

answered Dec 11 '18 at 23:19

Andrew Tobilko

26.8k104284

2

This will exhibit better locality than the accepted answer, which splits the map on either side of the sort.
– Alex Reinking
Dec 12 '18 at 6:08

3

@AlexReinking While a agree with you, I just want to point out that the only reason why I’ve decided against using one map operation at the time of posting was to keep the logic on each intermediate operation short and easy see to follow thus making it easier for the OP. Remember at the end of the day, the OP seems like a new person to the Streams API, talking about anything else is a bonus but takes things away from the their main point which is to simply uppercase the first character. btw, seems like now the OP knows that one can use more than one “same” intermediate operation :).
– Aomine
Dec 12 '18 at 6:43

add a comment |

You can use WordUtils::capitalizeFully from Apache Commons Lang for this.

 list.stream()

     .sorted(Comparator.comparingInt(String::length))

     .map(WordUtils::capitalizeFully)

     .forEach(System.out::println);

edited Dec 12 '18 at 7:15

Peter Mortensen

13.5k1983111

answered Dec 11 '18 at 23:38

fastcodejava

24k19109162

1

OP wants to capitalise only the first letter. Besides, you didn't mention where WordUtils comes from...
– Andrew Tobilko
Dec 11 '18 at 23:39

1

@AndrewTobilko WordUtils::capitalizeFully does just that. I have mentioned where WordUtils comes from now.
– fastcodejava
Dec 11 '18 at 23:42

4

New code should use the commons-text version of this method instead, as the commons-lang one has been deprecated.
– Alex Reinking
Dec 12 '18 at 6:10

add a comment |

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

Something like this should suffice:

 list.stream()

     .map(n -> n.toLowerCase())

     .sorted(Comparator.comparingInt(String::length))

     .map(s -> Character.toUpperCase(s.charAt(0)) + s.substring(1))

     .forEachOrdered(n -> System.out.println(n));

note that I've changed the comparator, which is essentially the idiomatic approach to do it.

I've added a map operation after sorting to uppercase the first letter.

edited Dec 12 '18 at 7:48

answered Dec 11 '18 at 23:16

Aomine

41.6k74071

Yes that works, thank you! I was unaware I could use Map multiple times for the same stream.
– Devin
Dec 11 '18 at 23:19

2

@Devin you can chain as many intermediate operations as you like.
– Aomine
Dec 11 '18 at 23:19

3

Keep in mind that forEach makes no ordering guaranties, so to be sure to see the elements in the sorted order, you have to use forEachOrdered.
– Holger
Dec 12 '18 at 7:47

@Devin, use as many intermediate operations (filter/map/distinct/sorted/peek) as you need. After you have applied a terminal method (reduce/collect/foreach) you have "ended" the stream.
– Viktor Mellgren
Dec 12 '18 at 8:58

Will fail for empty strings. Use .map(s -> s.isEmpty() ? "" : Character.toUpperCase(s.charAt(0)) + s.substring(1))
– ssz
Jan 6 at 21:28

|
show 4 more comments

Something like this should suffice:

 list.stream()

     .map(n -> n.toLowerCase())

     .sorted(Comparator.comparingInt(String::length))

     .map(s -> Character.toUpperCase(s.charAt(0)) + s.substring(1))

     .forEachOrdered(n -> System.out.println(n));

note that I've changed the comparator, which is essentially the idiomatic approach to do it.

I've added a map operation after sorting to uppercase the first letter.

edited Dec 12 '18 at 7:48

answered Dec 11 '18 at 23:16

Aomine

41.6k74071

Yes that works, thank you! I was unaware I could use Map multiple times for the same stream.
– Devin
Dec 11 '18 at 23:19

2

@Devin you can chain as many intermediate operations as you like.
– Aomine
Dec 11 '18 at 23:19

3

Keep in mind that forEach makes no ordering guaranties, so to be sure to see the elements in the sorted order, you have to use forEachOrdered.
– Holger
Dec 12 '18 at 7:47

@Devin, use as many intermediate operations (filter/map/distinct/sorted/peek) as you need. After you have applied a terminal method (reduce/collect/foreach) you have "ended" the stream.
– Viktor Mellgren
Dec 12 '18 at 8:58

Will fail for empty strings. Use .map(s -> s.isEmpty() ? "" : Character.toUpperCase(s.charAt(0)) + s.substring(1))
– ssz
Jan 6 at 21:28

|
show 4 more comments

Something like this should suffice:

 list.stream()

     .map(n -> n.toLowerCase())

     .sorted(Comparator.comparingInt(String::length))

     .map(s -> Character.toUpperCase(s.charAt(0)) + s.substring(1))

     .forEachOrdered(n -> System.out.println(n));

note that I've changed the comparator, which is essentially the idiomatic approach to do it.

I've added a map operation after sorting to uppercase the first letter.

edited Dec 12 '18 at 7:48

answered Dec 11 '18 at 23:16

Aomine

41.6k74071

Something like this should suffice:

 list.stream()

     .map(n -> n.toLowerCase())

     .sorted(Comparator.comparingInt(String::length))

     .map(s -> Character.toUpperCase(s.charAt(0)) + s.substring(1))

     .forEachOrdered(n -> System.out.println(n));

note that I've changed the comparator, which is essentially the idiomatic approach to do it.

I've added a map operation after sorting to uppercase the first letter.

edited Dec 12 '18 at 7:48

answered Dec 11 '18 at 23:16

Aomine

41.6k74071

edited Dec 12 '18 at 7:48

answered Dec 11 '18 at 23:16

Aomine

41.6k74071

answered Dec 11 '18 at 23:16

Aomine

41.6k74071

answered Dec 11 '18 at 23:16

Aomine

41.6k74071

Yes that works, thank you! I was unaware I could use Map multiple times for the same stream.
– Devin
Dec 11 '18 at 23:19

2

@Devin you can chain as many intermediate operations as you like.
– Aomine
Dec 11 '18 at 23:19

3

Keep in mind that forEach makes no ordering guaranties, so to be sure to see the elements in the sorted order, you have to use forEachOrdered.
– Holger
Dec 12 '18 at 7:47

@Devin, use as many intermediate operations (filter/map/distinct/sorted/peek) as you need. After you have applied a terminal method (reduce/collect/foreach) you have "ended" the stream.
– Viktor Mellgren
Dec 12 '18 at 8:58

Will fail for empty strings. Use .map(s -> s.isEmpty() ? "" : Character.toUpperCase(s.charAt(0)) + s.substring(1))
– ssz
Jan 6 at 21:28

|
show 4 more comments

Yes that works, thank you! I was unaware I could use Map multiple times for the same stream.
– Devin
Dec 11 '18 at 23:19

2

@Devin you can chain as many intermediate operations as you like.
– Aomine
Dec 11 '18 at 23:19

3

Keep in mind that forEach makes no ordering guaranties, so to be sure to see the elements in the sorted order, you have to use forEachOrdered.
– Holger
Dec 12 '18 at 7:47

@Devin, use as many intermediate operations (filter/map/distinct/sorted/peek) as you need. After you have applied a terminal method (reduce/collect/foreach) you have "ended" the stream.
– Viktor Mellgren
Dec 12 '18 at 8:58

Will fail for empty strings. Use .map(s -> s.isEmpty() ? "" : Character.toUpperCase(s.charAt(0)) + s.substring(1))
– ssz
Jan 6 at 21:28

Yes that works, thank you! I was unaware I could use Map multiple times for the same stream.
– Devin
Dec 11 '18 at 23:19

@Devin you can chain as many intermediate operations as you like.
– Aomine
Dec 11 '18 at 23:19

Keep in mind that forEach makes no ordering guaranties, so to be sure to see the elements in the sorted order, you have to use forEachOrdered.
– Holger
Dec 12 '18 at 7:47

@Devin, use as many intermediate operations (filter/map/distinct/sorted/peek) as you need. After you have applied a terminal method (reduce/collect/foreach) you have "ended" the stream.
– Viktor Mellgren
Dec 12 '18 at 8:58

Will fail for empty strings. Use .map(s -> s.isEmpty() ? "" : Character.toUpperCase(s.charAt(0)) + s.substring(1))
– ssz
Jan 6 at 21:28

|
show 4 more comments

list.stream()

    .map(s -> s.substring(0, 1).toUpperCase() + s.substring(1).toLowerCase())

    .sorted(Comparator.comparingInt(String::length))

    .forEach(System.out::println);

For readability, the line performing capitalisation should be moved into a method,

public class StringUtils {

    public static String capitalise(String s) {

        return s.substring(0, 1).toUpperCase() + s.substring(1).toLowerCase();

    }

}

so you can refer to it via an eloquent method reference:

list.stream()

    .map(StringUtils::capitalise)

    .sorted(Comparator.comparingInt(String::length))

    .forEach(System.out::println);

edited Dec 11 '18 at 23:44

answered Dec 11 '18 at 23:19

Andrew Tobilko

26.8k104284

2

This will exhibit better locality than the accepted answer, which splits the map on either side of the sort.
– Alex Reinking
Dec 12 '18 at 6:08

3

@AlexReinking While a agree with you, I just want to point out that the only reason why I’ve decided against using one map operation at the time of posting was to keep the logic on each intermediate operation short and easy see to follow thus making it easier for the OP. Remember at the end of the day, the OP seems like a new person to the Streams API, talking about anything else is a bonus but takes things away from the their main point which is to simply uppercase the first character. btw, seems like now the OP knows that one can use more than one “same” intermediate operation :).
– Aomine
Dec 12 '18 at 6:43

add a comment |

list.stream()

    .map(s -> s.substring(0, 1).toUpperCase() + s.substring(1).toLowerCase())

    .sorted(Comparator.comparingInt(String::length))

    .forEach(System.out::println);

For readability, the line performing capitalisation should be moved into a method,

public class StringUtils {

    public static String capitalise(String s) {

        return s.substring(0, 1).toUpperCase() + s.substring(1).toLowerCase();

    }

}

so you can refer to it via an eloquent method reference:

list.stream()

    .map(StringUtils::capitalise)

    .sorted(Comparator.comparingInt(String::length))

    .forEach(System.out::println);

edited Dec 11 '18 at 23:44

answered Dec 11 '18 at 23:19

Andrew Tobilko

26.8k104284

2

This will exhibit better locality than the accepted answer, which splits the map on either side of the sort.
– Alex Reinking
Dec 12 '18 at 6:08

3

@AlexReinking While a agree with you, I just want to point out that the only reason why I’ve decided against using one map operation at the time of posting was to keep the logic on each intermediate operation short and easy see to follow thus making it easier for the OP. Remember at the end of the day, the OP seems like a new person to the Streams API, talking about anything else is a bonus but takes things away from the their main point which is to simply uppercase the first character. btw, seems like now the OP knows that one can use more than one “same” intermediate operation :).
– Aomine
Dec 12 '18 at 6:43

add a comment |

list.stream()

    .map(s -> s.substring(0, 1).toUpperCase() + s.substring(1).toLowerCase())

    .sorted(Comparator.comparingInt(String::length))

    .forEach(System.out::println);

For readability, the line performing capitalisation should be moved into a method,

public class StringUtils {

    public static String capitalise(String s) {

        return s.substring(0, 1).toUpperCase() + s.substring(1).toLowerCase();

    }

}

so you can refer to it via an eloquent method reference:

list.stream()

    .map(StringUtils::capitalise)

    .sorted(Comparator.comparingInt(String::length))

    .forEach(System.out::println);

edited Dec 11 '18 at 23:44

answered Dec 11 '18 at 23:19

Andrew Tobilko

26.8k104284

list.stream()

    .map(s -> s.substring(0, 1).toUpperCase() + s.substring(1).toLowerCase())

    .sorted(Comparator.comparingInt(String::length))

    .forEach(System.out::println);

For readability, the line performing capitalisation should be moved into a method,

public class StringUtils {

    public static String capitalise(String s) {

        return s.substring(0, 1).toUpperCase() + s.substring(1).toLowerCase();

    }

}

so you can refer to it via an eloquent method reference:

list.stream()

    .map(StringUtils::capitalise)

    .sorted(Comparator.comparingInt(String::length))

    .forEach(System.out::println);

edited Dec 11 '18 at 23:44

answered Dec 11 '18 at 23:19

Andrew Tobilko

26.8k104284

edited Dec 11 '18 at 23:44

answered Dec 11 '18 at 23:19

Andrew Tobilko

26.8k104284

answered Dec 11 '18 at 23:19

Andrew Tobilko

26.8k104284

answered Dec 11 '18 at 23:19

Andrew Tobilko

26.8k104284

2

This will exhibit better locality than the accepted answer, which splits the map on either side of the sort.
– Alex Reinking
Dec 12 '18 at 6:08

3

@AlexReinking While a agree with you, I just want to point out that the only reason why I’ve decided against using one map operation at the time of posting was to keep the logic on each intermediate operation short and easy see to follow thus making it easier for the OP. Remember at the end of the day, the OP seems like a new person to the Streams API, talking about anything else is a bonus but takes things away from the their main point which is to simply uppercase the first character. btw, seems like now the OP knows that one can use more than one “same” intermediate operation :).
– Aomine
Dec 12 '18 at 6:43

add a comment |

2

This will exhibit better locality than the accepted answer, which splits the map on either side of the sort.
– Alex Reinking
Dec 12 '18 at 6:08

3

@AlexReinking While a agree with you, I just want to point out that the only reason why I’ve decided against using one map operation at the time of posting was to keep the logic on each intermediate operation short and easy see to follow thus making it easier for the OP. Remember at the end of the day, the OP seems like a new person to the Streams API, talking about anything else is a bonus but takes things away from the their main point which is to simply uppercase the first character. btw, seems like now the OP knows that one can use more than one “same” intermediate operation :).
– Aomine
Dec 12 '18 at 6:43

This will exhibit better locality than the accepted answer, which splits the map on either side of the sort.
– Alex Reinking
Dec 12 '18 at 6:08

@AlexReinking While a agree with you, I just want to point out that the only reason why I’ve decided against using one map operation at the time of posting was to keep the logic on each intermediate operation short and easy see to follow thus making it easier for the OP. Remember at the end of the day, the OP seems like a new person to the Streams API, talking about anything else is a bonus but takes things away from the their main point which is to simply uppercase the first character. btw, seems like now the OP knows that one can use more than one “same” intermediate operation :).
– Aomine
Dec 12 '18 at 6:43

add a comment |

You can use WordUtils::capitalizeFully from Apache Commons Lang for this.

 list.stream()

     .sorted(Comparator.comparingInt(String::length))

     .map(WordUtils::capitalizeFully)

     .forEach(System.out::println);

edited Dec 12 '18 at 7:15

Peter Mortensen

13.5k1983111

answered Dec 11 '18 at 23:38

fastcodejava

24k19109162

1

OP wants to capitalise only the first letter. Besides, you didn't mention where WordUtils comes from...
– Andrew Tobilko
Dec 11 '18 at 23:39

1

@AndrewTobilko WordUtils::capitalizeFully does just that. I have mentioned where WordUtils comes from now.
– fastcodejava
Dec 11 '18 at 23:42

4

New code should use the commons-text version of this method instead, as the commons-lang one has been deprecated.
– Alex Reinking
Dec 12 '18 at 6:10

add a comment |

You can use WordUtils::capitalizeFully from Apache Commons Lang for this.

 list.stream()

     .sorted(Comparator.comparingInt(String::length))

     .map(WordUtils::capitalizeFully)

     .forEach(System.out::println);

edited Dec 12 '18 at 7:15

Peter Mortensen

13.5k1983111

answered Dec 11 '18 at 23:38

fastcodejava

24k19109162

1

OP wants to capitalise only the first letter. Besides, you didn't mention where WordUtils comes from...
– Andrew Tobilko
Dec 11 '18 at 23:39

1

@AndrewTobilko WordUtils::capitalizeFully does just that. I have mentioned where WordUtils comes from now.
– fastcodejava
Dec 11 '18 at 23:42

4

New code should use the commons-text version of this method instead, as the commons-lang one has been deprecated.
– Alex Reinking
Dec 12 '18 at 6:10

add a comment |

You can use WordUtils::capitalizeFully from Apache Commons Lang for this.

 list.stream()

     .sorted(Comparator.comparingInt(String::length))

     .map(WordUtils::capitalizeFully)

     .forEach(System.out::println);

edited Dec 12 '18 at 7:15

Peter Mortensen

13.5k1983111

answered Dec 11 '18 at 23:38

fastcodejava

24k19109162

You can use WordUtils::capitalizeFully from Apache Commons Lang for this.

 list.stream()

     .sorted(Comparator.comparingInt(String::length))

     .map(WordUtils::capitalizeFully)

     .forEach(System.out::println);

edited Dec 12 '18 at 7:15

Peter Mortensen

13.5k1983111

answered Dec 11 '18 at 23:38

fastcodejava

24k19109162

edited Dec 12 '18 at 7:15

Peter Mortensen

13.5k1983111

edited Dec 12 '18 at 7:15

Peter Mortensen

13.5k1983111

edited Dec 12 '18 at 7:15

Peter Mortensen

13.5k1983111

answered Dec 11 '18 at 23:38

fastcodejava

24k19109162

answered Dec 11 '18 at 23:38

fastcodejava

24k19109162

answered Dec 11 '18 at 23:38

fastcodejava

24k19109162

1

OP wants to capitalise only the first letter. Besides, you didn't mention where WordUtils comes from...
– Andrew Tobilko
Dec 11 '18 at 23:39

1

@AndrewTobilko WordUtils::capitalizeFully does just that. I have mentioned where WordUtils comes from now.
– fastcodejava
Dec 11 '18 at 23:42

4

New code should use the commons-text version of this method instead, as the commons-lang one has been deprecated.
– Alex Reinking
Dec 12 '18 at 6:10

add a comment |

1

OP wants to capitalise only the first letter. Besides, you didn't mention where WordUtils comes from...
– Andrew Tobilko
Dec 11 '18 at 23:39

1

@AndrewTobilko WordUtils::capitalizeFully does just that. I have mentioned where WordUtils comes from now.
– fastcodejava
Dec 11 '18 at 23:42

4

New code should use the commons-text version of this method instead, as the commons-lang one has been deprecated.
– Alex Reinking
Dec 12 '18 at 6:10

OP wants to capitalise only the first letter. Besides, you didn't mention where WordUtils comes from...
– Andrew Tobilko
Dec 11 '18 at 23:39

@AndrewTobilko WordUtils::capitalizeFully does just that. I have mentioned where WordUtils comes from now.
– fastcodejava
Dec 11 '18 at 23:42

New code should use the commons-text version of this method instead, as the commons-lang one has been deprecated.
– Alex Reinking
Dec 12 '18 at 6:10

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