Changing directory in script doesn't change directory — why?
I've seen this answer since searching for this, but initially I wrote this script:
for i in `seq 1 $1`;
do cd ../;
done;
It doesn't change directory. Why is this, running as
./updir.sh 5
bash bash-scripting
asked Dec 6 '18 at 16:15
David Boshton
1104
add a comment |
I've seen this answer since searching for this, but initially I wrote this script:
for i in `seq 1 $1`;
do cd ../;
done;
It doesn't change directory. Why is this, running as
./updir.sh 5
bash bash-scripting
asked Dec 6 '18 at 16:15
David Boshton
1104
Thanks guys. I've gone with the function solution with:function updir() { a=""; for i inseq 1 $1; do a=$a"../"; done; cd $a; }. This allows use ofcd -as expected.
– David Boshton
Dec 6 '18 at 17:39
add a comment |
I've seen this answer since searching for this, but initially I wrote this script:
for i in `seq 1 $1`;
do cd ../;
done;
It doesn't change directory. Why is this, running as
./updir.sh 5
bash bash-scripting
asked Dec 6 '18 at 16:15
David Boshton
1104
I've seen this answer since searching for this, but initially I wrote this script:
for i in `seq 1 $1`;
do cd ../;
done;
It doesn't change directory. Why is this, running as
./updir.sh 5
bash bash-scripting
bash bash-scripting
asked Dec 6 '18 at 16:15
David Boshton
1104
asked Dec 6 '18 at 16:15
David Boshton
1104
edited Dec 6 '18 at 16:34
asked Dec 6 '18 at 16:15
David Boshton
1104
asked Dec 6 '18 at 16:15
David Boshton
1104
asked Dec 6 '18 at 16:15
David Boshton
1104
1104
Thanks guys. I've gone with the function solution with:function updir() { a=""; for i inseq 1 $1; do a=$a"../"; done; cd $a; }. This allows use ofcd -as expected.
– David Boshton
Dec 6 '18 at 17:39
add a comment |
Thanks guys. I've gone with the function solution with:function updir() { a=""; for i inseq 1 $1; do a=$a"../"; done; cd $a; }. This allows use ofcd -as expected.
– David Boshton
Dec 6 '18 at 17:39
Thanks guys. I've gone with the function solution with:
function updir() { a=""; for i in seq 1 $1; do a=$a"../"; done; cd $a; }. This allows use of cd - as expected.– David Boshton
Dec 6 '18 at 17:39
Thanks guys. I've gone with the function solution with:
function updir() { a=""; for i in seq 1 $1; do a=$a"../"; done; cd $a; }. This allows use of cd - as expected.– David Boshton
Dec 6 '18 at 17:39
add a comment |
2 Answers
2
active
oldest
votes
Running a script as you show creates a copied environment in a sub-shell, and any changes you make, such as setting directories or environment variables, affect only this sub-shell environment, not the calling shell.
In order to make changes to the current shell from a script, you must run the script within the current shell using the source or . command:
. ./updir.sh 5
You can make this automatic with an alias:
alias updir='. ./updir.sh'
Alternatively, you can use a function instead of a script:
updir()
{ for i in `seq 1 $1`;
do cd ../;
done
}
answered Dec 6 '18 at 16:30
AFH
13.9k31938
add a comment |
Because scripts are run in a subshell, which keeps track of the current working directory separately. The simplest solution is to use a function:
function updir() {
for i in $(seq 1 $1); do
cd ..
done
}
edited Dec 6 '18 at 16:35
Kamil Maciorowski
24.5k155277
answered Dec 6 '18 at 16:27
Program man
1211
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 '18 at 16:33
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Running a script as you show creates a copied environment in a sub-shell, and any changes you make, such as setting directories or environment variables, affect only this sub-shell environment, not the calling shell.
In order to make changes to the current shell from a script, you must run the script within the current shell using the source or . command:
. ./updir.sh 5
You can make this automatic with an alias:
alias updir='. ./updir.sh'
Alternatively, you can use a function instead of a script:
updir()
{ for i in `seq 1 $1`;
do cd ../;
done
}
answered Dec 6 '18 at 16:30
AFH
13.9k31938
add a comment |
Running a script as you show creates a copied environment in a sub-shell, and any changes you make, such as setting directories or environment variables, affect only this sub-shell environment, not the calling shell.
In order to make changes to the current shell from a script, you must run the script within the current shell using the source or . command:
. ./updir.sh 5
You can make this automatic with an alias:
alias updir='. ./updir.sh'
Alternatively, you can use a function instead of a script:
updir()
{ for i in `seq 1 $1`;
do cd ../;
done
}
answered Dec 6 '18 at 16:30
AFH
13.9k31938
add a comment |
Running a script as you show creates a copied environment in a sub-shell, and any changes you make, such as setting directories or environment variables, affect only this sub-shell environment, not the calling shell.
In order to make changes to the current shell from a script, you must run the script within the current shell using the source or . command:
. ./updir.sh 5
You can make this automatic with an alias:
alias updir='. ./updir.sh'
Alternatively, you can use a function instead of a script:
updir()
{ for i in `seq 1 $1`;
do cd ../;
done
}
answered Dec 6 '18 at 16:30
AFH
13.9k31938
Running a script as you show creates a copied environment in a sub-shell, and any changes you make, such as setting directories or environment variables, affect only this sub-shell environment, not the calling shell.
In order to make changes to the current shell from a script, you must run the script within the current shell using the source or . command:
. ./updir.sh 5
You can make this automatic with an alias:
alias updir='. ./updir.sh'
Alternatively, you can use a function instead of a script:
updir()
{ for i in `seq 1 $1`;
do cd ../;
done
}
answered Dec 6 '18 at 16:30
AFH
13.9k31938
answered Dec 6 '18 at 16:30
AFH
13.9k31938
answered Dec 6 '18 at 16:30
AFH
13.9k31938
answered Dec 6 '18 at 16:30
AFH
13.9k31938
13.9k31938
add a comment |
add a comment |
Because scripts are run in a subshell, which keeps track of the current working directory separately. The simplest solution is to use a function:
function updir() {
for i in $(seq 1 $1); do
cd ..
done
}
edited Dec 6 '18 at 16:35
Kamil Maciorowski
24.5k155277
answered Dec 6 '18 at 16:27
Program man
1211
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 '18 at 16:33
add a comment |
Because scripts are run in a subshell, which keeps track of the current working directory separately. The simplest solution is to use a function:
function updir() {
for i in $(seq 1 $1); do
cd ..
done
}
edited Dec 6 '18 at 16:35
Kamil Maciorowski
24.5k155277
answered Dec 6 '18 at 16:27
Program man
1211
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 '18 at 16:33
add a comment |
Because scripts are run in a subshell, which keeps track of the current working directory separately. The simplest solution is to use a function:
function updir() {
for i in $(seq 1 $1); do
cd ..
done
}
edited Dec 6 '18 at 16:35
Kamil Maciorowski
24.5k155277
answered Dec 6 '18 at 16:27
Program man
1211
Because scripts are run in a subshell, which keeps track of the current working directory separately. The simplest solution is to use a function:
function updir() {
for i in $(seq 1 $1); do
cd ..
done
}
edited Dec 6 '18 at 16:35
Kamil Maciorowski
24.5k155277
answered Dec 6 '18 at 16:27
Program man
1211
edited Dec 6 '18 at 16:35
Kamil Maciorowski
24.5k155277
edited Dec 6 '18 at 16:35
Kamil Maciorowski
24.5k155277
edited Dec 6 '18 at 16:35
Kamil Maciorowski
24.5k155277
24.5k155277
answered Dec 6 '18 at 16:27
Program man
1211
answered Dec 6 '18 at 16:27
Program man
1211
answered Dec 6 '18 at 16:27
Program man
1211
1211
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 '18 at 16:33
add a comment |
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 '18 at 16:33
1
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 '18 at 16:33
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 '18 at 16:33
add a comment |
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Thanks guys. I've gone with the function solution with:
function updir() { a=""; for i inseq 1 $1; do a=$a"../"; done; cd $a; }. This allows use ofcd -as expected.– David Boshton
Dec 6 '18 at 17:39