Iteratively checking array of array of strings
$begingroup$
The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs
You are given 2 arguments:
possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
'134.0', 'USD', 'M53'],
['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]
personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
'USD','M53', '37'],
['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]
Return an output (as an array of strings) that checks the arguments against each other in the
following format:
scanner(possible_criminals, personal_information) =
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
'criminal']]
def scanner(possible_criminals , personal_information)
'''
this problem can be simplified by understanding that the output
contains an array of 3 values
1) index[0] from argument 1
2) index[0] from argument 2
3) a value calculated by our function db_checker
steps to solve the problem:
- creating value 1) and 2) in output by extracting index 0 from given
arguments(possible_criminals , personal_information)
- "prepare" the arguments(possible_criminals , personal_information) for comparison
by sanitizing them:
- run "".lower() to account for case-insensitive matches
- pop unnecessary values
- calculating whether the arguments match by using a function
that compares possible_criminals with their personal_information
- function checks how many matches are there
'''
def db_checker(A, B):
counter = 0
for x in A:
if B.count(x) == 0:
counter += 1
if counter == 0:
return "criminal"
elif counter == 1:
return "possible"
elif counter == 2:
return "unlikely"
else:
return "none"
def init_output(N, M):
outputs =
for i in range(len(N)):
output =
output += [N[i].pop(0)] + [M[i].pop(0)]
outputs.append(output)
N[i].pop(2) # remove undesired values
M[i].pop(-1)
N[i] = [y.lower() for y in N[i]]
M[i] = [k.lower() for k in M[i]]
return outputs, N, M
# driver program
final = init_output(possible_criminals , personal_information )
for i in range(len(final[1])):
final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
return final[0]
assert scanner(possible_criminals , personal_information) ==
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]
python formatting
asked 5 mins ago
sgezasgeza
133
$endgroup$
add a comment |
$begingroup$
The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs
You are given 2 arguments:
possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
'134.0', 'USD', 'M53'],
['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]
personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
'USD','M53', '37'],
['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]
Return an output (as an array of strings) that checks the arguments against each other in the
following format:
scanner(possible_criminals, personal_information) =
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
'criminal']]
def scanner(possible_criminals , personal_information)
'''
this problem can be simplified by understanding that the output
contains an array of 3 values
1) index[0] from argument 1
2) index[0] from argument 2
3) a value calculated by our function db_checker
steps to solve the problem:
- creating value 1) and 2) in output by extracting index 0 from given
arguments(possible_criminals , personal_information)
- "prepare" the arguments(possible_criminals , personal_information) for comparison
by sanitizing them:
- run "".lower() to account for case-insensitive matches
- pop unnecessary values
- calculating whether the arguments match by using a function
that compares possible_criminals with their personal_information
- function checks how many matches are there
'''
def db_checker(A, B):
counter = 0
for x in A:
if B.count(x) == 0:
counter += 1
if counter == 0:
return "criminal"
elif counter == 1:
return "possible"
elif counter == 2:
return "unlikely"
else:
return "none"
def init_output(N, M):
outputs =
for i in range(len(N)):
output =
output += [N[i].pop(0)] + [M[i].pop(0)]
outputs.append(output)
N[i].pop(2) # remove undesired values
M[i].pop(-1)
N[i] = [y.lower() for y in N[i]]
M[i] = [k.lower() for k in M[i]]
return outputs, N, M
# driver program
final = init_output(possible_criminals , personal_information )
for i in range(len(final[1])):
final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
return final[0]
assert scanner(possible_criminals , personal_information) ==
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]
python formatting
asked 5 mins ago
sgezasgeza
133
$endgroup$
add a comment |
$begingroup$
The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs
You are given 2 arguments:
possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
'134.0', 'USD', 'M53'],
['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]
personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
'USD','M53', '37'],
['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]
Return an output (as an array of strings) that checks the arguments against each other in the
following format:
scanner(possible_criminals, personal_information) =
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
'criminal']]
def scanner(possible_criminals , personal_information)
'''
this problem can be simplified by understanding that the output
contains an array of 3 values
1) index[0] from argument 1
2) index[0] from argument 2
3) a value calculated by our function db_checker
steps to solve the problem:
- creating value 1) and 2) in output by extracting index 0 from given
arguments(possible_criminals , personal_information)
- "prepare" the arguments(possible_criminals , personal_information) for comparison
by sanitizing them:
- run "".lower() to account for case-insensitive matches
- pop unnecessary values
- calculating whether the arguments match by using a function
that compares possible_criminals with their personal_information
- function checks how many matches are there
'''
def db_checker(A, B):
counter = 0
for x in A:
if B.count(x) == 0:
counter += 1
if counter == 0:
return "criminal"
elif counter == 1:
return "possible"
elif counter == 2:
return "unlikely"
else:
return "none"
def init_output(N, M):
outputs =
for i in range(len(N)):
output =
output += [N[i].pop(0)] + [M[i].pop(0)]
outputs.append(output)
N[i].pop(2) # remove undesired values
M[i].pop(-1)
N[i] = [y.lower() for y in N[i]]
M[i] = [k.lower() for k in M[i]]
return outputs, N, M
# driver program
final = init_output(possible_criminals , personal_information )
for i in range(len(final[1])):
final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
return final[0]
assert scanner(possible_criminals , personal_information) ==
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]
python formatting
asked 5 mins ago
sgezasgeza
133
$endgroup$
The goal is to reduce the run-time of the operation, the function is working as intended but I'm struggling to make it more efficient larger inputs
You are given 2 arguments:
possible_criminals = [['9AheT-12=', 'Daniel', 'Lenny', '3512-6910',
'134.0', 'USD', 'M53'],
['zOvfqFxTWqQ=', 'Sylar', 'Seil', '1081-6760', '331.0', 'GBP', 'A46047']]
personal_information = [['Tzhq+56p=', 'Daniel', 'Lenny', '134.0',
'USD','M53', '37'],
['qWNmZankudw=', 'Sylar', 'Seil', '331.0', 'GBP', 'A46047', '676']]
Return an output (as an array of strings) that checks the arguments against each other in the
following format:
scanner(possible_criminals, personal_information) =
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=',
'criminal']]
def scanner(possible_criminals , personal_information)
'''
this problem can be simplified by understanding that the output
contains an array of 3 values
1) index[0] from argument 1
2) index[0] from argument 2
3) a value calculated by our function db_checker
steps to solve the problem:
- creating value 1) and 2) in output by extracting index 0 from given
arguments(possible_criminals , personal_information)
- "prepare" the arguments(possible_criminals , personal_information) for comparison
by sanitizing them:
- run "".lower() to account for case-insensitive matches
- pop unnecessary values
- calculating whether the arguments match by using a function
that compares possible_criminals with their personal_information
- function checks how many matches are there
'''
def db_checker(A, B):
counter = 0
for x in A:
if B.count(x) == 0:
counter += 1
if counter == 0:
return "criminal"
elif counter == 1:
return "possible"
elif counter == 2:
return "unlikely"
else:
return "none"
def init_output(N, M):
outputs =
for i in range(len(N)):
output =
output += [N[i].pop(0)] + [M[i].pop(0)]
outputs.append(output)
N[i].pop(2) # remove undesired values
M[i].pop(-1)
N[i] = [y.lower() for y in N[i]]
M[i] = [k.lower() for k in M[i]]
return outputs, N, M
# driver program
final = init_output(possible_criminals , personal_information )
for i in range(len(final[1])):
final[0][i].append(confidence_calculator(final[1][i], final[2][i]))
return final[0]
assert scanner(possible_criminals , personal_information) ==
[['9AheT-12=', 'Tzhq+56p=', 'criminal'], ['zOvfqFxTWqQ=', 'qWNmZankudw=', 'criminal']]
python formatting
python formatting
asked 5 mins ago
sgezasgeza
133
asked 5 mins ago
sgezasgeza
133
asked 5 mins ago
sgezasgeza
133
asked 5 mins ago
sgezasgeza
133
asked 5 mins ago
sgezasgeza
133
133
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "196"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f215591%2fiteratively-checking-array-of-array-of-strings%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f215591%2fiteratively-checking-array-of-array-of-strings%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
