algorithm in booth multiplier
0
$begingroup$
i have got following code for booth multiplier but i am not able to understand logic behind it. Not able to trace how really the program works
module Booth_Main #(parameter n=8)(out,a,b);
output [(2*n):0]out;
input [n:0]a,b;
wire [(2*n):0]w[n:0];
wire [n+1:0]q;
assign q = {b,1'b0};
assign out=w[0]+(w[1]<<1)+(w[2]<<2)+(w[3]<<3)+(w[4]<<4)+(w[5]<<5)+(w[6]<<6)+(w[7]<<7);
genvar i;
generate
for(i=0;i<=8;i=i+1)
begin
MUX #(.n(8))m1(w[i],a,q[i+1:i]);
end
endgenerate
endmodule
module MUX #(parameter n=8) (out,a,s);
output reg [(2*n):0]out;
input [n:0]a;
input [1:0]s; //mux select line
always @ (a,s)
begin
case(s)
2'b00: out<=0;
2'b01: out<= a;
2'b10: out<= ~a+1;
2'b11: out<=0;
endcase
end
endmodule
verilog
asked 4 mins ago
SHRIVATHSA TUNGASHRIVATHSA TUNGA
1
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$endgroup$
add a comment |
0
$begingroup$
i have got following code for booth multiplier but i am not able to understand logic behind it. Not able to trace how really the program works
module Booth_Main #(parameter n=8)(out,a,b);
output [(2*n):0]out;
input [n:0]a,b;
wire [(2*n):0]w[n:0];
wire [n+1:0]q;
assign q = {b,1'b0};
assign out=w[0]+(w[1]<<1)+(w[2]<<2)+(w[3]<<3)+(w[4]<<4)+(w[5]<<5)+(w[6]<<6)+(w[7]<<7);
genvar i;
generate
for(i=0;i<=8;i=i+1)
begin
MUX #(.n(8))m1(w[i],a,q[i+1:i]);
end
endgenerate
endmodule
module MUX #(parameter n=8) (out,a,s);
output reg [(2*n):0]out;
input [n:0]a;
input [1:0]s; //mux select line
always @ (a,s)
begin
case(s)
2'b00: out<=0;
2'b01: out<= a;
2'b10: out<= ~a+1;
2'b11: out<=0;
endcase
end
endmodule
verilog
asked 4 mins ago
SHRIVATHSA TUNGASHRIVATHSA TUNGA
1
New contributor
SHRIVATHSA TUNGA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
0
0
$begingroup$
i have got following code for booth multiplier but i am not able to understand logic behind it. Not able to trace how really the program works
module Booth_Main #(parameter n=8)(out,a,b);
output [(2*n):0]out;
input [n:0]a,b;
wire [(2*n):0]w[n:0];
wire [n+1:0]q;
assign q = {b,1'b0};
assign out=w[0]+(w[1]<<1)+(w[2]<<2)+(w[3]<<3)+(w[4]<<4)+(w[5]<<5)+(w[6]<<6)+(w[7]<<7);
genvar i;
generate
for(i=0;i<=8;i=i+1)
begin
MUX #(.n(8))m1(w[i],a,q[i+1:i]);
end
endgenerate
endmodule
module MUX #(parameter n=8) (out,a,s);
output reg [(2*n):0]out;
input [n:0]a;
input [1:0]s; //mux select line
always @ (a,s)
begin
case(s)
2'b00: out<=0;
2'b01: out<= a;
2'b10: out<= ~a+1;
2'b11: out<=0;
endcase
end
endmodule
verilog
asked 4 mins ago
SHRIVATHSA TUNGASHRIVATHSA TUNGA
1
New contributor
SHRIVATHSA TUNGA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
i have got following code for booth multiplier but i am not able to understand logic behind it. Not able to trace how really the program works
module Booth_Main #(parameter n=8)(out,a,b);
output [(2*n):0]out;
input [n:0]a,b;
wire [(2*n):0]w[n:0];
wire [n+1:0]q;
assign q = {b,1'b0};
assign out=w[0]+(w[1]<<1)+(w[2]<<2)+(w[3]<<3)+(w[4]<<4)+(w[5]<<5)+(w[6]<<6)+(w[7]<<7);
genvar i;
generate
for(i=0;i<=8;i=i+1)
begin
MUX #(.n(8))m1(w[i],a,q[i+1:i]);
end
endgenerate
endmodule
module MUX #(parameter n=8) (out,a,s);
output reg [(2*n):0]out;
input [n:0]a;
input [1:0]s; //mux select line
always @ (a,s)
begin
case(s)
2'b00: out<=0;
2'b01: out<= a;
2'b10: out<= ~a+1;
2'b11: out<=0;
endcase
end
endmodule
verilog
verilog
asked 4 mins ago
SHRIVATHSA TUNGASHRIVATHSA TUNGA
1
New contributor
SHRIVATHSA TUNGA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
SHRIVATHSA TUNGASHRIVATHSA TUNGA
1
New contributor
SHRIVATHSA TUNGA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
SHRIVATHSA TUNGASHRIVATHSA TUNGA
1
New contributor
SHRIVATHSA TUNGA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 mins ago
SHRIVATHSA TUNGASHRIVATHSA TUNGA
1
asked 4 mins ago
SHRIVATHSA TUNGASHRIVATHSA TUNGA
1
1
New contributor
SHRIVATHSA TUNGA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
SHRIVATHSA TUNGA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
SHRIVATHSA TUNGA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
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