Simple countdown programs to print “3, 2, 1, Action!” using while loop












8












$begingroup$


My program is a simple while loop making a countdown starting from 3 and shouts "Action!" upon reaching zero and then breaks. I would like to know which of the following ways is better in means of clarity and functionality. I am aware that there are other ways to achieve the same thing. I would like to hear your thoughts and suggestions.



countDown = 3

while (countDown >= 0):

    print(countDown)

    countDown = countDown - 1

    if countDown == 0:

        print("Action!")

        break


or



countDown = 3

while (countDown >= 0):

    if countDown != 0:

        print(countDown)

        countDown = countDown - 1

    else:

        print("Action!")

        break





python python-3.x comparative-review







share|improve this question











$endgroup$












  • $begingroup$
    Are you saying it has to be a while loop?
    $endgroup$
    – dangee1705
    Oct 3 '17 at 15:28
















8












$begingroup$


My program is a simple while loop making a countdown starting from 3 and shouts "Action!" upon reaching zero and then breaks. I would like to know which of the following ways is better in means of clarity and functionality. I am aware that there are other ways to achieve the same thing. I would like to hear your thoughts and suggestions.



countDown = 3

while (countDown >= 0):

    print(countDown)

    countDown = countDown - 1

    if countDown == 0:

        print("Action!")

        break


or



countDown = 3

while (countDown >= 0):

    if countDown != 0:

        print(countDown)

        countDown = countDown - 1

    else:

        print("Action!")

        break





python python-3.x comparative-review







share|improve this question











$endgroup$












  • $begingroup$
    Are you saying it has to be a while loop?
    $endgroup$
    – dangee1705
    Oct 3 '17 at 15:28














8












8








8


3



$begingroup$


My program is a simple while loop making a countdown starting from 3 and shouts "Action!" upon reaching zero and then breaks. I would like to know which of the following ways is better in means of clarity and functionality. I am aware that there are other ways to achieve the same thing. I would like to hear your thoughts and suggestions.



countDown = 3

while (countDown >= 0):

    print(countDown)

    countDown = countDown - 1

    if countDown == 0:

        print("Action!")

        break


or



countDown = 3

while (countDown >= 0):

    if countDown != 0:

        print(countDown)

        countDown = countDown - 1

    else:

        print("Action!")

        break





python python-3.x comparative-review







share|improve this question











$endgroup$




My program is a simple while loop making a countdown starting from 3 and shouts "Action!" upon reaching zero and then breaks. I would like to know which of the following ways is better in means of clarity and functionality. I am aware that there are other ways to achieve the same thing. I would like to hear your thoughts and suggestions.



countDown = 3

while (countDown >= 0):

    print(countDown)

    countDown = countDown - 1

    if countDown == 0:

        print("Action!")

        break


or



countDown = 3

while (countDown >= 0):

    if countDown != 0:

        print(countDown)

        countDown = countDown - 1

    else:

        print("Action!")

        break





python python-3.x comparative-review




python python-3.x comparative-review






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Oct 2 '17 at 22:22









200_success

129k15153416




129k15153416










asked Oct 2 '17 at 8:23









U.MarvinU.Marvin

41112




41112












  • $begingroup$
    Are you saying it has to be a while loop?
    $endgroup$
    – dangee1705
    Oct 3 '17 at 15:28


















  • $begingroup$
    Are you saying it has to be a while loop?
    $endgroup$
    – dangee1705
    Oct 3 '17 at 15:28
















$begingroup$
Are you saying it has to be a while loop?
$endgroup$
– dangee1705
Oct 3 '17 at 15:28




$begingroup$
Are you saying it has to be a while loop?
$endgroup$
– dangee1705
Oct 3 '17 at 15:28










5 Answers
5






active

oldest

votes


















17












$begingroup$

Why does it has to be a while?



Maybe it is preference but for loops look cleaner.



Reversing can be done by using reversed function which reverses a iteration



countdown = 3

for count in reversed(range(1, countdown+1)):

    print(count)

print('action!')


Or you could use the step parameter in range(start, end, step) and rewrite the for loop to



for count in range(countdown, 0, -1):





share|improve this answer











$endgroup$













  • $begingroup$
    Very good point, however list(range(1, 3, -1)) == . reversed(range(1, countdown + 1)) may be easier to understand, and reason with.
    $endgroup$
    – Peilonrayz
    Oct 2 '17 at 9:34






  • 10




    $begingroup$
    IMO, range(countdown, 0, -1) looks cleaner and more idiomatic than reversed(range(1, countdown+1)). Opinions may vary, of course.
    $endgroup$
    – Ilmari Karonen
    Oct 2 '17 at 10:45



















16












$begingroup$

You can get rid of some instructions by writing this instead:



count_down = 3

while (count_down):

   print(count_down)

   count_down -=  1

print('Action!')


Note that I have replaced countDown by count_down to comply with PEP8' naming conventions.



Code explanation:



count_down -= 1 is equivalent to count_down = count_down - 1. You can read more on Python basic operators.



You do not need to check within the while loop if count_down reached the 0 value because it is already done when you coded while (countDown>=0). I mean you are duplicating the checking. In order to keep DRY, I just decrement the value of count_down by 1 and the break instruction is done by default as I am testing while(count_down) meaning if count_down != 0 in this context (because it also means while count_down is not False or None).






share|improve this answer











$endgroup$









  • 10




    $begingroup$
    Why the parentheses in while (count_down):? And while it's somewhat a matter of taste, I'd argue that while count_down > 0: would express the implied intent better in this case. (In particular, it ensures that the loop will still terminate even if someone changes the initial value of count_down to, say, 3.5 or -1.)
    $endgroup$
    – Ilmari Karonen
    Oct 2 '17 at 10:40



















2












$begingroup$

Why not try recursion? Clean and simple.



num = 10



def countdown(num):

    if num == 0:

        print("Action!")

        return

    print(num)

    countdown(num-1)

countdown(num)





share|improve this answer









$endgroup$





















    1












    $begingroup$

    I think your first example is better in terms of clarity, although you could replace while (countDown >= 0): with while (countDown > 0):, allowing you to remove your break statement.



    Ex:



    countDown = 3
    
while (countDown > 0):
    
    print(countDown)
    
    countDown = countDown - 1
    
    if countDown == 0:
    
        print("Action!")





    share|improve this answer









    $endgroup$





















      -1












      $begingroup$

      This is how a counter should be...



      import time
      

      
def countdown(n):
      
    while n > 0:
      
        print(n)
      
        n = n - 1
      
        if n == 0:
      
            print('Times up')
      

      

      
countdown(50)





      share|improve this answer








      New contributor




      jerald king is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      $endgroup$













      • $begingroup$
        You import time but don't even use it in your answer. Also, this will never work, since the if statement is inside the loop, when n = 0 , the loop will be skipped and will just end without printing Times up
        $endgroup$
        – David White
        6 mins ago













      Your Answer





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      5 Answers
      5






      active

      oldest

      votes








      5 Answers
      5






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      17












      $begingroup$

      Why does it has to be a while?



      Maybe it is preference but for loops look cleaner.



      Reversing can be done by using reversed function which reverses a iteration



      countdown = 3
      
for count in reversed(range(1, countdown+1)):
      
    print(count)
      
print('action!')


      Or you could use the step parameter in range(start, end, step) and rewrite the for loop to



      for count in range(countdown, 0, -1):





      share|improve this answer











      $endgroup$













      • $begingroup$
        Very good point, however list(range(1, 3, -1)) == . reversed(range(1, countdown + 1)) may be easier to understand, and reason with.
        $endgroup$
        – Peilonrayz
        Oct 2 '17 at 9:34






      • 10




        $begingroup$
        IMO, range(countdown, 0, -1) looks cleaner and more idiomatic than reversed(range(1, countdown+1)). Opinions may vary, of course.
        $endgroup$
        – Ilmari Karonen
        Oct 2 '17 at 10:45
















      17












      $begingroup$

      Why does it has to be a while?



      Maybe it is preference but for loops look cleaner.



      Reversing can be done by using reversed function which reverses a iteration



      countdown = 3
      
for count in reversed(range(1, countdown+1)):
      
    print(count)
      
print('action!')


      Or you could use the step parameter in range(start, end, step) and rewrite the for loop to



      for count in range(countdown, 0, -1):





      share|improve this answer











      $endgroup$













      • $begingroup$
        Very good point, however list(range(1, 3, -1)) == . reversed(range(1, countdown + 1)) may be easier to understand, and reason with.
        $endgroup$
        – Peilonrayz
        Oct 2 '17 at 9:34






      • 10




        $begingroup$
        IMO, range(countdown, 0, -1) looks cleaner and more idiomatic than reversed(range(1, countdown+1)). Opinions may vary, of course.
        $endgroup$
        – Ilmari Karonen
        Oct 2 '17 at 10:45














      17












      17








      17





      $begingroup$

      Why does it has to be a while?



      Maybe it is preference but for loops look cleaner.



      Reversing can be done by using reversed function which reverses a iteration



      countdown = 3
      
for count in reversed(range(1, countdown+1)):
      
    print(count)
      
print('action!')


      Or you could use the step parameter in range(start, end, step) and rewrite the for loop to



      for count in range(countdown, 0, -1):





      share|improve this answer











      $endgroup$



      Why does it has to be a while?



      Maybe it is preference but for loops look cleaner.



      Reversing can be done by using reversed function which reverses a iteration



      countdown = 3
      
for count in reversed(range(1, countdown+1)):
      
    print(count)
      
print('action!')


      Or you could use the step parameter in range(start, end, step) and rewrite the for loop to



      for count in range(countdown, 0, -1):






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Oct 3 '17 at 9:04

























      answered Oct 2 '17 at 9:29









      LudisposedLudisposed

      7,96222060




      7,96222060












      • $begingroup$
        Very good point, however list(range(1, 3, -1)) == . reversed(range(1, countdown + 1)) may be easier to understand, and reason with.
        $endgroup$
        – Peilonrayz
        Oct 2 '17 at 9:34






      • 10




        $begingroup$
        IMO, range(countdown, 0, -1) looks cleaner and more idiomatic than reversed(range(1, countdown+1)). Opinions may vary, of course.
        $endgroup$
        – Ilmari Karonen
        Oct 2 '17 at 10:45


















      • $begingroup$
        Very good point, however list(range(1, 3, -1)) == . reversed(range(1, countdown + 1)) may be easier to understand, and reason with.
        $endgroup$
        – Peilonrayz
        Oct 2 '17 at 9:34






      • 10




        $begingroup$
        IMO, range(countdown, 0, -1) looks cleaner and more idiomatic than reversed(range(1, countdown+1)). Opinions may vary, of course.
        $endgroup$
        – Ilmari Karonen
        Oct 2 '17 at 10:45
















      $begingroup$
      Very good point, however list(range(1, 3, -1)) == . reversed(range(1, countdown + 1)) may be easier to understand, and reason with.
      $endgroup$
      – Peilonrayz
      Oct 2 '17 at 9:34




      $begingroup$
      Very good point, however list(range(1, 3, -1)) == . reversed(range(1, countdown + 1)) may be easier to understand, and reason with.
      $endgroup$
      – Peilonrayz
      Oct 2 '17 at 9:34




      10




      10




      $begingroup$
      IMO, range(countdown, 0, -1) looks cleaner and more idiomatic than reversed(range(1, countdown+1)). Opinions may vary, of course.
      $endgroup$
      – Ilmari Karonen
      Oct 2 '17 at 10:45




      $begingroup$
      IMO, range(countdown, 0, -1) looks cleaner and more idiomatic than reversed(range(1, countdown+1)). Opinions may vary, of course.
      $endgroup$
      – Ilmari Karonen
      Oct 2 '17 at 10:45













      16












      $begingroup$

      You can get rid of some instructions by writing this instead:



      count_down = 3
      
while (count_down):
      
   print(count_down)
      
   count_down -=  1
      
print('Action!')


      Note that I have replaced countDown by count_down to comply with PEP8' naming conventions.



      Code explanation:



      count_down -= 1 is equivalent to count_down = count_down - 1. You can read more on Python basic operators.



      You do not need to check within the while loop if count_down reached the 0 value because it is already done when you coded while (countDown>=0). I mean you are duplicating the checking. In order to keep DRY, I just decrement the value of count_down by 1 and the break instruction is done by default as I am testing while(count_down) meaning if count_down != 0 in this context (because it also means while count_down is not False or None).






      share|improve this answer











      $endgroup$









      • 10




        $begingroup$
        Why the parentheses in while (count_down):? And while it's somewhat a matter of taste, I'd argue that while count_down > 0: would express the implied intent better in this case. (In particular, it ensures that the loop will still terminate even if someone changes the initial value of count_down to, say, 3.5 or -1.)
        $endgroup$
        – Ilmari Karonen
        Oct 2 '17 at 10:40
















      16












      $begingroup$

      You can get rid of some instructions by writing this instead:



      count_down = 3
      
while (count_down):
      
   print(count_down)
      
   count_down -=  1
      
print('Action!')


      Note that I have replaced countDown by count_down to comply with PEP8' naming conventions.



      Code explanation:



      count_down -= 1 is equivalent to count_down = count_down - 1. You can read more on Python basic operators.



      You do not need to check within the while loop if count_down reached the 0 value because it is already done when you coded while (countDown>=0). I mean you are duplicating the checking. In order to keep DRY, I just decrement the value of count_down by 1 and the break instruction is done by default as I am testing while(count_down) meaning if count_down != 0 in this context (because it also means while count_down is not False or None).






      share|improve this answer











      $endgroup$









      • 10




        $begingroup$
        Why the parentheses in while (count_down):? And while it's somewhat a matter of taste, I'd argue that while count_down > 0: would express the implied intent better in this case. (In particular, it ensures that the loop will still terminate even if someone changes the initial value of count_down to, say, 3.5 or -1.)
        $endgroup$
        – Ilmari Karonen
        Oct 2 '17 at 10:40














      16












      16








      16





      $begingroup$

      You can get rid of some instructions by writing this instead:



      count_down = 3
      
while (count_down):
      
   print(count_down)
      
   count_down -=  1
      
print('Action!')


      Note that I have replaced countDown by count_down to comply with PEP8' naming conventions.



      Code explanation:



      count_down -= 1 is equivalent to count_down = count_down - 1. You can read more on Python basic operators.



      You do not need to check within the while loop if count_down reached the 0 value because it is already done when you coded while (countDown>=0). I mean you are duplicating the checking. In order to keep DRY, I just decrement the value of count_down by 1 and the break instruction is done by default as I am testing while(count_down) meaning if count_down != 0 in this context (because it also means while count_down is not False or None).






      share|improve this answer











      $endgroup$



      You can get rid of some instructions by writing this instead:



      count_down = 3
      
while (count_down):
      
   print(count_down)
      
   count_down -=  1
      
print('Action!')


      Note that I have replaced countDown by count_down to comply with PEP8' naming conventions.



      Code explanation:



      count_down -= 1 is equivalent to count_down = count_down - 1. You can read more on Python basic operators.



      You do not need to check within the while loop if count_down reached the 0 value because it is already done when you coded while (countDown>=0). I mean you are duplicating the checking. In order to keep DRY, I just decrement the value of count_down by 1 and the break instruction is done by default as I am testing while(count_down) meaning if count_down != 0 in this context (because it also means while count_down is not False or None).







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Oct 2 '17 at 8:57

























      answered Oct 2 '17 at 8:34









      Billal BegueradjBillal Begueradj

      1




      1








      • 10




        $begingroup$
        Why the parentheses in while (count_down):? And while it's somewhat a matter of taste, I'd argue that while count_down > 0: would express the implied intent better in this case. (In particular, it ensures that the loop will still terminate even if someone changes the initial value of count_down to, say, 3.5 or -1.)
        $endgroup$
        – Ilmari Karonen
        Oct 2 '17 at 10:40














      • 10




        $begingroup$
        Why the parentheses in while (count_down):? And while it's somewhat a matter of taste, I'd argue that while count_down > 0: would express the implied intent better in this case. (In particular, it ensures that the loop will still terminate even if someone changes the initial value of count_down to, say, 3.5 or -1.)
        $endgroup$
        – Ilmari Karonen
        Oct 2 '17 at 10:40








      10




      10




      $begingroup$
      Why the parentheses in while (count_down):? And while it's somewhat a matter of taste, I'd argue that while count_down > 0: would express the implied intent better in this case. (In particular, it ensures that the loop will still terminate even if someone changes the initial value of count_down to, say, 3.5 or -1.)
      $endgroup$
      – Ilmari Karonen
      Oct 2 '17 at 10:40




      $begingroup$
      Why the parentheses in while (count_down):? And while it's somewhat a matter of taste, I'd argue that while count_down > 0: would express the implied intent better in this case. (In particular, it ensures that the loop will still terminate even if someone changes the initial value of count_down to, say, 3.5 or -1.)
      $endgroup$
      – Ilmari Karonen
      Oct 2 '17 at 10:40











      2












      $begingroup$

      Why not try recursion? Clean and simple.



      num = 10
      

      
def countdown(num):
      
    if num == 0:
      
        print("Action!")
      
        return
      
    print(num)
      
    countdown(num-1)
      
countdown(num)





      share|improve this answer









      $endgroup$


















        2












        $begingroup$

        Why not try recursion? Clean and simple.



        num = 10
        

        
def countdown(num):
        
    if num == 0:
        
        print("Action!")
        
        return
        
    print(num)
        
    countdown(num-1)
        
countdown(num)





        share|improve this answer









        $endgroup$
















          2












          2








          2





          $begingroup$

          Why not try recursion? Clean and simple.



          num = 10
          

          
def countdown(num):
          
    if num == 0:
          
        print("Action!")
          
        return
          
    print(num)
          
    countdown(num-1)
          
countdown(num)





          share|improve this answer









          $endgroup$



          Why not try recursion? Clean and simple.



          num = 10
          

          
def countdown(num):
          
    if num == 0:
          
        print("Action!")
          
        return
          
    print(num)
          
    countdown(num-1)
          
countdown(num)






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Oct 3 '17 at 13:24









          amin.avanamin.avan

          211




          211























              1












              $begingroup$

              I think your first example is better in terms of clarity, although you could replace while (countDown >= 0): with while (countDown > 0):, allowing you to remove your break statement.



              Ex:



              countDown = 3
              
while (countDown > 0):
              
    print(countDown)
              
    countDown = countDown - 1
              
    if countDown == 0:
              
        print("Action!")





              share|improve this answer









              $endgroup$


















                1












                $begingroup$

                I think your first example is better in terms of clarity, although you could replace while (countDown >= 0): with while (countDown > 0):, allowing you to remove your break statement.



                Ex:



                countDown = 3
                
while (countDown > 0):
                
    print(countDown)
                
    countDown = countDown - 1
                
    if countDown == 0:
                
        print("Action!")





                share|improve this answer









                $endgroup$
















                  1












                  1








                  1





                  $begingroup$

                  I think your first example is better in terms of clarity, although you could replace while (countDown >= 0): with while (countDown > 0):, allowing you to remove your break statement.



                  Ex:



                  countDown = 3
                  
while (countDown > 0):
                  
    print(countDown)
                  
    countDown = countDown - 1
                  
    if countDown == 0:
                  
        print("Action!")





                  share|improve this answer









                  $endgroup$



                  I think your first example is better in terms of clarity, although you could replace while (countDown >= 0): with while (countDown > 0):, allowing you to remove your break statement.



                  Ex:



                  countDown = 3
                  
while (countDown > 0):
                  
    print(countDown)
                  
    countDown = countDown - 1
                  
    if countDown == 0:
                  
        print("Action!")






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Oct 4 '17 at 2:40









                  ConfettimakerConfettimaker

                  145212




                  145212























                      -1












                      $begingroup$

                      This is how a counter should be...



                      import time
                      

                      
def countdown(n):
                      
    while n > 0:
                      
        print(n)
                      
        n = n - 1
                      
        if n == 0:
                      
            print('Times up')
                      

                      

                      
countdown(50)





                      share|improve this answer








                      New contributor




                      jerald king is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      $endgroup$













                      • $begingroup$
                        You import time but don't even use it in your answer. Also, this will never work, since the if statement is inside the loop, when n = 0 , the loop will be skipped and will just end without printing Times up
                        $endgroup$
                        – David White
                        6 mins ago


















                      -1












                      $begingroup$

                      This is how a counter should be...



                      import time
                      

                      
def countdown(n):
                      
    while n > 0:
                      
        print(n)
                      
        n = n - 1
                      
        if n == 0:
                      
            print('Times up')
                      

                      

                      
countdown(50)





                      share|improve this answer








                      New contributor




                      jerald king is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      $endgroup$













                      • $begingroup$
                        You import time but don't even use it in your answer. Also, this will never work, since the if statement is inside the loop, when n = 0 , the loop will be skipped and will just end without printing Times up
                        $endgroup$
                        – David White
                        6 mins ago
















                      -1












                      -1








                      -1





                      $begingroup$

                      This is how a counter should be...



                      import time
                      

                      
def countdown(n):
                      
    while n > 0:
                      
        print(n)
                      
        n = n - 1
                      
        if n == 0:
                      
            print('Times up')
                      

                      

                      
countdown(50)





                      share|improve this answer








                      New contributor




                      jerald king is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      $endgroup$



                      This is how a counter should be...



                      import time
                      

                      
def countdown(n):
                      
    while n > 0:
                      
        print(n)
                      
        n = n - 1
                      
        if n == 0:
                      
            print('Times up')
                      

                      

                      
countdown(50)






                      share|improve this answer








                      New contributor




                      jerald king is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.









                      share|improve this answer



                      share|improve this answer






                      New contributor




                      jerald king is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.









                      answered 17 mins ago









                      jerald kingjerald king

                      1




                      1




                      New contributor




                      jerald king is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.





                      New contributor





                      jerald king is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      jerald king is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.












                      • $begingroup$
                        You import time but don't even use it in your answer. Also, this will never work, since the if statement is inside the loop, when n = 0 , the loop will be skipped and will just end without printing Times up
                        $endgroup$
                        – David White
                        6 mins ago




















                      • $begingroup$
                        You import time but don't even use it in your answer. Also, this will never work, since the if statement is inside the loop, when n = 0 , the loop will be skipped and will just end without printing Times up
                        $endgroup$
                        – David White
                        6 mins ago


















                      $begingroup$
                      You import time but don't even use it in your answer. Also, this will never work, since the if statement is inside the loop, when n = 0 , the loop will be skipped and will just end without printing Times up
                      $endgroup$
                      – David White
                      6 mins ago






                      $begingroup$
                      You import time but don't even use it in your answer. Also, this will never work, since the if statement is inside the loop, when n = 0 , the loop will be skipped and will just end without printing Times up
                      $endgroup$
                      – David White
                      6 mins ago




















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