Sorting a list while keeping its correspondence to another list












5














I have the following two lists:



ids = {5, 11, 17, 24, 31, 37, 40, 39, 38, 33, 32, 25}



values = {0.0351563, 0.131836, 0.086792, 0.0637894, 0.065752, 0.191388, 0.063796, 0.173784, 0.0503769, 0.0875244, 0.0146484, 0.0351563}


where entries in values correspond to entries in ids.



I now wish to sort ids in ascending order while maintaining the correspondence to values, such that elements in values must be changed according to the changes made to ids.



How can that be achieved?






list-manipulation







share|improve this question
























  • values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
    – user1066
    Dec 2 at 17:53
















5














I have the following two lists:



ids = {5, 11, 17, 24, 31, 37, 40, 39, 38, 33, 32, 25}



values = {0.0351563, 0.131836, 0.086792, 0.0637894, 0.065752, 0.191388, 0.063796, 0.173784, 0.0503769, 0.0875244, 0.0146484, 0.0351563}


where entries in values correspond to entries in ids.



I now wish to sort ids in ascending order while maintaining the correspondence to values, such that elements in values must be changed according to the changes made to ids.



How can that be achieved?






list-manipulation







share|improve this question
























  • values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
    – user1066
    Dec 2 at 17:53














5












5








5


1





I have the following two lists:



ids = {5, 11, 17, 24, 31, 37, 40, 39, 38, 33, 32, 25}



values = {0.0351563, 0.131836, 0.086792, 0.0637894, 0.065752, 0.191388, 0.063796, 0.173784, 0.0503769, 0.0875244, 0.0146484, 0.0351563}


where entries in values correspond to entries in ids.



I now wish to sort ids in ascending order while maintaining the correspondence to values, such that elements in values must be changed according to the changes made to ids.



How can that be achieved?






list-manipulation







share|improve this question















I have the following two lists:



ids = {5, 11, 17, 24, 31, 37, 40, 39, 38, 33, 32, 25}



values = {0.0351563, 0.131836, 0.086792, 0.0637894, 0.065752, 0.191388, 0.063796, 0.173784, 0.0503769, 0.0875244, 0.0146484, 0.0351563}


where entries in values correspond to entries in ids.



I now wish to sort ids in ascending order while maintaining the correspondence to values, such that elements in values must be changed according to the changes made to ids.



How can that be achieved?






list-manipulation




list-manipulation






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 2 at 16:49

























asked Dec 2 at 16:40









user120911

55518




55518












  • values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
    – user1066
    Dec 2 at 17:53


















  • values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
    – user1066
    Dec 2 at 17:53
















values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
– user1066
Dec 2 at 17:53




values[[Ordering@ids]] and SortBy[Transpose[{ids, values}], First] == Transpose[{Sort@ids, values[[Ordering@ids]]}]
– user1066
Dec 2 at 17:53










4 Answers
4






active

oldest

votes


















5














With[{p = Ordering[ids]},

 idsnew = ids[[p]];

 valuesnew = values[[p]];

 ]

idsnew

valuesnew



{5, 11, 17, 24, 25, 31, 32, 33, 37, 38, 39, 40}



{0.0351563, 0.131836, 0.086792, 0.0637894, 0.0351563, 0.065752, 0.0146484, 0.0875244, 0.191388, 0.0503769, 0.173784, 0.063796}







share|improve this answer























  • This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
    – user120911
    Dec 2 at 16:59










  • Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
    – Henrik Schumacher
    Dec 2 at 17:07



















4














I would keep them together while sorting.



SortBy[Transpose[{ids, values}], First]





{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,

   0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37, 

  0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}






share|improve this answer





















  • See also my remark under Okke's post.
    – Henrik Schumacher
    Dec 2 at 18:17



















4














AssociationThread[ids, values] // KeySort


Edit
To extract keys and values



sorted = AssociationThread[ids, values] // KeySort

sortedIds = Keys[sorted]

sortedValues = Values[sorted]





share|improve this answer























  • This looks simple, but how do I work with these afterwards?
    – user120911
    Dec 2 at 17:00










  • @user120911 Added sorted key / value extraction.
    – Rohit Namjoshi
    Dec 2 at 17:24



















2














Since Sort sort it by the first entry by default 



Sort@Transpose@{ids, values}



{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,
0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37,
0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}







share|improve this answer

















  • 1




    A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
    – Henrik Schumacher
    Dec 2 at 18:16











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4 Answers
4






active

oldest

votes








4 Answers
4






active

oldest

votes









active

oldest

votes






active

oldest

votes









5














With[{p = Ordering[ids]},

 idsnew = ids[[p]];

 valuesnew = values[[p]];

 ]

idsnew

valuesnew



{5, 11, 17, 24, 25, 31, 32, 33, 37, 38, 39, 40}



{0.0351563, 0.131836, 0.086792, 0.0637894, 0.0351563, 0.065752, 0.0146484, 0.0875244, 0.191388, 0.0503769, 0.173784, 0.063796}







share|improve this answer























  • This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
    – user120911
    Dec 2 at 16:59










  • Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
    – Henrik Schumacher
    Dec 2 at 17:07
















5














With[{p = Ordering[ids]},

 idsnew = ids[[p]];

 valuesnew = values[[p]];

 ]

idsnew

valuesnew



{5, 11, 17, 24, 25, 31, 32, 33, 37, 38, 39, 40}



{0.0351563, 0.131836, 0.086792, 0.0637894, 0.0351563, 0.065752, 0.0146484, 0.0875244, 0.191388, 0.0503769, 0.173784, 0.063796}







share|improve this answer























  • This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
    – user120911
    Dec 2 at 16:59










  • Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
    – Henrik Schumacher
    Dec 2 at 17:07














5












5








5






With[{p = Ordering[ids]},

 idsnew = ids[[p]];

 valuesnew = values[[p]];

 ]

idsnew

valuesnew



{5, 11, 17, 24, 25, 31, 32, 33, 37, 38, 39, 40}



{0.0351563, 0.131836, 0.086792, 0.0637894, 0.0351563, 0.065752, 0.0146484, 0.0875244, 0.191388, 0.0503769, 0.173784, 0.063796}







share|improve this answer














With[{p = Ordering[ids]},

 idsnew = ids[[p]];

 valuesnew = values[[p]];

 ]

idsnew

valuesnew



{5, 11, 17, 24, 25, 31, 32, 33, 37, 38, 39, 40}



{0.0351563, 0.131836, 0.086792, 0.0637894, 0.0351563, 0.065752, 0.0146484, 0.0875244, 0.191388, 0.0503769, 0.173784, 0.063796}








share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 2 at 17:06

























answered Dec 2 at 16:48









Henrik Schumacher

48.1k467136




48.1k467136












  • This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
    – user120911
    Dec 2 at 16:59










  • Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
    – Henrik Schumacher
    Dec 2 at 17:07


















  • This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
    – user120911
    Dec 2 at 16:59










  • Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
    – Henrik Schumacher
    Dec 2 at 17:07
















This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
– user120911
Dec 2 at 16:59




This generates an error for me: Set::write: Tag Times in valuesnew {5,11,17,24,25,31,32,33,37,38,39,40} is Protected.
– user120911
Dec 2 at 16:59












Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
– Henrik Schumacher
Dec 2 at 17:07




Sorry, I missed a semicolon that was necessary after wrapping everything with With. Please try again.
– Henrik Schumacher
Dec 2 at 17:07











4














I would keep them together while sorting.



SortBy[Transpose[{ids, values}], First]





{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,

   0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37, 

  0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}






share|improve this answer





















  • See also my remark under Okke's post.
    – Henrik Schumacher
    Dec 2 at 18:17
















4














I would keep them together while sorting.



SortBy[Transpose[{ids, values}], First]





{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,

   0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37, 

  0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}






share|improve this answer





















  • See also my remark under Okke's post.
    – Henrik Schumacher
    Dec 2 at 18:17














4












4








4






I would keep them together while sorting.



SortBy[Transpose[{ids, values}], First]





{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,

   0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37, 

  0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}






share|improve this answer












I would keep them together while sorting.



SortBy[Transpose[{ids, values}], First]





{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,

   0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37, 

  0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}







share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 2 at 16:45









Johu

3,6531037




3,6531037












  • See also my remark under Okke's post.
    – Henrik Schumacher
    Dec 2 at 18:17


















  • See also my remark under Okke's post.
    – Henrik Schumacher
    Dec 2 at 18:17
















See also my remark under Okke's post.
– Henrik Schumacher
Dec 2 at 18:17




See also my remark under Okke's post.
– Henrik Schumacher
Dec 2 at 18:17











4














AssociationThread[ids, values] // KeySort


Edit
To extract keys and values



sorted = AssociationThread[ids, values] // KeySort

sortedIds = Keys[sorted]

sortedValues = Values[sorted]





share|improve this answer























  • This looks simple, but how do I work with these afterwards?
    – user120911
    Dec 2 at 17:00










  • @user120911 Added sorted key / value extraction.
    – Rohit Namjoshi
    Dec 2 at 17:24
















4














AssociationThread[ids, values] // KeySort


Edit
To extract keys and values



sorted = AssociationThread[ids, values] // KeySort

sortedIds = Keys[sorted]

sortedValues = Values[sorted]





share|improve this answer























  • This looks simple, but how do I work with these afterwards?
    – user120911
    Dec 2 at 17:00










  • @user120911 Added sorted key / value extraction.
    – Rohit Namjoshi
    Dec 2 at 17:24














4












4








4






AssociationThread[ids, values] // KeySort


Edit
To extract keys and values



sorted = AssociationThread[ids, values] // KeySort

sortedIds = Keys[sorted]

sortedValues = Values[sorted]





share|improve this answer














AssociationThread[ids, values] // KeySort


Edit
To extract keys and values



sorted = AssociationThread[ids, values] // KeySort

sortedIds = Keys[sorted]

sortedValues = Values[sorted]






share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 2 at 17:24

























answered Dec 2 at 16:46









Rohit Namjoshi

7871111




7871111












  • This looks simple, but how do I work with these afterwards?
    – user120911
    Dec 2 at 17:00










  • @user120911 Added sorted key / value extraction.
    – Rohit Namjoshi
    Dec 2 at 17:24


















  • This looks simple, but how do I work with these afterwards?
    – user120911
    Dec 2 at 17:00










  • @user120911 Added sorted key / value extraction.
    – Rohit Namjoshi
    Dec 2 at 17:24
















This looks simple, but how do I work with these afterwards?
– user120911
Dec 2 at 17:00




This looks simple, but how do I work with these afterwards?
– user120911
Dec 2 at 17:00












@user120911 Added sorted key / value extraction.
– Rohit Namjoshi
Dec 2 at 17:24




@user120911 Added sorted key / value extraction.
– Rohit Namjoshi
Dec 2 at 17:24











2














Since Sort sort it by the first entry by default 



Sort@Transpose@{ids, values}



{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,
0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37,
0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}







share|improve this answer

















  • 1




    A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
    – Henrik Schumacher
    Dec 2 at 18:16
















2














Since Sort sort it by the first entry by default 



Sort@Transpose@{ids, values}



{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,
0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37,
0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}







share|improve this answer

















  • 1




    A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
    – Henrik Schumacher
    Dec 2 at 18:16














2












2








2






Since Sort sort it by the first entry by default 



Sort@Transpose@{ids, values}



{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,
0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37,
0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}







share|improve this answer












Since Sort sort it by the first entry by default 



Sort@Transpose@{ids, values}



{{5, 0.0351563}, {11, 0.131836}, {17, 0.086792}, {24, 0.0637894}, {25,
0.0351563}, {31, 0.065752}, {32, 0.0146484}, {33, 0.0875244}, {37,
0.191388}, {38, 0.0503769}, {39, 0.173784}, {40, 0.063796}}








share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 2 at 18:07









Okkes Dulgerci

3,9001816




3,9001816








  • 1




    A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
    – Henrik Schumacher
    Dec 2 at 18:16














  • 1




    A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
    – Henrik Schumacher
    Dec 2 at 18:16








1




1




A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
– Henrik Schumacher
Dec 2 at 18:16




A problem that arises here with Transpose is is that it unpacks arrays: ids is a list of integers and values is a list of machine reals. So both can be packed separately; but not Transpose@{ids, values} as it has mixed data types. This may become important when processing large datasets.
– Henrik Schumacher
Dec 2 at 18:16


















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8-я гвардейская общевойсковая ордена Ленина армия Награды: Войска: РККА → Советская армия → СВ России Род войск: Формирование: 1943 Расформирование (преобразование): 1992 Предшественник: 62-я армия (1942—43) → 8-я гвардейская общевойсковая армия (1943—92) → 8-й гвардейский армейский корпус (1992—98) Боевой путь Изюм-Барвенковская операция Донбасская операция Запорожская операция Битва за Днепр Днепропетровская операция Березнеговато-Снигирёвская операция Одесская операция Люблин-Брестская операция Варшавско-Познанская операция Восточно-Померанская операция Берлинская наступательная операция У этого термина существуют и другие значения, см. 8-я армия. Фотография Гвардейского Красного Знамени (лицевая сторона) 8-й гвардейской армии , образца 1943 года. Фотография Гвардейского Красного Знамени (оборотная сторона) 8-й гвардейской армии , образца 1943 года. 8-я гвардейская общевойсковая ордена Ленина армия  — гвардейское фор...
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Алькесар

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Муниципалитет Алькесар Alquézar Герб 42°10′16″ с. ш. 0°01′27″ в. д. H G Я O L Страна Испания   Испания Автономное сообщество Арагон Провинция Уэска Комарка Сомонтано-де-Барбастро Алькальд Хосе Марияно Альтемир Ласкорс (ИСРП) История и география Площадь 32,36 км² Высота НУМ 660 м Часовой пояс UTC+1, летом UTC+2 Население Население 313 человек ( 2010 ) Плотность 9,92 чел./км² Этнохороним alquezarano/-a Цифровые идентификаторы Телефонный код +34 974 Почтовые индексы 22112 Автомобильный код HU alquezar.org   (исп.) Показать/скрыть карты Алькесар Алькесар Алькесар  Аудио, фото и видео на Викискладе Алькесар (исп.  Alquézar ) — муниципалитет в Испании, входит в провинцию Уэска, в составе автономного сообщества Арагон. Муниципалитет находится в составе района (комарки) Сомонтано-де-Барбастро. Занимает площадь 32,36 км². Население — 321 челове...
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