Search customer by ID not printing
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}
$begingroup$
I dont know why my code is not working at all. In my Eclipse there's no errors shown at all.
I want to use the id to print the name of my customers, and that's my goal
Customer custArray = { new Customer("Chen",35), new Customer("You",36) };
public Customer searchCustomerByID(int custID){
for(Customer c:customers){
if(c.getID() == custID)
return c;
}
return null;
}
````
java
New contributor
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add a comment |
$begingroup$
I dont know why my code is not working at all. In my Eclipse there's no errors shown at all.
I want to use the id to print the name of my customers, and that's my goal
Customer custArray = { new Customer("Chen",35), new Customer("You",36) };
public Customer searchCustomerByID(int custID){
for(Customer c:customers){
if(c.getID() == custID)
return c;
}
return null;
}
````
java
New contributor
$endgroup$
add a comment |
$begingroup$
I dont know why my code is not working at all. In my Eclipse there's no errors shown at all.
I want to use the id to print the name of my customers, and that's my goal
Customer custArray = { new Customer("Chen",35), new Customer("You",36) };
public Customer searchCustomerByID(int custID){
for(Customer c:customers){
if(c.getID() == custID)
return c;
}
return null;
}
````
java
New contributor
$endgroup$
I dont know why my code is not working at all. In my Eclipse there's no errors shown at all.
I want to use the id to print the name of my customers, and that's my goal
Customer custArray = { new Customer("Chen",35), new Customer("You",36) };
public Customer searchCustomerByID(int custID){
for(Customer c:customers){
if(c.getID() == custID)
return c;
}
return null;
}
````
java
java
New contributor
New contributor
New contributor
asked 1 hour ago
Bravooo121334Bravooo121334
1
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1 Answer
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$begingroup$
You wrote this:
for (Customer c : customers)
{
if (c.getID == customID) return c;
}
The array is called custArray
. And the for-each is iterating over an array of Customer
s cales customers
. So, the simple solution is to change customers
to custArray
! Hope that helps. ;)
EDIT: this should be on Stack Overflow.
New contributor
$endgroup$
add a comment |
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1 Answer
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1 Answer
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active
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active
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active
oldest
votes
$begingroup$
You wrote this:
for (Customer c : customers)
{
if (c.getID == customID) return c;
}
The array is called custArray
. And the for-each is iterating over an array of Customer
s cales customers
. So, the simple solution is to change customers
to custArray
! Hope that helps. ;)
EDIT: this should be on Stack Overflow.
New contributor
$endgroup$
add a comment |
$begingroup$
You wrote this:
for (Customer c : customers)
{
if (c.getID == customID) return c;
}
The array is called custArray
. And the for-each is iterating over an array of Customer
s cales customers
. So, the simple solution is to change customers
to custArray
! Hope that helps. ;)
EDIT: this should be on Stack Overflow.
New contributor
$endgroup$
add a comment |
$begingroup$
You wrote this:
for (Customer c : customers)
{
if (c.getID == customID) return c;
}
The array is called custArray
. And the for-each is iterating over an array of Customer
s cales customers
. So, the simple solution is to change customers
to custArray
! Hope that helps. ;)
EDIT: this should be on Stack Overflow.
New contributor
$endgroup$
You wrote this:
for (Customer c : customers)
{
if (c.getID == customID) return c;
}
The array is called custArray
. And the for-each is iterating over an array of Customer
s cales customers
. So, the simple solution is to change customers
to custArray
! Hope that helps. ;)
EDIT: this should be on Stack Overflow.
New contributor
New contributor
answered 40 mins ago
itzjackyscodeitzjackyscode
1
1
New contributor
New contributor
add a comment |
add a comment |
Bravooo121334 is a new contributor. Be nice, and check out our Code of Conduct.
Bravooo121334 is a new contributor. Be nice, and check out our Code of Conduct.
Bravooo121334 is a new contributor. Be nice, and check out our Code of Conduct.
Bravooo121334 is a new contributor. Be nice, and check out our Code of Conduct.
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