Kattis Problem 'Mali'
Multi tool use
$begingroup$
I wrote a solution to the Mali problem on Kattis:
Given inputs a1, a2, a3, …, an and b1, b2, b3, …, bn, determine n pairings (ai, bj) such that each number in the A sequence is used in exactly one pairing, each number in the B sequence is used in exactly one pairing, and the maximum of all sums ai + bj is minimal.
Input
The first line of input contains a single integer N (1 ≤ N ≤ 100000), the number of rounds.
The next N lines contain two integers A and B (1 ≤ A, B ≤ 100), the numbers given in that round.
Output
The output consists of N lines, one for each round. Each line should contain the smallest maximal sum for that round.
I'm fairly sure I can get the right answer 100% of the time, but the code exceeds the time limit of one second. I was wondering if you could help me optimize my code to help it run in time, or if you could explain why my code is inefficient.
#include <iostream>
#include <vector>
int main() {
int x, c = 0, big = 0;
std::cin >> x;
std::vector<int> as, bs;
for (int i = 0; i < x; i++) {
bool founda = false, foundb = false;
int a, b;
std::cin >> a >> b;
c++;
if (c == 1) {
as.push_back(a);
bs.push_back(b);
}
else {
for (int i = 0; i < c; i++) {
if (as[i] < a || i == c-1) {
as.insert(as.begin()+i, a);
founda = true;
}
if (bs[i] < b || i == c-1) {
bs.insert(bs.begin()+i, b);
foundb = true;
}
if (founda == true && foundb == true)
break;
}
}
for (int i = 0; i < c; i++) {
if (as[i] + bs[c-1-i] > big)
big = as[i] + bs[c-1-i];
}
std::cout << big << std::endl;
}
}
c++ programming-challenge time-limit-exceeded
edited 13 mins ago
200_success
131k17156422
asked 33 mins ago
Griffin WongGriffin Wong
61
New contributor
Griffin Wong is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I wrote a solution to the Mali problem on Kattis:
Given inputs a1, a2, a3, …, an and b1, b2, b3, …, bn, determine n pairings (ai, bj) such that each number in the A sequence is used in exactly one pairing, each number in the B sequence is used in exactly one pairing, and the maximum of all sums ai + bj is minimal.
Input
The first line of input contains a single integer N (1 ≤ N ≤ 100000), the number of rounds.
The next N lines contain two integers A and B (1 ≤ A, B ≤ 100), the numbers given in that round.
Output
The output consists of N lines, one for each round. Each line should contain the smallest maximal sum for that round.
I'm fairly sure I can get the right answer 100% of the time, but the code exceeds the time limit of one second. I was wondering if you could help me optimize my code to help it run in time, or if you could explain why my code is inefficient.
#include <iostream>
#include <vector>
int main() {
int x, c = 0, big = 0;
std::cin >> x;
std::vector<int> as, bs;
for (int i = 0; i < x; i++) {
bool founda = false, foundb = false;
int a, b;
std::cin >> a >> b;
c++;
if (c == 1) {
as.push_back(a);
bs.push_back(b);
}
else {
for (int i = 0; i < c; i++) {
if (as[i] < a || i == c-1) {
as.insert(as.begin()+i, a);
founda = true;
}
if (bs[i] < b || i == c-1) {
bs.insert(bs.begin()+i, b);
foundb = true;
}
if (founda == true && foundb == true)
break;
}
}
for (int i = 0; i < c; i++) {
if (as[i] + bs[c-1-i] > big)
big = as[i] + bs[c-1-i];
}
std::cout << big << std::endl;
}
}
c++ programming-challenge time-limit-exceeded
edited 13 mins ago
200_success
131k17156422
asked 33 mins ago
Griffin WongGriffin Wong
61
New contributor
Griffin Wong is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I wrote a solution to the Mali problem on Kattis:
Given inputs a1, a2, a3, …, an and b1, b2, b3, …, bn, determine n pairings (ai, bj) such that each number in the A sequence is used in exactly one pairing, each number in the B sequence is used in exactly one pairing, and the maximum of all sums ai + bj is minimal.
Input
The first line of input contains a single integer N (1 ≤ N ≤ 100000), the number of rounds.
The next N lines contain two integers A and B (1 ≤ A, B ≤ 100), the numbers given in that round.
Output
The output consists of N lines, one for each round. Each line should contain the smallest maximal sum for that round.
I'm fairly sure I can get the right answer 100% of the time, but the code exceeds the time limit of one second. I was wondering if you could help me optimize my code to help it run in time, or if you could explain why my code is inefficient.
#include <iostream>
#include <vector>
int main() {
int x, c = 0, big = 0;
std::cin >> x;
std::vector<int> as, bs;
for (int i = 0; i < x; i++) {
bool founda = false, foundb = false;
int a, b;
std::cin >> a >> b;
c++;
if (c == 1) {
as.push_back(a);
bs.push_back(b);
}
else {
for (int i = 0; i < c; i++) {
if (as[i] < a || i == c-1) {
as.insert(as.begin()+i, a);
founda = true;
}
if (bs[i] < b || i == c-1) {
bs.insert(bs.begin()+i, b);
foundb = true;
}
if (founda == true && foundb == true)
break;
}
}
for (int i = 0; i < c; i++) {
if (as[i] + bs[c-1-i] > big)
big = as[i] + bs[c-1-i];
}
std::cout << big << std::endl;
}
}
c++ programming-challenge time-limit-exceeded
edited 13 mins ago
200_success
131k17156422
asked 33 mins ago
Griffin WongGriffin Wong
61
New contributor
Griffin Wong is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I wrote a solution to the Mali problem on Kattis:
Given inputs a1, a2, a3, …, an and b1, b2, b3, …, bn, determine n pairings (ai, bj) such that each number in the A sequence is used in exactly one pairing, each number in the B sequence is used in exactly one pairing, and the maximum of all sums ai + bj is minimal.
Input
The first line of input contains a single integer N (1 ≤ N ≤ 100000), the number of rounds.
The next N lines contain two integers A and B (1 ≤ A, B ≤ 100), the numbers given in that round.
Output
The output consists of N lines, one for each round. Each line should contain the smallest maximal sum for that round.
I'm fairly sure I can get the right answer 100% of the time, but the code exceeds the time limit of one second. I was wondering if you could help me optimize my code to help it run in time, or if you could explain why my code is inefficient.
#include <iostream>
#include <vector>
int main() {
int x, c = 0, big = 0;
std::cin >> x;
std::vector<int> as, bs;
for (int i = 0; i < x; i++) {
bool founda = false, foundb = false;
int a, b;
std::cin >> a >> b;
c++;
if (c == 1) {
as.push_back(a);
bs.push_back(b);
}
else {
for (int i = 0; i < c; i++) {
if (as[i] < a || i == c-1) {
as.insert(as.begin()+i, a);
founda = true;
}
if (bs[i] < b || i == c-1) {
bs.insert(bs.begin()+i, b);
foundb = true;
}
if (founda == true && foundb == true)
break;
}
}
for (int i = 0; i < c; i++) {
if (as[i] + bs[c-1-i] > big)
big = as[i] + bs[c-1-i];
}
std::cout << big << std::endl;
}
}
c++ programming-challenge time-limit-exceeded
c++ programming-challenge time-limit-exceeded
edited 13 mins ago
200_success
131k17156422
asked 33 mins ago
Griffin WongGriffin Wong
61
New contributor
Griffin Wong is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 13 mins ago
200_success
131k17156422
asked 33 mins ago
Griffin WongGriffin Wong
61
New contributor
Griffin Wong is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 13 mins ago
200_success
131k17156422
edited 13 mins ago
200_success
131k17156422
edited 13 mins ago
200_success
131k17156422
131k17156422
asked 33 mins ago
Griffin WongGriffin Wong
61
New contributor
Griffin Wong is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 33 mins ago
Griffin WongGriffin Wong
61
asked 33 mins ago
Griffin WongGriffin Wong
61
61
New contributor
Griffin Wong is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Griffin Wong is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Griffin Wong is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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Griffin Wong is a new contributor. Be nice, and check out our Code of Conduct.
Griffin Wong is a new contributor. Be nice, and check out our Code of Conduct.
Griffin Wong is a new contributor. Be nice, and check out our Code of Conduct.
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