Dijkstra's algorithm, output shortest path from source to destination












-3












$begingroup$


I got this code from tutorial horizon and I'm trying to modify it to get it to:




  1. only output the shortest path from source to destination, currently outputs shortest path to all edges from source


  2. output the pathway to the shortest path





static class Edge {
int start;
int end;
int weight;
int length;
Edge previous;

public Edge(int start, int end, int weight) {
this.start = start;
this.end = end;
this.weight = weight;
//this.length = length;
}
}
static class ResultSet{
int parent;
int weight;
}

static class Graph {
int vertex;
LinkedList<Edge> adjacencylist;

Graph(int vertex) {
this.vertex = vertex;
adjacencylist = new LinkedList[vertex];
for (int i = 0; i < vertex; i++) {
adjacencylist[i] = new LinkedList<>();
}
}


public void addEdge(int start, int end, int weight) {
Edge edge = new Edge(start, end, weight);
adjacencylist[start].addFirst(edge);

edge = new Edge(end,start,weight);
adjacencylist[end].addFirst(edge);
}

public ArrayList<String> dijkstra(int startvertex){
boolean SPT = new boolean[vertex];
int distance = new int[vertex];
for(int i =0; i<vertex;i++){
distance[i] = Integer.MAX_VALUE;
}
PriorityQueue<Pair<Integer,Integer>> pq = new PriorityQueue<>(vertex, new Comparator<Pair<Integer, Integer>>() {
@Override
public int compare(Pair<Integer, Integer> o1, Pair<Integer, Integer> o2) {
int key1 = o1.getKey();
int key2 = o2.getKey();
return key1 - key2;
}
});
distance[0] = 0;
Pair<Integer,Integer> p0 = new Pair<>(distance[0],0);
pq.offer(p0);
while(!pq.isEmpty()){
Pair<Integer,Integer> extractedPair = pq.poll();
int extractedVertex = extractedPair.getValue();
if(SPT[extractedVertex]==false){
SPT[extractedVertex] = true;
LinkedList<Edge> list = adjacencylist[extractedVertex];
for (int i = 0; i<list.size();i++){
Edge edge = list.get(i);
//System.out.println(edge.start + ":" + edge.weight + ":" + edge.end);
int end = edge.end;
if(SPT[end] == false){
int newKey = distance[extractedVertex] + edge.weight;
int currentKey = distance[end];
if(currentKey>newKey){
Pair<Integer,Integer> p = new Pair<>(newKey,end);
pq.offer(p);
distance[end] = newKey;
}
}
}
}
}
printDijkstra(distance,startvertex);
ArrayList<String> stuff = checkDijkstra(distance,startvertex);
return stuff;
}









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  • $begingroup$
    Hi, I'm sorry to inform you but Code Review requires not only coffee to already do what you want, but for it also to be written by you. Please see the help center for more information.
    $endgroup$
    – bruglesco
    8 mins ago
















-3












$begingroup$


I got this code from tutorial horizon and I'm trying to modify it to get it to:




  1. only output the shortest path from source to destination, currently outputs shortest path to all edges from source


  2. output the pathway to the shortest path





static class Edge {
int start;
int end;
int weight;
int length;
Edge previous;

public Edge(int start, int end, int weight) {
this.start = start;
this.end = end;
this.weight = weight;
//this.length = length;
}
}
static class ResultSet{
int parent;
int weight;
}

static class Graph {
int vertex;
LinkedList<Edge> adjacencylist;

Graph(int vertex) {
this.vertex = vertex;
adjacencylist = new LinkedList[vertex];
for (int i = 0; i < vertex; i++) {
adjacencylist[i] = new LinkedList<>();
}
}


public void addEdge(int start, int end, int weight) {
Edge edge = new Edge(start, end, weight);
adjacencylist[start].addFirst(edge);

edge = new Edge(end,start,weight);
adjacencylist[end].addFirst(edge);
}

public ArrayList<String> dijkstra(int startvertex){
boolean SPT = new boolean[vertex];
int distance = new int[vertex];
for(int i =0; i<vertex;i++){
distance[i] = Integer.MAX_VALUE;
}
PriorityQueue<Pair<Integer,Integer>> pq = new PriorityQueue<>(vertex, new Comparator<Pair<Integer, Integer>>() {
@Override
public int compare(Pair<Integer, Integer> o1, Pair<Integer, Integer> o2) {
int key1 = o1.getKey();
int key2 = o2.getKey();
return key1 - key2;
}
});
distance[0] = 0;
Pair<Integer,Integer> p0 = new Pair<>(distance[0],0);
pq.offer(p0);
while(!pq.isEmpty()){
Pair<Integer,Integer> extractedPair = pq.poll();
int extractedVertex = extractedPair.getValue();
if(SPT[extractedVertex]==false){
SPT[extractedVertex] = true;
LinkedList<Edge> list = adjacencylist[extractedVertex];
for (int i = 0; i<list.size();i++){
Edge edge = list.get(i);
//System.out.println(edge.start + ":" + edge.weight + ":" + edge.end);
int end = edge.end;
if(SPT[end] == false){
int newKey = distance[extractedVertex] + edge.weight;
int currentKey = distance[end];
if(currentKey>newKey){
Pair<Integer,Integer> p = new Pair<>(newKey,end);
pq.offer(p);
distance[end] = newKey;
}
}
}
}
}
printDijkstra(distance,startvertex);
ArrayList<String> stuff = checkDijkstra(distance,startvertex);
return stuff;
}









share|improve this question









New contributor




mdl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$












  • $begingroup$
    Hi, I'm sorry to inform you but Code Review requires not only coffee to already do what you want, but for it also to be written by you. Please see the help center for more information.
    $endgroup$
    – bruglesco
    8 mins ago














-3












-3








-3





$begingroup$


I got this code from tutorial horizon and I'm trying to modify it to get it to:




  1. only output the shortest path from source to destination, currently outputs shortest path to all edges from source


  2. output the pathway to the shortest path





static class Edge {
int start;
int end;
int weight;
int length;
Edge previous;

public Edge(int start, int end, int weight) {
this.start = start;
this.end = end;
this.weight = weight;
//this.length = length;
}
}
static class ResultSet{
int parent;
int weight;
}

static class Graph {
int vertex;
LinkedList<Edge> adjacencylist;

Graph(int vertex) {
this.vertex = vertex;
adjacencylist = new LinkedList[vertex];
for (int i = 0; i < vertex; i++) {
adjacencylist[i] = new LinkedList<>();
}
}


public void addEdge(int start, int end, int weight) {
Edge edge = new Edge(start, end, weight);
adjacencylist[start].addFirst(edge);

edge = new Edge(end,start,weight);
adjacencylist[end].addFirst(edge);
}

public ArrayList<String> dijkstra(int startvertex){
boolean SPT = new boolean[vertex];
int distance = new int[vertex];
for(int i =0; i<vertex;i++){
distance[i] = Integer.MAX_VALUE;
}
PriorityQueue<Pair<Integer,Integer>> pq = new PriorityQueue<>(vertex, new Comparator<Pair<Integer, Integer>>() {
@Override
public int compare(Pair<Integer, Integer> o1, Pair<Integer, Integer> o2) {
int key1 = o1.getKey();
int key2 = o2.getKey();
return key1 - key2;
}
});
distance[0] = 0;
Pair<Integer,Integer> p0 = new Pair<>(distance[0],0);
pq.offer(p0);
while(!pq.isEmpty()){
Pair<Integer,Integer> extractedPair = pq.poll();
int extractedVertex = extractedPair.getValue();
if(SPT[extractedVertex]==false){
SPT[extractedVertex] = true;
LinkedList<Edge> list = adjacencylist[extractedVertex];
for (int i = 0; i<list.size();i++){
Edge edge = list.get(i);
//System.out.println(edge.start + ":" + edge.weight + ":" + edge.end);
int end = edge.end;
if(SPT[end] == false){
int newKey = distance[extractedVertex] + edge.weight;
int currentKey = distance[end];
if(currentKey>newKey){
Pair<Integer,Integer> p = new Pair<>(newKey,end);
pq.offer(p);
distance[end] = newKey;
}
}
}
}
}
printDijkstra(distance,startvertex);
ArrayList<String> stuff = checkDijkstra(distance,startvertex);
return stuff;
}









share|improve this question









New contributor




mdl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I got this code from tutorial horizon and I'm trying to modify it to get it to:




  1. only output the shortest path from source to destination, currently outputs shortest path to all edges from source


  2. output the pathway to the shortest path





static class Edge {
int start;
int end;
int weight;
int length;
Edge previous;

public Edge(int start, int end, int weight) {
this.start = start;
this.end = end;
this.weight = weight;
//this.length = length;
}
}
static class ResultSet{
int parent;
int weight;
}

static class Graph {
int vertex;
LinkedList<Edge> adjacencylist;

Graph(int vertex) {
this.vertex = vertex;
adjacencylist = new LinkedList[vertex];
for (int i = 0; i < vertex; i++) {
adjacencylist[i] = new LinkedList<>();
}
}


public void addEdge(int start, int end, int weight) {
Edge edge = new Edge(start, end, weight);
adjacencylist[start].addFirst(edge);

edge = new Edge(end,start,weight);
adjacencylist[end].addFirst(edge);
}

public ArrayList<String> dijkstra(int startvertex){
boolean SPT = new boolean[vertex];
int distance = new int[vertex];
for(int i =0; i<vertex;i++){
distance[i] = Integer.MAX_VALUE;
}
PriorityQueue<Pair<Integer,Integer>> pq = new PriorityQueue<>(vertex, new Comparator<Pair<Integer, Integer>>() {
@Override
public int compare(Pair<Integer, Integer> o1, Pair<Integer, Integer> o2) {
int key1 = o1.getKey();
int key2 = o2.getKey();
return key1 - key2;
}
});
distance[0] = 0;
Pair<Integer,Integer> p0 = new Pair<>(distance[0],0);
pq.offer(p0);
while(!pq.isEmpty()){
Pair<Integer,Integer> extractedPair = pq.poll();
int extractedVertex = extractedPair.getValue();
if(SPT[extractedVertex]==false){
SPT[extractedVertex] = true;
LinkedList<Edge> list = adjacencylist[extractedVertex];
for (int i = 0; i<list.size();i++){
Edge edge = list.get(i);
//System.out.println(edge.start + ":" + edge.weight + ":" + edge.end);
int end = edge.end;
if(SPT[end] == false){
int newKey = distance[extractedVertex] + edge.weight;
int currentKey = distance[end];
if(currentKey>newKey){
Pair<Integer,Integer> p = new Pair<>(newKey,end);
pq.offer(p);
distance[end] = newKey;
}
}
}
}
}
printDijkstra(distance,startvertex);
ArrayList<String> stuff = checkDijkstra(distance,startvertex);
return stuff;
}






java






share|improve this question









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mdl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




mdl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




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edited 1 hour ago









Jamal

30.6k11121227




30.6k11121227






New contributor




mdl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 1 hour ago









mdlmdl

11




11




New contributor




mdl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





mdl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






mdl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • $begingroup$
    Hi, I'm sorry to inform you but Code Review requires not only coffee to already do what you want, but for it also to be written by you. Please see the help center for more information.
    $endgroup$
    – bruglesco
    8 mins ago


















  • $begingroup$
    Hi, I'm sorry to inform you but Code Review requires not only coffee to already do what you want, but for it also to be written by you. Please see the help center for more information.
    $endgroup$
    – bruglesco
    8 mins ago
















$begingroup$
Hi, I'm sorry to inform you but Code Review requires not only coffee to already do what you want, but for it also to be written by you. Please see the help center for more information.
$endgroup$
– bruglesco
8 mins ago




$begingroup$
Hi, I'm sorry to inform you but Code Review requires not only coffee to already do what you want, but for it also to be written by you. Please see the help center for more information.
$endgroup$
– bruglesco
8 mins ago










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