What does the permission string lrwxrwxrwx mean?












6














when I cd to / and enter the command:



ls -ls


For some files/folders it gives output like



0 lrwxrwxrwx.   1 root   root         7 Jan 30  2018 bin -> usr/bin


So what actually is this lrwxrwxrwx?










share|improve this question









New contributor




idaljeetsingh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • 3




    @Kulfy I think the fact that OP provided ls -l in their question suggests they already know how to view permissions. They're more interested in the meaning of the output in this particular case of symlinks. So I don't think that's an appropriate duplicate
    – Sergiy Kolodyazhnyy
    Jan 3 at 23:48










  • @Serg g_p's answer has the info OP is looking for, but I agree it's not a duplicate question.
    – wjandrea
    Jan 4 at 1:10










  • @Serg The dup Q&A is generically orientated on meaning of permissions. If a question of lwrxwrxwrx (see /vmlinuz) like this is unique, would a question of dwrxwrxwrx (see /tmp/) be unique as well? If each combination of permissions is a unique question we can have untold number of what could be considered psuedo-dups. For example "What does permissions of dr-xr-xr-x for /proc directory mean"?.
    – WinEunuuchs2Unix
    Jan 4 at 1:42








  • 2




    @WinEunuuchs2Unix While I agree the dup is general and should cover wide range, including this one, this question happens to talk about specific file type and the set of permissions lrwxrwxrwx is typical to all symlinks, which Zanna's answer covered very well in detail. If you feel like this should be covered in the linked dup, feel free to either post an answer or edit the existing ones there.
    – Sergiy Kolodyazhnyy
    Jan 4 at 1:47






  • 1




    @WinEunuuchs2Unix That's a slippery slope fallacy. The purpose of the duplicates is to provide appropriate information, not cover everything, nor they are meant to prevent people from asking similar questions. I've already expressed my opinion - Zanna's post here does better job than what's covered in the link, and the questions differ somewhat. The rest may the community decide
    – Sergiy Kolodyazhnyy
    Jan 4 at 2:10
















6














when I cd to / and enter the command:



ls -ls


For some files/folders it gives output like



0 lrwxrwxrwx.   1 root   root         7 Jan 30  2018 bin -> usr/bin


So what actually is this lrwxrwxrwx?










share|improve this question









New contributor




idaljeetsingh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 3




    @Kulfy I think the fact that OP provided ls -l in their question suggests they already know how to view permissions. They're more interested in the meaning of the output in this particular case of symlinks. So I don't think that's an appropriate duplicate
    – Sergiy Kolodyazhnyy
    Jan 3 at 23:48










  • @Serg g_p's answer has the info OP is looking for, but I agree it's not a duplicate question.
    – wjandrea
    Jan 4 at 1:10










  • @Serg The dup Q&A is generically orientated on meaning of permissions. If a question of lwrxwrxwrx (see /vmlinuz) like this is unique, would a question of dwrxwrxwrx (see /tmp/) be unique as well? If each combination of permissions is a unique question we can have untold number of what could be considered psuedo-dups. For example "What does permissions of dr-xr-xr-x for /proc directory mean"?.
    – WinEunuuchs2Unix
    Jan 4 at 1:42








  • 2




    @WinEunuuchs2Unix While I agree the dup is general and should cover wide range, including this one, this question happens to talk about specific file type and the set of permissions lrwxrwxrwx is typical to all symlinks, which Zanna's answer covered very well in detail. If you feel like this should be covered in the linked dup, feel free to either post an answer or edit the existing ones there.
    – Sergiy Kolodyazhnyy
    Jan 4 at 1:47






  • 1




    @WinEunuuchs2Unix That's a slippery slope fallacy. The purpose of the duplicates is to provide appropriate information, not cover everything, nor they are meant to prevent people from asking similar questions. I've already expressed my opinion - Zanna's post here does better job than what's covered in the link, and the questions differ somewhat. The rest may the community decide
    – Sergiy Kolodyazhnyy
    Jan 4 at 2:10














6












6








6







when I cd to / and enter the command:



ls -ls


For some files/folders it gives output like



0 lrwxrwxrwx.   1 root   root         7 Jan 30  2018 bin -> usr/bin


So what actually is this lrwxrwxrwx?










share|improve this question









New contributor




idaljeetsingh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











when I cd to / and enter the command:



ls -ls


For some files/folders it gives output like



0 lrwxrwxrwx.   1 root   root         7 Jan 30  2018 bin -> usr/bin


So what actually is this lrwxrwxrwx?







permissions






share|improve this question









New contributor




idaljeetsingh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




idaljeetsingh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited Jan 4 at 1:14









wjandrea

8,47842259




8,47842259






New contributor




idaljeetsingh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Jan 3 at 18:03









idaljeetsingh

335




335




New contributor




idaljeetsingh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





idaljeetsingh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






idaljeetsingh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 3




    @Kulfy I think the fact that OP provided ls -l in their question suggests they already know how to view permissions. They're more interested in the meaning of the output in this particular case of symlinks. So I don't think that's an appropriate duplicate
    – Sergiy Kolodyazhnyy
    Jan 3 at 23:48










  • @Serg g_p's answer has the info OP is looking for, but I agree it's not a duplicate question.
    – wjandrea
    Jan 4 at 1:10










  • @Serg The dup Q&A is generically orientated on meaning of permissions. If a question of lwrxwrxwrx (see /vmlinuz) like this is unique, would a question of dwrxwrxwrx (see /tmp/) be unique as well? If each combination of permissions is a unique question we can have untold number of what could be considered psuedo-dups. For example "What does permissions of dr-xr-xr-x for /proc directory mean"?.
    – WinEunuuchs2Unix
    Jan 4 at 1:42








  • 2




    @WinEunuuchs2Unix While I agree the dup is general and should cover wide range, including this one, this question happens to talk about specific file type and the set of permissions lrwxrwxrwx is typical to all symlinks, which Zanna's answer covered very well in detail. If you feel like this should be covered in the linked dup, feel free to either post an answer or edit the existing ones there.
    – Sergiy Kolodyazhnyy
    Jan 4 at 1:47






  • 1




    @WinEunuuchs2Unix That's a slippery slope fallacy. The purpose of the duplicates is to provide appropriate information, not cover everything, nor they are meant to prevent people from asking similar questions. I've already expressed my opinion - Zanna's post here does better job than what's covered in the link, and the questions differ somewhat. The rest may the community decide
    – Sergiy Kolodyazhnyy
    Jan 4 at 2:10














  • 3




    @Kulfy I think the fact that OP provided ls -l in their question suggests they already know how to view permissions. They're more interested in the meaning of the output in this particular case of symlinks. So I don't think that's an appropriate duplicate
    – Sergiy Kolodyazhnyy
    Jan 3 at 23:48










  • @Serg g_p's answer has the info OP is looking for, but I agree it's not a duplicate question.
    – wjandrea
    Jan 4 at 1:10










  • @Serg The dup Q&A is generically orientated on meaning of permissions. If a question of lwrxwrxwrx (see /vmlinuz) like this is unique, would a question of dwrxwrxwrx (see /tmp/) be unique as well? If each combination of permissions is a unique question we can have untold number of what could be considered psuedo-dups. For example "What does permissions of dr-xr-xr-x for /proc directory mean"?.
    – WinEunuuchs2Unix
    Jan 4 at 1:42








  • 2




    @WinEunuuchs2Unix While I agree the dup is general and should cover wide range, including this one, this question happens to talk about specific file type and the set of permissions lrwxrwxrwx is typical to all symlinks, which Zanna's answer covered very well in detail. If you feel like this should be covered in the linked dup, feel free to either post an answer or edit the existing ones there.
    – Sergiy Kolodyazhnyy
    Jan 4 at 1:47






  • 1




    @WinEunuuchs2Unix That's a slippery slope fallacy. The purpose of the duplicates is to provide appropriate information, not cover everything, nor they are meant to prevent people from asking similar questions. I've already expressed my opinion - Zanna's post here does better job than what's covered in the link, and the questions differ somewhat. The rest may the community decide
    – Sergiy Kolodyazhnyy
    Jan 4 at 2:10








3




3




@Kulfy I think the fact that OP provided ls -l in their question suggests they already know how to view permissions. They're more interested in the meaning of the output in this particular case of symlinks. So I don't think that's an appropriate duplicate
– Sergiy Kolodyazhnyy
Jan 3 at 23:48




@Kulfy I think the fact that OP provided ls -l in their question suggests they already know how to view permissions. They're more interested in the meaning of the output in this particular case of symlinks. So I don't think that's an appropriate duplicate
– Sergiy Kolodyazhnyy
Jan 3 at 23:48












@Serg g_p's answer has the info OP is looking for, but I agree it's not a duplicate question.
– wjandrea
Jan 4 at 1:10




@Serg g_p's answer has the info OP is looking for, but I agree it's not a duplicate question.
– wjandrea
Jan 4 at 1:10












@Serg The dup Q&A is generically orientated on meaning of permissions. If a question of lwrxwrxwrx (see /vmlinuz) like this is unique, would a question of dwrxwrxwrx (see /tmp/) be unique as well? If each combination of permissions is a unique question we can have untold number of what could be considered psuedo-dups. For example "What does permissions of dr-xr-xr-x for /proc directory mean"?.
– WinEunuuchs2Unix
Jan 4 at 1:42






@Serg The dup Q&A is generically orientated on meaning of permissions. If a question of lwrxwrxwrx (see /vmlinuz) like this is unique, would a question of dwrxwrxwrx (see /tmp/) be unique as well? If each combination of permissions is a unique question we can have untold number of what could be considered psuedo-dups. For example "What does permissions of dr-xr-xr-x for /proc directory mean"?.
– WinEunuuchs2Unix
Jan 4 at 1:42






2




2




@WinEunuuchs2Unix While I agree the dup is general and should cover wide range, including this one, this question happens to talk about specific file type and the set of permissions lrwxrwxrwx is typical to all symlinks, which Zanna's answer covered very well in detail. If you feel like this should be covered in the linked dup, feel free to either post an answer or edit the existing ones there.
– Sergiy Kolodyazhnyy
Jan 4 at 1:47




@WinEunuuchs2Unix While I agree the dup is general and should cover wide range, including this one, this question happens to talk about specific file type and the set of permissions lrwxrwxrwx is typical to all symlinks, which Zanna's answer covered very well in detail. If you feel like this should be covered in the linked dup, feel free to either post an answer or edit the existing ones there.
– Sergiy Kolodyazhnyy
Jan 4 at 1:47




1




1




@WinEunuuchs2Unix That's a slippery slope fallacy. The purpose of the duplicates is to provide appropriate information, not cover everything, nor they are meant to prevent people from asking similar questions. I've already expressed my opinion - Zanna's post here does better job than what's covered in the link, and the questions differ somewhat. The rest may the community decide
– Sergiy Kolodyazhnyy
Jan 4 at 2:10




@WinEunuuchs2Unix That's a slippery slope fallacy. The purpose of the duplicates is to provide appropriate information, not cover everything, nor they are meant to prevent people from asking similar questions. I've already expressed my opinion - Zanna's post here does better job than what's covered in the link, and the questions differ somewhat. The rest may the community decide
– Sergiy Kolodyazhnyy
Jan 4 at 2:10










1 Answer
1






active

oldest

votes


















12














The leading l indicates that this file is a symlink, in contrast to - which indicates a regular file, d which indicates a directory, and other less common prefixes.



A symlink is type of file which only contains a link to another file. Reading a symlink reads the real file. Writing to a symlink writes to the real file. cding to a symlink that is to a directory results in behaviour almost identical to what would happen if you had cd'd into the real directory.



The permission bits are displayed as rwxrwxrwx. All symlinks show these bits, but they are "dummy permissions". The actual (or effective) permissions of a symlink are the permissions of the real file it links to. You can get the real permissions (and file type) by running stat on the symlink, for example:



$ stat -Lc '%a %A' /initrd.img
644 -rw-r--r--




  • stat read file metadata


  • -L dereference (follow) symlinks


  • -c select output according to specified string


  • %a octal permissions


  • %A "human readable" permissions






share|improve this answer



















  • 1




    No need to use readlink, just use option -L to dereference symlinks. You can do stat -L or ls -L.
    – wjandrea
    Jan 3 at 19:36








  • 1




    @wjandrea awesome! thanks :D I edited
    – Zanna
    Jan 3 at 19:38






  • 2




    ls also has a -L option to follow the link.
    – Barmar
    Jan 3 at 20:06










  • @Barmar good point :)
    – Zanna
    Jan 3 at 20:08










  • The actual permissions of a symlink are the permissions of the real file it links to. Um, not quite. This needs to be reworded. Symlinks are symlinks - you already mentioned they show dummy permissions that all symlinks show, and actual file is different from symlink. Nonetheless, good and detailed answer. +1'ed already
    – Sergiy Kolodyazhnyy
    Jan 3 at 23:46











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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









12














The leading l indicates that this file is a symlink, in contrast to - which indicates a regular file, d which indicates a directory, and other less common prefixes.



A symlink is type of file which only contains a link to another file. Reading a symlink reads the real file. Writing to a symlink writes to the real file. cding to a symlink that is to a directory results in behaviour almost identical to what would happen if you had cd'd into the real directory.



The permission bits are displayed as rwxrwxrwx. All symlinks show these bits, but they are "dummy permissions". The actual (or effective) permissions of a symlink are the permissions of the real file it links to. You can get the real permissions (and file type) by running stat on the symlink, for example:



$ stat -Lc '%a %A' /initrd.img
644 -rw-r--r--




  • stat read file metadata


  • -L dereference (follow) symlinks


  • -c select output according to specified string


  • %a octal permissions


  • %A "human readable" permissions






share|improve this answer



















  • 1




    No need to use readlink, just use option -L to dereference symlinks. You can do stat -L or ls -L.
    – wjandrea
    Jan 3 at 19:36








  • 1




    @wjandrea awesome! thanks :D I edited
    – Zanna
    Jan 3 at 19:38






  • 2




    ls also has a -L option to follow the link.
    – Barmar
    Jan 3 at 20:06










  • @Barmar good point :)
    – Zanna
    Jan 3 at 20:08










  • The actual permissions of a symlink are the permissions of the real file it links to. Um, not quite. This needs to be reworded. Symlinks are symlinks - you already mentioned they show dummy permissions that all symlinks show, and actual file is different from symlink. Nonetheless, good and detailed answer. +1'ed already
    – Sergiy Kolodyazhnyy
    Jan 3 at 23:46
















12














The leading l indicates that this file is a symlink, in contrast to - which indicates a regular file, d which indicates a directory, and other less common prefixes.



A symlink is type of file which only contains a link to another file. Reading a symlink reads the real file. Writing to a symlink writes to the real file. cding to a symlink that is to a directory results in behaviour almost identical to what would happen if you had cd'd into the real directory.



The permission bits are displayed as rwxrwxrwx. All symlinks show these bits, but they are "dummy permissions". The actual (or effective) permissions of a symlink are the permissions of the real file it links to. You can get the real permissions (and file type) by running stat on the symlink, for example:



$ stat -Lc '%a %A' /initrd.img
644 -rw-r--r--




  • stat read file metadata


  • -L dereference (follow) symlinks


  • -c select output according to specified string


  • %a octal permissions


  • %A "human readable" permissions






share|improve this answer



















  • 1




    No need to use readlink, just use option -L to dereference symlinks. You can do stat -L or ls -L.
    – wjandrea
    Jan 3 at 19:36








  • 1




    @wjandrea awesome! thanks :D I edited
    – Zanna
    Jan 3 at 19:38






  • 2




    ls also has a -L option to follow the link.
    – Barmar
    Jan 3 at 20:06










  • @Barmar good point :)
    – Zanna
    Jan 3 at 20:08










  • The actual permissions of a symlink are the permissions of the real file it links to. Um, not quite. This needs to be reworded. Symlinks are symlinks - you already mentioned they show dummy permissions that all symlinks show, and actual file is different from symlink. Nonetheless, good and detailed answer. +1'ed already
    – Sergiy Kolodyazhnyy
    Jan 3 at 23:46














12












12








12






The leading l indicates that this file is a symlink, in contrast to - which indicates a regular file, d which indicates a directory, and other less common prefixes.



A symlink is type of file which only contains a link to another file. Reading a symlink reads the real file. Writing to a symlink writes to the real file. cding to a symlink that is to a directory results in behaviour almost identical to what would happen if you had cd'd into the real directory.



The permission bits are displayed as rwxrwxrwx. All symlinks show these bits, but they are "dummy permissions". The actual (or effective) permissions of a symlink are the permissions of the real file it links to. You can get the real permissions (and file type) by running stat on the symlink, for example:



$ stat -Lc '%a %A' /initrd.img
644 -rw-r--r--




  • stat read file metadata


  • -L dereference (follow) symlinks


  • -c select output according to specified string


  • %a octal permissions


  • %A "human readable" permissions






share|improve this answer














The leading l indicates that this file is a symlink, in contrast to - which indicates a regular file, d which indicates a directory, and other less common prefixes.



A symlink is type of file which only contains a link to another file. Reading a symlink reads the real file. Writing to a symlink writes to the real file. cding to a symlink that is to a directory results in behaviour almost identical to what would happen if you had cd'd into the real directory.



The permission bits are displayed as rwxrwxrwx. All symlinks show these bits, but they are "dummy permissions". The actual (or effective) permissions of a symlink are the permissions of the real file it links to. You can get the real permissions (and file type) by running stat on the symlink, for example:



$ stat -Lc '%a %A' /initrd.img
644 -rw-r--r--




  • stat read file metadata


  • -L dereference (follow) symlinks


  • -c select output according to specified string


  • %a octal permissions


  • %A "human readable" permissions







share|improve this answer














share|improve this answer



share|improve this answer








edited 2 days ago

























answered Jan 3 at 18:48









Zanna

50.2k13133241




50.2k13133241








  • 1




    No need to use readlink, just use option -L to dereference symlinks. You can do stat -L or ls -L.
    – wjandrea
    Jan 3 at 19:36








  • 1




    @wjandrea awesome! thanks :D I edited
    – Zanna
    Jan 3 at 19:38






  • 2




    ls also has a -L option to follow the link.
    – Barmar
    Jan 3 at 20:06










  • @Barmar good point :)
    – Zanna
    Jan 3 at 20:08










  • The actual permissions of a symlink are the permissions of the real file it links to. Um, not quite. This needs to be reworded. Symlinks are symlinks - you already mentioned they show dummy permissions that all symlinks show, and actual file is different from symlink. Nonetheless, good and detailed answer. +1'ed already
    – Sergiy Kolodyazhnyy
    Jan 3 at 23:46














  • 1




    No need to use readlink, just use option -L to dereference symlinks. You can do stat -L or ls -L.
    – wjandrea
    Jan 3 at 19:36








  • 1




    @wjandrea awesome! thanks :D I edited
    – Zanna
    Jan 3 at 19:38






  • 2




    ls also has a -L option to follow the link.
    – Barmar
    Jan 3 at 20:06










  • @Barmar good point :)
    – Zanna
    Jan 3 at 20:08










  • The actual permissions of a symlink are the permissions of the real file it links to. Um, not quite. This needs to be reworded. Symlinks are symlinks - you already mentioned they show dummy permissions that all symlinks show, and actual file is different from symlink. Nonetheless, good and detailed answer. +1'ed already
    – Sergiy Kolodyazhnyy
    Jan 3 at 23:46








1




1




No need to use readlink, just use option -L to dereference symlinks. You can do stat -L or ls -L.
– wjandrea
Jan 3 at 19:36






No need to use readlink, just use option -L to dereference symlinks. You can do stat -L or ls -L.
– wjandrea
Jan 3 at 19:36






1




1




@wjandrea awesome! thanks :D I edited
– Zanna
Jan 3 at 19:38




@wjandrea awesome! thanks :D I edited
– Zanna
Jan 3 at 19:38




2




2




ls also has a -L option to follow the link.
– Barmar
Jan 3 at 20:06




ls also has a -L option to follow the link.
– Barmar
Jan 3 at 20:06












@Barmar good point :)
– Zanna
Jan 3 at 20:08




@Barmar good point :)
– Zanna
Jan 3 at 20:08












The actual permissions of a symlink are the permissions of the real file it links to. Um, not quite. This needs to be reworded. Symlinks are symlinks - you already mentioned they show dummy permissions that all symlinks show, and actual file is different from symlink. Nonetheless, good and detailed answer. +1'ed already
– Sergiy Kolodyazhnyy
Jan 3 at 23:46




The actual permissions of a symlink are the permissions of the real file it links to. Um, not quite. This needs to be reworded. Symlinks are symlinks - you already mentioned they show dummy permissions that all symlinks show, and actual file is different from symlink. Nonetheless, good and detailed answer. +1'ed already
– Sergiy Kolodyazhnyy
Jan 3 at 23:46










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