New password generation











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  public static GeneratePassword(minPassLength) {
let small = "a b c d e f g h i j k l m n o p q r s t u v w x y z".split(' ');
let big = "A B C D E F G H I J K L M N O P Q R S T U V W X Y Z".split(' ');
let numbers = "0 1 2 3 4 5 6 7 8 9".split(' ');
let special = "! " # $ % & ( ) * + - . : ; < = > ? @ [ ] _ { | }".split(' ');

var pass = "";
for (let i = 0; i < minPassLength; i++) {
pass += small[this.randomIntFromInterval(0, small.length - 1)];
}
for (let i = 0; i < minPassLength / 4; i++) {
pass += big[this.randomIntFromInterval(0, big.length - 1)];
}
for (let i = 0; i < minPassLength / 4; i++) {
pass += numbers[this.randomIntFromInterval(0, numbers.length - 1)];
}
for (let i = 0; i < minPassLength / 4; i++) {
pass += special[this.randomIntFromInterval(0, special.length - 1)];
}
pass = pass.split('').sort(function () { return 0.5 - Math.random() }).join('');
return pass;
}

private static randomIntFromInterval(min, max) // min and max included
{
return Math.floor(Math.random() * (max - min + 1) + min);
}


A simple function to generate a new password with at least X (this is function parameter) chars including 1 special, 1 number and 1 uppercase.



Please a code review :-)










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    up vote
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      public static GeneratePassword(minPassLength) {
    let small = "a b c d e f g h i j k l m n o p q r s t u v w x y z".split(' ');
    let big = "A B C D E F G H I J K L M N O P Q R S T U V W X Y Z".split(' ');
    let numbers = "0 1 2 3 4 5 6 7 8 9".split(' ');
    let special = "! " # $ % & ( ) * + - . : ; < = > ? @ [ ] _ { | }".split(' ');

    var pass = "";
    for (let i = 0; i < minPassLength; i++) {
    pass += small[this.randomIntFromInterval(0, small.length - 1)];
    }
    for (let i = 0; i < minPassLength / 4; i++) {
    pass += big[this.randomIntFromInterval(0, big.length - 1)];
    }
    for (let i = 0; i < minPassLength / 4; i++) {
    pass += numbers[this.randomIntFromInterval(0, numbers.length - 1)];
    }
    for (let i = 0; i < minPassLength / 4; i++) {
    pass += special[this.randomIntFromInterval(0, special.length - 1)];
    }
    pass = pass.split('').sort(function () { return 0.5 - Math.random() }).join('');
    return pass;
    }

    private static randomIntFromInterval(min, max) // min and max included
    {
    return Math.floor(Math.random() * (max - min + 1) + min);
    }


    A simple function to generate a new password with at least X (this is function parameter) chars including 1 special, 1 number and 1 uppercase.



    Please a code review :-)










    share|improve this question









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    jdimko is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      2
      down vote

      favorite
      1









      up vote
      2
      down vote

      favorite
      1






      1





        public static GeneratePassword(minPassLength) {
      let small = "a b c d e f g h i j k l m n o p q r s t u v w x y z".split(' ');
      let big = "A B C D E F G H I J K L M N O P Q R S T U V W X Y Z".split(' ');
      let numbers = "0 1 2 3 4 5 6 7 8 9".split(' ');
      let special = "! " # $ % & ( ) * + - . : ; < = > ? @ [ ] _ { | }".split(' ');

      var pass = "";
      for (let i = 0; i < minPassLength; i++) {
      pass += small[this.randomIntFromInterval(0, small.length - 1)];
      }
      for (let i = 0; i < minPassLength / 4; i++) {
      pass += big[this.randomIntFromInterval(0, big.length - 1)];
      }
      for (let i = 0; i < minPassLength / 4; i++) {
      pass += numbers[this.randomIntFromInterval(0, numbers.length - 1)];
      }
      for (let i = 0; i < minPassLength / 4; i++) {
      pass += special[this.randomIntFromInterval(0, special.length - 1)];
      }
      pass = pass.split('').sort(function () { return 0.5 - Math.random() }).join('');
      return pass;
      }

      private static randomIntFromInterval(min, max) // min and max included
      {
      return Math.floor(Math.random() * (max - min + 1) + min);
      }


      A simple function to generate a new password with at least X (this is function parameter) chars including 1 special, 1 number and 1 uppercase.



      Please a code review :-)










      share|improve this question









      New contributor




      jdimko is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











        public static GeneratePassword(minPassLength) {
      let small = "a b c d e f g h i j k l m n o p q r s t u v w x y z".split(' ');
      let big = "A B C D E F G H I J K L M N O P Q R S T U V W X Y Z".split(' ');
      let numbers = "0 1 2 3 4 5 6 7 8 9".split(' ');
      let special = "! " # $ % & ( ) * + - . : ; < = > ? @ [ ] _ { | }".split(' ');

      var pass = "";
      for (let i = 0; i < minPassLength; i++) {
      pass += small[this.randomIntFromInterval(0, small.length - 1)];
      }
      for (let i = 0; i < minPassLength / 4; i++) {
      pass += big[this.randomIntFromInterval(0, big.length - 1)];
      }
      for (let i = 0; i < minPassLength / 4; i++) {
      pass += numbers[this.randomIntFromInterval(0, numbers.length - 1)];
      }
      for (let i = 0; i < minPassLength / 4; i++) {
      pass += special[this.randomIntFromInterval(0, special.length - 1)];
      }
      pass = pass.split('').sort(function () { return 0.5 - Math.random() }).join('');
      return pass;
      }

      private static randomIntFromInterval(min, max) // min and max included
      {
      return Math.floor(Math.random() * (max - min + 1) + min);
      }


      A simple function to generate a new password with at least X (this is function parameter) chars including 1 special, 1 number and 1 uppercase.



      Please a code review :-)







      strings random typescript






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      edited Nov 13 at 15:22









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      asked Nov 13 at 15:04









      jdimko

      111




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          2 Answers
          2






          active

          oldest

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          up vote
          1
          down vote













          You've four for-loops that are doing the same with different input. Make a function for this logic and call it with the different arrays.



          I don't know how typescript handles it and how often you call this function, but it could be better to define your characters outside of this because generating them every time you call this function is not necessary.



          Besides, you don't need to define your alphabet twice. You can use toUpperCase/toLowerCase.



          And last: From an outsiders perspective, I have no idea what this code is for:



           return 0.5 - Math.random()


          You should make a function for it or at the very least, write a comment for it.






          share|improve this answer





















          • The 0.5 - Math.random() is a basic (not very good) way to achieve string shuffle
            – Peter B
            Nov 13 at 16:41


















          up vote
          0
          down vote













          Not sure about typescript, but I think you don't need 4 for loops. Not tested but here is what i came up with on the go:



          public static GeneratePassword(minPassLength) {
          let small = "a b c d e f g h i j k l m n o p q r s t u v w x y z".split(' ');
          let big = "A B C D E F G H I J K L M N O P Q R S T U V W X Y Z".split(' ');
          let numbers = "0 1 2 3 4 5 6 7 8 9".split(' ');
          let special = "! " # $ % & ( ) * + - . : ; < = > ? @ [ ] _ { | }".split(' ');

          var pass = "";

          if (minPassLength % 2 == 1){
          minPassLength++;
          }
          for (let i = 0; i < minPassLength/4; i++) {
          appendPass (pass, small[this.randomIntFromInterval(0, small.length - 1)]);
          appendPass (pass, big[this.randomIntFromInterval(0, big.length - 1)]);
          appendPass (pass, numbers[this.randomIntFromInterval(0, numbers.length - 1)]);
          appendPass (pass, special[this.randomIntFromInterval(0, special.length - 1)]);
          }

          pass = pass.split('').sort(function () { return 0.5 - Math.random() }).join('');


          return pass;
          }

          private static randomIntFromInterval(min, max) // min and max included
          {
          return Math.floor(Math.random() * (max - min + 1) + min);
          }

          private static appendPass(passwrd, interval)
          {
          passwrd += interval;
          }





          share|improve this answer








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          Check out our Code of Conduct.


















          • Thanks for your reply
            – jdimko
            Nov 14 at 8:23










          • You're welcome.. please mark it as answered if it helped
            – DrDev
            Nov 14 at 9:23











          Your Answer





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          2 Answers
          2






          active

          oldest

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          2 Answers
          2






          active

          oldest

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          active

          oldest

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          active

          oldest

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          up vote
          1
          down vote













          You've four for-loops that are doing the same with different input. Make a function for this logic and call it with the different arrays.



          I don't know how typescript handles it and how often you call this function, but it could be better to define your characters outside of this because generating them every time you call this function is not necessary.



          Besides, you don't need to define your alphabet twice. You can use toUpperCase/toLowerCase.



          And last: From an outsiders perspective, I have no idea what this code is for:



           return 0.5 - Math.random()


          You should make a function for it or at the very least, write a comment for it.






          share|improve this answer





















          • The 0.5 - Math.random() is a basic (not very good) way to achieve string shuffle
            – Peter B
            Nov 13 at 16:41















          up vote
          1
          down vote













          You've four for-loops that are doing the same with different input. Make a function for this logic and call it with the different arrays.



          I don't know how typescript handles it and how often you call this function, but it could be better to define your characters outside of this because generating them every time you call this function is not necessary.



          Besides, you don't need to define your alphabet twice. You can use toUpperCase/toLowerCase.



          And last: From an outsiders perspective, I have no idea what this code is for:



           return 0.5 - Math.random()


          You should make a function for it or at the very least, write a comment for it.






          share|improve this answer





















          • The 0.5 - Math.random() is a basic (not very good) way to achieve string shuffle
            – Peter B
            Nov 13 at 16:41













          up vote
          1
          down vote










          up vote
          1
          down vote









          You've four for-loops that are doing the same with different input. Make a function for this logic and call it with the different arrays.



          I don't know how typescript handles it and how often you call this function, but it could be better to define your characters outside of this because generating them every time you call this function is not necessary.



          Besides, you don't need to define your alphabet twice. You can use toUpperCase/toLowerCase.



          And last: From an outsiders perspective, I have no idea what this code is for:



           return 0.5 - Math.random()


          You should make a function for it or at the very least, write a comment for it.






          share|improve this answer












          You've four for-loops that are doing the same with different input. Make a function for this logic and call it with the different arrays.



          I don't know how typescript handles it and how often you call this function, but it could be better to define your characters outside of this because generating them every time you call this function is not necessary.



          Besides, you don't need to define your alphabet twice. You can use toUpperCase/toLowerCase.



          And last: From an outsiders perspective, I have no idea what this code is for:



           return 0.5 - Math.random()


          You should make a function for it or at the very least, write a comment for it.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 at 15:21









          Synth

          1165




          1165












          • The 0.5 - Math.random() is a basic (not very good) way to achieve string shuffle
            – Peter B
            Nov 13 at 16:41


















          • The 0.5 - Math.random() is a basic (not very good) way to achieve string shuffle
            – Peter B
            Nov 13 at 16:41
















          The 0.5 - Math.random() is a basic (not very good) way to achieve string shuffle
          – Peter B
          Nov 13 at 16:41




          The 0.5 - Math.random() is a basic (not very good) way to achieve string shuffle
          – Peter B
          Nov 13 at 16:41












          up vote
          0
          down vote













          Not sure about typescript, but I think you don't need 4 for loops. Not tested but here is what i came up with on the go:



          public static GeneratePassword(minPassLength) {
          let small = "a b c d e f g h i j k l m n o p q r s t u v w x y z".split(' ');
          let big = "A B C D E F G H I J K L M N O P Q R S T U V W X Y Z".split(' ');
          let numbers = "0 1 2 3 4 5 6 7 8 9".split(' ');
          let special = "! " # $ % & ( ) * + - . : ; < = > ? @ [ ] _ { | }".split(' ');

          var pass = "";

          if (minPassLength % 2 == 1){
          minPassLength++;
          }
          for (let i = 0; i < minPassLength/4; i++) {
          appendPass (pass, small[this.randomIntFromInterval(0, small.length - 1)]);
          appendPass (pass, big[this.randomIntFromInterval(0, big.length - 1)]);
          appendPass (pass, numbers[this.randomIntFromInterval(0, numbers.length - 1)]);
          appendPass (pass, special[this.randomIntFromInterval(0, special.length - 1)]);
          }

          pass = pass.split('').sort(function () { return 0.5 - Math.random() }).join('');


          return pass;
          }

          private static randomIntFromInterval(min, max) // min and max included
          {
          return Math.floor(Math.random() * (max - min + 1) + min);
          }

          private static appendPass(passwrd, interval)
          {
          passwrd += interval;
          }





          share|improve this answer








          New contributor




          DrDev is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.


















          • Thanks for your reply
            – jdimko
            Nov 14 at 8:23










          • You're welcome.. please mark it as answered if it helped
            – DrDev
            Nov 14 at 9:23















          up vote
          0
          down vote













          Not sure about typescript, but I think you don't need 4 for loops. Not tested but here is what i came up with on the go:



          public static GeneratePassword(minPassLength) {
          let small = "a b c d e f g h i j k l m n o p q r s t u v w x y z".split(' ');
          let big = "A B C D E F G H I J K L M N O P Q R S T U V W X Y Z".split(' ');
          let numbers = "0 1 2 3 4 5 6 7 8 9".split(' ');
          let special = "! " # $ % & ( ) * + - . : ; < = > ? @ [ ] _ { | }".split(' ');

          var pass = "";

          if (minPassLength % 2 == 1){
          minPassLength++;
          }
          for (let i = 0; i < minPassLength/4; i++) {
          appendPass (pass, small[this.randomIntFromInterval(0, small.length - 1)]);
          appendPass (pass, big[this.randomIntFromInterval(0, big.length - 1)]);
          appendPass (pass, numbers[this.randomIntFromInterval(0, numbers.length - 1)]);
          appendPass (pass, special[this.randomIntFromInterval(0, special.length - 1)]);
          }

          pass = pass.split('').sort(function () { return 0.5 - Math.random() }).join('');


          return pass;
          }

          private static randomIntFromInterval(min, max) // min and max included
          {
          return Math.floor(Math.random() * (max - min + 1) + min);
          }

          private static appendPass(passwrd, interval)
          {
          passwrd += interval;
          }





          share|improve this answer








          New contributor




          DrDev is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.


















          • Thanks for your reply
            – jdimko
            Nov 14 at 8:23










          • You're welcome.. please mark it as answered if it helped
            – DrDev
            Nov 14 at 9:23













          up vote
          0
          down vote










          up vote
          0
          down vote









          Not sure about typescript, but I think you don't need 4 for loops. Not tested but here is what i came up with on the go:



          public static GeneratePassword(minPassLength) {
          let small = "a b c d e f g h i j k l m n o p q r s t u v w x y z".split(' ');
          let big = "A B C D E F G H I J K L M N O P Q R S T U V W X Y Z".split(' ');
          let numbers = "0 1 2 3 4 5 6 7 8 9".split(' ');
          let special = "! " # $ % & ( ) * + - . : ; < = > ? @ [ ] _ { | }".split(' ');

          var pass = "";

          if (minPassLength % 2 == 1){
          minPassLength++;
          }
          for (let i = 0; i < minPassLength/4; i++) {
          appendPass (pass, small[this.randomIntFromInterval(0, small.length - 1)]);
          appendPass (pass, big[this.randomIntFromInterval(0, big.length - 1)]);
          appendPass (pass, numbers[this.randomIntFromInterval(0, numbers.length - 1)]);
          appendPass (pass, special[this.randomIntFromInterval(0, special.length - 1)]);
          }

          pass = pass.split('').sort(function () { return 0.5 - Math.random() }).join('');


          return pass;
          }

          private static randomIntFromInterval(min, max) // min and max included
          {
          return Math.floor(Math.random() * (max - min + 1) + min);
          }

          private static appendPass(passwrd, interval)
          {
          passwrd += interval;
          }





          share|improve this answer








          New contributor




          DrDev is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          Not sure about typescript, but I think you don't need 4 for loops. Not tested but here is what i came up with on the go:



          public static GeneratePassword(minPassLength) {
          let small = "a b c d e f g h i j k l m n o p q r s t u v w x y z".split(' ');
          let big = "A B C D E F G H I J K L M N O P Q R S T U V W X Y Z".split(' ');
          let numbers = "0 1 2 3 4 5 6 7 8 9".split(' ');
          let special = "! " # $ % & ( ) * + - . : ; < = > ? @ [ ] _ { | }".split(' ');

          var pass = "";

          if (minPassLength % 2 == 1){
          minPassLength++;
          }
          for (let i = 0; i < minPassLength/4; i++) {
          appendPass (pass, small[this.randomIntFromInterval(0, small.length - 1)]);
          appendPass (pass, big[this.randomIntFromInterval(0, big.length - 1)]);
          appendPass (pass, numbers[this.randomIntFromInterval(0, numbers.length - 1)]);
          appendPass (pass, special[this.randomIntFromInterval(0, special.length - 1)]);
          }

          pass = pass.split('').sort(function () { return 0.5 - Math.random() }).join('');


          return pass;
          }

          private static randomIntFromInterval(min, max) // min and max included
          {
          return Math.floor(Math.random() * (max - min + 1) + min);
          }

          private static appendPass(passwrd, interval)
          {
          passwrd += interval;
          }






          share|improve this answer








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          answered Nov 13 at 16:57









          DrDev

          1014




          1014




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          • Thanks for your reply
            – jdimko
            Nov 14 at 8:23










          • You're welcome.. please mark it as answered if it helped
            – DrDev
            Nov 14 at 9:23


















          • Thanks for your reply
            – jdimko
            Nov 14 at 8:23










          • You're welcome.. please mark it as answered if it helped
            – DrDev
            Nov 14 at 9:23
















          Thanks for your reply
          – jdimko
          Nov 14 at 8:23




          Thanks for your reply
          – jdimko
          Nov 14 at 8:23












          You're welcome.. please mark it as answered if it helped
          – DrDev
          Nov 14 at 9:23




          You're welcome.. please mark it as answered if it helped
          – DrDev
          Nov 14 at 9:23










          jdimko is a new contributor. Be nice, and check out our Code of Conduct.










           

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