Avoid or warn on implicit conversion from const char* to bool in GCC












22















Consider the following code:



void foo(bool parameter) {

    std::cout << parameter << "n";

}



int main() {

    foo("const char *argument");

}


I want the compiler to raise a warning when passing const char* instead of bool as a parameter to function foo.



But GCC implicitly converts it. I tried -Wall, -Wextra, and -Wpedantic, but none of these issue a warning. Is there a flag that could catch such an implicit conversion (invalid parameter type)?



Ignore the fact that the function has an argument of type bool, which some may see as bad code style. I can't refactor that part.



The standard just mentions such an implicit conversion will occur:




A prvalue of integral, floating-point, unscoped enumeration, pointer, and pointer-to-member types can be converted to a prvalue of type bool.




I know such behavior is very convenient in if (ptr) statements, but for me, in the case of passing parameters, it is clearly wrong and a source of bugs.






c++ gcc implicit-conversion gcc-warning







share|improve this question




















  • 7





    ...and good for bad surprises: If there is a function which accepts std::string and another which accepts bool instead, guess which one is chosen for "const char *argument". (Spoiler alert: yes the second - and it drove me crazy until I got a clue.) ;-)

    – Scheff
    16 hours ago






  • 2





    a bit offtopic, but I am puzzled why you think having a bool parameter would be bad coding-style..

    – user463035818
    16 hours ago






  • 1





    @user463035818 "Uncle Bob said so" could be a good reason. He argues that function with bool parameter never has a single responsibility. Uncle Bob has many strong opinions about coding though.

    – Yksisarvinen
    16 hours ago











  • @Yksisarvinen you mean that there should be a fooTrue and a fooFalse instead? Hum, maybe i could agree in some cases, but not in general, though if Bob said so there must be some truth to it

    – user463035818
    15 hours ago











  • You may have another overload void foo(const char *parameter).

    – Hi I'm Frogatto
    15 hours ago
















22















Consider the following code:



void foo(bool parameter) {

    std::cout << parameter << "n";

}



int main() {

    foo("const char *argument");

}


I want the compiler to raise a warning when passing const char* instead of bool as a parameter to function foo.



But GCC implicitly converts it. I tried -Wall, -Wextra, and -Wpedantic, but none of these issue a warning. Is there a flag that could catch such an implicit conversion (invalid parameter type)?



Ignore the fact that the function has an argument of type bool, which some may see as bad code style. I can't refactor that part.



The standard just mentions such an implicit conversion will occur:




A prvalue of integral, floating-point, unscoped enumeration, pointer, and pointer-to-member types can be converted to a prvalue of type bool.




I know such behavior is very convenient in if (ptr) statements, but for me, in the case of passing parameters, it is clearly wrong and a source of bugs.






c++ gcc implicit-conversion gcc-warning







share|improve this question




















  • 7





    ...and good for bad surprises: If there is a function which accepts std::string and another which accepts bool instead, guess which one is chosen for "const char *argument". (Spoiler alert: yes the second - and it drove me crazy until I got a clue.) ;-)

    – Scheff
    16 hours ago






  • 2





    a bit offtopic, but I am puzzled why you think having a bool parameter would be bad coding-style..

    – user463035818
    16 hours ago






  • 1





    @user463035818 "Uncle Bob said so" could be a good reason. He argues that function with bool parameter never has a single responsibility. Uncle Bob has many strong opinions about coding though.

    – Yksisarvinen
    16 hours ago











  • @Yksisarvinen you mean that there should be a fooTrue and a fooFalse instead? Hum, maybe i could agree in some cases, but not in general, though if Bob said so there must be some truth to it

    – user463035818
    15 hours ago











  • You may have another overload void foo(const char *parameter).

    – Hi I'm Frogatto
    15 hours ago














22












22








22


2






Consider the following code:



void foo(bool parameter) {

    std::cout << parameter << "n";

}



int main() {

    foo("const char *argument");

}


I want the compiler to raise a warning when passing const char* instead of bool as a parameter to function foo.



But GCC implicitly converts it. I tried -Wall, -Wextra, and -Wpedantic, but none of these issue a warning. Is there a flag that could catch such an implicit conversion (invalid parameter type)?



Ignore the fact that the function has an argument of type bool, which some may see as bad code style. I can't refactor that part.



The standard just mentions such an implicit conversion will occur:




A prvalue of integral, floating-point, unscoped enumeration, pointer, and pointer-to-member types can be converted to a prvalue of type bool.




I know such behavior is very convenient in if (ptr) statements, but for me, in the case of passing parameters, it is clearly wrong and a source of bugs.






c++ gcc implicit-conversion gcc-warning







share|improve this question
















Consider the following code:



void foo(bool parameter) {

    std::cout << parameter << "n";

}



int main() {

    foo("const char *argument");

}


I want the compiler to raise a warning when passing const char* instead of bool as a parameter to function foo.



But GCC implicitly converts it. I tried -Wall, -Wextra, and -Wpedantic, but none of these issue a warning. Is there a flag that could catch such an implicit conversion (invalid parameter type)?



Ignore the fact that the function has an argument of type bool, which some may see as bad code style. I can't refactor that part.



The standard just mentions such an implicit conversion will occur:




A prvalue of integral, floating-point, unscoped enumeration, pointer, and pointer-to-member types can be converted to a prvalue of type bool.




I know such behavior is very convenient in if (ptr) statements, but for me, in the case of passing parameters, it is clearly wrong and a source of bugs.






c++ gcc implicit-conversion gcc-warning




c++ gcc implicit-conversion gcc-warning






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 39 mins ago









Cody Gray♦

192k35377464




192k35377464










asked 16 hours ago









Szymon ZimnowodaSzymon Zimnowoda

1215




1215








  • 7





    ...and good for bad surprises: If there is a function which accepts std::string and another which accepts bool instead, guess which one is chosen for "const char *argument". (Spoiler alert: yes the second - and it drove me crazy until I got a clue.) ;-)

    – Scheff
    16 hours ago






  • 2





    a bit offtopic, but I am puzzled why you think having a bool parameter would be bad coding-style..

    – user463035818
    16 hours ago






  • 1





    @user463035818 "Uncle Bob said so" could be a good reason. He argues that function with bool parameter never has a single responsibility. Uncle Bob has many strong opinions about coding though.

    – Yksisarvinen
    16 hours ago











  • @Yksisarvinen you mean that there should be a fooTrue and a fooFalse instead? Hum, maybe i could agree in some cases, but not in general, though if Bob said so there must be some truth to it

    – user463035818
    15 hours ago











  • You may have another overload void foo(const char *parameter).

    – Hi I'm Frogatto
    15 hours ago














  • 7





    ...and good for bad surprises: If there is a function which accepts std::string and another which accepts bool instead, guess which one is chosen for "const char *argument". (Spoiler alert: yes the second - and it drove me crazy until I got a clue.) ;-)

    – Scheff
    16 hours ago






  • 2





    a bit offtopic, but I am puzzled why you think having a bool parameter would be bad coding-style..

    – user463035818
    16 hours ago






  • 1





    @user463035818 "Uncle Bob said so" could be a good reason. He argues that function with bool parameter never has a single responsibility. Uncle Bob has many strong opinions about coding though.

    – Yksisarvinen
    16 hours ago











  • @Yksisarvinen you mean that there should be a fooTrue and a fooFalse instead? Hum, maybe i could agree in some cases, but not in general, though if Bob said so there must be some truth to it

    – user463035818
    15 hours ago











  • You may have another overload void foo(const char *parameter).

    – Hi I'm Frogatto
    15 hours ago








7




7





...and good for bad surprises: If there is a function which accepts std::string and another which accepts bool instead, guess which one is chosen for "const char *argument". (Spoiler alert: yes the second - and it drove me crazy until I got a clue.) ;-)

– Scheff
16 hours ago





...and good for bad surprises: If there is a function which accepts std::string and another which accepts bool instead, guess which one is chosen for "const char *argument". (Spoiler alert: yes the second - and it drove me crazy until I got a clue.) ;-)

– Scheff
16 hours ago




2




2





a bit offtopic, but I am puzzled why you think having a bool parameter would be bad coding-style..

– user463035818
16 hours ago





a bit offtopic, but I am puzzled why you think having a bool parameter would be bad coding-style..

– user463035818
16 hours ago




1




1





@user463035818 "Uncle Bob said so" could be a good reason. He argues that function with bool parameter never has a single responsibility. Uncle Bob has many strong opinions about coding though.

– Yksisarvinen
16 hours ago





@user463035818 "Uncle Bob said so" could be a good reason. He argues that function with bool parameter never has a single responsibility. Uncle Bob has many strong opinions about coding though.

– Yksisarvinen
16 hours ago













@Yksisarvinen you mean that there should be a fooTrue and a fooFalse instead? Hum, maybe i could agree in some cases, but not in general, though if Bob said so there must be some truth to it

– user463035818
15 hours ago





@Yksisarvinen you mean that there should be a fooTrue and a fooFalse instead? Hum, maybe i could agree in some cases, but not in general, though if Bob said so there must be some truth to it

– user463035818
15 hours ago













You may have another overload void foo(const char *parameter).

– Hi I'm Frogatto
15 hours ago





You may have another overload void foo(const char *parameter).

– Hi I'm Frogatto
15 hours ago












2 Answers
2






active

oldest

votes


















25














You could declare an overload of foo for pointers as deleted:



template <class T>

void foo(T*) = delete;


Or better yet, as @Ted comments, simply declare a vanilla overload to not compile any implicit conversions:



template <class T>

void foo(T) = delete;





share|improve this answer





















  • 2





    Not wrong but in a real world example these are probably (multiple) functions (maybe even from other files/sources) and that could make this seem quite exhausting.

    – Stack Danny
    16 hours ago






  • 3





    Starting from C++11, you shoul actually declare it as deleted… this will generate earlier and more meaningful error messages. Alternatively, declare it with a body that raises a static_assert if T is not bool (template is ill-formed if it always raises a static_assert, that's the only reason for this check).

    – Arne Vogel
    15 hours ago






  • 2





    ... or just void foo(T) = delete; to delete all implicit conversions.

    – Ted Lyngmo
    14 hours ago



















15















I want the compiler to raise a warning when passing const char* instead of bool as a parameter to function foo. ... I tried -Wall, -Wextra, and -Wpedantic




You need to add -Wconversion to your compiler flags. Note that seems to work with clang (recent or older version), but not with gcc.



If this triggers too many warnings that you don't want to handle, you can selectively enable -Wstring-conversion (clang only).






share|improve this answer





















  • 1





    I tried but without luck: Live Demo on coliru. Did I oversee something?

    – Scheff
    16 hours ago






  • 1





    @Scheff Weird, it seems to be handled differently in clang and gcc. Updated the answer accordingly.

    – lubgr
    16 hours ago








  • 1





    I just found this The new Wconversion option and in fact the implicit conversion from const char* to bool isn't mentioned at all. Looks like it isn't covered in gcc...

    – Scheff
    16 hours ago











  • @Scheff fwiw also no error/warning for uniform initialization of a bool with a const char*

    – user463035818
    16 hours ago











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









25














You could declare an overload of foo for pointers as deleted:



template <class T>

void foo(T*) = delete;


Or better yet, as @Ted comments, simply declare a vanilla overload to not compile any implicit conversions:



template <class T>

void foo(T) = delete;





share|improve this answer





















  • 2





    Not wrong but in a real world example these are probably (multiple) functions (maybe even from other files/sources) and that could make this seem quite exhausting.

    – Stack Danny
    16 hours ago






  • 3





    Starting from C++11, you shoul actually declare it as deleted… this will generate earlier and more meaningful error messages. Alternatively, declare it with a body that raises a static_assert if T is not bool (template is ill-formed if it always raises a static_assert, that's the only reason for this check).

    – Arne Vogel
    15 hours ago






  • 2





    ... or just void foo(T) = delete; to delete all implicit conversions.

    – Ted Lyngmo
    14 hours ago
















25














You could declare an overload of foo for pointers as deleted:



template <class T>

void foo(T*) = delete;


Or better yet, as @Ted comments, simply declare a vanilla overload to not compile any implicit conversions:



template <class T>

void foo(T) = delete;





share|improve this answer





















  • 2





    Not wrong but in a real world example these are probably (multiple) functions (maybe even from other files/sources) and that could make this seem quite exhausting.

    – Stack Danny
    16 hours ago






  • 3





    Starting from C++11, you shoul actually declare it as deleted… this will generate earlier and more meaningful error messages. Alternatively, declare it with a body that raises a static_assert if T is not bool (template is ill-formed if it always raises a static_assert, that's the only reason for this check).

    – Arne Vogel
    15 hours ago






  • 2





    ... or just void foo(T) = delete; to delete all implicit conversions.

    – Ted Lyngmo
    14 hours ago














25












25








25







You could declare an overload of foo for pointers as deleted:



template <class T>

void foo(T*) = delete;


Or better yet, as @Ted comments, simply declare a vanilla overload to not compile any implicit conversions:



template <class T>

void foo(T) = delete;





share|improve this answer















You could declare an overload of foo for pointers as deleted:



template <class T>

void foo(T*) = delete;


Or better yet, as @Ted comments, simply declare a vanilla overload to not compile any implicit conversions:



template <class T>

void foo(T) = delete;






share|improve this answer














share|improve this answer



share|improve this answer








edited 14 hours ago









Ted Lyngmo

2,5211317




2,5211317










answered 16 hours ago









Paul EvansPaul Evans

19k32138




19k32138








  • 2





    Not wrong but in a real world example these are probably (multiple) functions (maybe even from other files/sources) and that could make this seem quite exhausting.

    – Stack Danny
    16 hours ago






  • 3





    Starting from C++11, you shoul actually declare it as deleted… this will generate earlier and more meaningful error messages. Alternatively, declare it with a body that raises a static_assert if T is not bool (template is ill-formed if it always raises a static_assert, that's the only reason for this check).

    – Arne Vogel
    15 hours ago






  • 2





    ... or just void foo(T) = delete; to delete all implicit conversions.

    – Ted Lyngmo
    14 hours ago














  • 2





    Not wrong but in a real world example these are probably (multiple) functions (maybe even from other files/sources) and that could make this seem quite exhausting.

    – Stack Danny
    16 hours ago






  • 3





    Starting from C++11, you shoul actually declare it as deleted… this will generate earlier and more meaningful error messages. Alternatively, declare it with a body that raises a static_assert if T is not bool (template is ill-formed if it always raises a static_assert, that's the only reason for this check).

    – Arne Vogel
    15 hours ago






  • 2





    ... or just void foo(T) = delete; to delete all implicit conversions.

    – Ted Lyngmo
    14 hours ago








2




2





Not wrong but in a real world example these are probably (multiple) functions (maybe even from other files/sources) and that could make this seem quite exhausting.

– Stack Danny
16 hours ago





Not wrong but in a real world example these are probably (multiple) functions (maybe even from other files/sources) and that could make this seem quite exhausting.

– Stack Danny
16 hours ago




3




3





Starting from C++11, you shoul actually declare it as deleted… this will generate earlier and more meaningful error messages. Alternatively, declare it with a body that raises a static_assert if T is not bool (template is ill-formed if it always raises a static_assert, that's the only reason for this check).

– Arne Vogel
15 hours ago





Starting from C++11, you shoul actually declare it as deleted… this will generate earlier and more meaningful error messages. Alternatively, declare it with a body that raises a static_assert if T is not bool (template is ill-formed if it always raises a static_assert, that's the only reason for this check).

– Arne Vogel
15 hours ago




2




2





... or just void foo(T) = delete; to delete all implicit conversions.

– Ted Lyngmo
14 hours ago





... or just void foo(T) = delete; to delete all implicit conversions.

– Ted Lyngmo
14 hours ago













15















I want the compiler to raise a warning when passing const char* instead of bool as a parameter to function foo. ... I tried -Wall, -Wextra, and -Wpedantic




You need to add -Wconversion to your compiler flags. Note that seems to work with clang (recent or older version), but not with gcc.



If this triggers too many warnings that you don't want to handle, you can selectively enable -Wstring-conversion (clang only).






share|improve this answer





















  • 1





    I tried but without luck: Live Demo on coliru. Did I oversee something?

    – Scheff
    16 hours ago






  • 1





    @Scheff Weird, it seems to be handled differently in clang and gcc. Updated the answer accordingly.

    – lubgr
    16 hours ago








  • 1





    I just found this The new Wconversion option and in fact the implicit conversion from const char* to bool isn't mentioned at all. Looks like it isn't covered in gcc...

    – Scheff
    16 hours ago











  • @Scheff fwiw also no error/warning for uniform initialization of a bool with a const char*

    – user463035818
    16 hours ago
















15















I want the compiler to raise a warning when passing const char* instead of bool as a parameter to function foo. ... I tried -Wall, -Wextra, and -Wpedantic




You need to add -Wconversion to your compiler flags. Note that seems to work with clang (recent or older version), but not with gcc.



If this triggers too many warnings that you don't want to handle, you can selectively enable -Wstring-conversion (clang only).






share|improve this answer





















  • 1





    I tried but without luck: Live Demo on coliru. Did I oversee something?

    – Scheff
    16 hours ago






  • 1





    @Scheff Weird, it seems to be handled differently in clang and gcc. Updated the answer accordingly.

    – lubgr
    16 hours ago








  • 1





    I just found this The new Wconversion option and in fact the implicit conversion from const char* to bool isn't mentioned at all. Looks like it isn't covered in gcc...

    – Scheff
    16 hours ago











  • @Scheff fwiw also no error/warning for uniform initialization of a bool with a const char*

    – user463035818
    16 hours ago














15












15








15








I want the compiler to raise a warning when passing const char* instead of bool as a parameter to function foo. ... I tried -Wall, -Wextra, and -Wpedantic




You need to add -Wconversion to your compiler flags. Note that seems to work with clang (recent or older version), but not with gcc.



If this triggers too many warnings that you don't want to handle, you can selectively enable -Wstring-conversion (clang only).






share|improve this answer
















I want the compiler to raise a warning when passing const char* instead of bool as a parameter to function foo. ... I tried -Wall, -Wextra, and -Wpedantic




You need to add -Wconversion to your compiler flags. Note that seems to work with clang (recent or older version), but not with gcc.



If this triggers too many warnings that you don't want to handle, you can selectively enable -Wstring-conversion (clang only).







share|improve this answer














share|improve this answer



share|improve this answer








edited 14 hours ago









Peter Mortensen

13.6k1984111




13.6k1984111










answered 16 hours ago









lubgrlubgr

11.5k21846




11.5k21846








  • 1





    I tried but without luck: Live Demo on coliru. Did I oversee something?

    – Scheff
    16 hours ago






  • 1





    @Scheff Weird, it seems to be handled differently in clang and gcc. Updated the answer accordingly.

    – lubgr
    16 hours ago








  • 1





    I just found this The new Wconversion option and in fact the implicit conversion from const char* to bool isn't mentioned at all. Looks like it isn't covered in gcc...

    – Scheff
    16 hours ago











  • @Scheff fwiw also no error/warning for uniform initialization of a bool with a const char*

    – user463035818
    16 hours ago














  • 1





    I tried but without luck: Live Demo on coliru. Did I oversee something?

    – Scheff
    16 hours ago






  • 1





    @Scheff Weird, it seems to be handled differently in clang and gcc. Updated the answer accordingly.

    – lubgr
    16 hours ago








  • 1





    I just found this The new Wconversion option and in fact the implicit conversion from const char* to bool isn't mentioned at all. Looks like it isn't covered in gcc...

    – Scheff
    16 hours ago











  • @Scheff fwiw also no error/warning for uniform initialization of a bool with a const char*

    – user463035818
    16 hours ago








1




1





I tried but without luck: Live Demo on coliru. Did I oversee something?

– Scheff
16 hours ago





I tried but without luck: Live Demo on coliru. Did I oversee something?

– Scheff
16 hours ago




1




1





@Scheff Weird, it seems to be handled differently in clang and gcc. Updated the answer accordingly.

– lubgr
16 hours ago







@Scheff Weird, it seems to be handled differently in clang and gcc. Updated the answer accordingly.

– lubgr
16 hours ago






1




1





I just found this The new Wconversion option and in fact the implicit conversion from const char* to bool isn't mentioned at all. Looks like it isn't covered in gcc...

– Scheff
16 hours ago





I just found this The new Wconversion option and in fact the implicit conversion from const char* to bool isn't mentioned at all. Looks like it isn't covered in gcc...

– Scheff
16 hours ago













@Scheff fwiw also no error/warning for uniform initialization of a bool with a const char*

– user463035818
16 hours ago





@Scheff fwiw also no error/warning for uniform initialization of a bool with a const char*

– user463035818
16 hours ago


















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Сан-Квентин

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Сан-Квентин Местоположение Сан-Квентин, Калифорния Координаты 37°56′13″ с. ш. 122°29′20″ з. д. H G Я O L Текущий статус Действует Режим безопасности минимальный и максимальный Количество мест 3 302 Открытие Июнь 1852 Находится в ведомстве California Department of Corrections and Rehabilitation Начальник Mike Martel, начальник  Сан-Квентин на Викискладе Сан-Квентин (англ.  San Quentin ) — тюрьма, располагающаяся на 432 акрах (около 1,7 км²), на мысе Сан-Квентин, в округе Марин, штат Калифорния, США. Тюрьма штата Калифорния Сан-Квентин была открыта в июле 1852 года и является старейшей в штате. Она была построена заключёнными, которые проживали в течение строительства на тюремном судне Вабан. В Сан-Квентине отбывали наказание и мужчины, и женщины до 1934 года, когда построили женскую тюрьму в Техачапи и туда перевели всех заключённых женщин. В Сан-Квентине приводятся в исполнение смертные казни, для этого имеется газовая камера, но
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Алькесар

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Муниципалитет Алькесар Alquézar Герб 42°10′16″ с. ш. 0°01′27″ в. д. H G Я O L Страна Испания   Испания Автономное сообщество Арагон Провинция Уэска Комарка Сомонтано-де-Барбастро Алькальд Хосе Марияно Альтемир Ласкорс (ИСРП) История и география Площадь 32,36 км² Высота НУМ 660 м Часовой пояс UTC+1, летом UTC+2 Население Население 313 человек ( 2010 ) Плотность 9,92 чел./км² Этнохороним alquezarano/-a Цифровые идентификаторы Телефонный код +34 974 Почтовые индексы 22112 Автомобильный код HU alquezar.org   (исп.) Показать/скрыть карты Алькесар Алькесар Алькесар  Аудио, фото и видео на Викискладе Алькесар (исп.  Alquézar ) — муниципалитет в Испании, входит в провинцию Уэска, в составе автономного сообщества Арагон. Муниципалитет находится в составе района (комарки) Сомонтано-де-Барбастро. Занимает площадь 32,36 км². Население — 321 челове
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Josef Freinademetz

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San Ujöp (Giuseppe/Josef) Freinademetz Josef Freinademetz in abiti cinesi   Religioso e missionario   Nascita 15 aprile 1852 Morte 28 gennaio 1908 Venerato da Chiesa cattolica Beatificazione 1975 Canonizzazione 5 ottobre 2003 Ricorrenza 28 gennaio Manuale Ujöp Freinademetz noto anche come Giuseppe o Josef Freinademetz (Oies, 15 aprile 1852 – Taikia, 28 gennaio 1908) è stato un presbitero austriaco, membro della Società del Verbo Divino, fu missionario in Cina; è venerato come santo dalla Chiesa cattolica. .mw-parser-output .citazione-table{margin-bottom:.5em;font-size:95%}.mw-parser-output .citazione-table td{padding:0 1.2em 0 2.4em}.mw-parser-output .citazione-lang{vertical-align:top}.mw-parser-output .citazione-lang td{width:50%}.mw-parser-output .citazione-lang td:first-child{padding:0 0 0 2.4em}.mw-parser-output .citazione-lang td:nth-child(2){padding:0 1.2em} «Io amo la Cina e i cinesi; voglio morire in mezzo a loro, e tra loro
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