What does the angle bracket mean in variance formula?
$begingroup$
When I check the formula of variance in Mathworld which is
$$
sigma^2 equiv langle (X - mu)^2 rangle
$$
Though I'm more familiar with the other formula, I just wanted to know what does the angle bracket mean aside from the formula in variance.
variance notation
New contributor
$endgroup$
add a comment |
$begingroup$
When I check the formula of variance in Mathworld which is
$$
sigma^2 equiv langle (X - mu)^2 rangle
$$
Though I'm more familiar with the other formula, I just wanted to know what does the angle bracket mean aside from the formula in variance.
variance notation
New contributor
$endgroup$
1
$begingroup$
math world defines it: and <X> denotes the expectation value of X.
$endgroup$
– seanv507
18 hours ago
1
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see mathworld.wolfram.com/AngleBracket.html - the last sentence of the article proper.
$endgroup$
– Glen_b♦
15 hours ago
1
$begingroup$
It means a physicist (or possibly a pure mathematician) is writing about probability :-).
$endgroup$
– whuber♦
13 hours ago
add a comment |
$begingroup$
When I check the formula of variance in Mathworld which is
$$
sigma^2 equiv langle (X - mu)^2 rangle
$$
Though I'm more familiar with the other formula, I just wanted to know what does the angle bracket mean aside from the formula in variance.
variance notation
New contributor
$endgroup$
When I check the formula of variance in Mathworld which is
$$
sigma^2 equiv langle (X - mu)^2 rangle
$$
Though I'm more familiar with the other formula, I just wanted to know what does the angle bracket mean aside from the formula in variance.
variance notation
variance notation
New contributor
New contributor
edited 17 hours ago
Nick Cox
38.2k483128
38.2k483128
New contributor
asked 19 hours ago
isemajisemaj
312
312
New contributor
New contributor
1
$begingroup$
math world defines it: and <X> denotes the expectation value of X.
$endgroup$
– seanv507
18 hours ago
1
$begingroup$
see mathworld.wolfram.com/AngleBracket.html - the last sentence of the article proper.
$endgroup$
– Glen_b♦
15 hours ago
1
$begingroup$
It means a physicist (or possibly a pure mathematician) is writing about probability :-).
$endgroup$
– whuber♦
13 hours ago
add a comment |
1
$begingroup$
math world defines it: and <X> denotes the expectation value of X.
$endgroup$
– seanv507
18 hours ago
1
$begingroup$
see mathworld.wolfram.com/AngleBracket.html - the last sentence of the article proper.
$endgroup$
– Glen_b♦
15 hours ago
1
$begingroup$
It means a physicist (or possibly a pure mathematician) is writing about probability :-).
$endgroup$
– whuber♦
13 hours ago
1
1
$begingroup$
math world defines it: and <X> denotes the expectation value of X.
$endgroup$
– seanv507
18 hours ago
$begingroup$
math world defines it: and <X> denotes the expectation value of X.
$endgroup$
– seanv507
18 hours ago
1
1
$begingroup$
see mathworld.wolfram.com/AngleBracket.html - the last sentence of the article proper.
$endgroup$
– Glen_b♦
15 hours ago
$begingroup$
see mathworld.wolfram.com/AngleBracket.html - the last sentence of the article proper.
$endgroup$
– Glen_b♦
15 hours ago
1
1
$begingroup$
It means a physicist (or possibly a pure mathematician) is writing about probability :-).
$endgroup$
– whuber♦
13 hours ago
$begingroup$
It means a physicist (or possibly a pure mathematician) is writing about probability :-).
$endgroup$
– whuber♦
13 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
It's the expected value of $(X-mu)^2$, i.e., it's the same as $sigma^2=E[(X-mu)^2]$.
New contributor
$endgroup$
1
$begingroup$
Thank you. But is there any other reason why the one is use than the other?
$endgroup$
– isemaj
17 hours ago
$begingroup$
@isemaj Besides OmG's answer, you might also be interested in the generalisation of expectations to matrix elements in the bra-ket formalism of quantum mechanics, which upon suppression of explicit states gives the "angle" formalism for expectations.
$endgroup$
– J.G.
8 hours ago
add a comment |
$begingroup$
It means an inner product for the multi-dimensional case. When $X in mathbb{R}^n$ and $n geq 2$ and want to define variance, the definition of the variance is related to the inner product of $X-mu$ to itself, and denoted as $langle X-mu, X-murangle$
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add a comment |
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2 Answers
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2 Answers
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active
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votes
$begingroup$
It's the expected value of $(X-mu)^2$, i.e., it's the same as $sigma^2=E[(X-mu)^2]$.
New contributor
$endgroup$
1
$begingroup$
Thank you. But is there any other reason why the one is use than the other?
$endgroup$
– isemaj
17 hours ago
$begingroup$
@isemaj Besides OmG's answer, you might also be interested in the generalisation of expectations to matrix elements in the bra-ket formalism of quantum mechanics, which upon suppression of explicit states gives the "angle" formalism for expectations.
$endgroup$
– J.G.
8 hours ago
add a comment |
$begingroup$
It's the expected value of $(X-mu)^2$, i.e., it's the same as $sigma^2=E[(X-mu)^2]$.
New contributor
$endgroup$
1
$begingroup$
Thank you. But is there any other reason why the one is use than the other?
$endgroup$
– isemaj
17 hours ago
$begingroup$
@isemaj Besides OmG's answer, you might also be interested in the generalisation of expectations to matrix elements in the bra-ket formalism of quantum mechanics, which upon suppression of explicit states gives the "angle" formalism for expectations.
$endgroup$
– J.G.
8 hours ago
add a comment |
$begingroup$
It's the expected value of $(X-mu)^2$, i.e., it's the same as $sigma^2=E[(X-mu)^2]$.
New contributor
$endgroup$
It's the expected value of $(X-mu)^2$, i.e., it's the same as $sigma^2=E[(X-mu)^2]$.
New contributor
New contributor
answered 19 hours ago
FrederikDSFrederikDS
512
512
New contributor
New contributor
1
$begingroup$
Thank you. But is there any other reason why the one is use than the other?
$endgroup$
– isemaj
17 hours ago
$begingroup$
@isemaj Besides OmG's answer, you might also be interested in the generalisation of expectations to matrix elements in the bra-ket formalism of quantum mechanics, which upon suppression of explicit states gives the "angle" formalism for expectations.
$endgroup$
– J.G.
8 hours ago
add a comment |
1
$begingroup$
Thank you. But is there any other reason why the one is use than the other?
$endgroup$
– isemaj
17 hours ago
$begingroup$
@isemaj Besides OmG's answer, you might also be interested in the generalisation of expectations to matrix elements in the bra-ket formalism of quantum mechanics, which upon suppression of explicit states gives the "angle" formalism for expectations.
$endgroup$
– J.G.
8 hours ago
1
1
$begingroup$
Thank you. But is there any other reason why the one is use than the other?
$endgroup$
– isemaj
17 hours ago
$begingroup$
Thank you. But is there any other reason why the one is use than the other?
$endgroup$
– isemaj
17 hours ago
$begingroup$
@isemaj Besides OmG's answer, you might also be interested in the generalisation of expectations to matrix elements in the bra-ket formalism of quantum mechanics, which upon suppression of explicit states gives the "angle" formalism for expectations.
$endgroup$
– J.G.
8 hours ago
$begingroup$
@isemaj Besides OmG's answer, you might also be interested in the generalisation of expectations to matrix elements in the bra-ket formalism of quantum mechanics, which upon suppression of explicit states gives the "angle" formalism for expectations.
$endgroup$
– J.G.
8 hours ago
add a comment |
$begingroup$
It means an inner product for the multi-dimensional case. When $X in mathbb{R}^n$ and $n geq 2$ and want to define variance, the definition of the variance is related to the inner product of $X-mu$ to itself, and denoted as $langle X-mu, X-murangle$
$endgroup$
add a comment |
$begingroup$
It means an inner product for the multi-dimensional case. When $X in mathbb{R}^n$ and $n geq 2$ and want to define variance, the definition of the variance is related to the inner product of $X-mu$ to itself, and denoted as $langle X-mu, X-murangle$
$endgroup$
add a comment |
$begingroup$
It means an inner product for the multi-dimensional case. When $X in mathbb{R}^n$ and $n geq 2$ and want to define variance, the definition of the variance is related to the inner product of $X-mu$ to itself, and denoted as $langle X-mu, X-murangle$
$endgroup$
It means an inner product for the multi-dimensional case. When $X in mathbb{R}^n$ and $n geq 2$ and want to define variance, the definition of the variance is related to the inner product of $X-mu$ to itself, and denoted as $langle X-mu, X-murangle$
answered 19 hours ago
OmGOmG
31628
31628
add a comment |
add a comment |
isemaj is a new contributor. Be nice, and check out our Code of Conduct.
isemaj is a new contributor. Be nice, and check out our Code of Conduct.
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isemaj is a new contributor. Be nice, and check out our Code of Conduct.
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1
$begingroup$
math world defines it: and <X> denotes the expectation value of X.
$endgroup$
– seanv507
18 hours ago
1
$begingroup$
see mathworld.wolfram.com/AngleBracket.html - the last sentence of the article proper.
$endgroup$
– Glen_b♦
15 hours ago
1
$begingroup$
It means a physicist (or possibly a pure mathematician) is writing about probability :-).
$endgroup$
– whuber♦
13 hours ago