Converting input containing special character to float











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This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.



I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.



def toNum(interest):

if '/' not in interest:
if float(interest) > 1:
return float(interest)/100

else:
return float(interest)


else:
l=
n = 0
count = 1

list_interest=
for e in interest:
list_interest.append(e)

for e in list_interest:

if count == 1 or count == 3:
l.append(e)
count = count +1
continue


if e == '/':
n = n + 1
count = count +1
else:
l[n] = l[n] + e

return int(l[0]) / int(l[1])









interest = input("Interest rate: ")
interest = toNum(interest)
print(interest)









share|improve this question


























    up vote
    4
    down vote

    favorite












    This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.



    I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.



    def toNum(interest):

    if '/' not in interest:
    if float(interest) > 1:
    return float(interest)/100

    else:
    return float(interest)


    else:
    l=
    n = 0
    count = 1

    list_interest=
    for e in interest:
    list_interest.append(e)

    for e in list_interest:

    if count == 1 or count == 3:
    l.append(e)
    count = count +1
    continue


    if e == '/':
    n = n + 1
    count = count +1
    else:
    l[n] = l[n] + e

    return int(l[0]) / int(l[1])









    interest = input("Interest rate: ")
    interest = toNum(interest)
    print(interest)









    share|improve this question
























      up vote
      4
      down vote

      favorite









      up vote
      4
      down vote

      favorite











      This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.



      I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.



      def toNum(interest):

      if '/' not in interest:
      if float(interest) > 1:
      return float(interest)/100

      else:
      return float(interest)


      else:
      l=
      n = 0
      count = 1

      list_interest=
      for e in interest:
      list_interest.append(e)

      for e in list_interest:

      if count == 1 or count == 3:
      l.append(e)
      count = count +1
      continue


      if e == '/':
      n = n + 1
      count = count +1
      else:
      l[n] = l[n] + e

      return int(l[0]) / int(l[1])









      interest = input("Interest rate: ")
      interest = toNum(interest)
      print(interest)









      share|improve this question













      This is the beginning of my program that calculates simple interest. Interest rate will have the following format : 0.97 , 0.67 , 0.17 etc. They won't be bigger than 1. So if the user enter 9 for the interest, program will convert it to 0.09 (by dividing it by 100) . Also user can enter input using '/'. So program will convert input like 97/100 to 0.97.



      I wrote the code below. It works but it seems to me that there might be a easier and more elegant solution to this. Maybe using more build-in functions etc. If you help me with that I would be very appreciated.



      def toNum(interest):

      if '/' not in interest:
      if float(interest) > 1:
      return float(interest)/100

      else:
      return float(interest)


      else:
      l=
      n = 0
      count = 1

      list_interest=
      for e in interest:
      list_interest.append(e)

      for e in list_interest:

      if count == 1 or count == 3:
      l.append(e)
      count = count +1
      continue


      if e == '/':
      n = n + 1
      count = count +1
      else:
      l[n] = l[n] + e

      return int(l[0]) / int(l[1])









      interest = input("Interest rate: ")
      interest = toNum(interest)
      print(interest)






      python python-3.x






      share|improve this question













      share|improve this question











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      share|improve this question










      asked Nov 26 at 13:51









      ikadorus

      234




      234






















          2 Answers
          2






          active

          oldest

          votes

















          up vote
          4
          down vote



          accepted










          For reading a fraction such as "97/100", you can use the fractions library.



          For example:





          from fractions import Fraction

          f = Fraction("97/100")

          print(float(f)) # prints 0.97


          And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:



          from fractions import Fraction

          def toNum(interest):
          f = Fraction(interest)
          f = float(f)

          if f > 1:
          f /= 100

          return f

          print(toNum("97/100")) # prints 0.97
          print(toNum(0.97)) # prints 0.97
          print(toNum(9)) # prints 0.09





          share|improve this answer



















          • 1




            Why convert to float at all and not keep a fractions.Fraction object all along?
            – Mathias Ettinger
            Nov 26 at 15:59










          • @MathiasEttinger That's also a good option, just depends on preference.
            – esote
            Nov 26 at 16:14


















          up vote
          1
          down vote













          While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:



          if "/" in interest:
          numerator, denominator = map(int, interest.split("/"))
          return numerator / denominator


          Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.



          Note also that using sensible names makes it immediately obvious what this code does.






          share|improve this answer





















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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            4
            down vote



            accepted










            For reading a fraction such as "97/100", you can use the fractions library.



            For example:





            from fractions import Fraction

            f = Fraction("97/100")

            print(float(f)) # prints 0.97


            And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:



            from fractions import Fraction

            def toNum(interest):
            f = Fraction(interest)
            f = float(f)

            if f > 1:
            f /= 100

            return f

            print(toNum("97/100")) # prints 0.97
            print(toNum(0.97)) # prints 0.97
            print(toNum(9)) # prints 0.09





            share|improve this answer



















            • 1




              Why convert to float at all and not keep a fractions.Fraction object all along?
              – Mathias Ettinger
              Nov 26 at 15:59










            • @MathiasEttinger That's also a good option, just depends on preference.
              – esote
              Nov 26 at 16:14















            up vote
            4
            down vote



            accepted










            For reading a fraction such as "97/100", you can use the fractions library.



            For example:





            from fractions import Fraction

            f = Fraction("97/100")

            print(float(f)) # prints 0.97


            And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:



            from fractions import Fraction

            def toNum(interest):
            f = Fraction(interest)
            f = float(f)

            if f > 1:
            f /= 100

            return f

            print(toNum("97/100")) # prints 0.97
            print(toNum(0.97)) # prints 0.97
            print(toNum(9)) # prints 0.09





            share|improve this answer



















            • 1




              Why convert to float at all and not keep a fractions.Fraction object all along?
              – Mathias Ettinger
              Nov 26 at 15:59










            • @MathiasEttinger That's also a good option, just depends on preference.
              – esote
              Nov 26 at 16:14













            up vote
            4
            down vote



            accepted







            up vote
            4
            down vote



            accepted






            For reading a fraction such as "97/100", you can use the fractions library.



            For example:





            from fractions import Fraction

            f = Fraction("97/100")

            print(float(f)) # prints 0.97


            And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:



            from fractions import Fraction

            def toNum(interest):
            f = Fraction(interest)
            f = float(f)

            if f > 1:
            f /= 100

            return f

            print(toNum("97/100")) # prints 0.97
            print(toNum(0.97)) # prints 0.97
            print(toNum(9)) # prints 0.09





            share|improve this answer














            For reading a fraction such as "97/100", you can use the fractions library.



            For example:





            from fractions import Fraction

            f = Fraction("97/100")

            print(float(f)) # prints 0.97


            And because the constructor also takes a float, we can remove the check for /. Therefore, the final code is:



            from fractions import Fraction

            def toNum(interest):
            f = Fraction(interest)
            f = float(f)

            if f > 1:
            f /= 100

            return f

            print(toNum("97/100")) # prints 0.97
            print(toNum(0.97)) # prints 0.97
            print(toNum(9)) # prints 0.09






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 26 at 15:03

























            answered Nov 26 at 14:11









            esote

            1,4151731




            1,4151731








            • 1




              Why convert to float at all and not keep a fractions.Fraction object all along?
              – Mathias Ettinger
              Nov 26 at 15:59










            • @MathiasEttinger That's also a good option, just depends on preference.
              – esote
              Nov 26 at 16:14














            • 1




              Why convert to float at all and not keep a fractions.Fraction object all along?
              – Mathias Ettinger
              Nov 26 at 15:59










            • @MathiasEttinger That's also a good option, just depends on preference.
              – esote
              Nov 26 at 16:14








            1




            1




            Why convert to float at all and not keep a fractions.Fraction object all along?
            – Mathias Ettinger
            Nov 26 at 15:59




            Why convert to float at all and not keep a fractions.Fraction object all along?
            – Mathias Ettinger
            Nov 26 at 15:59












            @MathiasEttinger That's also a good option, just depends on preference.
            – esote
            Nov 26 at 16:14




            @MathiasEttinger That's also a good option, just depends on preference.
            – esote
            Nov 26 at 16:14












            up vote
            1
            down vote













            While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:



            if "/" in interest:
            numerator, denominator = map(int, interest.split("/"))
            return numerator / denominator


            Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.



            Note also that using sensible names makes it immediately obvious what this code does.






            share|improve this answer

























              up vote
              1
              down vote













              While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:



              if "/" in interest:
              numerator, denominator = map(int, interest.split("/"))
              return numerator / denominator


              Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.



              Note also that using sensible names makes it immediately obvious what this code does.






              share|improve this answer























                up vote
                1
                down vote










                up vote
                1
                down vote









                While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:



                if "/" in interest:
                numerator, denominator = map(int, interest.split("/"))
                return numerator / denominator


                Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.



                Note also that using sensible names makes it immediately obvious what this code does.






                share|improve this answer












                While the answer by @esote is correct and I would also recommend using the fractions module, you should also work on your text parsing. In this case you could have used a simple str.split and map to parse the string containing a /:



                if "/" in interest:
                numerator, denominator = map(int, interest.split("/"))
                return numerator / denominator


                Note that int ignores whitespace, so this works with both "97/100", "97 / 100" and any combination thereof.



                Note also that using sensible names makes it immediately obvious what this code does.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 27 at 11:27









                Graipher

                22.6k53384




                22.6k53384






























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