How to exclude a circle from a rectangle when drawing a contour figure?

up vote
3
down vote

favorite

I need to draw a contour figure defined by coordinate x and y. The domain is a rectangle (-100<=x<=100,-100<=y<=100) excluding a circle (center at the origin, and radius of 5). The object function is 'z=x+y'.

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

asked Nov 15 at 3:26

Robin_Lyn

836

add a comment |

up vote
3
down vote

favorite

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

asked Nov 15 at 3:26

Robin_Lyn

836

add a comment |

up vote
3
down vote

favorite

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

asked Nov 15 at 3:26

Robin_Lyn

836

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

plotting

asked Nov 15 at 3:26

Robin_Lyn

836

asked Nov 15 at 3:26

Robin_Lyn

836

asked Nov 15 at 3:26

Robin_Lyn

836

asked Nov 15 at 3:26

Robin_Lyn

836

asked Nov 15 at 3:26

Robin_Lyn

836

add a comment |

2 Answers
2

active

oldest

votes

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered Nov 15 at 5:20

kglr

171k8194399

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited Nov 15 at 16:12

answered Nov 15 at 3:41

Okkes Dulgerci

3,5781716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
Nov 15 at 6:07

add a comment |

Your Answer

StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\$","\$"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});

}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f186014%2fhow-to-exclude-a-circle-from-a-rectangle-when-drawing-a-contour-figure%23new-answer', 'question_page');
}
);

Post as a guest

Name

Required, but never shown

2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered Nov 15 at 5:20

kglr

171k8194399

add a comment |

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered Nov 15 at 5:20

kglr

171k8194399

add a comment |

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered Nov 15 at 5:20

kglr

171k8194399

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered Nov 15 at 5:20

kglr

171k8194399

answered Nov 15 at 5:20

kglr

171k8194399

answered Nov 15 at 5:20

kglr

171k8194399

answered Nov 15 at 5:20

kglr

171k8194399

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited Nov 15 at 16:12

answered Nov 15 at 3:41

Okkes Dulgerci

3,5781716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
Nov 15 at 6:07

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited Nov 15 at 16:12

answered Nov 15 at 3:41

Okkes Dulgerci

3,5781716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
Nov 15 at 6:07

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited Nov 15 at 16:12

answered Nov 15 at 3:41

Okkes Dulgerci

3,5781716

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited Nov 15 at 16:12

answered Nov 15 at 3:41

Okkes Dulgerci

3,5781716

edited Nov 15 at 16:12

answered Nov 15 at 3:41

Okkes Dulgerci

3,5781716

answered Nov 15 at 3:41

Okkes Dulgerci

3,5781716

answered Nov 15 at 3:41

Okkes Dulgerci

3,5781716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
Nov 15 at 6:07

add a comment |

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
Nov 15 at 6:07

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
Nov 15 at 6:07

add a comment |

draft saved

draft discarded

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Post as a guest

Name

Required, but never shown

Name

Required, but never shown

Name

Required, but never shown

This page is only for reference, If you need detailed information, please check here

搜尋此網誌

Gfrktyl