Move cursor by line number when moving through multiple lines (e.g. `5j`), move by display line when moving...
In Vim, I have the following set in order to have ragged right soft-wrapping of lines:
set linebreak
set wrap
When traversing multiple lines at once, an annoying side effect is that 5j will not move the cursor down 5 lines, it will move it down by 5 display lines. If I have a line that is soft-wrapped into 6 lines, if my cursor is on the top line and I type 5j I will not move down by 5 actual lines, but rather to the bottom of the current line, down by 5 display lines.
How can I stop this behaviour so that j moves the cursor down by 1 display line (soft-wrapped or otherwise), while 5j moves the cursor down by 5 actual lines?
vim vimrc
asked Feb 2 at 12:30
John GodleeJohn Godlee
656
add a comment |
In Vim, I have the following set in order to have ragged right soft-wrapping of lines:
set linebreak
set wrap
When traversing multiple lines at once, an annoying side effect is that 5j will not move the cursor down 5 lines, it will move it down by 5 display lines. If I have a line that is soft-wrapped into 6 lines, if my cursor is on the top line and I type 5j I will not move down by 5 actual lines, but rather to the bottom of the current line, down by 5 display lines.
How can I stop this behaviour so that j moves the cursor down by 1 display line (soft-wrapped or otherwise), while 5j moves the cursor down by 5 actual lines?
vim vimrc
asked Feb 2 at 12:30
John GodleeJohn Godlee
656
add a comment |
In Vim, I have the following set in order to have ragged right soft-wrapping of lines:
set linebreak
set wrap
When traversing multiple lines at once, an annoying side effect is that 5j will not move the cursor down 5 lines, it will move it down by 5 display lines. If I have a line that is soft-wrapped into 6 lines, if my cursor is on the top line and I type 5j I will not move down by 5 actual lines, but rather to the bottom of the current line, down by 5 display lines.
How can I stop this behaviour so that j moves the cursor down by 1 display line (soft-wrapped or otherwise), while 5j moves the cursor down by 5 actual lines?
vim vimrc
asked Feb 2 at 12:30
John GodleeJohn Godlee
656
In Vim, I have the following set in order to have ragged right soft-wrapping of lines:
set linebreak
set wrap
When traversing multiple lines at once, an annoying side effect is that 5j will not move the cursor down 5 lines, it will move it down by 5 display lines. If I have a line that is soft-wrapped into 6 lines, if my cursor is on the top line and I type 5j I will not move down by 5 actual lines, but rather to the bottom of the current line, down by 5 display lines.
How can I stop this behaviour so that j moves the cursor down by 1 display line (soft-wrapped or otherwise), while 5j moves the cursor down by 5 actual lines?
vim vimrc
vim vimrc
asked Feb 2 at 12:30
John GodleeJohn Godlee
656
asked Feb 2 at 12:30
John GodleeJohn Godlee
656
asked Feb 2 at 12:30
John GodleeJohn Godlee
656
asked Feb 2 at 12:30
John GodleeJohn Godlee
656
asked Feb 2 at 12:30
John GodleeJohn Godlee
656
656
add a comment |
add a comment |
1 Answer
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By default the j and k movements always move by physical lines and not by screen lines. So I think you must have a map like nmap j gj somewhere in your .vimrc.
For the behaviour you want, I have the following in my .vimrc:
" Map j and k to gj/gk, but only when no count is given
" However, for larger jumps like 6j add the current position to the jump list
" so that you can use <c-o>/<c-i> to jump to the previous position
nnoremap <expr> j v:count ? (v:count > 5 ? "m'" . v:count : '') . 'j' : 'gj'
nnoremap <expr> k v:count ? (v:count > 5 ? "m'" . v:count : '') . 'k' : 'gk'
answered Feb 3 at 10:06
Christian BrabandtChristian Brabandt
1,10675
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
By default the j and k movements always move by physical lines and not by screen lines. So I think you must have a map like nmap j gj somewhere in your .vimrc.
For the behaviour you want, I have the following in my .vimrc:
" Map j and k to gj/gk, but only when no count is given
" However, for larger jumps like 6j add the current position to the jump list
" so that you can use <c-o>/<c-i> to jump to the previous position
nnoremap <expr> j v:count ? (v:count > 5 ? "m'" . v:count : '') . 'j' : 'gj'
nnoremap <expr> k v:count ? (v:count > 5 ? "m'" . v:count : '') . 'k' : 'gk'
answered Feb 3 at 10:06
Christian BrabandtChristian Brabandt
1,10675
add a comment |
By default the j and k movements always move by physical lines and not by screen lines. So I think you must have a map like nmap j gj somewhere in your .vimrc.
For the behaviour you want, I have the following in my .vimrc:
" Map j and k to gj/gk, but only when no count is given
" However, for larger jumps like 6j add the current position to the jump list
" so that you can use <c-o>/<c-i> to jump to the previous position
nnoremap <expr> j v:count ? (v:count > 5 ? "m'" . v:count : '') . 'j' : 'gj'
nnoremap <expr> k v:count ? (v:count > 5 ? "m'" . v:count : '') . 'k' : 'gk'
answered Feb 3 at 10:06
Christian BrabandtChristian Brabandt
1,10675
add a comment |
By default the j and k movements always move by physical lines and not by screen lines. So I think you must have a map like nmap j gj somewhere in your .vimrc.
For the behaviour you want, I have the following in my .vimrc:
" Map j and k to gj/gk, but only when no count is given
" However, for larger jumps like 6j add the current position to the jump list
" so that you can use <c-o>/<c-i> to jump to the previous position
nnoremap <expr> j v:count ? (v:count > 5 ? "m'" . v:count : '') . 'j' : 'gj'
nnoremap <expr> k v:count ? (v:count > 5 ? "m'" . v:count : '') . 'k' : 'gk'
answered Feb 3 at 10:06
Christian BrabandtChristian Brabandt
1,10675
By default the j and k movements always move by physical lines and not by screen lines. So I think you must have a map like nmap j gj somewhere in your .vimrc.
For the behaviour you want, I have the following in my .vimrc:
" Map j and k to gj/gk, but only when no count is given
" However, for larger jumps like 6j add the current position to the jump list
" so that you can use <c-o>/<c-i> to jump to the previous position
nnoremap <expr> j v:count ? (v:count > 5 ? "m'" . v:count : '') . 'j' : 'gj'
nnoremap <expr> k v:count ? (v:count > 5 ? "m'" . v:count : '') . 'k' : 'gk'
answered Feb 3 at 10:06
Christian BrabandtChristian Brabandt
1,10675
answered Feb 3 at 10:06
Christian BrabandtChristian Brabandt
1,10675
answered Feb 3 at 10:06
Christian BrabandtChristian Brabandt
1,10675
answered Feb 3 at 10:06
Christian BrabandtChristian Brabandt
1,10675
1,10675
add a comment |
add a comment |
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