How can I find the number of users online in Linux?












10















How can I see how many people are logged on to a Linux machine? I know the 'users' command shows all the people logged in but I need a number. Is there a switch for users that I am missing in the man page? I thought of using the grep -c command, but there must be something that is the same in each username for this to work. Is there an easier way?










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    10















    How can I see how many people are logged on to a Linux machine? I know the 'users' command shows all the people logged in but I need a number. Is there a switch for users that I am missing in the man page? I thought of using the grep -c command, but there must be something that is the same in each username for this to work. Is there an easier way?










    share|improve this question



























      10












      10








      10


      5






      How can I see how many people are logged on to a Linux machine? I know the 'users' command shows all the people logged in but I need a number. Is there a switch for users that I am missing in the man page? I thought of using the grep -c command, but there must be something that is the same in each username for this to work. Is there an easier way?










      share|improve this question
















      How can I see how many people are logged on to a Linux machine? I know the 'users' command shows all the people logged in but I need a number. Is there a switch for users that I am missing in the man page? I thought of using the grep -c command, but there must be something that is the same in each username for this to work. Is there an easier way?







      linux






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      share|improve this question








      edited Feb 14 '16 at 0:17









      Jamal

      4561617




      4561617










      asked Jul 26 '09 at 3:26





































          13 Answers
          13






          active

          oldest

          votes


















          16














          You are looking for the wc (word count) command.



          Try this:



          users | wc -w





          share|improve this answer
























          • note that this approach (an who/w solutions) show only users logged in, not necessarily active users (i.e. users that start a process and then logout leaving the running process behind). Just to give a heads up about the difference.

            – estani
            Mar 18 '13 at 13:45



















          18














          Classically, the command is 'who' rather than 'users', but 'who' gives you more information. Looking back at the original Unix articles (mid-70s), the example would have been:



          who | wc -l


          Using 'wc -l' counts lines of output - it works with both 'users' and 'who'. Using '-w' only works reliably when there is one word per user (as with 'users' but not with 'who').



          You could use 'grep -c' to count the lines. Since you are only interested in non-blank user names, you could do:



          who | grep -c .


          There's always at least one character on each line.





          As noted in the comments by John T, the users command differs from who in a number of respects. The most important one is that instead of giving one name per line, it spreads the names out several per line — I don't have a machine with enough different users logged in to test what happens when the number of users becomes large. The other difference is that 'who' reports on terminal connections in use. With multiple terminal windows open, it will show multiple lines for a single user, whereas 'users' seems to list a logged in user just once.



          As a consequence of this difference, the 'grep -c .' formulation won't work with the 'users' command; 'wc -w' is necessary.






          share|improve this answer


























          • small nitpick - the users command does not print 1 line per user, it just prints id's sequentially, so grep -c . would not work in this case. Smart thinking though.

            – John T
            Jul 26 '09 at 3:59











          • this also means that wc -l will not work with the users command, as shown here: i26.tinypic.com/4pw0vd.png

            – John T
            Jul 26 '09 at 4:11











          • @John T: oh - well, given screen shot, you're correct. I tested 'users' on MacOS X - but with just one user logged in. When I double checked with a second user logged in, I see the 'all on one line' behaviour.

            – Jonathan Leffler
            Jul 26 '09 at 5:52






          • 1





            to simulate more users you can SSH into your own box :)

            – John T
            Jul 26 '09 at 5:59











          • Thank you for this valuable information, although I wanted to stick with the "users" command. Also upvoted you, thanks.

            – Anonymous
            Aug 1 '09 at 23:54



















          7














          Open a shell and type:



          who -q


          The last line will give you a count.



          EDIT:



          (sigh) I misunderstood the question. Here's a somewhat brute-force approach:



          To see unique user names:



          who | awk '{ print $1 }' | sort | uniq


          To see a count of unique users:



          who | awk '{ print $1 }' | sort | uniq | wc -l 





          share|improve this answer


























          • that counts all logins of the same user in the total.

            – hayalci
            Jul 26 '09 at 18:56











          • check the re-edit, I think you'll find that the new answers address that.

            – Avery Payne
            Jul 27 '09 at 15:33











          • This still doesn't work, uniq only removes duplicate successive lines, you need to sort the output of who first.

            – theotherreceive
            Jul 27 '09 at 18:10











          • that's what I get for posting answers at 1am. (sigh) fixed.

            – Avery Payne
            Jul 27 '09 at 19:37



















          3














          Do you want to see the number of sessions, or the number of actual users?



          $ who
          andrew tty1 2009-07-26 15:31 (:0)
          andrew pts/0 2009-07-27 00:11 (:0.0)
          andrew pts/1 2009-07-27 01:58 (:0.0)


          That's on my laptop, so i'm the only user, but i'm logged on three times.



          $ who | wc -l
          3
          $ users | wc -w
          3


          It is fairly easy to filter out these duplicates though to get the number of actual users.



          $ users | tr ' ' 'n' | sort -u 
          andrew
          $ users | tr ' ' 'n' | sort -u | wc -l
          1





          share|improve this answer































            3














            Here's a bash version of tink's great awk post:



            set $(users)
            declare -A user
            for u ; do ((user[$u]++)) ; done
            for key in "${!user[@]}" ; do echo "$key: ${user[$key]}" ; done | column -t | sort -nk 2


            Ok, it's a little bit longer, but was worth finding this one ... :).



            While testing, do before next attempt:



            shift $#                # clear positional parameters
            unset user # remove associative array variable





            share|improve this answer

































              2














              number of the users currently logged in:



              who |cut -c 1-9 |sort -u |wc -l


              the above buta with their account name:



              who |cut -c 1-9 |sort -u |tee /dev/tty |wc -l





              share|improve this answer































                1














                who | cut --delimiter=' ' -f 1 | sort -u | wc -l


                Who prints out the list, cut removes everything but the first row, sort -u sort it and removes duplicates and wc -l counts the lines. Works fine for me on ubuntu/bash :)






                share|improve this answer































                  1














                  You can simply use w (/usr/bin/w on my Red Hat based system) or uptime, they show the actual number of logged in users.



                  w:



                                                v
                  22:40:38 up 3 days, 22 min, 1 user, load average: 0.02, 0.01, 0.00
                  USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT
                  manuel pts/0 pc-manuel 09:35 0.00s 0.07s 0.00s /usr/bin/screen -xRR


                  uptime:



                                                v
                  22:39:18 up 3 days, 21 min, 1 user, load average: 0.08, 0.02, 0.01





                  share|improve this answer































                    1














                    And a method that uses only one pipe...



                    users | awk '{for(i=1;i<=NF;i++){a[$i]++}}END{for(i in a){print i"t"a[i]}}'


                    :}






                    share|improve this answer































                      1














                      http://www.gnu.org/software/coreutils/manual/html_node/who-invocation.html



                      "who" prints information about users who are currently logged on. Synopsis:



                      who [option] [file] [am i]






                      share|improve this answer































                        0














                        You could always download the free tool for unix called TOP. It produces a list of the users and also what they are doing on the system at the time and will continue to update as long as it is running.



                        It is located at http://www.unixtop.org/



                        It has many command line switches so you should be able to extract the information you are looking for.






                        share|improve this answer
























                        • I've yet to find a linux distro that doesn't include top by default, let alone not have an option to install it from packages.

                          – theotherreceive
                          Jul 27 '09 at 1:32



















                        0














                        who | cut -d ' ' -f1 | uniq | wc -l





                        share|improve this answer





















                        • 2





                          This seems like a minor variation of Kim's answer, and it contains no explanation. It might be more appropriate as a comment on that answer (which requires a little more rep). The intention is that each answer provide a solution that is substantively different from what has already been contributed.

                          – fixer1234
                          Feb 1 at 7:20



















                        -2














                        If you are looking for the total number of users logged in and logged off in a proper sequence, the best command to run is



                        cat -n /etc/passwd





                        share|improve this answer





















                        • 2





                          No, that's not what that command does. cat -n just prints all lines in the file, numbering each one. You'll get a list of users that exist on that system, but you won't get much login info.

                          – cpast
                          Feb 21 '13 at 5:01












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                        13 Answers
                        13






                        active

                        oldest

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                        13 Answers
                        13






                        active

                        oldest

                        votes









                        active

                        oldest

                        votes






                        active

                        oldest

                        votes









                        16














                        You are looking for the wc (word count) command.



                        Try this:



                        users | wc -w





                        share|improve this answer
























                        • note that this approach (an who/w solutions) show only users logged in, not necessarily active users (i.e. users that start a process and then logout leaving the running process behind). Just to give a heads up about the difference.

                          – estani
                          Mar 18 '13 at 13:45
















                        16














                        You are looking for the wc (word count) command.



                        Try this:



                        users | wc -w





                        share|improve this answer
























                        • note that this approach (an who/w solutions) show only users logged in, not necessarily active users (i.e. users that start a process and then logout leaving the running process behind). Just to give a heads up about the difference.

                          – estani
                          Mar 18 '13 at 13:45














                        16












                        16








                        16







                        You are looking for the wc (word count) command.



                        Try this:



                        users | wc -w





                        share|improve this answer













                        You are looking for the wc (word count) command.



                        Try this:



                        users | wc -w






                        share|improve this answer












                        share|improve this answer



                        share|improve this answer










                        answered Jul 26 '09 at 3:26









                        John TJohn T

                        143k20295331




                        143k20295331













                        • note that this approach (an who/w solutions) show only users logged in, not necessarily active users (i.e. users that start a process and then logout leaving the running process behind). Just to give a heads up about the difference.

                          – estani
                          Mar 18 '13 at 13:45



















                        • note that this approach (an who/w solutions) show only users logged in, not necessarily active users (i.e. users that start a process and then logout leaving the running process behind). Just to give a heads up about the difference.

                          – estani
                          Mar 18 '13 at 13:45

















                        note that this approach (an who/w solutions) show only users logged in, not necessarily active users (i.e. users that start a process and then logout leaving the running process behind). Just to give a heads up about the difference.

                        – estani
                        Mar 18 '13 at 13:45





                        note that this approach (an who/w solutions) show only users logged in, not necessarily active users (i.e. users that start a process and then logout leaving the running process behind). Just to give a heads up about the difference.

                        – estani
                        Mar 18 '13 at 13:45













                        18














                        Classically, the command is 'who' rather than 'users', but 'who' gives you more information. Looking back at the original Unix articles (mid-70s), the example would have been:



                        who | wc -l


                        Using 'wc -l' counts lines of output - it works with both 'users' and 'who'. Using '-w' only works reliably when there is one word per user (as with 'users' but not with 'who').



                        You could use 'grep -c' to count the lines. Since you are only interested in non-blank user names, you could do:



                        who | grep -c .


                        There's always at least one character on each line.





                        As noted in the comments by John T, the users command differs from who in a number of respects. The most important one is that instead of giving one name per line, it spreads the names out several per line — I don't have a machine with enough different users logged in to test what happens when the number of users becomes large. The other difference is that 'who' reports on terminal connections in use. With multiple terminal windows open, it will show multiple lines for a single user, whereas 'users' seems to list a logged in user just once.



                        As a consequence of this difference, the 'grep -c .' formulation won't work with the 'users' command; 'wc -w' is necessary.






                        share|improve this answer


























                        • small nitpick - the users command does not print 1 line per user, it just prints id's sequentially, so grep -c . would not work in this case. Smart thinking though.

                          – John T
                          Jul 26 '09 at 3:59











                        • this also means that wc -l will not work with the users command, as shown here: i26.tinypic.com/4pw0vd.png

                          – John T
                          Jul 26 '09 at 4:11











                        • @John T: oh - well, given screen shot, you're correct. I tested 'users' on MacOS X - but with just one user logged in. When I double checked with a second user logged in, I see the 'all on one line' behaviour.

                          – Jonathan Leffler
                          Jul 26 '09 at 5:52






                        • 1





                          to simulate more users you can SSH into your own box :)

                          – John T
                          Jul 26 '09 at 5:59











                        • Thank you for this valuable information, although I wanted to stick with the "users" command. Also upvoted you, thanks.

                          – Anonymous
                          Aug 1 '09 at 23:54
















                        18














                        Classically, the command is 'who' rather than 'users', but 'who' gives you more information. Looking back at the original Unix articles (mid-70s), the example would have been:



                        who | wc -l


                        Using 'wc -l' counts lines of output - it works with both 'users' and 'who'. Using '-w' only works reliably when there is one word per user (as with 'users' but not with 'who').



                        You could use 'grep -c' to count the lines. Since you are only interested in non-blank user names, you could do:



                        who | grep -c .


                        There's always at least one character on each line.





                        As noted in the comments by John T, the users command differs from who in a number of respects. The most important one is that instead of giving one name per line, it spreads the names out several per line — I don't have a machine with enough different users logged in to test what happens when the number of users becomes large. The other difference is that 'who' reports on terminal connections in use. With multiple terminal windows open, it will show multiple lines for a single user, whereas 'users' seems to list a logged in user just once.



                        As a consequence of this difference, the 'grep -c .' formulation won't work with the 'users' command; 'wc -w' is necessary.






                        share|improve this answer


























                        • small nitpick - the users command does not print 1 line per user, it just prints id's sequentially, so grep -c . would not work in this case. Smart thinking though.

                          – John T
                          Jul 26 '09 at 3:59











                        • this also means that wc -l will not work with the users command, as shown here: i26.tinypic.com/4pw0vd.png

                          – John T
                          Jul 26 '09 at 4:11











                        • @John T: oh - well, given screen shot, you're correct. I tested 'users' on MacOS X - but with just one user logged in. When I double checked with a second user logged in, I see the 'all on one line' behaviour.

                          – Jonathan Leffler
                          Jul 26 '09 at 5:52






                        • 1





                          to simulate more users you can SSH into your own box :)

                          – John T
                          Jul 26 '09 at 5:59











                        • Thank you for this valuable information, although I wanted to stick with the "users" command. Also upvoted you, thanks.

                          – Anonymous
                          Aug 1 '09 at 23:54














                        18












                        18








                        18







                        Classically, the command is 'who' rather than 'users', but 'who' gives you more information. Looking back at the original Unix articles (mid-70s), the example would have been:



                        who | wc -l


                        Using 'wc -l' counts lines of output - it works with both 'users' and 'who'. Using '-w' only works reliably when there is one word per user (as with 'users' but not with 'who').



                        You could use 'grep -c' to count the lines. Since you are only interested in non-blank user names, you could do:



                        who | grep -c .


                        There's always at least one character on each line.





                        As noted in the comments by John T, the users command differs from who in a number of respects. The most important one is that instead of giving one name per line, it spreads the names out several per line — I don't have a machine with enough different users logged in to test what happens when the number of users becomes large. The other difference is that 'who' reports on terminal connections in use. With multiple terminal windows open, it will show multiple lines for a single user, whereas 'users' seems to list a logged in user just once.



                        As a consequence of this difference, the 'grep -c .' formulation won't work with the 'users' command; 'wc -w' is necessary.






                        share|improve this answer















                        Classically, the command is 'who' rather than 'users', but 'who' gives you more information. Looking back at the original Unix articles (mid-70s), the example would have been:



                        who | wc -l


                        Using 'wc -l' counts lines of output - it works with both 'users' and 'who'. Using '-w' only works reliably when there is one word per user (as with 'users' but not with 'who').



                        You could use 'grep -c' to count the lines. Since you are only interested in non-blank user names, you could do:



                        who | grep -c .


                        There's always at least one character on each line.





                        As noted in the comments by John T, the users command differs from who in a number of respects. The most important one is that instead of giving one name per line, it spreads the names out several per line — I don't have a machine with enough different users logged in to test what happens when the number of users becomes large. The other difference is that 'who' reports on terminal connections in use. With multiple terminal windows open, it will show multiple lines for a single user, whereas 'users' seems to list a logged in user just once.



                        As a consequence of this difference, the 'grep -c .' formulation won't work with the 'users' command; 'wc -w' is necessary.







                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited Mar 20 '17 at 10:17









                        Community

                        1




                        1










                        answered Jul 26 '09 at 3:53









                        Jonathan LefflerJonathan Leffler

                        4,19612336




                        4,19612336













                        • small nitpick - the users command does not print 1 line per user, it just prints id's sequentially, so grep -c . would not work in this case. Smart thinking though.

                          – John T
                          Jul 26 '09 at 3:59











                        • this also means that wc -l will not work with the users command, as shown here: i26.tinypic.com/4pw0vd.png

                          – John T
                          Jul 26 '09 at 4:11











                        • @John T: oh - well, given screen shot, you're correct. I tested 'users' on MacOS X - but with just one user logged in. When I double checked with a second user logged in, I see the 'all on one line' behaviour.

                          – Jonathan Leffler
                          Jul 26 '09 at 5:52






                        • 1





                          to simulate more users you can SSH into your own box :)

                          – John T
                          Jul 26 '09 at 5:59











                        • Thank you for this valuable information, although I wanted to stick with the "users" command. Also upvoted you, thanks.

                          – Anonymous
                          Aug 1 '09 at 23:54



















                        • small nitpick - the users command does not print 1 line per user, it just prints id's sequentially, so grep -c . would not work in this case. Smart thinking though.

                          – John T
                          Jul 26 '09 at 3:59











                        • this also means that wc -l will not work with the users command, as shown here: i26.tinypic.com/4pw0vd.png

                          – John T
                          Jul 26 '09 at 4:11











                        • @John T: oh - well, given screen shot, you're correct. I tested 'users' on MacOS X - but with just one user logged in. When I double checked with a second user logged in, I see the 'all on one line' behaviour.

                          – Jonathan Leffler
                          Jul 26 '09 at 5:52






                        • 1





                          to simulate more users you can SSH into your own box :)

                          – John T
                          Jul 26 '09 at 5:59











                        • Thank you for this valuable information, although I wanted to stick with the "users" command. Also upvoted you, thanks.

                          – Anonymous
                          Aug 1 '09 at 23:54

















                        small nitpick - the users command does not print 1 line per user, it just prints id's sequentially, so grep -c . would not work in this case. Smart thinking though.

                        – John T
                        Jul 26 '09 at 3:59





                        small nitpick - the users command does not print 1 line per user, it just prints id's sequentially, so grep -c . would not work in this case. Smart thinking though.

                        – John T
                        Jul 26 '09 at 3:59













                        this also means that wc -l will not work with the users command, as shown here: i26.tinypic.com/4pw0vd.png

                        – John T
                        Jul 26 '09 at 4:11





                        this also means that wc -l will not work with the users command, as shown here: i26.tinypic.com/4pw0vd.png

                        – John T
                        Jul 26 '09 at 4:11













                        @John T: oh - well, given screen shot, you're correct. I tested 'users' on MacOS X - but with just one user logged in. When I double checked with a second user logged in, I see the 'all on one line' behaviour.

                        – Jonathan Leffler
                        Jul 26 '09 at 5:52





                        @John T: oh - well, given screen shot, you're correct. I tested 'users' on MacOS X - but with just one user logged in. When I double checked with a second user logged in, I see the 'all on one line' behaviour.

                        – Jonathan Leffler
                        Jul 26 '09 at 5:52




                        1




                        1





                        to simulate more users you can SSH into your own box :)

                        – John T
                        Jul 26 '09 at 5:59





                        to simulate more users you can SSH into your own box :)

                        – John T
                        Jul 26 '09 at 5:59













                        Thank you for this valuable information, although I wanted to stick with the "users" command. Also upvoted you, thanks.

                        – Anonymous
                        Aug 1 '09 at 23:54





                        Thank you for this valuable information, although I wanted to stick with the "users" command. Also upvoted you, thanks.

                        – Anonymous
                        Aug 1 '09 at 23:54











                        7














                        Open a shell and type:



                        who -q


                        The last line will give you a count.



                        EDIT:



                        (sigh) I misunderstood the question. Here's a somewhat brute-force approach:



                        To see unique user names:



                        who | awk '{ print $1 }' | sort | uniq


                        To see a count of unique users:



                        who | awk '{ print $1 }' | sort | uniq | wc -l 





                        share|improve this answer


























                        • that counts all logins of the same user in the total.

                          – hayalci
                          Jul 26 '09 at 18:56











                        • check the re-edit, I think you'll find that the new answers address that.

                          – Avery Payne
                          Jul 27 '09 at 15:33











                        • This still doesn't work, uniq only removes duplicate successive lines, you need to sort the output of who first.

                          – theotherreceive
                          Jul 27 '09 at 18:10











                        • that's what I get for posting answers at 1am. (sigh) fixed.

                          – Avery Payne
                          Jul 27 '09 at 19:37
















                        7














                        Open a shell and type:



                        who -q


                        The last line will give you a count.



                        EDIT:



                        (sigh) I misunderstood the question. Here's a somewhat brute-force approach:



                        To see unique user names:



                        who | awk '{ print $1 }' | sort | uniq


                        To see a count of unique users:



                        who | awk '{ print $1 }' | sort | uniq | wc -l 





                        share|improve this answer


























                        • that counts all logins of the same user in the total.

                          – hayalci
                          Jul 26 '09 at 18:56











                        • check the re-edit, I think you'll find that the new answers address that.

                          – Avery Payne
                          Jul 27 '09 at 15:33











                        • This still doesn't work, uniq only removes duplicate successive lines, you need to sort the output of who first.

                          – theotherreceive
                          Jul 27 '09 at 18:10











                        • that's what I get for posting answers at 1am. (sigh) fixed.

                          – Avery Payne
                          Jul 27 '09 at 19:37














                        7












                        7








                        7







                        Open a shell and type:



                        who -q


                        The last line will give you a count.



                        EDIT:



                        (sigh) I misunderstood the question. Here's a somewhat brute-force approach:



                        To see unique user names:



                        who | awk '{ print $1 }' | sort | uniq


                        To see a count of unique users:



                        who | awk '{ print $1 }' | sort | uniq | wc -l 





                        share|improve this answer















                        Open a shell and type:



                        who -q


                        The last line will give you a count.



                        EDIT:



                        (sigh) I misunderstood the question. Here's a somewhat brute-force approach:



                        To see unique user names:



                        who | awk '{ print $1 }' | sort | uniq


                        To see a count of unique users:



                        who | awk '{ print $1 }' | sort | uniq | wc -l 






                        share|improve this answer














                        share|improve this answer



                        share|improve this answer








                        edited Jul 27 '09 at 19:37

























                        answered Jul 26 '09 at 4:27









                        Avery PayneAvery Payne

                        2,19611824




                        2,19611824













                        • that counts all logins of the same user in the total.

                          – hayalci
                          Jul 26 '09 at 18:56











                        • check the re-edit, I think you'll find that the new answers address that.

                          – Avery Payne
                          Jul 27 '09 at 15:33











                        • This still doesn't work, uniq only removes duplicate successive lines, you need to sort the output of who first.

                          – theotherreceive
                          Jul 27 '09 at 18:10











                        • that's what I get for posting answers at 1am. (sigh) fixed.

                          – Avery Payne
                          Jul 27 '09 at 19:37



















                        • that counts all logins of the same user in the total.

                          – hayalci
                          Jul 26 '09 at 18:56











                        • check the re-edit, I think you'll find that the new answers address that.

                          – Avery Payne
                          Jul 27 '09 at 15:33











                        • This still doesn't work, uniq only removes duplicate successive lines, you need to sort the output of who first.

                          – theotherreceive
                          Jul 27 '09 at 18:10











                        • that's what I get for posting answers at 1am. (sigh) fixed.

                          – Avery Payne
                          Jul 27 '09 at 19:37

















                        that counts all logins of the same user in the total.

                        – hayalci
                        Jul 26 '09 at 18:56





                        that counts all logins of the same user in the total.

                        – hayalci
                        Jul 26 '09 at 18:56













                        check the re-edit, I think you'll find that the new answers address that.

                        – Avery Payne
                        Jul 27 '09 at 15:33





                        check the re-edit, I think you'll find that the new answers address that.

                        – Avery Payne
                        Jul 27 '09 at 15:33













                        This still doesn't work, uniq only removes duplicate successive lines, you need to sort the output of who first.

                        – theotherreceive
                        Jul 27 '09 at 18:10





                        This still doesn't work, uniq only removes duplicate successive lines, you need to sort the output of who first.

                        – theotherreceive
                        Jul 27 '09 at 18:10













                        that's what I get for posting answers at 1am. (sigh) fixed.

                        – Avery Payne
                        Jul 27 '09 at 19:37





                        that's what I get for posting answers at 1am. (sigh) fixed.

                        – Avery Payne
                        Jul 27 '09 at 19:37











                        3














                        Do you want to see the number of sessions, or the number of actual users?



                        $ who
                        andrew tty1 2009-07-26 15:31 (:0)
                        andrew pts/0 2009-07-27 00:11 (:0.0)
                        andrew pts/1 2009-07-27 01:58 (:0.0)


                        That's on my laptop, so i'm the only user, but i'm logged on three times.



                        $ who | wc -l
                        3
                        $ users | wc -w
                        3


                        It is fairly easy to filter out these duplicates though to get the number of actual users.



                        $ users | tr ' ' 'n' | sort -u 
                        andrew
                        $ users | tr ' ' 'n' | sort -u | wc -l
                        1





                        share|improve this answer




























                          3














                          Do you want to see the number of sessions, or the number of actual users?



                          $ who
                          andrew tty1 2009-07-26 15:31 (:0)
                          andrew pts/0 2009-07-27 00:11 (:0.0)
                          andrew pts/1 2009-07-27 01:58 (:0.0)


                          That's on my laptop, so i'm the only user, but i'm logged on three times.



                          $ who | wc -l
                          3
                          $ users | wc -w
                          3


                          It is fairly easy to filter out these duplicates though to get the number of actual users.



                          $ users | tr ' ' 'n' | sort -u 
                          andrew
                          $ users | tr ' ' 'n' | sort -u | wc -l
                          1





                          share|improve this answer


























                            3












                            3








                            3







                            Do you want to see the number of sessions, or the number of actual users?



                            $ who
                            andrew tty1 2009-07-26 15:31 (:0)
                            andrew pts/0 2009-07-27 00:11 (:0.0)
                            andrew pts/1 2009-07-27 01:58 (:0.0)


                            That's on my laptop, so i'm the only user, but i'm logged on three times.



                            $ who | wc -l
                            3
                            $ users | wc -w
                            3


                            It is fairly easy to filter out these duplicates though to get the number of actual users.



                            $ users | tr ' ' 'n' | sort -u 
                            andrew
                            $ users | tr ' ' 'n' | sort -u | wc -l
                            1





                            share|improve this answer













                            Do you want to see the number of sessions, or the number of actual users?



                            $ who
                            andrew tty1 2009-07-26 15:31 (:0)
                            andrew pts/0 2009-07-27 00:11 (:0.0)
                            andrew pts/1 2009-07-27 01:58 (:0.0)


                            That's on my laptop, so i'm the only user, but i'm logged on three times.



                            $ who | wc -l
                            3
                            $ users | wc -w
                            3


                            It is fairly easy to filter out these duplicates though to get the number of actual users.



                            $ users | tr ' ' 'n' | sort -u 
                            andrew
                            $ users | tr ' ' 'n' | sort -u | wc -l
                            1






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Jul 27 '09 at 1:32









                            theotherreceivetheotherreceive

                            753611




                            753611























                                3














                                Here's a bash version of tink's great awk post:



                                set $(users)
                                declare -A user
                                for u ; do ((user[$u]++)) ; done
                                for key in "${!user[@]}" ; do echo "$key: ${user[$key]}" ; done | column -t | sort -nk 2


                                Ok, it's a little bit longer, but was worth finding this one ... :).



                                While testing, do before next attempt:



                                shift $#                # clear positional parameters
                                unset user # remove associative array variable





                                share|improve this answer






























                                  3














                                  Here's a bash version of tink's great awk post:



                                  set $(users)
                                  declare -A user
                                  for u ; do ((user[$u]++)) ; done
                                  for key in "${!user[@]}" ; do echo "$key: ${user[$key]}" ; done | column -t | sort -nk 2


                                  Ok, it's a little bit longer, but was worth finding this one ... :).



                                  While testing, do before next attempt:



                                  shift $#                # clear positional parameters
                                  unset user # remove associative array variable





                                  share|improve this answer




























                                    3












                                    3








                                    3







                                    Here's a bash version of tink's great awk post:



                                    set $(users)
                                    declare -A user
                                    for u ; do ((user[$u]++)) ; done
                                    for key in "${!user[@]}" ; do echo "$key: ${user[$key]}" ; done | column -t | sort -nk 2


                                    Ok, it's a little bit longer, but was worth finding this one ... :).



                                    While testing, do before next attempt:



                                    shift $#                # clear positional parameters
                                    unset user # remove associative array variable





                                    share|improve this answer















                                    Here's a bash version of tink's great awk post:



                                    set $(users)
                                    declare -A user
                                    for u ; do ((user[$u]++)) ; done
                                    for key in "${!user[@]}" ; do echo "$key: ${user[$key]}" ; done | column -t | sort -nk 2


                                    Ok, it's a little bit longer, but was worth finding this one ... :).



                                    While testing, do before next attempt:



                                    shift $#                # clear positional parameters
                                    unset user # remove associative array variable






                                    share|improve this answer














                                    share|improve this answer



                                    share|improve this answer








                                    edited Jun 10 '16 at 10:35

























                                    answered Jun 9 '16 at 13:19









                                    SaschSasch

                                    313




                                    313























                                        2














                                        number of the users currently logged in:



                                        who |cut -c 1-9 |sort -u |wc -l


                                        the above buta with their account name:



                                        who |cut -c 1-9 |sort -u |tee /dev/tty |wc -l





                                        share|improve this answer




























                                          2














                                          number of the users currently logged in:



                                          who |cut -c 1-9 |sort -u |wc -l


                                          the above buta with their account name:



                                          who |cut -c 1-9 |sort -u |tee /dev/tty |wc -l





                                          share|improve this answer


























                                            2












                                            2








                                            2







                                            number of the users currently logged in:



                                            who |cut -c 1-9 |sort -u |wc -l


                                            the above buta with their account name:



                                            who |cut -c 1-9 |sort -u |tee /dev/tty |wc -l





                                            share|improve this answer













                                            number of the users currently logged in:



                                            who |cut -c 1-9 |sort -u |wc -l


                                            the above buta with their account name:



                                            who |cut -c 1-9 |sort -u |tee /dev/tty |wc -l






                                            share|improve this answer












                                            share|improve this answer



                                            share|improve this answer










                                            answered Jan 23 '12 at 19:58









                                            CrisCris

                                            211




                                            211























                                                1














                                                who | cut --delimiter=' ' -f 1 | sort -u | wc -l


                                                Who prints out the list, cut removes everything but the first row, sort -u sort it and removes duplicates and wc -l counts the lines. Works fine for me on ubuntu/bash :)






                                                share|improve this answer




























                                                  1














                                                  who | cut --delimiter=' ' -f 1 | sort -u | wc -l


                                                  Who prints out the list, cut removes everything but the first row, sort -u sort it and removes duplicates and wc -l counts the lines. Works fine for me on ubuntu/bash :)






                                                  share|improve this answer


























                                                    1












                                                    1








                                                    1







                                                    who | cut --delimiter=' ' -f 1 | sort -u | wc -l


                                                    Who prints out the list, cut removes everything but the first row, sort -u sort it and removes duplicates and wc -l counts the lines. Works fine for me on ubuntu/bash :)






                                                    share|improve this answer













                                                    who | cut --delimiter=' ' -f 1 | sort -u | wc -l


                                                    Who prints out the list, cut removes everything but the first row, sort -u sort it and removes duplicates and wc -l counts the lines. Works fine for me on ubuntu/bash :)







                                                    share|improve this answer












                                                    share|improve this answer



                                                    share|improve this answer










                                                    answered Jul 26 '09 at 20:36









                                                    KimKim

                                                    2,01021426




                                                    2,01021426























                                                        1














                                                        You can simply use w (/usr/bin/w on my Red Hat based system) or uptime, they show the actual number of logged in users.



                                                        w:



                                                                                      v
                                                        22:40:38 up 3 days, 22 min, 1 user, load average: 0.02, 0.01, 0.00
                                                        USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT
                                                        manuel pts/0 pc-manuel 09:35 0.00s 0.07s 0.00s /usr/bin/screen -xRR


                                                        uptime:



                                                                                      v
                                                        22:39:18 up 3 days, 21 min, 1 user, load average: 0.08, 0.02, 0.01





                                                        share|improve this answer




























                                                          1














                                                          You can simply use w (/usr/bin/w on my Red Hat based system) or uptime, they show the actual number of logged in users.



                                                          w:



                                                                                        v
                                                          22:40:38 up 3 days, 22 min, 1 user, load average: 0.02, 0.01, 0.00
                                                          USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT
                                                          manuel pts/0 pc-manuel 09:35 0.00s 0.07s 0.00s /usr/bin/screen -xRR


                                                          uptime:



                                                                                        v
                                                          22:39:18 up 3 days, 21 min, 1 user, load average: 0.08, 0.02, 0.01





                                                          share|improve this answer


























                                                            1












                                                            1








                                                            1







                                                            You can simply use w (/usr/bin/w on my Red Hat based system) or uptime, they show the actual number of logged in users.



                                                            w:



                                                                                          v
                                                            22:40:38 up 3 days, 22 min, 1 user, load average: 0.02, 0.01, 0.00
                                                            USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT
                                                            manuel pts/0 pc-manuel 09:35 0.00s 0.07s 0.00s /usr/bin/screen -xRR


                                                            uptime:



                                                                                          v
                                                            22:39:18 up 3 days, 21 min, 1 user, load average: 0.08, 0.02, 0.01





                                                            share|improve this answer













                                                            You can simply use w (/usr/bin/w on my Red Hat based system) or uptime, they show the actual number of logged in users.



                                                            w:



                                                                                          v
                                                            22:40:38 up 3 days, 22 min, 1 user, load average: 0.02, 0.01, 0.00
                                                            USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT
                                                            manuel pts/0 pc-manuel 09:35 0.00s 0.07s 0.00s /usr/bin/screen -xRR


                                                            uptime:



                                                                                          v
                                                            22:39:18 up 3 days, 21 min, 1 user, load average: 0.08, 0.02, 0.01






                                                            share|improve this answer












                                                            share|improve this answer



                                                            share|improve this answer










                                                            answered Jul 26 '09 at 20:42









                                                            Manuel FauxManuel Faux

                                                            6611611




                                                            6611611























                                                                1














                                                                And a method that uses only one pipe...



                                                                users | awk '{for(i=1;i<=NF;i++){a[$i]++}}END{for(i in a){print i"t"a[i]}}'


                                                                :}






                                                                share|improve this answer




























                                                                  1














                                                                  And a method that uses only one pipe...



                                                                  users | awk '{for(i=1;i<=NF;i++){a[$i]++}}END{for(i in a){print i"t"a[i]}}'


                                                                  :}






                                                                  share|improve this answer


























                                                                    1












                                                                    1








                                                                    1







                                                                    And a method that uses only one pipe...



                                                                    users | awk '{for(i=1;i<=NF;i++){a[$i]++}}END{for(i in a){print i"t"a[i]}}'


                                                                    :}






                                                                    share|improve this answer













                                                                    And a method that uses only one pipe...



                                                                    users | awk '{for(i=1;i<=NF;i++){a[$i]++}}END{for(i in a){print i"t"a[i]}}'


                                                                    :}







                                                                    share|improve this answer












                                                                    share|improve this answer



                                                                    share|improve this answer










                                                                    answered Feb 17 '13 at 19:20









                                                                    tinktink

                                                                    1,3271914




                                                                    1,3271914























                                                                        1














                                                                        http://www.gnu.org/software/coreutils/manual/html_node/who-invocation.html



                                                                        "who" prints information about users who are currently logged on. Synopsis:



                                                                        who [option] [file] [am i]






                                                                        share|improve this answer




























                                                                          1














                                                                          http://www.gnu.org/software/coreutils/manual/html_node/who-invocation.html



                                                                          "who" prints information about users who are currently logged on. Synopsis:



                                                                          who [option] [file] [am i]






                                                                          share|improve this answer


























                                                                            1












                                                                            1








                                                                            1







                                                                            http://www.gnu.org/software/coreutils/manual/html_node/who-invocation.html



                                                                            "who" prints information about users who are currently logged on. Synopsis:



                                                                            who [option] [file] [am i]






                                                                            share|improve this answer













                                                                            http://www.gnu.org/software/coreutils/manual/html_node/who-invocation.html



                                                                            "who" prints information about users who are currently logged on. Synopsis:



                                                                            who [option] [file] [am i]







                                                                            share|improve this answer












                                                                            share|improve this answer



                                                                            share|improve this answer










                                                                            answered Jan 29 '15 at 6:22









                                                                            TonyTony

                                                                            1111




                                                                            1111























                                                                                0














                                                                                You could always download the free tool for unix called TOP. It produces a list of the users and also what they are doing on the system at the time and will continue to update as long as it is running.



                                                                                It is located at http://www.unixtop.org/



                                                                                It has many command line switches so you should be able to extract the information you are looking for.






                                                                                share|improve this answer
























                                                                                • I've yet to find a linux distro that doesn't include top by default, let alone not have an option to install it from packages.

                                                                                  – theotherreceive
                                                                                  Jul 27 '09 at 1:32
















                                                                                0














                                                                                You could always download the free tool for unix called TOP. It produces a list of the users and also what they are doing on the system at the time and will continue to update as long as it is running.



                                                                                It is located at http://www.unixtop.org/



                                                                                It has many command line switches so you should be able to extract the information you are looking for.






                                                                                share|improve this answer
























                                                                                • I've yet to find a linux distro that doesn't include top by default, let alone not have an option to install it from packages.

                                                                                  – theotherreceive
                                                                                  Jul 27 '09 at 1:32














                                                                                0












                                                                                0








                                                                                0







                                                                                You could always download the free tool for unix called TOP. It produces a list of the users and also what they are doing on the system at the time and will continue to update as long as it is running.



                                                                                It is located at http://www.unixtop.org/



                                                                                It has many command line switches so you should be able to extract the information you are looking for.






                                                                                share|improve this answer













                                                                                You could always download the free tool for unix called TOP. It produces a list of the users and also what they are doing on the system at the time and will continue to update as long as it is running.



                                                                                It is located at http://www.unixtop.org/



                                                                                It has many command line switches so you should be able to extract the information you are looking for.







                                                                                share|improve this answer












                                                                                share|improve this answer



                                                                                share|improve this answer










                                                                                answered Jul 26 '09 at 4:17









                                                                                AxxmasterrAxxmasterr

                                                                                6,80363557




                                                                                6,80363557













                                                                                • I've yet to find a linux distro that doesn't include top by default, let alone not have an option to install it from packages.

                                                                                  – theotherreceive
                                                                                  Jul 27 '09 at 1:32



















                                                                                • I've yet to find a linux distro that doesn't include top by default, let alone not have an option to install it from packages.

                                                                                  – theotherreceive
                                                                                  Jul 27 '09 at 1:32

















                                                                                I've yet to find a linux distro that doesn't include top by default, let alone not have an option to install it from packages.

                                                                                – theotherreceive
                                                                                Jul 27 '09 at 1:32





                                                                                I've yet to find a linux distro that doesn't include top by default, let alone not have an option to install it from packages.

                                                                                – theotherreceive
                                                                                Jul 27 '09 at 1:32











                                                                                0














                                                                                who | cut -d ' ' -f1 | uniq | wc -l





                                                                                share|improve this answer





















                                                                                • 2





                                                                                  This seems like a minor variation of Kim's answer, and it contains no explanation. It might be more appropriate as a comment on that answer (which requires a little more rep). The intention is that each answer provide a solution that is substantively different from what has already been contributed.

                                                                                  – fixer1234
                                                                                  Feb 1 at 7:20
















                                                                                0














                                                                                who | cut -d ' ' -f1 | uniq | wc -l





                                                                                share|improve this answer





















                                                                                • 2





                                                                                  This seems like a minor variation of Kim's answer, and it contains no explanation. It might be more appropriate as a comment on that answer (which requires a little more rep). The intention is that each answer provide a solution that is substantively different from what has already been contributed.

                                                                                  – fixer1234
                                                                                  Feb 1 at 7:20














                                                                                0












                                                                                0








                                                                                0







                                                                                who | cut -d ' ' -f1 | uniq | wc -l





                                                                                share|improve this answer















                                                                                who | cut -d ' ' -f1 | uniq | wc -l






                                                                                share|improve this answer














                                                                                share|improve this answer



                                                                                share|improve this answer








                                                                                edited Feb 1 at 8:41









                                                                                Mureinik

                                                                                2,86171725




                                                                                2,86171725










                                                                                answered Feb 1 at 5:14









                                                                                Arjun DandagiArjun Dandagi

                                                                                11




                                                                                11








                                                                                • 2





                                                                                  This seems like a minor variation of Kim's answer, and it contains no explanation. It might be more appropriate as a comment on that answer (which requires a little more rep). The intention is that each answer provide a solution that is substantively different from what has already been contributed.

                                                                                  – fixer1234
                                                                                  Feb 1 at 7:20














                                                                                • 2





                                                                                  This seems like a minor variation of Kim's answer, and it contains no explanation. It might be more appropriate as a comment on that answer (which requires a little more rep). The intention is that each answer provide a solution that is substantively different from what has already been contributed.

                                                                                  – fixer1234
                                                                                  Feb 1 at 7:20








                                                                                2




                                                                                2





                                                                                This seems like a minor variation of Kim's answer, and it contains no explanation. It might be more appropriate as a comment on that answer (which requires a little more rep). The intention is that each answer provide a solution that is substantively different from what has already been contributed.

                                                                                – fixer1234
                                                                                Feb 1 at 7:20





                                                                                This seems like a minor variation of Kim's answer, and it contains no explanation. It might be more appropriate as a comment on that answer (which requires a little more rep). The intention is that each answer provide a solution that is substantively different from what has already been contributed.

                                                                                – fixer1234
                                                                                Feb 1 at 7:20











                                                                                -2














                                                                                If you are looking for the total number of users logged in and logged off in a proper sequence, the best command to run is



                                                                                cat -n /etc/passwd





                                                                                share|improve this answer





















                                                                                • 2





                                                                                  No, that's not what that command does. cat -n just prints all lines in the file, numbering each one. You'll get a list of users that exist on that system, but you won't get much login info.

                                                                                  – cpast
                                                                                  Feb 21 '13 at 5:01
















                                                                                -2














                                                                                If you are looking for the total number of users logged in and logged off in a proper sequence, the best command to run is



                                                                                cat -n /etc/passwd





                                                                                share|improve this answer





















                                                                                • 2





                                                                                  No, that's not what that command does. cat -n just prints all lines in the file, numbering each one. You'll get a list of users that exist on that system, but you won't get much login info.

                                                                                  – cpast
                                                                                  Feb 21 '13 at 5:01














                                                                                -2












                                                                                -2








                                                                                -2







                                                                                If you are looking for the total number of users logged in and logged off in a proper sequence, the best command to run is



                                                                                cat -n /etc/passwd





                                                                                share|improve this answer















                                                                                If you are looking for the total number of users logged in and logged off in a proper sequence, the best command to run is



                                                                                cat -n /etc/passwd






                                                                                share|improve this answer














                                                                                share|improve this answer



                                                                                share|improve this answer








                                                                                edited Feb 21 '13 at 6:29









                                                                                cpast

                                                                                2,11421426




                                                                                2,11421426










                                                                                answered Feb 21 '13 at 4:34









                                                                                Amrik SinghAmrik Singh

                                                                                7




                                                                                7








                                                                                • 2





                                                                                  No, that's not what that command does. cat -n just prints all lines in the file, numbering each one. You'll get a list of users that exist on that system, but you won't get much login info.

                                                                                  – cpast
                                                                                  Feb 21 '13 at 5:01














                                                                                • 2





                                                                                  No, that's not what that command does. cat -n just prints all lines in the file, numbering each one. You'll get a list of users that exist on that system, but you won't get much login info.

                                                                                  – cpast
                                                                                  Feb 21 '13 at 5:01








                                                                                2




                                                                                2





                                                                                No, that's not what that command does. cat -n just prints all lines in the file, numbering each one. You'll get a list of users that exist on that system, but you won't get much login info.

                                                                                – cpast
                                                                                Feb 21 '13 at 5:01





                                                                                No, that's not what that command does. cat -n just prints all lines in the file, numbering each one. You'll get a list of users that exist on that system, but you won't get much login info.

                                                                                – cpast
                                                                                Feb 21 '13 at 5:01


















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