Replacing function, how to use + as delimiter
4
I am using a function for summing numbers like in paper and my input at arguments is like this:
showsum{123+456}
I need to replace the custom function with other from package xlop - opadd.
I want the same function name but there are 2 separated arguments in opadd and I want to use {123+456} for opadd arguments. How to make this delimiter?
documentclass{article}
usepackage{xlop}
usepackage{amsmath}
usepackage{setspace}
newcommand{showsum}[2][c]{%
$edeforiginalplusmathcode{themathcode`+}%
begingrouplccode`~=`+ lowercase{endgroupdef~}{\mathcharoriginalplusmathcode&}%
edeforiginalminusmathcode{themathcode`-}%
begingrouplccode`~=`- lowercase{endgroupdef~}{\mathcharoriginalminusmathcode&}%
mathcode`+ "8000
mathcode`- "8000
begin{array}[#1]{@{}r@{;}r@{}}
& #2 \
hline
& thenumexpr#2relax
end{array}%
$%
}
begin{document}
Original function(don't need anymore)showsum{123+456}
\
\
Replacement needed opadd{123}{456}
end{document}
delimiters
asked 2 days ago
Simeon SimeonovSimeon Simeonov
3306
add a comment |
4
I am using a function for summing numbers like in paper and my input at arguments is like this:
showsum{123+456}
I need to replace the custom function with other from package xlop - opadd.
I want the same function name but there are 2 separated arguments in opadd and I want to use {123+456} for opadd arguments. How to make this delimiter?
documentclass{article}
usepackage{xlop}
usepackage{amsmath}
usepackage{setspace}
newcommand{showsum}[2][c]{%
$edeforiginalplusmathcode{themathcode`+}%
begingrouplccode`~=`+ lowercase{endgroupdef~}{\mathcharoriginalplusmathcode&}%
edeforiginalminusmathcode{themathcode`-}%
begingrouplccode`~=`- lowercase{endgroupdef~}{\mathcharoriginalminusmathcode&}%
mathcode`+ "8000
mathcode`- "8000
begin{array}[#1]{@{}r@{;}r@{}}
& #2 \
hline
& thenumexpr#2relax
end{array}%
$%
}
begin{document}
Original function(don't need anymore)showsum{123+456}
\
\
Replacement needed opadd{123}{456}
end{document}
delimiters
asked 2 days ago
Simeon SimeonovSimeon Simeonov
3306
add a comment |
4
4
4
I am using a function for summing numbers like in paper and my input at arguments is like this:
showsum{123+456}
I need to replace the custom function with other from package xlop - opadd.
I want the same function name but there are 2 separated arguments in opadd and I want to use {123+456} for opadd arguments. How to make this delimiter?
documentclass{article}
usepackage{xlop}
usepackage{amsmath}
usepackage{setspace}
newcommand{showsum}[2][c]{%
$edeforiginalplusmathcode{themathcode`+}%
begingrouplccode`~=`+ lowercase{endgroupdef~}{\mathcharoriginalplusmathcode&}%
edeforiginalminusmathcode{themathcode`-}%
begingrouplccode`~=`- lowercase{endgroupdef~}{\mathcharoriginalminusmathcode&}%
mathcode`+ "8000
mathcode`- "8000
begin{array}[#1]{@{}r@{;}r@{}}
& #2 \
hline
& thenumexpr#2relax
end{array}%
$%
}
begin{document}
Original function(don't need anymore)showsum{123+456}
\
\
Replacement needed opadd{123}{456}
end{document}
delimiters
asked 2 days ago
Simeon SimeonovSimeon Simeonov
3306
I am using a function for summing numbers like in paper and my input at arguments is like this:
showsum{123+456}
I need to replace the custom function with other from package xlop - opadd.
I want the same function name but there are 2 separated arguments in opadd and I want to use {123+456} for opadd arguments. How to make this delimiter?
documentclass{article}
usepackage{xlop}
usepackage{amsmath}
usepackage{setspace}
newcommand{showsum}[2][c]{%
$edeforiginalplusmathcode{themathcode`+}%
begingrouplccode`~=`+ lowercase{endgroupdef~}{\mathcharoriginalplusmathcode&}%
edeforiginalminusmathcode{themathcode`-}%
begingrouplccode`~=`- lowercase{endgroupdef~}{\mathcharoriginalminusmathcode&}%
mathcode`+ "8000
mathcode`- "8000
begin{array}[#1]{@{}r@{;}r@{}}
& #2 \
hline
& thenumexpr#2relax
end{array}%
$%
}
begin{document}
Original function(don't need anymore)showsum{123+456}
\
\
Replacement needed opadd{123}{456}
end{document}
delimiters
delimiters
asked 2 days ago
Simeon SimeonovSimeon Simeonov
3306
asked 2 days ago
Simeon SimeonovSimeon Simeonov
3306
asked 2 days ago
Simeon SimeonovSimeon Simeonov
3306
asked 2 days ago
Simeon SimeonovSimeon Simeonov
3306
asked 2 days ago
Simeon SimeonovSimeon Simeonov
3306
3306
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
7
You can use a macro with delimited arguments:
documentclass{article}
usepackage{xlop}
newcommand{showsum}[1]{doshowsum#1doshowsum}
defdoshowsum#1+#2doshowsum{opadd{#1}{#2}}
begin{document}
showsum{123+456} qquad opadd{123}{456}
end{document}
You can also support subtraction:
documentclass{article}
usepackage{xparse}
usepackage{xlop}
ExplSyntaxOn
NewDocumentCommand{showsum}{m}
{
regex_match:nnTF { + } { #1 }
{
simeon_showsum:nnn { #1 } { + } { opadd }
}
{
simeon_showsum:nnn { #1 } { - } { opsub }
}
}
cs_new_protected:Nn simeon_showsum:nnn
{
tl_set:Nn l_tmpa_tl { #1 }
% remove all spaces
regex_replace_all:nnN { s } { } l_tmpa_tl
% replace <number>+<number> with opadd{<number>}{<number>} or
% replace <number>-<number> with opsub{<number>}{<number>}
regex_replace_once:nnN
{ A ([^#2]*) #2 (.*) Z }
{ c{#3}cB{1cE}cB{2cE} }
l_tmpa_tl
% deliver the result
tl_use:N l_tmpa_tl
}
ExplSyntaxOff
begin{document}
showsum{123+456} qquad showsum{456-123}
end{document}
answered 2 days ago
egregegreg
710k8618893173
Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
– Simeon Simeonov
2 days ago
1
@SimeonSimeonov I added removal of spaces
– egreg
2 days ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
7
You can use a macro with delimited arguments:
documentclass{article}
usepackage{xlop}
newcommand{showsum}[1]{doshowsum#1doshowsum}
defdoshowsum#1+#2doshowsum{opadd{#1}{#2}}
begin{document}
showsum{123+456} qquad opadd{123}{456}
end{document}
You can also support subtraction:
documentclass{article}
usepackage{xparse}
usepackage{xlop}
ExplSyntaxOn
NewDocumentCommand{showsum}{m}
{
regex_match:nnTF { + } { #1 }
{
simeon_showsum:nnn { #1 } { + } { opadd }
}
{
simeon_showsum:nnn { #1 } { - } { opsub }
}
}
cs_new_protected:Nn simeon_showsum:nnn
{
tl_set:Nn l_tmpa_tl { #1 }
% remove all spaces
regex_replace_all:nnN { s } { } l_tmpa_tl
% replace <number>+<number> with opadd{<number>}{<number>} or
% replace <number>-<number> with opsub{<number>}{<number>}
regex_replace_once:nnN
{ A ([^#2]*) #2 (.*) Z }
{ c{#3}cB{1cE}cB{2cE} }
l_tmpa_tl
% deliver the result
tl_use:N l_tmpa_tl
}
ExplSyntaxOff
begin{document}
showsum{123+456} qquad showsum{456-123}
end{document}
answered 2 days ago
egregegreg
710k8618893173
Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
– Simeon Simeonov
2 days ago
1
@SimeonSimeonov I added removal of spaces
– egreg
2 days ago
add a comment |
7
You can use a macro with delimited arguments:
documentclass{article}
usepackage{xlop}
newcommand{showsum}[1]{doshowsum#1doshowsum}
defdoshowsum#1+#2doshowsum{opadd{#1}{#2}}
begin{document}
showsum{123+456} qquad opadd{123}{456}
end{document}
You can also support subtraction:
documentclass{article}
usepackage{xparse}
usepackage{xlop}
ExplSyntaxOn
NewDocumentCommand{showsum}{m}
{
regex_match:nnTF { + } { #1 }
{
simeon_showsum:nnn { #1 } { + } { opadd }
}
{
simeon_showsum:nnn { #1 } { - } { opsub }
}
}
cs_new_protected:Nn simeon_showsum:nnn
{
tl_set:Nn l_tmpa_tl { #1 }
% remove all spaces
regex_replace_all:nnN { s } { } l_tmpa_tl
% replace <number>+<number> with opadd{<number>}{<number>} or
% replace <number>-<number> with opsub{<number>}{<number>}
regex_replace_once:nnN
{ A ([^#2]*) #2 (.*) Z }
{ c{#3}cB{1cE}cB{2cE} }
l_tmpa_tl
% deliver the result
tl_use:N l_tmpa_tl
}
ExplSyntaxOff
begin{document}
showsum{123+456} qquad showsum{456-123}
end{document}
answered 2 days ago
egregegreg
710k8618893173
Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
– Simeon Simeonov
2 days ago
1
@SimeonSimeonov I added removal of spaces
– egreg
2 days ago
add a comment |
7
7
7
You can use a macro with delimited arguments:
documentclass{article}
usepackage{xlop}
newcommand{showsum}[1]{doshowsum#1doshowsum}
defdoshowsum#1+#2doshowsum{opadd{#1}{#2}}
begin{document}
showsum{123+456} qquad opadd{123}{456}
end{document}
You can also support subtraction:
documentclass{article}
usepackage{xparse}
usepackage{xlop}
ExplSyntaxOn
NewDocumentCommand{showsum}{m}
{
regex_match:nnTF { + } { #1 }
{
simeon_showsum:nnn { #1 } { + } { opadd }
}
{
simeon_showsum:nnn { #1 } { - } { opsub }
}
}
cs_new_protected:Nn simeon_showsum:nnn
{
tl_set:Nn l_tmpa_tl { #1 }
% remove all spaces
regex_replace_all:nnN { s } { } l_tmpa_tl
% replace <number>+<number> with opadd{<number>}{<number>} or
% replace <number>-<number> with opsub{<number>}{<number>}
regex_replace_once:nnN
{ A ([^#2]*) #2 (.*) Z }
{ c{#3}cB{1cE}cB{2cE} }
l_tmpa_tl
% deliver the result
tl_use:N l_tmpa_tl
}
ExplSyntaxOff
begin{document}
showsum{123+456} qquad showsum{456-123}
end{document}
answered 2 days ago
egregegreg
710k8618893173
You can use a macro with delimited arguments:
documentclass{article}
usepackage{xlop}
newcommand{showsum}[1]{doshowsum#1doshowsum}
defdoshowsum#1+#2doshowsum{opadd{#1}{#2}}
begin{document}
showsum{123+456} qquad opadd{123}{456}
end{document}
You can also support subtraction:
documentclass{article}
usepackage{xparse}
usepackage{xlop}
ExplSyntaxOn
NewDocumentCommand{showsum}{m}
{
regex_match:nnTF { + } { #1 }
{
simeon_showsum:nnn { #1 } { + } { opadd }
}
{
simeon_showsum:nnn { #1 } { - } { opsub }
}
}
cs_new_protected:Nn simeon_showsum:nnn
{
tl_set:Nn l_tmpa_tl { #1 }
% remove all spaces
regex_replace_all:nnN { s } { } l_tmpa_tl
% replace <number>+<number> with opadd{<number>}{<number>} or
% replace <number>-<number> with opsub{<number>}{<number>}
regex_replace_once:nnN
{ A ([^#2]*) #2 (.*) Z }
{ c{#3}cB{1cE}cB{2cE} }
l_tmpa_tl
% deliver the result
tl_use:N l_tmpa_tl
}
ExplSyntaxOff
begin{document}
showsum{123+456} qquad showsum{456-123}
end{document}
answered 2 days ago
egregegreg
710k8618893173
edited 2 days ago
answered 2 days ago
egregegreg
710k8618893173
answered 2 days ago
egregegreg
710k8618893173
answered 2 days ago
egregegreg
710k8618893173
710k8618893173
Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
– Simeon Simeonov
2 days ago
1
@SimeonSimeonov I added removal of spaces
– egreg
2 days ago
add a comment |
Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
– Simeon Simeonov
2 days ago
1
@SimeonSimeonov I added removal of spaces
– egreg
2 days ago
Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
– Simeon Simeonov
2 days ago
Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
– Simeon Simeonov
2 days ago
1
1
@SimeonSimeonov I added removal of spaces
– egreg
2 days ago
@SimeonSimeonov I added removal of spaces
– egreg
2 days ago
add a comment |
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