Python set variables to shorter list and list length
$begingroup$
I have a simple task that I can't find an elegant solution to. Say I have two arrays and I want to find which one is shorter and create variables for both their lengths (specifying them as long and short). Here's an inelegant way to do it:
l1 = len(arr1)
l2 = len(arr2)
if l1 < l2:
short_arr = arr1
long_arr = arr2
lshort = l1
llong = l2
else:
short_arr = arr2
long_arr = arr1
lshort = l2
llong = l1
What's a better way to do it?
python
asked 34 mins ago
jss367jss367
18629
$endgroup$
add a comment |
$begingroup$
I have a simple task that I can't find an elegant solution to. Say I have two arrays and I want to find which one is shorter and create variables for both their lengths (specifying them as long and short). Here's an inelegant way to do it:
l1 = len(arr1)
l2 = len(arr2)
if l1 < l2:
short_arr = arr1
long_arr = arr2
lshort = l1
llong = l2
else:
short_arr = arr2
long_arr = arr1
lshort = l2
llong = l1
What's a better way to do it?
python
asked 34 mins ago
jss367jss367
18629
$endgroup$
add a comment |
$begingroup$
I have a simple task that I can't find an elegant solution to. Say I have two arrays and I want to find which one is shorter and create variables for both their lengths (specifying them as long and short). Here's an inelegant way to do it:
l1 = len(arr1)
l2 = len(arr2)
if l1 < l2:
short_arr = arr1
long_arr = arr2
lshort = l1
llong = l2
else:
short_arr = arr2
long_arr = arr1
lshort = l2
llong = l1
What's a better way to do it?
python
asked 34 mins ago
jss367jss367
18629
$endgroup$
I have a simple task that I can't find an elegant solution to. Say I have two arrays and I want to find which one is shorter and create variables for both their lengths (specifying them as long and short). Here's an inelegant way to do it:
l1 = len(arr1)
l2 = len(arr2)
if l1 < l2:
short_arr = arr1
long_arr = arr2
lshort = l1
llong = l2
else:
short_arr = arr2
long_arr = arr1
lshort = l2
llong = l1
What's a better way to do it?
python
python
asked 34 mins ago
jss367jss367
18629
asked 34 mins ago
jss367jss367
18629
asked 34 mins ago
jss367jss367
18629
asked 34 mins ago
jss367jss367
18629
asked 34 mins ago
jss367jss367
18629
18629
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
I can’t claim this is more elegant, but it is shorter:
short_arr, long_arr = (arr1, arr2) if len(arr1) < len(arr2) else (arr2, arr1)
lshort, llong = len(short_arr), len(long_arr)
And the absolutely wrong way to do it would be:
((lshort, short_arr), (llong, long_arr)) = sorted([(len(arr1), arr1), (len(arr2), arr2)])
answered 21 mins ago
AJNeufeldAJNeufeld
4,727318
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add a comment |
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
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active
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votes
$begingroup$
I can’t claim this is more elegant, but it is shorter:
short_arr, long_arr = (arr1, arr2) if len(arr1) < len(arr2) else (arr2, arr1)
lshort, llong = len(short_arr), len(long_arr)
And the absolutely wrong way to do it would be:
((lshort, short_arr), (llong, long_arr)) = sorted([(len(arr1), arr1), (len(arr2), arr2)])
answered 21 mins ago
AJNeufeldAJNeufeld
4,727318
$endgroup$
add a comment |
$begingroup$
I can’t claim this is more elegant, but it is shorter:
short_arr, long_arr = (arr1, arr2) if len(arr1) < len(arr2) else (arr2, arr1)
lshort, llong = len(short_arr), len(long_arr)
And the absolutely wrong way to do it would be:
((lshort, short_arr), (llong, long_arr)) = sorted([(len(arr1), arr1), (len(arr2), arr2)])
answered 21 mins ago
AJNeufeldAJNeufeld
4,727318
$endgroup$
add a comment |
$begingroup$
I can’t claim this is more elegant, but it is shorter:
short_arr, long_arr = (arr1, arr2) if len(arr1) < len(arr2) else (arr2, arr1)
lshort, llong = len(short_arr), len(long_arr)
And the absolutely wrong way to do it would be:
((lshort, short_arr), (llong, long_arr)) = sorted([(len(arr1), arr1), (len(arr2), arr2)])
answered 21 mins ago
AJNeufeldAJNeufeld
4,727318
$endgroup$
I can’t claim this is more elegant, but it is shorter:
short_arr, long_arr = (arr1, arr2) if len(arr1) < len(arr2) else (arr2, arr1)
lshort, llong = len(short_arr), len(long_arr)
And the absolutely wrong way to do it would be:
((lshort, short_arr), (llong, long_arr)) = sorted([(len(arr1), arr1), (len(arr2), arr2)])
answered 21 mins ago
AJNeufeldAJNeufeld
4,727318
edited 11 mins ago
answered 21 mins ago
AJNeufeldAJNeufeld
4,727318
answered 21 mins ago
AJNeufeldAJNeufeld
4,727318
answered 21 mins ago
AJNeufeldAJNeufeld
4,727318
4,727318
add a comment |
add a comment |
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