Counting number of pairs in an integer array
$begingroup$
So, I wanted to have the count for number of pairs of same integer there are in an array for which I used a HashMap
Input contains two lines:
Integer n:
Signifies the size of input
Input numbers separated by white space character:
E.g 4 6 6 7 7 8 7 6 4
For the same input,
Expected Output:
3
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class SockMerchant {
public int returnsockArr() {
Scanner sc = new Scanner(System.in);
int arraySize = sc.nextInt();
int sockArr = new int[arraySize];
for(int i = 0;i <= arraySize-1; i++) {
sockArr[i] = sc.nextInt();
}
sc.close();
return sockArr;
}
public int returnCount(Map<String, Object> mapCount) {
int count = 0;
for(String keyName : mapCount.keySet()) {
int value = (int)mapCount.get(keyName);
count = count+(value/2);
}
return count;
}
public int setMapAndReturnCount(int sockArr) {
Map<String, Object> mapCount = new HashMap<String, Object>();
for(int j = 0;j<= sockArr.length-1;j++) {
if(mapCount.containsKey(Integer.toString(sockArr[j]))) {
mapCount.put(Integer.toString(sockArr[j]), (int)mapCount.get(Integer.toString(sockArr[j]))+1);
}
else {
mapCount.put(Integer.toString(sockArr[j]), 1);
}
}
return returnCount(mapCount);
}
public static void main(String args) {
SockMerchant sm = new SockMerchant();
int sockArr = sm.returnsockArr();
int finalCount = sm.setMapAndReturnCount(sockArr);
System.out.println(finalCount);
}
}
I think that I have complicated the solution a bit too much
Is there a better approach to do the same thing?
java beginner array
$endgroup$
add a comment |
$begingroup$
So, I wanted to have the count for number of pairs of same integer there are in an array for which I used a HashMap
Input contains two lines:
Integer n:
Signifies the size of input
Input numbers separated by white space character:
E.g 4 6 6 7 7 8 7 6 4
For the same input,
Expected Output:
3
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class SockMerchant {
public int returnsockArr() {
Scanner sc = new Scanner(System.in);
int arraySize = sc.nextInt();
int sockArr = new int[arraySize];
for(int i = 0;i <= arraySize-1; i++) {
sockArr[i] = sc.nextInt();
}
sc.close();
return sockArr;
}
public int returnCount(Map<String, Object> mapCount) {
int count = 0;
for(String keyName : mapCount.keySet()) {
int value = (int)mapCount.get(keyName);
count = count+(value/2);
}
return count;
}
public int setMapAndReturnCount(int sockArr) {
Map<String, Object> mapCount = new HashMap<String, Object>();
for(int j = 0;j<= sockArr.length-1;j++) {
if(mapCount.containsKey(Integer.toString(sockArr[j]))) {
mapCount.put(Integer.toString(sockArr[j]), (int)mapCount.get(Integer.toString(sockArr[j]))+1);
}
else {
mapCount.put(Integer.toString(sockArr[j]), 1);
}
}
return returnCount(mapCount);
}
public static void main(String args) {
SockMerchant sm = new SockMerchant();
int sockArr = sm.returnsockArr();
int finalCount = sm.setMapAndReturnCount(sockArr);
System.out.println(finalCount);
}
}
I think that I have complicated the solution a bit too much
Is there a better approach to do the same thing?
java beginner array
$endgroup$
add a comment |
$begingroup$
So, I wanted to have the count for number of pairs of same integer there are in an array for which I used a HashMap
Input contains two lines:
Integer n:
Signifies the size of input
Input numbers separated by white space character:
E.g 4 6 6 7 7 8 7 6 4
For the same input,
Expected Output:
3
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class SockMerchant {
public int returnsockArr() {
Scanner sc = new Scanner(System.in);
int arraySize = sc.nextInt();
int sockArr = new int[arraySize];
for(int i = 0;i <= arraySize-1; i++) {
sockArr[i] = sc.nextInt();
}
sc.close();
return sockArr;
}
public int returnCount(Map<String, Object> mapCount) {
int count = 0;
for(String keyName : mapCount.keySet()) {
int value = (int)mapCount.get(keyName);
count = count+(value/2);
}
return count;
}
public int setMapAndReturnCount(int sockArr) {
Map<String, Object> mapCount = new HashMap<String, Object>();
for(int j = 0;j<= sockArr.length-1;j++) {
if(mapCount.containsKey(Integer.toString(sockArr[j]))) {
mapCount.put(Integer.toString(sockArr[j]), (int)mapCount.get(Integer.toString(sockArr[j]))+1);
}
else {
mapCount.put(Integer.toString(sockArr[j]), 1);
}
}
return returnCount(mapCount);
}
public static void main(String args) {
SockMerchant sm = new SockMerchant();
int sockArr = sm.returnsockArr();
int finalCount = sm.setMapAndReturnCount(sockArr);
System.out.println(finalCount);
}
}
I think that I have complicated the solution a bit too much
Is there a better approach to do the same thing?
java beginner array
$endgroup$
So, I wanted to have the count for number of pairs of same integer there are in an array for which I used a HashMap
Input contains two lines:
Integer n:
Signifies the size of input
Input numbers separated by white space character:
E.g 4 6 6 7 7 8 7 6 4
For the same input,
Expected Output:
3
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class SockMerchant {
public int returnsockArr() {
Scanner sc = new Scanner(System.in);
int arraySize = sc.nextInt();
int sockArr = new int[arraySize];
for(int i = 0;i <= arraySize-1; i++) {
sockArr[i] = sc.nextInt();
}
sc.close();
return sockArr;
}
public int returnCount(Map<String, Object> mapCount) {
int count = 0;
for(String keyName : mapCount.keySet()) {
int value = (int)mapCount.get(keyName);
count = count+(value/2);
}
return count;
}
public int setMapAndReturnCount(int sockArr) {
Map<String, Object> mapCount = new HashMap<String, Object>();
for(int j = 0;j<= sockArr.length-1;j++) {
if(mapCount.containsKey(Integer.toString(sockArr[j]))) {
mapCount.put(Integer.toString(sockArr[j]), (int)mapCount.get(Integer.toString(sockArr[j]))+1);
}
else {
mapCount.put(Integer.toString(sockArr[j]), 1);
}
}
return returnCount(mapCount);
}
public static void main(String args) {
SockMerchant sm = new SockMerchant();
int sockArr = sm.returnsockArr();
int finalCount = sm.setMapAndReturnCount(sockArr);
System.out.println(finalCount);
}
}
I think that I have complicated the solution a bit too much
Is there a better approach to do the same thing?
java beginner array
java beginner array
asked 16 hours ago
Akash SinghAkash Singh
132
132
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
There are couple of improvement possible in your code.
In this method setMapAndReturnCount
you should change the declaration of map from,
Map<String, Object> mapCount = new HashMap<String, Object>();
to
Map<Integer, Integer> mapCount = new HashMap<Integer, Integer>();
As you know, you want to store the input array numbers as key in Map and value is the count of occurence of a particular number in the array.
By using Object
class as value in Map, you are defeating one of the main purpose of having generics implementation in Java. If you use Object
then you need to uselessly cast, and otherwise don't have to.
Another point in same method, you can write your for loop in a better way like this, instead of your current code which does double work of first checking through containsKey
and then uses mapCount.get
to again pick the value of key.
public int setMapAndReturnCount(int sockArr) {
Map<Integer, Integer> mapCount = new HashMap<Integer, Integer>();
for (int j = 0; j < sockArr.length; j++) {
Integer count = mapCount.get(sockArr[j]);
if (count == null) {
mapCount.put(sockArr[j], 1);
} else {
mapCount.put(sockArr[j], count + 1);
}
}
return returnCount(mapCount);
}
Similarly, you can change returnCount
method to this,
public int returnCount(Map<Integer, Integer> mapCount) {
int count = 0;
for (Integer value : mapCount.values()) {
count += (value / 2);
}
return count;
}
As you don't need to first iterate on keySet and then retrieve the values with get
which will be slower, and instead just iterate it on values as that is what you need for calculating number of pairs, which will be relatively faster.
Also, if you are using Java-8 and above,
You can change your returnCount
to one liner like this,
public int returnCount(Map<Integer, Integer> mapCount) {
return mapCount.values().stream().mapToInt(x -> x / 2).sum();
}
$endgroup$
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
There are couple of improvement possible in your code.
In this method setMapAndReturnCount
you should change the declaration of map from,
Map<String, Object> mapCount = new HashMap<String, Object>();
to
Map<Integer, Integer> mapCount = new HashMap<Integer, Integer>();
As you know, you want to store the input array numbers as key in Map and value is the count of occurence of a particular number in the array.
By using Object
class as value in Map, you are defeating one of the main purpose of having generics implementation in Java. If you use Object
then you need to uselessly cast, and otherwise don't have to.
Another point in same method, you can write your for loop in a better way like this, instead of your current code which does double work of first checking through containsKey
and then uses mapCount.get
to again pick the value of key.
public int setMapAndReturnCount(int sockArr) {
Map<Integer, Integer> mapCount = new HashMap<Integer, Integer>();
for (int j = 0; j < sockArr.length; j++) {
Integer count = mapCount.get(sockArr[j]);
if (count == null) {
mapCount.put(sockArr[j], 1);
} else {
mapCount.put(sockArr[j], count + 1);
}
}
return returnCount(mapCount);
}
Similarly, you can change returnCount
method to this,
public int returnCount(Map<Integer, Integer> mapCount) {
int count = 0;
for (Integer value : mapCount.values()) {
count += (value / 2);
}
return count;
}
As you don't need to first iterate on keySet and then retrieve the values with get
which will be slower, and instead just iterate it on values as that is what you need for calculating number of pairs, which will be relatively faster.
Also, if you are using Java-8 and above,
You can change your returnCount
to one liner like this,
public int returnCount(Map<Integer, Integer> mapCount) {
return mapCount.values().stream().mapToInt(x -> x / 2).sum();
}
$endgroup$
add a comment |
$begingroup$
There are couple of improvement possible in your code.
In this method setMapAndReturnCount
you should change the declaration of map from,
Map<String, Object> mapCount = new HashMap<String, Object>();
to
Map<Integer, Integer> mapCount = new HashMap<Integer, Integer>();
As you know, you want to store the input array numbers as key in Map and value is the count of occurence of a particular number in the array.
By using Object
class as value in Map, you are defeating one of the main purpose of having generics implementation in Java. If you use Object
then you need to uselessly cast, and otherwise don't have to.
Another point in same method, you can write your for loop in a better way like this, instead of your current code which does double work of first checking through containsKey
and then uses mapCount.get
to again pick the value of key.
public int setMapAndReturnCount(int sockArr) {
Map<Integer, Integer> mapCount = new HashMap<Integer, Integer>();
for (int j = 0; j < sockArr.length; j++) {
Integer count = mapCount.get(sockArr[j]);
if (count == null) {
mapCount.put(sockArr[j], 1);
} else {
mapCount.put(sockArr[j], count + 1);
}
}
return returnCount(mapCount);
}
Similarly, you can change returnCount
method to this,
public int returnCount(Map<Integer, Integer> mapCount) {
int count = 0;
for (Integer value : mapCount.values()) {
count += (value / 2);
}
return count;
}
As you don't need to first iterate on keySet and then retrieve the values with get
which will be slower, and instead just iterate it on values as that is what you need for calculating number of pairs, which will be relatively faster.
Also, if you are using Java-8 and above,
You can change your returnCount
to one liner like this,
public int returnCount(Map<Integer, Integer> mapCount) {
return mapCount.values().stream().mapToInt(x -> x / 2).sum();
}
$endgroup$
add a comment |
$begingroup$
There are couple of improvement possible in your code.
In this method setMapAndReturnCount
you should change the declaration of map from,
Map<String, Object> mapCount = new HashMap<String, Object>();
to
Map<Integer, Integer> mapCount = new HashMap<Integer, Integer>();
As you know, you want to store the input array numbers as key in Map and value is the count of occurence of a particular number in the array.
By using Object
class as value in Map, you are defeating one of the main purpose of having generics implementation in Java. If you use Object
then you need to uselessly cast, and otherwise don't have to.
Another point in same method, you can write your for loop in a better way like this, instead of your current code which does double work of first checking through containsKey
and then uses mapCount.get
to again pick the value of key.
public int setMapAndReturnCount(int sockArr) {
Map<Integer, Integer> mapCount = new HashMap<Integer, Integer>();
for (int j = 0; j < sockArr.length; j++) {
Integer count = mapCount.get(sockArr[j]);
if (count == null) {
mapCount.put(sockArr[j], 1);
} else {
mapCount.put(sockArr[j], count + 1);
}
}
return returnCount(mapCount);
}
Similarly, you can change returnCount
method to this,
public int returnCount(Map<Integer, Integer> mapCount) {
int count = 0;
for (Integer value : mapCount.values()) {
count += (value / 2);
}
return count;
}
As you don't need to first iterate on keySet and then retrieve the values with get
which will be slower, and instead just iterate it on values as that is what you need for calculating number of pairs, which will be relatively faster.
Also, if you are using Java-8 and above,
You can change your returnCount
to one liner like this,
public int returnCount(Map<Integer, Integer> mapCount) {
return mapCount.values().stream().mapToInt(x -> x / 2).sum();
}
$endgroup$
There are couple of improvement possible in your code.
In this method setMapAndReturnCount
you should change the declaration of map from,
Map<String, Object> mapCount = new HashMap<String, Object>();
to
Map<Integer, Integer> mapCount = new HashMap<Integer, Integer>();
As you know, you want to store the input array numbers as key in Map and value is the count of occurence of a particular number in the array.
By using Object
class as value in Map, you are defeating one of the main purpose of having generics implementation in Java. If you use Object
then you need to uselessly cast, and otherwise don't have to.
Another point in same method, you can write your for loop in a better way like this, instead of your current code which does double work of first checking through containsKey
and then uses mapCount.get
to again pick the value of key.
public int setMapAndReturnCount(int sockArr) {
Map<Integer, Integer> mapCount = new HashMap<Integer, Integer>();
for (int j = 0; j < sockArr.length; j++) {
Integer count = mapCount.get(sockArr[j]);
if (count == null) {
mapCount.put(sockArr[j], 1);
} else {
mapCount.put(sockArr[j], count + 1);
}
}
return returnCount(mapCount);
}
Similarly, you can change returnCount
method to this,
public int returnCount(Map<Integer, Integer> mapCount) {
int count = 0;
for (Integer value : mapCount.values()) {
count += (value / 2);
}
return count;
}
As you don't need to first iterate on keySet and then retrieve the values with get
which will be slower, and instead just iterate it on values as that is what you need for calculating number of pairs, which will be relatively faster.
Also, if you are using Java-8 and above,
You can change your returnCount
to one liner like this,
public int returnCount(Map<Integer, Integer> mapCount) {
return mapCount.values().stream().mapToInt(x -> x / 2).sum();
}
edited 15 hours ago
answered 15 hours ago
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
1413
1413
add a comment |
add a comment |
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