Using QGIS field calculator with geometry operations between layers











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A curiosity question. I am looking for making a field calculation with QGIS, I see is possible to include the geometry field of the same feature layer, nevertheless I was wondering if it is possible to use the geometry from other layers features in my calculation. For example, intersection or else.










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    up vote
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    A curiosity question. I am looking for making a field calculation with QGIS, I see is possible to include the geometry field of the same feature layer, nevertheless I was wondering if it is possible to use the geometry from other layers features in my calculation. For example, intersection or else.










    share|improve this question


























      up vote
      4
      down vote

      favorite
      1









      up vote
      4
      down vote

      favorite
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      1





      A curiosity question. I am looking for making a field calculation with QGIS, I see is possible to include the geometry field of the same feature layer, nevertheless I was wondering if it is possible to use the geometry from other layers features in my calculation. For example, intersection or else.










      share|improve this question















      A curiosity question. I am looking for making a field calculation with QGIS, I see is possible to include the geometry field of the same feature layer, nevertheless I was wondering if it is possible to use the geometry from other layers features in my calculation. For example, intersection or else.







      qgis field-calculator






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      edited Dec 10 at 15:41









      Jochen Schwarze

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      asked Dec 10 at 15:21









      George

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          Should be possible, the get_feature function enables you to access features from any layer. In combination with the geometry function you may obtain the features geometry for spatial relationship analyses etc. (geometry(get_feature())). Key challenge in my opinion is a clever selection of the features depending on the processed dataset:



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            up vote
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            Should be possible, the get_feature function enables you to access features from any layer. In combination with the geometry function you may obtain the features geometry for spatial relationship analyses etc. (geometry(get_feature())). Key challenge in my opinion is a clever selection of the features depending on the processed dataset:



            enter image description here






            share|improve this answer

























              up vote
              5
              down vote













              Should be possible, the get_feature function enables you to access features from any layer. In combination with the geometry function you may obtain the features geometry for spatial relationship analyses etc. (geometry(get_feature())). Key challenge in my opinion is a clever selection of the features depending on the processed dataset:



              enter image description here






              share|improve this answer























                up vote
                5
                down vote










                up vote
                5
                down vote









                Should be possible, the get_feature function enables you to access features from any layer. In combination with the geometry function you may obtain the features geometry for spatial relationship analyses etc. (geometry(get_feature())). Key challenge in my opinion is a clever selection of the features depending on the processed dataset:



                enter image description here






                share|improve this answer












                Should be possible, the get_feature function enables you to access features from any layer. In combination with the geometry function you may obtain the features geometry for spatial relationship analyses etc. (geometry(get_feature())). Key challenge in my opinion is a clever selection of the features depending on the processed dataset:



                enter image description here







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Dec 10 at 15:40









                Jochen Schwarze

                6,19131454




                6,19131454






























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