A cipher for people who don't normally enjoy ciphers
up vote
13
down vote
favorite
I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.
So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:
I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]
However, instead of just encrypting it once, I have done so six times, using six different methods.
The output for each encryption is as follows:
The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.
The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?
Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in
Method 3
How often do you see a 3-letter word have a higher value than a 4-letter word?
Method 6
The order of the letters doesn't seem logical in isolation, but if it ever got changed, many of us would struggle to adapt!
cipher
|
show 2 more comments
up vote
13
down vote
favorite
I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.
So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:
I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]
However, instead of just encrypting it once, I have done so six times, using six different methods.
The output for each encryption is as follows:
The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.
The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?
Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in
Method 3
How often do you see a 3-letter word have a higher value than a 4-letter word?
Method 6
The order of the letters doesn't seem logical in isolation, but if it ever got changed, many of us would struggle to adapt!
cipher
Shouldn't the phrase have 4 words?
– Display name
Nov 12 at 23:09
Oops! - thanks for catching that!
– Dmihawk
Nov 12 at 23:28
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
2 days ago
I'll need to double check in the morning
– Dmihawk
2 days ago
Sorry I was wrong
– Omega Krypton
2 days ago
|
show 2 more comments
up vote
13
down vote
favorite
up vote
13
down vote
favorite
I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.
So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:
I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]
However, instead of just encrypting it once, I have done so six times, using six different methods.
The output for each encryption is as follows:
The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.
The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?
Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in
Method 3
How often do you see a 3-letter word have a higher value than a 4-letter word?
Method 6
The order of the letters doesn't seem logical in isolation, but if it ever got changed, many of us would struggle to adapt!
cipher
I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.
So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:
I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]
However, instead of just encrypting it once, I have done so six times, using six different methods.
The output for each encryption is as follows:
The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.
The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?
Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in
Method 3
How often do you see a 3-letter word have a higher value than a 4-letter word?
Method 6
The order of the letters doesn't seem logical in isolation, but if it ever got changed, many of us would struggle to adapt!
cipher
cipher
edited yesterday
asked Nov 12 at 22:29
Dmihawk
1,615423
1,615423
Shouldn't the phrase have 4 words?
– Display name
Nov 12 at 23:09
Oops! - thanks for catching that!
– Dmihawk
Nov 12 at 23:28
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
2 days ago
I'll need to double check in the morning
– Dmihawk
2 days ago
Sorry I was wrong
– Omega Krypton
2 days ago
|
show 2 more comments
Shouldn't the phrase have 4 words?
– Display name
Nov 12 at 23:09
Oops! - thanks for catching that!
– Dmihawk
Nov 12 at 23:28
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
2 days ago
I'll need to double check in the morning
– Dmihawk
2 days ago
Sorry I was wrong
– Omega Krypton
2 days ago
Shouldn't the phrase have 4 words?
– Display name
Nov 12 at 23:09
Shouldn't the phrase have 4 words?
– Display name
Nov 12 at 23:09
Oops! - thanks for catching that!
– Dmihawk
Nov 12 at 23:28
Oops! - thanks for catching that!
– Dmihawk
Nov 12 at 23:28
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
2 days ago
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
2 days ago
I'll need to double check in the morning
– Dmihawk
2 days ago
I'll need to double check in the morning
– Dmihawk
2 days ago
Sorry I was wrong
– Omega Krypton
2 days ago
Sorry I was wrong
– Omega Krypton
2 days ago
|
show 2 more comments
4 Answers
4
active
oldest
votes
up vote
8
down vote
accepted
This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!
Partial Answer:
The phrase is:
WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)
Method 1 is
Sum of Scrabble values of each letter. So much thanks to @Braegh! (approved by OP in comment)
My original guess:
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)
Method 2 is:
Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)
Method 3 is:
The sum of values of each letter according to the frequency (descending): etaoi nshrd lcumw fgypb vkjxq z, where e=1, z=26,
"WELL"=15+1+11+11=38
THANKS TO @NudgeNudge!!
Method 4 is:
the sum of values of each letter on a telephone keypad, like this:
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39 (approved by OP in comment)
Method 5 is
the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)
And method 6:
is the sum of the values for each letter according to its position on a QWERTY keyboard, like this:
PS:
I really enjoyed this puzzle. Thanks so much, @Dmihawk!
Good spotting! :)
– Dmihawk
Nov 12 at 23:41
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
2 days ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
2 days ago
Sorry, meant 5!
– Dmihawk
2 days ago
2
For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
– NudgeNudge
yesterday
|
show 3 more comments
up vote
5
down vote
Method 2 is
Sum of A1Z26 values
add a comment |
up vote
5
down vote
I believe Method 1 is
the (English) Scrabble value for each word.
Well done! Good find :)
– Dmihawk
2 days ago
Thank you so much... +1 already
– Omega Krypton
yesterday
add a comment |
up vote
4
down vote
Based on @Omega Krypton's method 5, the phrase is:
WELL DONE, NOW UPVOTE PUZZLE
I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
Nov 13 at 0:37
1
I upvoted the puzzle lah :)
– Omega Krypton
Nov 13 at 2:57
add a comment |
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
8
down vote
accepted
This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!
Partial Answer:
The phrase is:
WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)
Method 1 is
Sum of Scrabble values of each letter. So much thanks to @Braegh! (approved by OP in comment)
My original guess:
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)
Method 2 is:
Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)
Method 3 is:
The sum of values of each letter according to the frequency (descending): etaoi nshrd lcumw fgypb vkjxq z, where e=1, z=26,
"WELL"=15+1+11+11=38
THANKS TO @NudgeNudge!!
Method 4 is:
the sum of values of each letter on a telephone keypad, like this:
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39 (approved by OP in comment)
Method 5 is
the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)
And method 6:
is the sum of the values for each letter according to its position on a QWERTY keyboard, like this:
PS:
I really enjoyed this puzzle. Thanks so much, @Dmihawk!
Good spotting! :)
– Dmihawk
Nov 12 at 23:41
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
2 days ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
2 days ago
Sorry, meant 5!
– Dmihawk
2 days ago
2
For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
– NudgeNudge
yesterday
|
show 3 more comments
up vote
8
down vote
accepted
This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!
Partial Answer:
The phrase is:
WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)
Method 1 is
Sum of Scrabble values of each letter. So much thanks to @Braegh! (approved by OP in comment)
My original guess:
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)
Method 2 is:
Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)
Method 3 is:
The sum of values of each letter according to the frequency (descending): etaoi nshrd lcumw fgypb vkjxq z, where e=1, z=26,
"WELL"=15+1+11+11=38
THANKS TO @NudgeNudge!!
Method 4 is:
the sum of values of each letter on a telephone keypad, like this:
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39 (approved by OP in comment)
Method 5 is
the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)
And method 6:
is the sum of the values for each letter according to its position on a QWERTY keyboard, like this:
PS:
I really enjoyed this puzzle. Thanks so much, @Dmihawk!
Good spotting! :)
– Dmihawk
Nov 12 at 23:41
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
2 days ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
2 days ago
Sorry, meant 5!
– Dmihawk
2 days ago
2
For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
– NudgeNudge
yesterday
|
show 3 more comments
up vote
8
down vote
accepted
up vote
8
down vote
accepted
This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!
Partial Answer:
The phrase is:
WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)
Method 1 is
Sum of Scrabble values of each letter. So much thanks to @Braegh! (approved by OP in comment)
My original guess:
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)
Method 2 is:
Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)
Method 3 is:
The sum of values of each letter according to the frequency (descending): etaoi nshrd lcumw fgypb vkjxq z, where e=1, z=26,
"WELL"=15+1+11+11=38
THANKS TO @NudgeNudge!!
Method 4 is:
the sum of values of each letter on a telephone keypad, like this:
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39 (approved by OP in comment)
Method 5 is
the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)
And method 6:
is the sum of the values for each letter according to its position on a QWERTY keyboard, like this:
PS:
I really enjoyed this puzzle. Thanks so much, @Dmihawk!
This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!
Partial Answer:
The phrase is:
WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)
Method 1 is
Sum of Scrabble values of each letter. So much thanks to @Braegh! (approved by OP in comment)
My original guess:
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)
Method 2 is:
Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)
Method 3 is:
The sum of values of each letter according to the frequency (descending): etaoi nshrd lcumw fgypb vkjxq z, where e=1, z=26,
"WELL"=15+1+11+11=38
THANKS TO @NudgeNudge!!
Method 4 is:
the sum of values of each letter on a telephone keypad, like this:
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39 (approved by OP in comment)
Method 5 is
the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)
And method 6:
is the sum of the values for each letter according to its position on a QWERTY keyboard, like this:
PS:
I really enjoyed this puzzle. Thanks so much, @Dmihawk!
edited yesterday
answered Nov 12 at 23:40
Omega Krypton
1,141114
1,141114
Good spotting! :)
– Dmihawk
Nov 12 at 23:41
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
2 days ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
2 days ago
Sorry, meant 5!
– Dmihawk
2 days ago
2
For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
– NudgeNudge
yesterday
|
show 3 more comments
Good spotting! :)
– Dmihawk
Nov 12 at 23:41
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
2 days ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
2 days ago
Sorry, meant 5!
– Dmihawk
2 days ago
2
For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
– NudgeNudge
yesterday
Good spotting! :)
– Dmihawk
Nov 12 at 23:41
Good spotting! :)
– Dmihawk
Nov 12 at 23:41
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
2 days ago
Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
– Dmihawk
2 days ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
2 days ago
Method 6? @Dmihawk Thanks!
– Omega Krypton
2 days ago
Sorry, meant 5!
– Dmihawk
2 days ago
Sorry, meant 5!
– Dmihawk
2 days ago
2
2
For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
– NudgeNudge
yesterday
For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
– NudgeNudge
yesterday
|
show 3 more comments
up vote
5
down vote
Method 2 is
Sum of A1Z26 values
add a comment |
up vote
5
down vote
Method 2 is
Sum of A1Z26 values
add a comment |
up vote
5
down vote
up vote
5
down vote
Method 2 is
Sum of A1Z26 values
Method 2 is
Sum of A1Z26 values
answered 2 days ago
ImongMama
50119
50119
add a comment |
add a comment |
up vote
5
down vote
I believe Method 1 is
the (English) Scrabble value for each word.
Well done! Good find :)
– Dmihawk
2 days ago
Thank you so much... +1 already
– Omega Krypton
yesterday
add a comment |
up vote
5
down vote
I believe Method 1 is
the (English) Scrabble value for each word.
Well done! Good find :)
– Dmihawk
2 days ago
Thank you so much... +1 already
– Omega Krypton
yesterday
add a comment |
up vote
5
down vote
up vote
5
down vote
I believe Method 1 is
the (English) Scrabble value for each word.
I believe Method 1 is
the (English) Scrabble value for each word.
answered 2 days ago
Braegh
1563
1563
Well done! Good find :)
– Dmihawk
2 days ago
Thank you so much... +1 already
– Omega Krypton
yesterday
add a comment |
Well done! Good find :)
– Dmihawk
2 days ago
Thank you so much... +1 already
– Omega Krypton
yesterday
Well done! Good find :)
– Dmihawk
2 days ago
Well done! Good find :)
– Dmihawk
2 days ago
Thank you so much... +1 already
– Omega Krypton
yesterday
Thank you so much... +1 already
– Omega Krypton
yesterday
add a comment |
up vote
4
down vote
Based on @Omega Krypton's method 5, the phrase is:
WELL DONE, NOW UPVOTE PUZZLE
I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
Nov 13 at 0:37
1
I upvoted the puzzle lah :)
– Omega Krypton
Nov 13 at 2:57
add a comment |
up vote
4
down vote
Based on @Omega Krypton's method 5, the phrase is:
WELL DONE, NOW UPVOTE PUZZLE
I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
Nov 13 at 0:37
1
I upvoted the puzzle lah :)
– Omega Krypton
Nov 13 at 2:57
add a comment |
up vote
4
down vote
up vote
4
down vote
Based on @Omega Krypton's method 5, the phrase is:
WELL DONE, NOW UPVOTE PUZZLE
I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...
Based on @Omega Krypton's method 5, the phrase is:
WELL DONE, NOW UPVOTE PUZZLE
I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...
answered Nov 13 at 0:36
Dr Xorile
10.7k12259
10.7k12259
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
Nov 13 at 0:37
1
I upvoted the puzzle lah :)
– Omega Krypton
Nov 13 at 2:57
add a comment |
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
Nov 13 at 0:37
1
I upvoted the puzzle lah :)
– Omega Krypton
Nov 13 at 2:57
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
Nov 13 at 0:37
Nicely done :) now you just need to deduce the other 5 encryption methods!
– Dmihawk
Nov 13 at 0:37
1
1
I upvoted the puzzle lah :)
– Omega Krypton
Nov 13 at 2:57
I upvoted the puzzle lah :)
– Omega Krypton
Nov 13 at 2:57
add a comment |
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Shouldn't the phrase have 4 words?
– Display name
Nov 12 at 23:09
Oops! - thanks for catching that!
– Dmihawk
Nov 12 at 23:28
I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
2 days ago
I'll need to double check in the morning
– Dmihawk
2 days ago
Sorry I was wrong
– Omega Krypton
2 days ago