Simplified DES encryption












6












$begingroup$


This is one of my first Python scripts and I was wondering if it meets the correct conventions. Also are there things that you would write different? I am looking for some good comments so I can start to improve my Python code from the start. (I was not supposed to use imports here)



Here's my implementation of Simplified DES:



__author__ = 'ßaron'

FIXED_IP = [2, 6, 3, 1, 4, 8, 5, 7]
FIXED_EP = [4, 1, 2, 3, 2, 3, 4, 1]
FIXED_IP_INVERSE = [4, 1, 3, 5, 7, 2, 8, 6]
FIXED_P10 = [3, 5, 2, 7, 4, 10, 1, 9, 8, 6]
FIXED_P8 = [6, 3, 7, 4, 8, 5, 10, 9]
FIXED_P4 = [2, 4, 3, 1]

S0 = [[1, 0, 3, 2],
[3, 2, 1, 0],
[0, 2, 1, 3],
[3, 1, 3, 2]]

S1 = [[0, 1, 2, 3],
[2, 0, 1, 3],
[3, 0, 1, 0],
[2, 1, 0, 3]]

KEY = '0111111101'


def permutate(original, fixed_key):
new = ''
for i in fixed_key:
new += original[i - 1]
return new


def left_half(bits):
return bits[:len(bits)/2]


def right_half(bits):
return bits[len(bits)/2:]


def shift(bits):
rotated_left_half = left_half(bits)[1:] + left_half(bits)[0]
rotated_right_half = right_half(bits)[1:] + right_half(bits)[0]
return rotated_left_half + rotated_right_half


def key1():
return permutate(shift(permutate(KEY, FIXED_P10)), FIXED_P8)


def key2():
return permutate(shift(shift(shift(permutate(KEY, FIXED_P10)))), FIXED_P8)


def xor(bits, key):
new = ''
for bit, key_bit in zip(bits, key):
new += str(((int(bit) + int(key_bit)) % 2))
return new


def lookup_in_sbox(bits, sbox):
row = int(bits[0] + bits[3], 2)
col = int(bits[1] + bits[2], 2)
return '{0:02b}'.format(sbox[row][col])


def f_k(bits, key):
L = left_half(bits)
R = right_half(bits)
bits = permutate(R, FIXED_EP)
bits = xor(bits, key)
bits = lookup_in_sbox(left_half(bits), S0) + lookup_in_sbox(right_half(bits), S1)
bits = permutate(bits, FIXED_P4)
return xor(bits, L)


def encrypt(plain_text):
bits = permutate(plain_text, FIXED_IP)
temp = f_k(bits, key1())
bits = right_half(bits) + temp
bits = f_k(bits, key2())
print permutate(bits + temp, FIXED_IP_INVERSE)


def decrypt(cipher_text):
bits = permutate(cipher_text, FIXED_IP)
temp = f_k(bits, key2())
bits = right_half(bits) + temp
bits = f_k(bits, key1())
print permutate(bits + temp, FIXED_IP_INVERSE)


encrypt('11101010')
decrypt('10100010')









share|improve this question











$endgroup$












  • $begingroup$
    Is doing this object-oriented allowed?
    $endgroup$
    – Mast
    Oct 19 '15 at 19:24










  • $begingroup$
    Yes, it is allowed.
    $endgroup$
    – ßaron
    Oct 19 '15 at 19:25










  • $begingroup$
    What is "Simplified DES"? Is it the algorithm described here?
    $endgroup$
    – Gareth Rees
    Oct 19 '15 at 19:25










  • $begingroup$
    Hello @Gareth Rees, that is indeed the algorithm, i should have given the link..
    $endgroup$
    – ßaron
    Oct 19 '15 at 19:27








  • 1




    $begingroup$
    @ßaron It affects the speed here is the main reason I asked, the more recent you're using the less of a difference Caridorc's answer makes. Also to reply to people in comments make sure you @ them as people don't always got notified otherwise!
    $endgroup$
    – SuperBiasedMan
    Oct 20 '15 at 12:47
















6












$begingroup$


This is one of my first Python scripts and I was wondering if it meets the correct conventions. Also are there things that you would write different? I am looking for some good comments so I can start to improve my Python code from the start. (I was not supposed to use imports here)



Here's my implementation of Simplified DES:



__author__ = 'ßaron'

FIXED_IP = [2, 6, 3, 1, 4, 8, 5, 7]
FIXED_EP = [4, 1, 2, 3, 2, 3, 4, 1]
FIXED_IP_INVERSE = [4, 1, 3, 5, 7, 2, 8, 6]
FIXED_P10 = [3, 5, 2, 7, 4, 10, 1, 9, 8, 6]
FIXED_P8 = [6, 3, 7, 4, 8, 5, 10, 9]
FIXED_P4 = [2, 4, 3, 1]

S0 = [[1, 0, 3, 2],
[3, 2, 1, 0],
[0, 2, 1, 3],
[3, 1, 3, 2]]

S1 = [[0, 1, 2, 3],
[2, 0, 1, 3],
[3, 0, 1, 0],
[2, 1, 0, 3]]

KEY = '0111111101'


def permutate(original, fixed_key):
new = ''
for i in fixed_key:
new += original[i - 1]
return new


def left_half(bits):
return bits[:len(bits)/2]


def right_half(bits):
return bits[len(bits)/2:]


def shift(bits):
rotated_left_half = left_half(bits)[1:] + left_half(bits)[0]
rotated_right_half = right_half(bits)[1:] + right_half(bits)[0]
return rotated_left_half + rotated_right_half


def key1():
return permutate(shift(permutate(KEY, FIXED_P10)), FIXED_P8)


def key2():
return permutate(shift(shift(shift(permutate(KEY, FIXED_P10)))), FIXED_P8)


def xor(bits, key):
new = ''
for bit, key_bit in zip(bits, key):
new += str(((int(bit) + int(key_bit)) % 2))
return new


def lookup_in_sbox(bits, sbox):
row = int(bits[0] + bits[3], 2)
col = int(bits[1] + bits[2], 2)
return '{0:02b}'.format(sbox[row][col])


def f_k(bits, key):
L = left_half(bits)
R = right_half(bits)
bits = permutate(R, FIXED_EP)
bits = xor(bits, key)
bits = lookup_in_sbox(left_half(bits), S0) + lookup_in_sbox(right_half(bits), S1)
bits = permutate(bits, FIXED_P4)
return xor(bits, L)


def encrypt(plain_text):
bits = permutate(plain_text, FIXED_IP)
temp = f_k(bits, key1())
bits = right_half(bits) + temp
bits = f_k(bits, key2())
print permutate(bits + temp, FIXED_IP_INVERSE)


def decrypt(cipher_text):
bits = permutate(cipher_text, FIXED_IP)
temp = f_k(bits, key2())
bits = right_half(bits) + temp
bits = f_k(bits, key1())
print permutate(bits + temp, FIXED_IP_INVERSE)


encrypt('11101010')
decrypt('10100010')









share|improve this question











$endgroup$












  • $begingroup$
    Is doing this object-oriented allowed?
    $endgroup$
    – Mast
    Oct 19 '15 at 19:24










  • $begingroup$
    Yes, it is allowed.
    $endgroup$
    – ßaron
    Oct 19 '15 at 19:25










  • $begingroup$
    What is "Simplified DES"? Is it the algorithm described here?
    $endgroup$
    – Gareth Rees
    Oct 19 '15 at 19:25










  • $begingroup$
    Hello @Gareth Rees, that is indeed the algorithm, i should have given the link..
    $endgroup$
    – ßaron
    Oct 19 '15 at 19:27








  • 1




    $begingroup$
    @ßaron It affects the speed here is the main reason I asked, the more recent you're using the less of a difference Caridorc's answer makes. Also to reply to people in comments make sure you @ them as people don't always got notified otherwise!
    $endgroup$
    – SuperBiasedMan
    Oct 20 '15 at 12:47














6












6








6


1



$begingroup$


This is one of my first Python scripts and I was wondering if it meets the correct conventions. Also are there things that you would write different? I am looking for some good comments so I can start to improve my Python code from the start. (I was not supposed to use imports here)



Here's my implementation of Simplified DES:



__author__ = 'ßaron'

FIXED_IP = [2, 6, 3, 1, 4, 8, 5, 7]
FIXED_EP = [4, 1, 2, 3, 2, 3, 4, 1]
FIXED_IP_INVERSE = [4, 1, 3, 5, 7, 2, 8, 6]
FIXED_P10 = [3, 5, 2, 7, 4, 10, 1, 9, 8, 6]
FIXED_P8 = [6, 3, 7, 4, 8, 5, 10, 9]
FIXED_P4 = [2, 4, 3, 1]

S0 = [[1, 0, 3, 2],
[3, 2, 1, 0],
[0, 2, 1, 3],
[3, 1, 3, 2]]

S1 = [[0, 1, 2, 3],
[2, 0, 1, 3],
[3, 0, 1, 0],
[2, 1, 0, 3]]

KEY = '0111111101'


def permutate(original, fixed_key):
new = ''
for i in fixed_key:
new += original[i - 1]
return new


def left_half(bits):
return bits[:len(bits)/2]


def right_half(bits):
return bits[len(bits)/2:]


def shift(bits):
rotated_left_half = left_half(bits)[1:] + left_half(bits)[0]
rotated_right_half = right_half(bits)[1:] + right_half(bits)[0]
return rotated_left_half + rotated_right_half


def key1():
return permutate(shift(permutate(KEY, FIXED_P10)), FIXED_P8)


def key2():
return permutate(shift(shift(shift(permutate(KEY, FIXED_P10)))), FIXED_P8)


def xor(bits, key):
new = ''
for bit, key_bit in zip(bits, key):
new += str(((int(bit) + int(key_bit)) % 2))
return new


def lookup_in_sbox(bits, sbox):
row = int(bits[0] + bits[3], 2)
col = int(bits[1] + bits[2], 2)
return '{0:02b}'.format(sbox[row][col])


def f_k(bits, key):
L = left_half(bits)
R = right_half(bits)
bits = permutate(R, FIXED_EP)
bits = xor(bits, key)
bits = lookup_in_sbox(left_half(bits), S0) + lookup_in_sbox(right_half(bits), S1)
bits = permutate(bits, FIXED_P4)
return xor(bits, L)


def encrypt(plain_text):
bits = permutate(plain_text, FIXED_IP)
temp = f_k(bits, key1())
bits = right_half(bits) + temp
bits = f_k(bits, key2())
print permutate(bits + temp, FIXED_IP_INVERSE)


def decrypt(cipher_text):
bits = permutate(cipher_text, FIXED_IP)
temp = f_k(bits, key2())
bits = right_half(bits) + temp
bits = f_k(bits, key1())
print permutate(bits + temp, FIXED_IP_INVERSE)


encrypt('11101010')
decrypt('10100010')









share|improve this question











$endgroup$




This is one of my first Python scripts and I was wondering if it meets the correct conventions. Also are there things that you would write different? I am looking for some good comments so I can start to improve my Python code from the start. (I was not supposed to use imports here)



Here's my implementation of Simplified DES:



__author__ = 'ßaron'

FIXED_IP = [2, 6, 3, 1, 4, 8, 5, 7]
FIXED_EP = [4, 1, 2, 3, 2, 3, 4, 1]
FIXED_IP_INVERSE = [4, 1, 3, 5, 7, 2, 8, 6]
FIXED_P10 = [3, 5, 2, 7, 4, 10, 1, 9, 8, 6]
FIXED_P8 = [6, 3, 7, 4, 8, 5, 10, 9]
FIXED_P4 = [2, 4, 3, 1]

S0 = [[1, 0, 3, 2],
[3, 2, 1, 0],
[0, 2, 1, 3],
[3, 1, 3, 2]]

S1 = [[0, 1, 2, 3],
[2, 0, 1, 3],
[3, 0, 1, 0],
[2, 1, 0, 3]]

KEY = '0111111101'


def permutate(original, fixed_key):
new = ''
for i in fixed_key:
new += original[i - 1]
return new


def left_half(bits):
return bits[:len(bits)/2]


def right_half(bits):
return bits[len(bits)/2:]


def shift(bits):
rotated_left_half = left_half(bits)[1:] + left_half(bits)[0]
rotated_right_half = right_half(bits)[1:] + right_half(bits)[0]
return rotated_left_half + rotated_right_half


def key1():
return permutate(shift(permutate(KEY, FIXED_P10)), FIXED_P8)


def key2():
return permutate(shift(shift(shift(permutate(KEY, FIXED_P10)))), FIXED_P8)


def xor(bits, key):
new = ''
for bit, key_bit in zip(bits, key):
new += str(((int(bit) + int(key_bit)) % 2))
return new


def lookup_in_sbox(bits, sbox):
row = int(bits[0] + bits[3], 2)
col = int(bits[1] + bits[2], 2)
return '{0:02b}'.format(sbox[row][col])


def f_k(bits, key):
L = left_half(bits)
R = right_half(bits)
bits = permutate(R, FIXED_EP)
bits = xor(bits, key)
bits = lookup_in_sbox(left_half(bits), S0) + lookup_in_sbox(right_half(bits), S1)
bits = permutate(bits, FIXED_P4)
return xor(bits, L)


def encrypt(plain_text):
bits = permutate(plain_text, FIXED_IP)
temp = f_k(bits, key1())
bits = right_half(bits) + temp
bits = f_k(bits, key2())
print permutate(bits + temp, FIXED_IP_INVERSE)


def decrypt(cipher_text):
bits = permutate(cipher_text, FIXED_IP)
temp = f_k(bits, key2())
bits = right_half(bits) + temp
bits = f_k(bits, key1())
print permutate(bits + temp, FIXED_IP_INVERSE)


encrypt('11101010')
decrypt('10100010')






python beginner reinventing-the-wheel cryptography






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Oct 20 '15 at 5:56







ßaron

















asked Oct 19 '15 at 19:15









ßaronßaron

4516




4516












  • $begingroup$
    Is doing this object-oriented allowed?
    $endgroup$
    – Mast
    Oct 19 '15 at 19:24










  • $begingroup$
    Yes, it is allowed.
    $endgroup$
    – ßaron
    Oct 19 '15 at 19:25










  • $begingroup$
    What is "Simplified DES"? Is it the algorithm described here?
    $endgroup$
    – Gareth Rees
    Oct 19 '15 at 19:25










  • $begingroup$
    Hello @Gareth Rees, that is indeed the algorithm, i should have given the link..
    $endgroup$
    – ßaron
    Oct 19 '15 at 19:27








  • 1




    $begingroup$
    @ßaron It affects the speed here is the main reason I asked, the more recent you're using the less of a difference Caridorc's answer makes. Also to reply to people in comments make sure you @ them as people don't always got notified otherwise!
    $endgroup$
    – SuperBiasedMan
    Oct 20 '15 at 12:47


















  • $begingroup$
    Is doing this object-oriented allowed?
    $endgroup$
    – Mast
    Oct 19 '15 at 19:24










  • $begingroup$
    Yes, it is allowed.
    $endgroup$
    – ßaron
    Oct 19 '15 at 19:25










  • $begingroup$
    What is "Simplified DES"? Is it the algorithm described here?
    $endgroup$
    – Gareth Rees
    Oct 19 '15 at 19:25










  • $begingroup$
    Hello @Gareth Rees, that is indeed the algorithm, i should have given the link..
    $endgroup$
    – ßaron
    Oct 19 '15 at 19:27








  • 1




    $begingroup$
    @ßaron It affects the speed here is the main reason I asked, the more recent you're using the less of a difference Caridorc's answer makes. Also to reply to people in comments make sure you @ them as people don't always got notified otherwise!
    $endgroup$
    – SuperBiasedMan
    Oct 20 '15 at 12:47
















$begingroup$
Is doing this object-oriented allowed?
$endgroup$
– Mast
Oct 19 '15 at 19:24




$begingroup$
Is doing this object-oriented allowed?
$endgroup$
– Mast
Oct 19 '15 at 19:24












$begingroup$
Yes, it is allowed.
$endgroup$
– ßaron
Oct 19 '15 at 19:25




$begingroup$
Yes, it is allowed.
$endgroup$
– ßaron
Oct 19 '15 at 19:25












$begingroup$
What is "Simplified DES"? Is it the algorithm described here?
$endgroup$
– Gareth Rees
Oct 19 '15 at 19:25




$begingroup$
What is "Simplified DES"? Is it the algorithm described here?
$endgroup$
– Gareth Rees
Oct 19 '15 at 19:25












$begingroup$
Hello @Gareth Rees, that is indeed the algorithm, i should have given the link..
$endgroup$
– ßaron
Oct 19 '15 at 19:27






$begingroup$
Hello @Gareth Rees, that is indeed the algorithm, i should have given the link..
$endgroup$
– ßaron
Oct 19 '15 at 19:27






1




1




$begingroup$
@ßaron It affects the speed here is the main reason I asked, the more recent you're using the less of a difference Caridorc's answer makes. Also to reply to people in comments make sure you @ them as people don't always got notified otherwise!
$endgroup$
– SuperBiasedMan
Oct 20 '15 at 12:47




$begingroup$
@ßaron It affects the speed here is the main reason I asked, the more recent you're using the less of a difference Caridorc's answer makes. Also to reply to people in comments make sure you @ them as people don't always got notified otherwise!
$endgroup$
– SuperBiasedMan
Oct 20 '15 at 12:47










3 Answers
3






active

oldest

votes


















2












$begingroup$

If you're using constants that are collections you'd be better off making them tuples, not lists. Trying to modify a tuple will raise an error as they're immutable, and using the tuple syntax makes it extra clear that these are unchanging constants.



FIXED_IP = (2, 6, 3, 1, 4, 8, 5, 7)
FIXED_EP = (4, 1, 2, 3, 2, 3, 4, 1)


As Caridorc said, using str.join is faster (depending on your version). It would also allow you to make permutate just one line.



def permutate(original, fixed_key):
return ''.join(original[i - 1] for i in fixed_key)


It would also be a bit faster to pre-convert all your values in bits and key to integers. You can use map to apply a function to every member of a list, and it's faster than doing it in a list. You could do this when creating the zip object.



def xor(bits, key):
new = ''
for bit, key_bit in zip(map(int, bits), map(int, key)):
new += str(((bit + key_bit) % 2))
return new


Of course if you wanted this could also be made into a str.join, albeit a long one:



def xor(bits, key):
return ''.join(str(((bit + key_bit) % 2)) for bit, key_bit in
zip(map(int, bits), map(int, key)))


There's a lot of functions here but not a lot of documentation. Explaining what individual functions do would make your code a lot easier to read. And I suspect you have some unnecessary duplicate functions, where you could pass a parameter instead of defining a whole new one. But it's hard to know when I don't entirely understand the functions you have here.






share|improve this answer









$endgroup$





















    1












    $begingroup$

    It is well written overall, but remember that string += thing is very slow when used in loops and you should join a generator expression for efficiency.






    share|improve this answer









    $endgroup$













    • $begingroup$
      In modern versions of CPython repeated string concatenation is usually only a little slower than join, so this is now only a worry if you want to be portable to other versions of Python like PyPy.
      $endgroup$
      – Gareth Rees
      Oct 19 '15 at 21:09










    • $begingroup$
      @GarethRees just tested, in my Cython 3.4 joining is actually slower (by 20%) but in pypy += is so slow as to be totally unusable (more than 100x the time of join and still running)
      $endgroup$
      – Caridorc
      Oct 19 '15 at 21:31










    • $begingroup$
      That's right, so I think that when you give the advice not to use string concatenation you should mention that the advice might not make any difference in CPython, but is still a good idea if you are concerned about portability.
      $endgroup$
      – Gareth Rees
      Oct 20 '15 at 11:31



















    0












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    Dhaval Tandale - Cognizant 3.38





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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2












      $begingroup$

      If you're using constants that are collections you'd be better off making them tuples, not lists. Trying to modify a tuple will raise an error as they're immutable, and using the tuple syntax makes it extra clear that these are unchanging constants.



      FIXED_IP = (2, 6, 3, 1, 4, 8, 5, 7)
      FIXED_EP = (4, 1, 2, 3, 2, 3, 4, 1)


      As Caridorc said, using str.join is faster (depending on your version). It would also allow you to make permutate just one line.



      def permutate(original, fixed_key):
      return ''.join(original[i - 1] for i in fixed_key)


      It would also be a bit faster to pre-convert all your values in bits and key to integers. You can use map to apply a function to every member of a list, and it's faster than doing it in a list. You could do this when creating the zip object.



      def xor(bits, key):
      new = ''
      for bit, key_bit in zip(map(int, bits), map(int, key)):
      new += str(((bit + key_bit) % 2))
      return new


      Of course if you wanted this could also be made into a str.join, albeit a long one:



      def xor(bits, key):
      return ''.join(str(((bit + key_bit) % 2)) for bit, key_bit in
      zip(map(int, bits), map(int, key)))


      There's a lot of functions here but not a lot of documentation. Explaining what individual functions do would make your code a lot easier to read. And I suspect you have some unnecessary duplicate functions, where you could pass a parameter instead of defining a whole new one. But it's hard to know when I don't entirely understand the functions you have here.






      share|improve this answer









      $endgroup$


















        2












        $begingroup$

        If you're using constants that are collections you'd be better off making them tuples, not lists. Trying to modify a tuple will raise an error as they're immutable, and using the tuple syntax makes it extra clear that these are unchanging constants.



        FIXED_IP = (2, 6, 3, 1, 4, 8, 5, 7)
        FIXED_EP = (4, 1, 2, 3, 2, 3, 4, 1)


        As Caridorc said, using str.join is faster (depending on your version). It would also allow you to make permutate just one line.



        def permutate(original, fixed_key):
        return ''.join(original[i - 1] for i in fixed_key)


        It would also be a bit faster to pre-convert all your values in bits and key to integers. You can use map to apply a function to every member of a list, and it's faster than doing it in a list. You could do this when creating the zip object.



        def xor(bits, key):
        new = ''
        for bit, key_bit in zip(map(int, bits), map(int, key)):
        new += str(((bit + key_bit) % 2))
        return new


        Of course if you wanted this could also be made into a str.join, albeit a long one:



        def xor(bits, key):
        return ''.join(str(((bit + key_bit) % 2)) for bit, key_bit in
        zip(map(int, bits), map(int, key)))


        There's a lot of functions here but not a lot of documentation. Explaining what individual functions do would make your code a lot easier to read. And I suspect you have some unnecessary duplicate functions, where you could pass a parameter instead of defining a whole new one. But it's hard to know when I don't entirely understand the functions you have here.






        share|improve this answer









        $endgroup$
















          2












          2








          2





          $begingroup$

          If you're using constants that are collections you'd be better off making them tuples, not lists. Trying to modify a tuple will raise an error as they're immutable, and using the tuple syntax makes it extra clear that these are unchanging constants.



          FIXED_IP = (2, 6, 3, 1, 4, 8, 5, 7)
          FIXED_EP = (4, 1, 2, 3, 2, 3, 4, 1)


          As Caridorc said, using str.join is faster (depending on your version). It would also allow you to make permutate just one line.



          def permutate(original, fixed_key):
          return ''.join(original[i - 1] for i in fixed_key)


          It would also be a bit faster to pre-convert all your values in bits and key to integers. You can use map to apply a function to every member of a list, and it's faster than doing it in a list. You could do this when creating the zip object.



          def xor(bits, key):
          new = ''
          for bit, key_bit in zip(map(int, bits), map(int, key)):
          new += str(((bit + key_bit) % 2))
          return new


          Of course if you wanted this could also be made into a str.join, albeit a long one:



          def xor(bits, key):
          return ''.join(str(((bit + key_bit) % 2)) for bit, key_bit in
          zip(map(int, bits), map(int, key)))


          There's a lot of functions here but not a lot of documentation. Explaining what individual functions do would make your code a lot easier to read. And I suspect you have some unnecessary duplicate functions, where you could pass a parameter instead of defining a whole new one. But it's hard to know when I don't entirely understand the functions you have here.






          share|improve this answer









          $endgroup$



          If you're using constants that are collections you'd be better off making them tuples, not lists. Trying to modify a tuple will raise an error as they're immutable, and using the tuple syntax makes it extra clear that these are unchanging constants.



          FIXED_IP = (2, 6, 3, 1, 4, 8, 5, 7)
          FIXED_EP = (4, 1, 2, 3, 2, 3, 4, 1)


          As Caridorc said, using str.join is faster (depending on your version). It would also allow you to make permutate just one line.



          def permutate(original, fixed_key):
          return ''.join(original[i - 1] for i in fixed_key)


          It would also be a bit faster to pre-convert all your values in bits and key to integers. You can use map to apply a function to every member of a list, and it's faster than doing it in a list. You could do this when creating the zip object.



          def xor(bits, key):
          new = ''
          for bit, key_bit in zip(map(int, bits), map(int, key)):
          new += str(((bit + key_bit) % 2))
          return new


          Of course if you wanted this could also be made into a str.join, albeit a long one:



          def xor(bits, key):
          return ''.join(str(((bit + key_bit) % 2)) for bit, key_bit in
          zip(map(int, bits), map(int, key)))


          There's a lot of functions here but not a lot of documentation. Explaining what individual functions do would make your code a lot easier to read. And I suspect you have some unnecessary duplicate functions, where you could pass a parameter instead of defining a whole new one. But it's hard to know when I don't entirely understand the functions you have here.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Oct 20 '15 at 10:47









          SuperBiasedManSuperBiasedMan

          11.8k52660




          11.8k52660

























              1












              $begingroup$

              It is well written overall, but remember that string += thing is very slow when used in loops and you should join a generator expression for efficiency.






              share|improve this answer









              $endgroup$













              • $begingroup$
                In modern versions of CPython repeated string concatenation is usually only a little slower than join, so this is now only a worry if you want to be portable to other versions of Python like PyPy.
                $endgroup$
                – Gareth Rees
                Oct 19 '15 at 21:09










              • $begingroup$
                @GarethRees just tested, in my Cython 3.4 joining is actually slower (by 20%) but in pypy += is so slow as to be totally unusable (more than 100x the time of join and still running)
                $endgroup$
                – Caridorc
                Oct 19 '15 at 21:31










              • $begingroup$
                That's right, so I think that when you give the advice not to use string concatenation you should mention that the advice might not make any difference in CPython, but is still a good idea if you are concerned about portability.
                $endgroup$
                – Gareth Rees
                Oct 20 '15 at 11:31
















              1












              $begingroup$

              It is well written overall, but remember that string += thing is very slow when used in loops and you should join a generator expression for efficiency.






              share|improve this answer









              $endgroup$













              • $begingroup$
                In modern versions of CPython repeated string concatenation is usually only a little slower than join, so this is now only a worry if you want to be portable to other versions of Python like PyPy.
                $endgroup$
                – Gareth Rees
                Oct 19 '15 at 21:09










              • $begingroup$
                @GarethRees just tested, in my Cython 3.4 joining is actually slower (by 20%) but in pypy += is so slow as to be totally unusable (more than 100x the time of join and still running)
                $endgroup$
                – Caridorc
                Oct 19 '15 at 21:31










              • $begingroup$
                That's right, so I think that when you give the advice not to use string concatenation you should mention that the advice might not make any difference in CPython, but is still a good idea if you are concerned about portability.
                $endgroup$
                – Gareth Rees
                Oct 20 '15 at 11:31














              1












              1








              1





              $begingroup$

              It is well written overall, but remember that string += thing is very slow when used in loops and you should join a generator expression for efficiency.






              share|improve this answer









              $endgroup$



              It is well written overall, but remember that string += thing is very slow when used in loops and you should join a generator expression for efficiency.







              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Oct 19 '15 at 20:33









              CaridorcCaridorc

              23k538116




              23k538116












              • $begingroup$
                In modern versions of CPython repeated string concatenation is usually only a little slower than join, so this is now only a worry if you want to be portable to other versions of Python like PyPy.
                $endgroup$
                – Gareth Rees
                Oct 19 '15 at 21:09










              • $begingroup$
                @GarethRees just tested, in my Cython 3.4 joining is actually slower (by 20%) but in pypy += is so slow as to be totally unusable (more than 100x the time of join and still running)
                $endgroup$
                – Caridorc
                Oct 19 '15 at 21:31










              • $begingroup$
                That's right, so I think that when you give the advice not to use string concatenation you should mention that the advice might not make any difference in CPython, but is still a good idea if you are concerned about portability.
                $endgroup$
                – Gareth Rees
                Oct 20 '15 at 11:31


















              • $begingroup$
                In modern versions of CPython repeated string concatenation is usually only a little slower than join, so this is now only a worry if you want to be portable to other versions of Python like PyPy.
                $endgroup$
                – Gareth Rees
                Oct 19 '15 at 21:09










              • $begingroup$
                @GarethRees just tested, in my Cython 3.4 joining is actually slower (by 20%) but in pypy += is so slow as to be totally unusable (more than 100x the time of join and still running)
                $endgroup$
                – Caridorc
                Oct 19 '15 at 21:31










              • $begingroup$
                That's right, so I think that when you give the advice not to use string concatenation you should mention that the advice might not make any difference in CPython, but is still a good idea if you are concerned about portability.
                $endgroup$
                – Gareth Rees
                Oct 20 '15 at 11:31
















              $begingroup$
              In modern versions of CPython repeated string concatenation is usually only a little slower than join, so this is now only a worry if you want to be portable to other versions of Python like PyPy.
              $endgroup$
              – Gareth Rees
              Oct 19 '15 at 21:09




              $begingroup$
              In modern versions of CPython repeated string concatenation is usually only a little slower than join, so this is now only a worry if you want to be portable to other versions of Python like PyPy.
              $endgroup$
              – Gareth Rees
              Oct 19 '15 at 21:09












              $begingroup$
              @GarethRees just tested, in my Cython 3.4 joining is actually slower (by 20%) but in pypy += is so slow as to be totally unusable (more than 100x the time of join and still running)
              $endgroup$
              – Caridorc
              Oct 19 '15 at 21:31




              $begingroup$
              @GarethRees just tested, in my Cython 3.4 joining is actually slower (by 20%) but in pypy += is so slow as to be totally unusable (more than 100x the time of join and still running)
              $endgroup$
              – Caridorc
              Oct 19 '15 at 21:31












              $begingroup$
              That's right, so I think that when you give the advice not to use string concatenation you should mention that the advice might not make any difference in CPython, but is still a good idea if you are concerned about portability.
              $endgroup$
              – Gareth Rees
              Oct 20 '15 at 11:31




              $begingroup$
              That's right, so I think that when you give the advice not to use string concatenation you should mention that the advice might not make any difference in CPython, but is still a good idea if you are concerned about portability.
              $endgroup$
              – Gareth Rees
              Oct 20 '15 at 11:31











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              Dhaval Tandale - Cognizant 3.38





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                Dhaval Tandale - Cognizant 3.38





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                  Dhaval Tandale - Cognizant 3.38





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                  Dhaval Tandale - Cognizant 3.38






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                  answered 5 mins ago









                  dhavaldhaval

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