Coordinate ring of a scheme in functorial algebraic geometry












4












$begingroup$


I will preface this by saying that I am new to algebraic geometry, but I am somewhat experienced with category theory.



I'm just reading the introduction to Milne's notes "Basic Theory of Affine Group Schemes". He uses the functorial point of view here, so I am viewing an affine scheme over $K$ as a representable functor $X: Kmathsf{Alg} to mathsf{Sets}$, and a scheme is likewise defined as a functor satisfying appropriate gluing properties. We can think of some general functor as a generalized scheme.



In section I.3 he has a subsection titled "The canonical coordinate ring of an affine group" but I noticed that his construction seems to define a canonical "coordinate ring" for every sort of "generalized scheme", not just affine group schemes. Indeed, if $X: Kmathsf{Alg} to mathsf{Sets}$ is a functor then $mathrm{Nat}(X, mathbb{A}^1_K)$ is a $K$-algebra (with operations defined pointwise), since the affine line over $K$ is the forgetful functor $mathbb{A}^1_K: Kmathsf{Alg} to mathsf{Sets}$.



So we have a functor $mathsf{Sets}^{Kmathsf{Alg}} to Kmathsf{Alg}$ defined by $X mapsto mathrm{Nat}(X, mathbb{A}^1_K)$.



Moreover, we have an obvious natural transformation $alpha: X to mathrm{Spec_K}(mathrm{Nat}(X, mathbb{A}^1_K))$,
where $mathrm{Spec}_K$ here is just the contravariant Yoneda embedding (since I am thinking of affine schemes as functors rather than ringed spaces). This natural transformation has components $alpha_A: X(A) to mathrm{Hom}(mathrm{Nat}(X, mathbb{A}^1_K), A)$ given by $x mapsto (f mapsto f_A(x))$.



My question is:





  1. Is it reasonable to call $mathrm{Nat}(X, mathbb{A}^1_K), A)$ the coordinate ring for any "generalize scheme" given by a functor $X: Kmathsf{Alg} to mathsf{Sets}$? If not, what should we call this?


  2. Is the functor $mathsf{Sets}^{Kmathsf{Alg}} to Kmathsf{Alg}$ mapping $X$ to $mathrm{Nat}(X, mathbb{A}^1_K)$ adjoint (on the left or right) to $mathrm{Spec}_K: Kmathsf{Alg}^{mathrm{opp}} to mathsf{Sets}^{Kmathsf{Alg}}$? My guess is that it is the left adjoint to $mathrm{Spec}_K$.


  3. Is there a name and interpretation for this natural transformation $alpha_A: X(A) to mathrm{Hom}(mathrm{Nat}(X, mathbb{A}^1_K), A)$? I can see that $X$ is an affine scheme over $K$ if and only if this is an isomorphism. But what if $X$ is not affine? How do we interpret this?












share|cite|improve this question











$endgroup$

















    4












    $begingroup$


    I will preface this by saying that I am new to algebraic geometry, but I am somewhat experienced with category theory.



    I'm just reading the introduction to Milne's notes "Basic Theory of Affine Group Schemes". He uses the functorial point of view here, so I am viewing an affine scheme over $K$ as a representable functor $X: Kmathsf{Alg} to mathsf{Sets}$, and a scheme is likewise defined as a functor satisfying appropriate gluing properties. We can think of some general functor as a generalized scheme.



    In section I.3 he has a subsection titled "The canonical coordinate ring of an affine group" but I noticed that his construction seems to define a canonical "coordinate ring" for every sort of "generalized scheme", not just affine group schemes. Indeed, if $X: Kmathsf{Alg} to mathsf{Sets}$ is a functor then $mathrm{Nat}(X, mathbb{A}^1_K)$ is a $K$-algebra (with operations defined pointwise), since the affine line over $K$ is the forgetful functor $mathbb{A}^1_K: Kmathsf{Alg} to mathsf{Sets}$.



    So we have a functor $mathsf{Sets}^{Kmathsf{Alg}} to Kmathsf{Alg}$ defined by $X mapsto mathrm{Nat}(X, mathbb{A}^1_K)$.



    Moreover, we have an obvious natural transformation $alpha: X to mathrm{Spec_K}(mathrm{Nat}(X, mathbb{A}^1_K))$,
    where $mathrm{Spec}_K$ here is just the contravariant Yoneda embedding (since I am thinking of affine schemes as functors rather than ringed spaces). This natural transformation has components $alpha_A: X(A) to mathrm{Hom}(mathrm{Nat}(X, mathbb{A}^1_K), A)$ given by $x mapsto (f mapsto f_A(x))$.



    My question is:





    1. Is it reasonable to call $mathrm{Nat}(X, mathbb{A}^1_K), A)$ the coordinate ring for any "generalize scheme" given by a functor $X: Kmathsf{Alg} to mathsf{Sets}$? If not, what should we call this?


    2. Is the functor $mathsf{Sets}^{Kmathsf{Alg}} to Kmathsf{Alg}$ mapping $X$ to $mathrm{Nat}(X, mathbb{A}^1_K)$ adjoint (on the left or right) to $mathrm{Spec}_K: Kmathsf{Alg}^{mathrm{opp}} to mathsf{Sets}^{Kmathsf{Alg}}$? My guess is that it is the left adjoint to $mathrm{Spec}_K$.


    3. Is there a name and interpretation for this natural transformation $alpha_A: X(A) to mathrm{Hom}(mathrm{Nat}(X, mathbb{A}^1_K), A)$? I can see that $X$ is an affine scheme over $K$ if and only if this is an isomorphism. But what if $X$ is not affine? How do we interpret this?












    share|cite|improve this question











    $endgroup$















      4












      4








      4


      1



      $begingroup$


      I will preface this by saying that I am new to algebraic geometry, but I am somewhat experienced with category theory.



      I'm just reading the introduction to Milne's notes "Basic Theory of Affine Group Schemes". He uses the functorial point of view here, so I am viewing an affine scheme over $K$ as a representable functor $X: Kmathsf{Alg} to mathsf{Sets}$, and a scheme is likewise defined as a functor satisfying appropriate gluing properties. We can think of some general functor as a generalized scheme.



      In section I.3 he has a subsection titled "The canonical coordinate ring of an affine group" but I noticed that his construction seems to define a canonical "coordinate ring" for every sort of "generalized scheme", not just affine group schemes. Indeed, if $X: Kmathsf{Alg} to mathsf{Sets}$ is a functor then $mathrm{Nat}(X, mathbb{A}^1_K)$ is a $K$-algebra (with operations defined pointwise), since the affine line over $K$ is the forgetful functor $mathbb{A}^1_K: Kmathsf{Alg} to mathsf{Sets}$.



      So we have a functor $mathsf{Sets}^{Kmathsf{Alg}} to Kmathsf{Alg}$ defined by $X mapsto mathrm{Nat}(X, mathbb{A}^1_K)$.



      Moreover, we have an obvious natural transformation $alpha: X to mathrm{Spec_K}(mathrm{Nat}(X, mathbb{A}^1_K))$,
      where $mathrm{Spec}_K$ here is just the contravariant Yoneda embedding (since I am thinking of affine schemes as functors rather than ringed spaces). This natural transformation has components $alpha_A: X(A) to mathrm{Hom}(mathrm{Nat}(X, mathbb{A}^1_K), A)$ given by $x mapsto (f mapsto f_A(x))$.



      My question is:





      1. Is it reasonable to call $mathrm{Nat}(X, mathbb{A}^1_K), A)$ the coordinate ring for any "generalize scheme" given by a functor $X: Kmathsf{Alg} to mathsf{Sets}$? If not, what should we call this?


      2. Is the functor $mathsf{Sets}^{Kmathsf{Alg}} to Kmathsf{Alg}$ mapping $X$ to $mathrm{Nat}(X, mathbb{A}^1_K)$ adjoint (on the left or right) to $mathrm{Spec}_K: Kmathsf{Alg}^{mathrm{opp}} to mathsf{Sets}^{Kmathsf{Alg}}$? My guess is that it is the left adjoint to $mathrm{Spec}_K$.


      3. Is there a name and interpretation for this natural transformation $alpha_A: X(A) to mathrm{Hom}(mathrm{Nat}(X, mathbb{A}^1_K), A)$? I can see that $X$ is an affine scheme over $K$ if and only if this is an isomorphism. But what if $X$ is not affine? How do we interpret this?












      share|cite|improve this question











      $endgroup$




      I will preface this by saying that I am new to algebraic geometry, but I am somewhat experienced with category theory.



      I'm just reading the introduction to Milne's notes "Basic Theory of Affine Group Schemes". He uses the functorial point of view here, so I am viewing an affine scheme over $K$ as a representable functor $X: Kmathsf{Alg} to mathsf{Sets}$, and a scheme is likewise defined as a functor satisfying appropriate gluing properties. We can think of some general functor as a generalized scheme.



      In section I.3 he has a subsection titled "The canonical coordinate ring of an affine group" but I noticed that his construction seems to define a canonical "coordinate ring" for every sort of "generalized scheme", not just affine group schemes. Indeed, if $X: Kmathsf{Alg} to mathsf{Sets}$ is a functor then $mathrm{Nat}(X, mathbb{A}^1_K)$ is a $K$-algebra (with operations defined pointwise), since the affine line over $K$ is the forgetful functor $mathbb{A}^1_K: Kmathsf{Alg} to mathsf{Sets}$.



      So we have a functor $mathsf{Sets}^{Kmathsf{Alg}} to Kmathsf{Alg}$ defined by $X mapsto mathrm{Nat}(X, mathbb{A}^1_K)$.



      Moreover, we have an obvious natural transformation $alpha: X to mathrm{Spec_K}(mathrm{Nat}(X, mathbb{A}^1_K))$,
      where $mathrm{Spec}_K$ here is just the contravariant Yoneda embedding (since I am thinking of affine schemes as functors rather than ringed spaces). This natural transformation has components $alpha_A: X(A) to mathrm{Hom}(mathrm{Nat}(X, mathbb{A}^1_K), A)$ given by $x mapsto (f mapsto f_A(x))$.



      My question is:





      1. Is it reasonable to call $mathrm{Nat}(X, mathbb{A}^1_K), A)$ the coordinate ring for any "generalize scheme" given by a functor $X: Kmathsf{Alg} to mathsf{Sets}$? If not, what should we call this?


      2. Is the functor $mathsf{Sets}^{Kmathsf{Alg}} to Kmathsf{Alg}$ mapping $X$ to $mathrm{Nat}(X, mathbb{A}^1_K)$ adjoint (on the left or right) to $mathrm{Spec}_K: Kmathsf{Alg}^{mathrm{opp}} to mathsf{Sets}^{Kmathsf{Alg}}$? My guess is that it is the left adjoint to $mathrm{Spec}_K$.


      3. Is there a name and interpretation for this natural transformation $alpha_A: X(A) to mathrm{Hom}(mathrm{Nat}(X, mathbb{A}^1_K), A)$? I can see that $X$ is an affine scheme over $K$ if and only if this is an isomorphism. But what if $X$ is not affine? How do we interpret this?









      algebraic-geometry ring-theory category-theory schemes algebraic-groups






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      edited Dec 13 '18 at 4:33







      ಠ_ಠ

















      asked Dec 13 '18 at 2:43









      ಠ_ಠಠ_ಠ

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          2 Answers
          2






          active

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          3












          $begingroup$


          1. Yes.


          2. The opposites confuse me about which of "left" and "right" I'm supposed to say. It should be left with the correct choice of ops.


          3. $alpha$ deserves to be called "affinization." It's the universal map from a scheme or generalized scheme into an affine scheme; that is, it's the left adjoint of the inclusion of affine schemes into schemes / generalized schemes. As a simple example, the affinization of projective space is a point.







          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you very much for your answer!
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 3:37










          • $begingroup$
            I am also curious: it seems like this construction works if we replace $K$-algebras by any sort of algebraic category, like say groups or non-commutative algebras. Is this a reasonable approach to non-commutative geometry?
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 4:33










          • $begingroup$
            ಠ_ಠ: there's not really anything here to do geometry with.
            $endgroup$
            – Qiaochu Yuan
            Dec 13 '18 at 4:45



















          1












          $begingroup$

          "Indeed, if $X:KAlg→Sets$ is a functor then $Nat(X,mathbb{A}^1_K)$ is a $K$-algebra (with operations defined pointwise),'' Not quite --- it may be a proper class (i.e., the underlying "set" may not be a set).






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Hmm...good point. Maybe somehow it follows from the affine line $mathbb{A}^1_K$ being representable? Otherwise maybe we can use a Grothendieck Universe to fix it (I don't know much about this to be honest).
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 4:27






          • 1




            $begingroup$
            We can require $X$ to be small (a small colimit of representables); I think that should fix it.
            $endgroup$
            – Qiaochu Yuan
            Dec 13 '18 at 4:45











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          2 Answers
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          2 Answers
          2






          active

          oldest

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          active

          oldest

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          active

          oldest

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          3












          $begingroup$


          1. Yes.


          2. The opposites confuse me about which of "left" and "right" I'm supposed to say. It should be left with the correct choice of ops.


          3. $alpha$ deserves to be called "affinization." It's the universal map from a scheme or generalized scheme into an affine scheme; that is, it's the left adjoint of the inclusion of affine schemes into schemes / generalized schemes. As a simple example, the affinization of projective space is a point.







          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you very much for your answer!
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 3:37










          • $begingroup$
            I am also curious: it seems like this construction works if we replace $K$-algebras by any sort of algebraic category, like say groups or non-commutative algebras. Is this a reasonable approach to non-commutative geometry?
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 4:33










          • $begingroup$
            ಠ_ಠ: there's not really anything here to do geometry with.
            $endgroup$
            – Qiaochu Yuan
            Dec 13 '18 at 4:45
















          3












          $begingroup$


          1. Yes.


          2. The opposites confuse me about which of "left" and "right" I'm supposed to say. It should be left with the correct choice of ops.


          3. $alpha$ deserves to be called "affinization." It's the universal map from a scheme or generalized scheme into an affine scheme; that is, it's the left adjoint of the inclusion of affine schemes into schemes / generalized schemes. As a simple example, the affinization of projective space is a point.







          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you very much for your answer!
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 3:37










          • $begingroup$
            I am also curious: it seems like this construction works if we replace $K$-algebras by any sort of algebraic category, like say groups or non-commutative algebras. Is this a reasonable approach to non-commutative geometry?
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 4:33










          • $begingroup$
            ಠ_ಠ: there's not really anything here to do geometry with.
            $endgroup$
            – Qiaochu Yuan
            Dec 13 '18 at 4:45














          3












          3








          3





          $begingroup$


          1. Yes.


          2. The opposites confuse me about which of "left" and "right" I'm supposed to say. It should be left with the correct choice of ops.


          3. $alpha$ deserves to be called "affinization." It's the universal map from a scheme or generalized scheme into an affine scheme; that is, it's the left adjoint of the inclusion of affine schemes into schemes / generalized schemes. As a simple example, the affinization of projective space is a point.







          share|cite|improve this answer









          $endgroup$




          1. Yes.


          2. The opposites confuse me about which of "left" and "right" I'm supposed to say. It should be left with the correct choice of ops.


          3. $alpha$ deserves to be called "affinization." It's the universal map from a scheme or generalized scheme into an affine scheme; that is, it's the left adjoint of the inclusion of affine schemes into schemes / generalized schemes. As a simple example, the affinization of projective space is a point.








          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 13 '18 at 3:36









          Qiaochu YuanQiaochu Yuan

          278k32583919




          278k32583919












          • $begingroup$
            Thank you very much for your answer!
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 3:37










          • $begingroup$
            I am also curious: it seems like this construction works if we replace $K$-algebras by any sort of algebraic category, like say groups or non-commutative algebras. Is this a reasonable approach to non-commutative geometry?
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 4:33










          • $begingroup$
            ಠ_ಠ: there's not really anything here to do geometry with.
            $endgroup$
            – Qiaochu Yuan
            Dec 13 '18 at 4:45


















          • $begingroup$
            Thank you very much for your answer!
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 3:37










          • $begingroup$
            I am also curious: it seems like this construction works if we replace $K$-algebras by any sort of algebraic category, like say groups or non-commutative algebras. Is this a reasonable approach to non-commutative geometry?
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 4:33










          • $begingroup$
            ಠ_ಠ: there's not really anything here to do geometry with.
            $endgroup$
            – Qiaochu Yuan
            Dec 13 '18 at 4:45
















          $begingroup$
          Thank you very much for your answer!
          $endgroup$
          – ಠ_ಠ
          Dec 13 '18 at 3:37




          $begingroup$
          Thank you very much for your answer!
          $endgroup$
          – ಠ_ಠ
          Dec 13 '18 at 3:37












          $begingroup$
          I am also curious: it seems like this construction works if we replace $K$-algebras by any sort of algebraic category, like say groups or non-commutative algebras. Is this a reasonable approach to non-commutative geometry?
          $endgroup$
          – ಠ_ಠ
          Dec 13 '18 at 4:33




          $begingroup$
          I am also curious: it seems like this construction works if we replace $K$-algebras by any sort of algebraic category, like say groups or non-commutative algebras. Is this a reasonable approach to non-commutative geometry?
          $endgroup$
          – ಠ_ಠ
          Dec 13 '18 at 4:33












          $begingroup$
          ಠ_ಠ: there's not really anything here to do geometry with.
          $endgroup$
          – Qiaochu Yuan
          Dec 13 '18 at 4:45




          $begingroup$
          ಠ_ಠ: there's not really anything here to do geometry with.
          $endgroup$
          – Qiaochu Yuan
          Dec 13 '18 at 4:45











          1












          $begingroup$

          "Indeed, if $X:KAlg→Sets$ is a functor then $Nat(X,mathbb{A}^1_K)$ is a $K$-algebra (with operations defined pointwise),'' Not quite --- it may be a proper class (i.e., the underlying "set" may not be a set).






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Hmm...good point. Maybe somehow it follows from the affine line $mathbb{A}^1_K$ being representable? Otherwise maybe we can use a Grothendieck Universe to fix it (I don't know much about this to be honest).
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 4:27






          • 1




            $begingroup$
            We can require $X$ to be small (a small colimit of representables); I think that should fix it.
            $endgroup$
            – Qiaochu Yuan
            Dec 13 '18 at 4:45
















          1












          $begingroup$

          "Indeed, if $X:KAlg→Sets$ is a functor then $Nat(X,mathbb{A}^1_K)$ is a $K$-algebra (with operations defined pointwise),'' Not quite --- it may be a proper class (i.e., the underlying "set" may not be a set).






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Hmm...good point. Maybe somehow it follows from the affine line $mathbb{A}^1_K$ being representable? Otherwise maybe we can use a Grothendieck Universe to fix it (I don't know much about this to be honest).
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 4:27






          • 1




            $begingroup$
            We can require $X$ to be small (a small colimit of representables); I think that should fix it.
            $endgroup$
            – Qiaochu Yuan
            Dec 13 '18 at 4:45














          1












          1








          1





          $begingroup$

          "Indeed, if $X:KAlg→Sets$ is a functor then $Nat(X,mathbb{A}^1_K)$ is a $K$-algebra (with operations defined pointwise),'' Not quite --- it may be a proper class (i.e., the underlying "set" may not be a set).






          share|cite|improve this answer









          $endgroup$



          "Indeed, if $X:KAlg→Sets$ is a functor then $Nat(X,mathbb{A}^1_K)$ is a $K$-algebra (with operations defined pointwise),'' Not quite --- it may be a proper class (i.e., the underlying "set" may not be a set).







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 13 '18 at 4:00









          anonanon

          812




          812












          • $begingroup$
            Hmm...good point. Maybe somehow it follows from the affine line $mathbb{A}^1_K$ being representable? Otherwise maybe we can use a Grothendieck Universe to fix it (I don't know much about this to be honest).
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 4:27






          • 1




            $begingroup$
            We can require $X$ to be small (a small colimit of representables); I think that should fix it.
            $endgroup$
            – Qiaochu Yuan
            Dec 13 '18 at 4:45


















          • $begingroup$
            Hmm...good point. Maybe somehow it follows from the affine line $mathbb{A}^1_K$ being representable? Otherwise maybe we can use a Grothendieck Universe to fix it (I don't know much about this to be honest).
            $endgroup$
            – ಠ_ಠ
            Dec 13 '18 at 4:27






          • 1




            $begingroup$
            We can require $X$ to be small (a small colimit of representables); I think that should fix it.
            $endgroup$
            – Qiaochu Yuan
            Dec 13 '18 at 4:45
















          $begingroup$
          Hmm...good point. Maybe somehow it follows from the affine line $mathbb{A}^1_K$ being representable? Otherwise maybe we can use a Grothendieck Universe to fix it (I don't know much about this to be honest).
          $endgroup$
          – ಠ_ಠ
          Dec 13 '18 at 4:27




          $begingroup$
          Hmm...good point. Maybe somehow it follows from the affine line $mathbb{A}^1_K$ being representable? Otherwise maybe we can use a Grothendieck Universe to fix it (I don't know much about this to be honest).
          $endgroup$
          – ಠ_ಠ
          Dec 13 '18 at 4:27




          1




          1




          $begingroup$
          We can require $X$ to be small (a small colimit of representables); I think that should fix it.
          $endgroup$
          – Qiaochu Yuan
          Dec 13 '18 at 4:45




          $begingroup$
          We can require $X$ to be small (a small colimit of representables); I think that should fix it.
          $endgroup$
          – Qiaochu Yuan
          Dec 13 '18 at 4:45


















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