calling a function on a function is it possible?
in the following code
const express = require('express');
const app = express()
app.use(express.static('public'));
express is a function so how it call "express.static('public')" method on it? is it possible in JavaScript to call a function which is inside a function
javascript node.js express
asked Dec 22 at 9:37
Ehsan sarshar
573
add a comment |
in the following code
const express = require('express');
const app = express()
app.use(express.static('public'));
express is a function so how it call "express.static('public')" method on it? is it possible in JavaScript to call a function which is inside a function
javascript node.js express
asked Dec 22 at 9:37
Ehsan sarshar
573
add a comment |
in the following code
const express = require('express');
const app = express()
app.use(express.static('public'));
express is a function so how it call "express.static('public')" method on it? is it possible in JavaScript to call a function which is inside a function
javascript node.js express
asked Dec 22 at 9:37
Ehsan sarshar
573
in the following code
const express = require('express');
const app = express()
app.use(express.static('public'));
express is a function so how it call "express.static('public')" method on it? is it possible in JavaScript to call a function which is inside a function
javascript node.js express
javascript node.js express
asked Dec 22 at 9:37
Ehsan sarshar
573
asked Dec 22 at 9:37
Ehsan sarshar
573
asked Dec 22 at 9:37
Ehsan sarshar
573
asked Dec 22 at 9:37
Ehsan sarshar
573
asked Dec 22 at 9:37
Ehsan sarshar
573
573
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
A functions is not only a first class function, but also a first class object and can contain properties.
function foo() {}
foo.bar = function () { console.log('i am bar'); };
foo.bar();answered Dec 22 at 9:40
Nina Scholz
175k1388153
5
Yes. From a static, OO point of view, this could be explained as “function application is just a special method you can call on a function object, with syntactic sugar that makes it look like maths function application”, i.e.express()would be syntactic sugar forexpress.<operator"()">(). From a dynamic, FP view, it would be explained as “OO methods are just special functions that take the name of the method as the first argument”, i.e.express.static('public')would be syntactic sugar forexpress(<methodname "static">, 'public').
– leftaroundabout
Dec 22 at 13:40
4
@leftaroundabout: Neither of those matches the formalism of how it's actually defined in Javascript, though.
– Henning Makholm
Dec 22 at 14:42
@HenningMakholm The first one actually does. The "<operator"()">" method is named [[call]] in the spec, although it is an internal method not a normal object property.
– Bergi
Dec 22 at 19:38
@Bergi: That's what I mean: [[call]] is special and not just sugar. And it's equally present in named method calls:foo.bar()would then be sugar forfoo["bar"].<operator()>()plus some additional semantics to setthisappropriately.
– Henning Makholm
Dec 22 at 21:54
add a comment |
You can attach a function as member data to another function (which is what is done in your example).
const express = () => {};
express.static = argument => console.log('argument');
express.static('public'); # console >>> 'public'
However, you cannot readily access a variable that is defined in a function body.
const express = () => {
const static = argument => console.log('argument');
};
express.static('public'); # console >>> Error: undefined in not a function
There is a signifiant difference between member data attached to a function (the first example) and the closure that wraps the body of the function (the second example).
So, to answer your question "is it possible in JavaScript to call a function which is inside a function?" No, this is not readily possible with the important note that this is not what is being done in your example.
answered Dec 22 at 17:28
Jared Goguen
7,09411031
add a comment |
Actually, it is possible to call a function inside another function in javaScript.
So it depends on the condition, Callback is widely used in js
(A callback is a function that is to be executed after another
function has finished executing)
function doHomework(subject, callback) {
alert(`Starting my ${subject} homework.`);
callback();
}
function alertFinished(){
alert('Finished my homework');
}
doHomework('math', alertFinished);
And the second example can be Closures
(A closure is a feature in JavaScript where an inner function has
access to the outer (enclosing) function's variables)
function outer() {
var b = 10;
function inner() {
var a = 20;
console.log(a+b);
}
return inner;
}
answered Dec 22 at 11:44
Nuriddin Kudratov
737
3
While the facts given here are technically correct (and are important ones to know in JS), I don't think this answer the specific question.
– Pac0
Dec 22 at 14:06
@Pac0 I believe this answer fully satisfies (is it possible in JavaScript to call a function which is inside a function) this part of the question. So there is no reason to vote as a not useful answer!
– Nuriddin Kudratov
Dec 22 at 21:27
@NurridanKudratov I didn't downvote or vote anything, but I strongly believe that when OP is talking about being "inside a function", he was tallkking about functions that could be used as an object while having a member function at the same time (expresscan be executed()and also hasstaticas member). This case is not among your examples.
– Pac0
Dec 23 at 9:45
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
A functions is not only a first class function, but also a first class object and can contain properties.
function foo() {}
foo.bar = function () { console.log('i am bar'); };
foo.bar();answered Dec 22 at 9:40
Nina Scholz
175k1388153
5
Yes. From a static, OO point of view, this could be explained as “function application is just a special method you can call on a function object, with syntactic sugar that makes it look like maths function application”, i.e.express()would be syntactic sugar forexpress.<operator"()">(). From a dynamic, FP view, it would be explained as “OO methods are just special functions that take the name of the method as the first argument”, i.e.express.static('public')would be syntactic sugar forexpress(<methodname "static">, 'public').
– leftaroundabout
Dec 22 at 13:40
4
@leftaroundabout: Neither of those matches the formalism of how it's actually defined in Javascript, though.
– Henning Makholm
Dec 22 at 14:42
@HenningMakholm The first one actually does. The "<operator"()">" method is named [[call]] in the spec, although it is an internal method not a normal object property.
– Bergi
Dec 22 at 19:38
@Bergi: That's what I mean: [[call]] is special and not just sugar. And it's equally present in named method calls:foo.bar()would then be sugar forfoo["bar"].<operator()>()plus some additional semantics to setthisappropriately.
– Henning Makholm
Dec 22 at 21:54
add a comment |
A functions is not only a first class function, but also a first class object and can contain properties.
function foo() {}
foo.bar = function () { console.log('i am bar'); };
foo.bar();answered Dec 22 at 9:40
Nina Scholz
175k1388153
5
Yes. From a static, OO point of view, this could be explained as “function application is just a special method you can call on a function object, with syntactic sugar that makes it look like maths function application”, i.e.express()would be syntactic sugar forexpress.<operator"()">(). From a dynamic, FP view, it would be explained as “OO methods are just special functions that take the name of the method as the first argument”, i.e.express.static('public')would be syntactic sugar forexpress(<methodname "static">, 'public').
– leftaroundabout
Dec 22 at 13:40
4
@leftaroundabout: Neither of those matches the formalism of how it's actually defined in Javascript, though.
– Henning Makholm
Dec 22 at 14:42
@HenningMakholm The first one actually does. The "<operator"()">" method is named [[call]] in the spec, although it is an internal method not a normal object property.
– Bergi
Dec 22 at 19:38
@Bergi: That's what I mean: [[call]] is special and not just sugar. And it's equally present in named method calls:foo.bar()would then be sugar forfoo["bar"].<operator()>()plus some additional semantics to setthisappropriately.
– Henning Makholm
Dec 22 at 21:54
add a comment |
A functions is not only a first class function, but also a first class object and can contain properties.
function foo() {}
foo.bar = function () { console.log('i am bar'); };
foo.bar();answered Dec 22 at 9:40
Nina Scholz
175k1388153
A functions is not only a first class function, but also a first class object and can contain properties.
function foo() {}
foo.bar = function () { console.log('i am bar'); };
foo.bar();function foo() {}
foo.bar = function () { console.log('i am bar'); };
foo.bar();function foo() {}
foo.bar = function () { console.log('i am bar'); };
foo.bar();answered Dec 22 at 9:40
Nina Scholz
175k1388153
answered Dec 22 at 9:40
Nina Scholz
175k1388153
answered Dec 22 at 9:40
Nina Scholz
175k1388153
answered Dec 22 at 9:40
Nina Scholz
175k1388153
175k1388153
5
Yes. From a static, OO point of view, this could be explained as “function application is just a special method you can call on a function object, with syntactic sugar that makes it look like maths function application”, i.e.express()would be syntactic sugar forexpress.<operator"()">(). From a dynamic, FP view, it would be explained as “OO methods are just special functions that take the name of the method as the first argument”, i.e.express.static('public')would be syntactic sugar forexpress(<methodname "static">, 'public').
– leftaroundabout
Dec 22 at 13:40
4
@leftaroundabout: Neither of those matches the formalism of how it's actually defined in Javascript, though.
– Henning Makholm
Dec 22 at 14:42
@HenningMakholm The first one actually does. The "<operator"()">" method is named [[call]] in the spec, although it is an internal method not a normal object property.
– Bergi
Dec 22 at 19:38
@Bergi: That's what I mean: [[call]] is special and not just sugar. And it's equally present in named method calls:foo.bar()would then be sugar forfoo["bar"].<operator()>()plus some additional semantics to setthisappropriately.
– Henning Makholm
Dec 22 at 21:54
add a comment |
5
Yes. From a static, OO point of view, this could be explained as “function application is just a special method you can call on a function object, with syntactic sugar that makes it look like maths function application”, i.e.express()would be syntactic sugar forexpress.<operator"()">(). From a dynamic, FP view, it would be explained as “OO methods are just special functions that take the name of the method as the first argument”, i.e.express.static('public')would be syntactic sugar forexpress(<methodname "static">, 'public').
– leftaroundabout
Dec 22 at 13:40
4
@leftaroundabout: Neither of those matches the formalism of how it's actually defined in Javascript, though.
– Henning Makholm
Dec 22 at 14:42
@HenningMakholm The first one actually does. The "<operator"()">" method is named [[call]] in the spec, although it is an internal method not a normal object property.
– Bergi
Dec 22 at 19:38
@Bergi: That's what I mean: [[call]] is special and not just sugar. And it's equally present in named method calls:foo.bar()would then be sugar forfoo["bar"].<operator()>()plus some additional semantics to setthisappropriately.
– Henning Makholm
Dec 22 at 21:54
5
5
Yes. From a static, OO point of view, this could be explained as “function application is just a special method you can call on a function object, with syntactic sugar that makes it look like maths function application”, i.e.
express() would be syntactic sugar for express.<operator"()">(). From a dynamic, FP view, it would be explained as “OO methods are just special functions that take the name of the method as the first argument”, i.e. express.static('public') would be syntactic sugar for express(<methodname "static">, 'public').– leftaroundabout
Dec 22 at 13:40
Yes. From a static, OO point of view, this could be explained as “function application is just a special method you can call on a function object, with syntactic sugar that makes it look like maths function application”, i.e.
express() would be syntactic sugar for express.<operator"()">(). From a dynamic, FP view, it would be explained as “OO methods are just special functions that take the name of the method as the first argument”, i.e. express.static('public') would be syntactic sugar for express(<methodname "static">, 'public').– leftaroundabout
Dec 22 at 13:40
4
4
@leftaroundabout: Neither of those matches the formalism of how it's actually defined in Javascript, though.
– Henning Makholm
Dec 22 at 14:42
@leftaroundabout: Neither of those matches the formalism of how it's actually defined in Javascript, though.
– Henning Makholm
Dec 22 at 14:42
@HenningMakholm The first one actually does. The "
<operator"()">" method is named [[call]] in the spec, although it is an internal method not a normal object property.– Bergi
Dec 22 at 19:38
@HenningMakholm The first one actually does. The "
<operator"()">" method is named [[call]] in the spec, although it is an internal method not a normal object property.– Bergi
Dec 22 at 19:38
@Bergi: That's what I mean: [[call]] is special and not just sugar. And it's equally present in named method calls:
foo.bar() would then be sugar for foo["bar"].<operator()>() plus some additional semantics to set this appropriately.– Henning Makholm
Dec 22 at 21:54
@Bergi: That's what I mean: [[call]] is special and not just sugar. And it's equally present in named method calls:
foo.bar() would then be sugar for foo["bar"].<operator()>() plus some additional semantics to set this appropriately.– Henning Makholm
Dec 22 at 21:54
add a comment |
You can attach a function as member data to another function (which is what is done in your example).
const express = () => {};
express.static = argument => console.log('argument');
express.static('public'); # console >>> 'public'
However, you cannot readily access a variable that is defined in a function body.
const express = () => {
const static = argument => console.log('argument');
};
express.static('public'); # console >>> Error: undefined in not a function
There is a signifiant difference between member data attached to a function (the first example) and the closure that wraps the body of the function (the second example).
So, to answer your question "is it possible in JavaScript to call a function which is inside a function?" No, this is not readily possible with the important note that this is not what is being done in your example.
answered Dec 22 at 17:28
Jared Goguen
7,09411031
add a comment |
You can attach a function as member data to another function (which is what is done in your example).
const express = () => {};
express.static = argument => console.log('argument');
express.static('public'); # console >>> 'public'
However, you cannot readily access a variable that is defined in a function body.
const express = () => {
const static = argument => console.log('argument');
};
express.static('public'); # console >>> Error: undefined in not a function
There is a signifiant difference between member data attached to a function (the first example) and the closure that wraps the body of the function (the second example).
So, to answer your question "is it possible in JavaScript to call a function which is inside a function?" No, this is not readily possible with the important note that this is not what is being done in your example.
answered Dec 22 at 17:28
Jared Goguen
7,09411031
add a comment |
You can attach a function as member data to another function (which is what is done in your example).
const express = () => {};
express.static = argument => console.log('argument');
express.static('public'); # console >>> 'public'
However, you cannot readily access a variable that is defined in a function body.
const express = () => {
const static = argument => console.log('argument');
};
express.static('public'); # console >>> Error: undefined in not a function
There is a signifiant difference between member data attached to a function (the first example) and the closure that wraps the body of the function (the second example).
So, to answer your question "is it possible in JavaScript to call a function which is inside a function?" No, this is not readily possible with the important note that this is not what is being done in your example.
answered Dec 22 at 17:28
Jared Goguen
7,09411031
You can attach a function as member data to another function (which is what is done in your example).
const express = () => {};
express.static = argument => console.log('argument');
express.static('public'); # console >>> 'public'
However, you cannot readily access a variable that is defined in a function body.
const express = () => {
const static = argument => console.log('argument');
};
express.static('public'); # console >>> Error: undefined in not a function
There is a signifiant difference between member data attached to a function (the first example) and the closure that wraps the body of the function (the second example).
So, to answer your question "is it possible in JavaScript to call a function which is inside a function?" No, this is not readily possible with the important note that this is not what is being done in your example.
answered Dec 22 at 17:28
Jared Goguen
7,09411031
answered Dec 22 at 17:28
Jared Goguen
7,09411031
answered Dec 22 at 17:28
Jared Goguen
7,09411031
answered Dec 22 at 17:28
Jared Goguen
7,09411031
7,09411031
add a comment |
add a comment |
Actually, it is possible to call a function inside another function in javaScript.
So it depends on the condition, Callback is widely used in js
(A callback is a function that is to be executed after another
function has finished executing)
function doHomework(subject, callback) {
alert(`Starting my ${subject} homework.`);
callback();
}
function alertFinished(){
alert('Finished my homework');
}
doHomework('math', alertFinished);
And the second example can be Closures
(A closure is a feature in JavaScript where an inner function has
access to the outer (enclosing) function's variables)
function outer() {
var b = 10;
function inner() {
var a = 20;
console.log(a+b);
}
return inner;
}
answered Dec 22 at 11:44
Nuriddin Kudratov
737
3
While the facts given here are technically correct (and are important ones to know in JS), I don't think this answer the specific question.
– Pac0
Dec 22 at 14:06
@Pac0 I believe this answer fully satisfies (is it possible in JavaScript to call a function which is inside a function) this part of the question. So there is no reason to vote as a not useful answer!
– Nuriddin Kudratov
Dec 22 at 21:27
@NurridanKudratov I didn't downvote or vote anything, but I strongly believe that when OP is talking about being "inside a function", he was tallkking about functions that could be used as an object while having a member function at the same time (expresscan be executed()and also hasstaticas member). This case is not among your examples.
– Pac0
Dec 23 at 9:45
add a comment |
Actually, it is possible to call a function inside another function in javaScript.
So it depends on the condition, Callback is widely used in js
(A callback is a function that is to be executed after another
function has finished executing)
function doHomework(subject, callback) {
alert(`Starting my ${subject} homework.`);
callback();
}
function alertFinished(){
alert('Finished my homework');
}
doHomework('math', alertFinished);
And the second example can be Closures
(A closure is a feature in JavaScript where an inner function has
access to the outer (enclosing) function's variables)
function outer() {
var b = 10;
function inner() {
var a = 20;
console.log(a+b);
}
return inner;
}
answered Dec 22 at 11:44
Nuriddin Kudratov
737
3
While the facts given here are technically correct (and are important ones to know in JS), I don't think this answer the specific question.
– Pac0
Dec 22 at 14:06
@Pac0 I believe this answer fully satisfies (is it possible in JavaScript to call a function which is inside a function) this part of the question. So there is no reason to vote as a not useful answer!
– Nuriddin Kudratov
Dec 22 at 21:27
@NurridanKudratov I didn't downvote or vote anything, but I strongly believe that when OP is talking about being "inside a function", he was tallkking about functions that could be used as an object while having a member function at the same time (expresscan be executed()and also hasstaticas member). This case is not among your examples.
– Pac0
Dec 23 at 9:45
add a comment |
Actually, it is possible to call a function inside another function in javaScript.
So it depends on the condition, Callback is widely used in js
(A callback is a function that is to be executed after another
function has finished executing)
function doHomework(subject, callback) {
alert(`Starting my ${subject} homework.`);
callback();
}
function alertFinished(){
alert('Finished my homework');
}
doHomework('math', alertFinished);
And the second example can be Closures
(A closure is a feature in JavaScript where an inner function has
access to the outer (enclosing) function's variables)
function outer() {
var b = 10;
function inner() {
var a = 20;
console.log(a+b);
}
return inner;
}
answered Dec 22 at 11:44
Nuriddin Kudratov
737
Actually, it is possible to call a function inside another function in javaScript.
So it depends on the condition, Callback is widely used in js
(A callback is a function that is to be executed after another
function has finished executing)
function doHomework(subject, callback) {
alert(`Starting my ${subject} homework.`);
callback();
}
function alertFinished(){
alert('Finished my homework');
}
doHomework('math', alertFinished);
And the second example can be Closures
(A closure is a feature in JavaScript where an inner function has
access to the outer (enclosing) function's variables)
function outer() {
var b = 10;
function inner() {
var a = 20;
console.log(a+b);
}
return inner;
}
answered Dec 22 at 11:44
Nuriddin Kudratov
737
answered Dec 22 at 11:44
Nuriddin Kudratov
737
answered Dec 22 at 11:44
Nuriddin Kudratov
737
answered Dec 22 at 11:44
Nuriddin Kudratov
737
737
3
While the facts given here are technically correct (and are important ones to know in JS), I don't think this answer the specific question.
– Pac0
Dec 22 at 14:06
@Pac0 I believe this answer fully satisfies (is it possible in JavaScript to call a function which is inside a function) this part of the question. So there is no reason to vote as a not useful answer!
– Nuriddin Kudratov
Dec 22 at 21:27
@NurridanKudratov I didn't downvote or vote anything, but I strongly believe that when OP is talking about being "inside a function", he was tallkking about functions that could be used as an object while having a member function at the same time (expresscan be executed()and also hasstaticas member). This case is not among your examples.
– Pac0
Dec 23 at 9:45
add a comment |
3
While the facts given here are technically correct (and are important ones to know in JS), I don't think this answer the specific question.
– Pac0
Dec 22 at 14:06
@Pac0 I believe this answer fully satisfies (is it possible in JavaScript to call a function which is inside a function) this part of the question. So there is no reason to vote as a not useful answer!
– Nuriddin Kudratov
Dec 22 at 21:27
@NurridanKudratov I didn't downvote or vote anything, but I strongly believe that when OP is talking about being "inside a function", he was tallkking about functions that could be used as an object while having a member function at the same time (expresscan be executed()and also hasstaticas member). This case is not among your examples.
– Pac0
Dec 23 at 9:45
3
3
While the facts given here are technically correct (and are important ones to know in JS), I don't think this answer the specific question.
– Pac0
Dec 22 at 14:06
While the facts given here are technically correct (and are important ones to know in JS), I don't think this answer the specific question.
– Pac0
Dec 22 at 14:06
@Pac0 I believe this answer fully satisfies (is it possible in JavaScript to call a function which is inside a function) this part of the question. So there is no reason to vote as a not useful answer!
– Nuriddin Kudratov
Dec 22 at 21:27
@Pac0 I believe this answer fully satisfies (is it possible in JavaScript to call a function which is inside a function) this part of the question. So there is no reason to vote as a not useful answer!
– Nuriddin Kudratov
Dec 22 at 21:27
@NurridanKudratov I didn't downvote or vote anything, but I strongly believe that when OP is talking about being "inside a function", he was tallkking about functions that could be used as an object while having a member function at the same time (
express can be executed () and also has static as member). This case is not among your examples.– Pac0
Dec 23 at 9:45
@NurridanKudratov I didn't downvote or vote anything, but I strongly believe that when OP is talking about being "inside a function", he was tallkking about functions that could be used as an object while having a member function at the same time (
express can be executed () and also has static as member). This case is not among your examples.– Pac0
Dec 23 at 9:45
add a comment |
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