Rearrangement of lists of strings
up vote
5
down vote
favorite
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
edited Nov 25 at 9:27
kglr
174k9196402
asked Nov 25 at 2:43
Suite401
959312
add a comment |
up vote
5
down vote
favorite
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
edited Nov 25 at 9:27
kglr
174k9196402
asked Nov 25 at 2:43
Suite401
959312
add a comment |
up vote
5
down vote
favorite
up vote
5
down vote
favorite
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
edited Nov 25 at 9:27
kglr
174k9196402
asked Nov 25 at 2:43
Suite401
959312
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
string-manipulation
edited Nov 25 at 9:27
kglr
174k9196402
asked Nov 25 at 2:43
Suite401
959312
edited Nov 25 at 9:27
kglr
174k9196402
asked Nov 25 at 2:43
Suite401
959312
edited Nov 25 at 9:27
kglr
174k9196402
edited Nov 25 at 9:27
kglr
174k9196402
edited Nov 25 at 9:27
kglr
174k9196402
174k9196402
asked Nov 25 at 2:43
Suite401
959312
asked Nov 25 at 2:43
Suite401
959312
asked Nov 25 at 2:43
Suite401
959312
959312
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
14
down vote
accepted
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 at 2:56
kglr
174k9196402
add a comment |
up vote
6
down vote
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 at 2:52
Bob Hanlon
57.9k23593
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
14
down vote
accepted
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 at 2:56
kglr
174k9196402
add a comment |
up vote
14
down vote
accepted
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 at 2:56
kglr
174k9196402
add a comment |
up vote
14
down vote
accepted
up vote
14
down vote
accepted
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 at 2:56
kglr
174k9196402
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 at 2:56
kglr
174k9196402
answered Nov 25 at 2:56
kglr
174k9196402
answered Nov 25 at 2:56
kglr
174k9196402
answered Nov 25 at 2:56
kglr
174k9196402
174k9196402
add a comment |
add a comment |
up vote
6
down vote
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 at 2:52
Bob Hanlon
57.9k23593
add a comment |
up vote
6
down vote
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 at 2:52
Bob Hanlon
57.9k23593
add a comment |
up vote
6
down vote
up vote
6
down vote
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 at 2:52
Bob Hanlon
57.9k23593
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 at 2:52
Bob Hanlon
57.9k23593
answered Nov 25 at 2:52
Bob Hanlon
57.9k23593
answered Nov 25 at 2:52
Bob Hanlon
57.9k23593
answered Nov 25 at 2:52
Bob Hanlon
57.9k23593
57.9k23593
add a comment |
add a comment |
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