Gfrktyl

I have a .ts file, but I don't have the source file(video file). I need to generate a m3u8 file from the .ts file itself without creating other .ts files. I used the following command.

ffmpeg -i mytsfile.ts -hls_list_size 0 mym3u8.m3u8 -hide_banner

When I used the above command, it has created almost 590 ts files with the name of mym3u8N.ts(where N is number from 1 to 590). I dont want ts files. I need only m3u8 file.

If you just want to generate an M3U8 file from an existing segment:

ffmpeg -i input.ts 

-map 0 -c copy 

-f segment -segment_list out.m3u8 

-segment_time 60 

out%03d.ts

Here, it's important that you specify a -segment_time equal to or larger than the actual input duration, as otherwise, ffmpeg will split the input file again.

The output M3U8 will contain a reference to the newly output TS file:

#EXTM3U

#EXT-X-VERSION:3

#EXT-X-MEDIA-SEQUENCE:0

#EXT-X-ALLOW-CACHE:YES

#EXT-X-TARGETDURATION:61

#EXTINF:60.033333,

out000.ts

#EXT-X-ENDLIST

You may use that, or delete the out000.ts file (since it's essentially the same as the input file), and change the file name in the M3U8 file, as the content of the media file will be the same.

You can do such a replacement e.g. using perl:

perl -pi -e 's/out000.ts/input.ts'

I should add that for the simple case of one segment file of which you know the duration, you can easily generate the M3U8 file manually. You then have to specify the EXT-X-TARGETDURATION and EXTINF: duration values manually as well.