Primes and Squares
up vote
7
down vote
favorite
Place a different prime or square number on each of the fifteen disks below so that the number in any disk that lies on two others is the sum of the numbers in those disks. Do so in such a way that the number on the apex is as small as possible.
mathematics arithmetic
add a comment |
up vote
7
down vote
favorite
Place a different prime or square number on each of the fifteen disks below so that the number in any disk that lies on two others is the sum of the numbers in those disks. Do so in such a way that the number on the apex is as small as possible.
mathematics arithmetic
is this something you composed yourself?
– Kate Gregory
Nov 26 at 15:13
@KateGregory: A variation on an old theme.
– Bernardo Recamán Santos
Nov 26 at 15:15
Zero (as a square) allowed?
– z100
Nov 26 at 20:43
1
@z100 You could not use a zero, since $x + 0 = x$, and therefore you'd have to have two $x$'es in your grid; that is disallowed. See imgur.com/a/gPWWkaN for explanation.
– Hugh
Nov 26 at 21:55
add a comment |
up vote
7
down vote
favorite
up vote
7
down vote
favorite
Place a different prime or square number on each of the fifteen disks below so that the number in any disk that lies on two others is the sum of the numbers in those disks. Do so in such a way that the number on the apex is as small as possible.
mathematics arithmetic
Place a different prime or square number on each of the fifteen disks below so that the number in any disk that lies on two others is the sum of the numbers in those disks. Do so in such a way that the number on the apex is as small as possible.
mathematics arithmetic
mathematics arithmetic
asked Nov 26 at 14:59
Bernardo Recamán Santos
2,2931141
2,2931141
is this something you composed yourself?
– Kate Gregory
Nov 26 at 15:13
@KateGregory: A variation on an old theme.
– Bernardo Recamán Santos
Nov 26 at 15:15
Zero (as a square) allowed?
– z100
Nov 26 at 20:43
1
@z100 You could not use a zero, since $x + 0 = x$, and therefore you'd have to have two $x$'es in your grid; that is disallowed. See imgur.com/a/gPWWkaN for explanation.
– Hugh
Nov 26 at 21:55
add a comment |
is this something you composed yourself?
– Kate Gregory
Nov 26 at 15:13
@KateGregory: A variation on an old theme.
– Bernardo Recamán Santos
Nov 26 at 15:15
Zero (as a square) allowed?
– z100
Nov 26 at 20:43
1
@z100 You could not use a zero, since $x + 0 = x$, and therefore you'd have to have two $x$'es in your grid; that is disallowed. See imgur.com/a/gPWWkaN for explanation.
– Hugh
Nov 26 at 21:55
is this something you composed yourself?
– Kate Gregory
Nov 26 at 15:13
is this something you composed yourself?
– Kate Gregory
Nov 26 at 15:13
@KateGregory: A variation on an old theme.
– Bernardo Recamán Santos
Nov 26 at 15:15
@KateGregory: A variation on an old theme.
– Bernardo Recamán Santos
Nov 26 at 15:15
Zero (as a square) allowed?
– z100
Nov 26 at 20:43
Zero (as a square) allowed?
– z100
Nov 26 at 20:43
1
1
@z100 You could not use a zero, since $x + 0 = x$, and therefore you'd have to have two $x$'es in your grid; that is disallowed. See imgur.com/a/gPWWkaN for explanation.
– Hugh
Nov 26 at 21:55
@z100 You could not use a zero, since $x + 0 = x$, and therefore you'd have to have two $x$'es in your grid; that is disallowed. See imgur.com/a/gPWWkaN for explanation.
– Hugh
Nov 26 at 21:55
add a comment |
2 Answers
2
active
oldest
votes
up vote
8
down vote
accepted
A much lower upper bound, which I'm fairly sure is optimal (assuming 0 is disallowed).
1669
576 || 1093
383 || 193 || 900
347 || 36 || 157 || 743
324 || 23 || 13 || 144 || 599
Algorithm used extening the order? E.G.: 1st order: 1 ; 2nd order: 3 (1 2) ; 3rd order: 16 (3 13) (1 2 11) ; or 16 (13 3) (12 1 2) ;
– z100
Nov 26 at 21:25
@z100 I'm afraid I'm not sure what you're asking - could you clarify?
– B. Mehta
Nov 26 at 21:33
1
My own (extremely shameful, dirty, brute-force) code confirms this answer is optimal. I can also provide the smallest apex value for a 4-level tree, which is 23.
– benj2240
Nov 27 at 1:03
1
@BernardoRecamánSantos Oh! You're right, 23 isn't possible. I didn't notice that I had a duplicated 3... Dirty code leads to dirty bugs. Let me correct myself: The smallest apex value for a 4-level tree is 59.
– benj2240
Nov 28 at 1:14
1
@benj2240: Yes, 59 is the lowest my students have achieved.
– Bernardo Recamán Santos
Nov 28 at 1:18
|
show 1 more comment
up vote
5
down vote
Alright, I’ve definitely got an upper bound here.
In text:
390625
140625 || 250000
50625 || 90000 || 160000
18225 || 32400 || 57600 || 102400
6561 || 11664 || 20736 || 36864 || 65536
However,
this uses all square numbers, and is far from optimal. I’ll have to see if I can reduce it by using primes.
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
8
down vote
accepted
A much lower upper bound, which I'm fairly sure is optimal (assuming 0 is disallowed).
1669
576 || 1093
383 || 193 || 900
347 || 36 || 157 || 743
324 || 23 || 13 || 144 || 599
Algorithm used extening the order? E.G.: 1st order: 1 ; 2nd order: 3 (1 2) ; 3rd order: 16 (3 13) (1 2 11) ; or 16 (13 3) (12 1 2) ;
– z100
Nov 26 at 21:25
@z100 I'm afraid I'm not sure what you're asking - could you clarify?
– B. Mehta
Nov 26 at 21:33
1
My own (extremely shameful, dirty, brute-force) code confirms this answer is optimal. I can also provide the smallest apex value for a 4-level tree, which is 23.
– benj2240
Nov 27 at 1:03
1
@BernardoRecamánSantos Oh! You're right, 23 isn't possible. I didn't notice that I had a duplicated 3... Dirty code leads to dirty bugs. Let me correct myself: The smallest apex value for a 4-level tree is 59.
– benj2240
Nov 28 at 1:14
1
@benj2240: Yes, 59 is the lowest my students have achieved.
– Bernardo Recamán Santos
Nov 28 at 1:18
|
show 1 more comment
up vote
8
down vote
accepted
A much lower upper bound, which I'm fairly sure is optimal (assuming 0 is disallowed).
1669
576 || 1093
383 || 193 || 900
347 || 36 || 157 || 743
324 || 23 || 13 || 144 || 599
Algorithm used extening the order? E.G.: 1st order: 1 ; 2nd order: 3 (1 2) ; 3rd order: 16 (3 13) (1 2 11) ; or 16 (13 3) (12 1 2) ;
– z100
Nov 26 at 21:25
@z100 I'm afraid I'm not sure what you're asking - could you clarify?
– B. Mehta
Nov 26 at 21:33
1
My own (extremely shameful, dirty, brute-force) code confirms this answer is optimal. I can also provide the smallest apex value for a 4-level tree, which is 23.
– benj2240
Nov 27 at 1:03
1
@BernardoRecamánSantos Oh! You're right, 23 isn't possible. I didn't notice that I had a duplicated 3... Dirty code leads to dirty bugs. Let me correct myself: The smallest apex value for a 4-level tree is 59.
– benj2240
Nov 28 at 1:14
1
@benj2240: Yes, 59 is the lowest my students have achieved.
– Bernardo Recamán Santos
Nov 28 at 1:18
|
show 1 more comment
up vote
8
down vote
accepted
up vote
8
down vote
accepted
A much lower upper bound, which I'm fairly sure is optimal (assuming 0 is disallowed).
1669
576 || 1093
383 || 193 || 900
347 || 36 || 157 || 743
324 || 23 || 13 || 144 || 599
A much lower upper bound, which I'm fairly sure is optimal (assuming 0 is disallowed).
1669
576 || 1093
383 || 193 || 900
347 || 36 || 157 || 743
324 || 23 || 13 || 144 || 599
edited Nov 26 at 21:20
answered Nov 26 at 20:28
B. Mehta
1963
1963
Algorithm used extening the order? E.G.: 1st order: 1 ; 2nd order: 3 (1 2) ; 3rd order: 16 (3 13) (1 2 11) ; or 16 (13 3) (12 1 2) ;
– z100
Nov 26 at 21:25
@z100 I'm afraid I'm not sure what you're asking - could you clarify?
– B. Mehta
Nov 26 at 21:33
1
My own (extremely shameful, dirty, brute-force) code confirms this answer is optimal. I can also provide the smallest apex value for a 4-level tree, which is 23.
– benj2240
Nov 27 at 1:03
1
@BernardoRecamánSantos Oh! You're right, 23 isn't possible. I didn't notice that I had a duplicated 3... Dirty code leads to dirty bugs. Let me correct myself: The smallest apex value for a 4-level tree is 59.
– benj2240
Nov 28 at 1:14
1
@benj2240: Yes, 59 is the lowest my students have achieved.
– Bernardo Recamán Santos
Nov 28 at 1:18
|
show 1 more comment
Algorithm used extening the order? E.G.: 1st order: 1 ; 2nd order: 3 (1 2) ; 3rd order: 16 (3 13) (1 2 11) ; or 16 (13 3) (12 1 2) ;
– z100
Nov 26 at 21:25
@z100 I'm afraid I'm not sure what you're asking - could you clarify?
– B. Mehta
Nov 26 at 21:33
1
My own (extremely shameful, dirty, brute-force) code confirms this answer is optimal. I can also provide the smallest apex value for a 4-level tree, which is 23.
– benj2240
Nov 27 at 1:03
1
@BernardoRecamánSantos Oh! You're right, 23 isn't possible. I didn't notice that I had a duplicated 3... Dirty code leads to dirty bugs. Let me correct myself: The smallest apex value for a 4-level tree is 59.
– benj2240
Nov 28 at 1:14
1
@benj2240: Yes, 59 is the lowest my students have achieved.
– Bernardo Recamán Santos
Nov 28 at 1:18
Algorithm used extening the order? E.G.: 1st order: 1 ; 2nd order: 3 (1 2) ; 3rd order: 16 (3 13) (1 2 11) ; or 16 (13 3) (12 1 2) ;
– z100
Nov 26 at 21:25
Algorithm used extening the order? E.G.: 1st order: 1 ; 2nd order: 3 (1 2) ; 3rd order: 16 (3 13) (1 2 11) ; or 16 (13 3) (12 1 2) ;
– z100
Nov 26 at 21:25
@z100 I'm afraid I'm not sure what you're asking - could you clarify?
– B. Mehta
Nov 26 at 21:33
@z100 I'm afraid I'm not sure what you're asking - could you clarify?
– B. Mehta
Nov 26 at 21:33
1
1
My own (extremely shameful, dirty, brute-force) code confirms this answer is optimal. I can also provide the smallest apex value for a 4-level tree, which is 23.
– benj2240
Nov 27 at 1:03
My own (extremely shameful, dirty, brute-force) code confirms this answer is optimal. I can also provide the smallest apex value for a 4-level tree, which is 23.
– benj2240
Nov 27 at 1:03
1
1
@BernardoRecamánSantos Oh! You're right, 23 isn't possible. I didn't notice that I had a duplicated 3... Dirty code leads to dirty bugs. Let me correct myself: The smallest apex value for a 4-level tree is 59.
– benj2240
Nov 28 at 1:14
@BernardoRecamánSantos Oh! You're right, 23 isn't possible. I didn't notice that I had a duplicated 3... Dirty code leads to dirty bugs. Let me correct myself: The smallest apex value for a 4-level tree is 59.
– benj2240
Nov 28 at 1:14
1
1
@benj2240: Yes, 59 is the lowest my students have achieved.
– Bernardo Recamán Santos
Nov 28 at 1:18
@benj2240: Yes, 59 is the lowest my students have achieved.
– Bernardo Recamán Santos
Nov 28 at 1:18
|
show 1 more comment
up vote
5
down vote
Alright, I’ve definitely got an upper bound here.
In text:
390625
140625 || 250000
50625 || 90000 || 160000
18225 || 32400 || 57600 || 102400
6561 || 11664 || 20736 || 36864 || 65536
However,
this uses all square numbers, and is far from optimal. I’ll have to see if I can reduce it by using primes.
add a comment |
up vote
5
down vote
Alright, I’ve definitely got an upper bound here.
In text:
390625
140625 || 250000
50625 || 90000 || 160000
18225 || 32400 || 57600 || 102400
6561 || 11664 || 20736 || 36864 || 65536
However,
this uses all square numbers, and is far from optimal. I’ll have to see if I can reduce it by using primes.
add a comment |
up vote
5
down vote
up vote
5
down vote
Alright, I’ve definitely got an upper bound here.
In text:
390625
140625 || 250000
50625 || 90000 || 160000
18225 || 32400 || 57600 || 102400
6561 || 11664 || 20736 || 36864 || 65536
However,
this uses all square numbers, and is far from optimal. I’ll have to see if I can reduce it by using primes.
Alright, I’ve definitely got an upper bound here.
In text:
390625
140625 || 250000
50625 || 90000 || 160000
18225 || 32400 || 57600 || 102400
6561 || 11664 || 20736 || 36864 || 65536
However,
this uses all square numbers, and is far from optimal. I’ll have to see if I can reduce it by using primes.
edited Nov 26 at 16:51
gabbo1092
4,683738
4,683738
answered Nov 26 at 16:32
Excited Raichu
4,777754
4,777754
add a comment |
add a comment |
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f75754%2fprimes-and-squares%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
is this something you composed yourself?
– Kate Gregory
Nov 26 at 15:13
@KateGregory: A variation on an old theme.
– Bernardo Recamán Santos
Nov 26 at 15:15
Zero (as a square) allowed?
– z100
Nov 26 at 20:43
1
@z100 You could not use a zero, since $x + 0 = x$, and therefore you'd have to have two $x$'es in your grid; that is disallowed. See imgur.com/a/gPWWkaN for explanation.
– Hugh
Nov 26 at 21:55