Gfrktyl

The output should display as follows...

PROGRAM: Vowel count



Please, enter a text string: fred

4 characters

a e i o u

0 1 0 0 0

b c d f g h j k l m n p q r s t v w x y z

0 0 1 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 

It works; but, I believe is way over long...; maybe, I should have used arrays/or, ASCII count/-etc.?

vowels="aeiou"

aCount=eCount=iCount=oCount=uCount=0



consonants="bcdfghjklmnpqrstvwxyz"

bCount=cCount=dCount=fCount=gCount=hCount=jCount=kCount=lCount=mCount=nCount=oCount=pCount=qCount=rCount=sCount=tCount=uCount=vCount=wCount=xCount=yCount=zCount=0



print("PROGRAM: Vowel countn")



aString=input("Please, enter a text string: ")



for eachChar in aString:



    if eachChar in vowels:

        if eachChar == "a": aCount+=1

        if eachChar == "e": eCount+=1

        if eachChar == "i": iCount+=1

        if eachChar == "o": oCount+=1

        if eachChar == "u": uCount+=1



    if eachChar in consonants:

        if eachChar == "b": bCount+=1

        if eachChar == "c": cCount+=1

        if eachChar == "d": dCount+=1

        if eachChar == "f": fCount+=1

        if eachChar == "g": gCount+=1        

        if eachChar == "h": hCount+=1

        if eachChar == "j": jCount+=1

        if eachChar == "k": kCount+=1

        if eachChar == "l": lCount+=1

        if eachChar == "m": mCount+=1

        if eachChar == "n": nCount+=1

        if eachChar == "p": pCount+=1

        if eachChar == "q": qCount+=1

        if eachChar == "r": rCount+=1

        if eachChar == "s": sCount+=1

        if eachChar == "t": tCount+=1

        if eachChar == "v": vCount+=1

        if eachChar == "w": wCount+=1

        if eachChar == "x": xCount+=1        

        if eachChar == "y": yCount+=1

        if eachChar == "z": zCount+=1



print(len(aString),"characters")



print("a","e","i","o","u")

print(aCount,eCount,iCount,oCount,uCount)



print("b","c","d","f","g","h","j","k","l","m","n","p","q","r","s","t","v","w","x","y","z")

print(bCount,cCount,dCount,fCount,gCount,hCount,jCount,kCount,lCount,mCount,nCount,pCount,qCount,rCount,sCount,tCount,vCount,wCount,xCount,yCount,zCount)

To count the occurrences of things, use collections.Counter.

The lowercase letters are available as a predefined constant string.ascii_lowercase. You can use a generator expression to filter out the vowels and obtain the consonants. PEP 8, the official style guide, suggests using ALL_CAPS as names for constants.

I've used the * operator when calling print() to treat each element of a tuple or list as a separate argument.

Note that your formatting will break when any character has more than 9 occurrences.

from collections import Counter

from string import ascii_lowercase



VOWELS = tuple("aeiou")

CONSONANTS = tuple(c for c in ascii_lowercase if c not in VOWELS)



print("PROGRAM: Vowel countn")

s = input("Please, enter a text string: ")

counts = Counter(s)



print('{0} characters'.format(len(s)))

print(*VOWELS)

print(*[counts[c] for c in VOWELS])

print(*CONSONANTS)

print(*[counts[c] for c in CONSONANTS])