A cipher for people who don't normally enjoy ciphers











up vote
13
down vote

favorite












I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.



So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:




I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]



However, instead of just encrypting it once, I have done so six times, using six different methods.



The output for each encryption is as follows:
Encryption Output




The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.



The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?



Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in



Method 3




How often do you see a 3-letter word have a higher value than a 4-letter word?




Method 6




The order of the letters doesn't seem logical in isolation, but if it ever got changed, many of us would struggle to adapt!











share|improve this question
























  • Shouldn't the phrase have 4 words?
    – Display name
    Nov 12 at 23:09










  • Oops! - thanks for catching that!
    – Dmihawk
    Nov 12 at 23:28










  • I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
    – Omega Krypton
    2 days ago










  • I'll need to double check in the morning
    – Dmihawk
    2 days ago










  • Sorry I was wrong
    – Omega Krypton
    2 days ago















up vote
13
down vote

favorite












I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.



So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:




I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]



However, instead of just encrypting it once, I have done so six times, using six different methods.



The output for each encryption is as follows:
Encryption Output




The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.



The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?



Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in



Method 3




How often do you see a 3-letter word have a higher value than a 4-letter word?




Method 6




The order of the letters doesn't seem logical in isolation, but if it ever got changed, many of us would struggle to adapt!











share|improve this question
























  • Shouldn't the phrase have 4 words?
    – Display name
    Nov 12 at 23:09










  • Oops! - thanks for catching that!
    – Dmihawk
    Nov 12 at 23:28










  • I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
    – Omega Krypton
    2 days ago










  • I'll need to double check in the morning
    – Dmihawk
    2 days ago










  • Sorry I was wrong
    – Omega Krypton
    2 days ago













up vote
13
down vote

favorite









up vote
13
down vote

favorite











I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.



So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:




I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]



However, instead of just encrypting it once, I have done so six times, using six different methods.



The output for each encryption is as follows:
Encryption Output




The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.



The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?



Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in



Method 3




How often do you see a 3-letter word have a higher value than a 4-letter word?




Method 6




The order of the letters doesn't seem logical in isolation, but if it ever got changed, many of us would struggle to adapt!











share|improve this question















I've never been a fan of ciphers/encryption. Truth be told, despite my love of puzzles (and the amount of time I spend here on Puzzling.SE), I'm just no good at them and haven't properly learnt the strategies for trying to crack them.



So in an effort to expand on the types of ciphers and hopefully broaden the audience, I offer you the following challenge:




I have encrypted a five-word phrase in the form
_ _ _ _/ _ _ _ _, / _ _ _/ _ _ _ _ _ _/ _ _ _ _ _ _
[word lengths are (4) (4), (3) (6) (6)]



However, instead of just encrypting it once, I have done so six times, using six different methods.



The output for each encryption is as follows:
Encryption Output




The final answer has two parts to it. First, the completed five-word phrase (which I suspect will be discovered first) and second, the six different encryption methods, all of which must be detailed in the answer.



The decrypted phrase will tell you to do something, so make sure you do it :) You wouldn't want to make the puzzle sad, would you?



Some excellent community effort so far! The phrase and methods 2, 4 and 5 have been cracked, so I'll throw some subtle hints for the remaining three methods in



Method 3




How often do you see a 3-letter word have a higher value than a 4-letter word?




Method 6




The order of the letters doesn't seem logical in isolation, but if it ever got changed, many of us would struggle to adapt!








cipher






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited yesterday

























asked Nov 12 at 22:29









Dmihawk

1,615423




1,615423












  • Shouldn't the phrase have 4 words?
    – Display name
    Nov 12 at 23:09










  • Oops! - thanks for catching that!
    – Dmihawk
    Nov 12 at 23:28










  • I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
    – Omega Krypton
    2 days ago










  • I'll need to double check in the morning
    – Dmihawk
    2 days ago










  • Sorry I was wrong
    – Omega Krypton
    2 days ago


















  • Shouldn't the phrase have 4 words?
    – Display name
    Nov 12 at 23:09










  • Oops! - thanks for catching that!
    – Dmihawk
    Nov 12 at 23:28










  • I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
    – Omega Krypton
    2 days ago










  • I'll need to double check in the morning
    – Dmihawk
    2 days ago










  • Sorry I was wrong
    – Omega Krypton
    2 days ago
















Shouldn't the phrase have 4 words?
– Display name
Nov 12 at 23:09




Shouldn't the phrase have 4 words?
– Display name
Nov 12 at 23:09












Oops! - thanks for catching that!
– Dmihawk
Nov 12 at 23:28




Oops! - thanks for catching that!
– Dmihawk
Nov 12 at 23:28












I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
2 days ago




I have an idea for Method 4, but only if word 1 is 35 instead of 45. thanks!
– Omega Krypton
2 days ago












I'll need to double check in the morning
– Dmihawk
2 days ago




I'll need to double check in the morning
– Dmihawk
2 days ago












Sorry I was wrong
– Omega Krypton
2 days ago




Sorry I was wrong
– Omega Krypton
2 days ago










4 Answers
4






active

oldest

votes

















up vote
8
down vote



accepted










This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!



Partial Answer:



The phrase is:




WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)




Method 1 is




Sum of Scrabble values of each letter. So much thanks to @Braegh! (approved by OP in comment)
My original guess:
Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)




Method 2 is:




Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)




Method 3 is:




The sum of values of each letter according to the frequency (descending): etaoi nshrd lcumw fgypb vkjxq z, where e=1, z=26,
"WELL"=15+1+11+11=38
THANKS TO @NudgeNudge!!




Method 4 is:




the sum of values of each letter on a telephone keypad, like this:
keypad
e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39 (approved by OP in comment)




Method 5 is




the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)




And method 6:




is the sum of the values for each letter according to its position on a QWERTY keyboard, like this:
qwerty encryption




PS:




I really enjoyed this puzzle. Thanks so much, @Dmihawk!







share|improve this answer























  • Good spotting! :)
    – Dmihawk
    Nov 12 at 23:41










  • Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
    – Dmihawk
    2 days ago










  • Method 6? @Dmihawk Thanks!
    – Omega Krypton
    2 days ago












  • Sorry, meant 5!
    – Dmihawk
    2 days ago






  • 2




    For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
    – NudgeNudge
    yesterday


















up vote
5
down vote













Method 2 is




Sum of A1Z26 values







share|improve this answer




























    up vote
    5
    down vote













    I believe Method 1 is




    the (English) Scrabble value for each word.







    share|improve this answer





















    • Well done! Good find :)
      – Dmihawk
      2 days ago










    • Thank you so much... +1 already
      – Omega Krypton
      yesterday


















    up vote
    4
    down vote













    Based on @Omega Krypton's method 5, the phrase is:




    WELL DONE, NOW UPVOTE PUZZLE




    I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...






    share|improve this answer





















    • Nicely done :) now you just need to deduce the other 5 encryption methods!
      – Dmihawk
      Nov 13 at 0:37






    • 1




      I upvoted the puzzle lah :)
      – Omega Krypton
      Nov 13 at 2:57











    Your Answer





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    4 Answers
    4






    active

    oldest

    votes








    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    8
    down vote



    accepted










    This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!



    Partial Answer:



    The phrase is:




    WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)




    Method 1 is




    Sum of Scrabble values of each letter. So much thanks to @Braegh! (approved by OP in comment)
    My original guess:
    Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)




    Method 2 is:




    Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)




    Method 3 is:




    The sum of values of each letter according to the frequency (descending): etaoi nshrd lcumw fgypb vkjxq z, where e=1, z=26,
    "WELL"=15+1+11+11=38
    THANKS TO @NudgeNudge!!




    Method 4 is:




    the sum of values of each letter on a telephone keypad, like this:
    keypad
    e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39 (approved by OP in comment)




    Method 5 is




    the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)




    And method 6:




    is the sum of the values for each letter according to its position on a QWERTY keyboard, like this:
    qwerty encryption




    PS:




    I really enjoyed this puzzle. Thanks so much, @Dmihawk!







    share|improve this answer























    • Good spotting! :)
      – Dmihawk
      Nov 12 at 23:41










    • Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
      – Dmihawk
      2 days ago










    • Method 6? @Dmihawk Thanks!
      – Omega Krypton
      2 days ago












    • Sorry, meant 5!
      – Dmihawk
      2 days ago






    • 2




      For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
      – NudgeNudge
      yesterday















    up vote
    8
    down vote



    accepted










    This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!



    Partial Answer:



    The phrase is:




    WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)




    Method 1 is




    Sum of Scrabble values of each letter. So much thanks to @Braegh! (approved by OP in comment)
    My original guess:
    Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)




    Method 2 is:




    Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)




    Method 3 is:




    The sum of values of each letter according to the frequency (descending): etaoi nshrd lcumw fgypb vkjxq z, where e=1, z=26,
    "WELL"=15+1+11+11=38
    THANKS TO @NudgeNudge!!




    Method 4 is:




    the sum of values of each letter on a telephone keypad, like this:
    keypad
    e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39 (approved by OP in comment)




    Method 5 is




    the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)




    And method 6:




    is the sum of the values for each letter according to its position on a QWERTY keyboard, like this:
    qwerty encryption




    PS:




    I really enjoyed this puzzle. Thanks so much, @Dmihawk!







    share|improve this answer























    • Good spotting! :)
      – Dmihawk
      Nov 12 at 23:41










    • Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
      – Dmihawk
      2 days ago










    • Method 6? @Dmihawk Thanks!
      – Omega Krypton
      2 days ago












    • Sorry, meant 5!
      – Dmihawk
      2 days ago






    • 2




      For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
      – NudgeNudge
      yesterday













    up vote
    8
    down vote



    accepted







    up vote
    8
    down vote



    accepted






    This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!



    Partial Answer:



    The phrase is:




    WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)




    Method 1 is




    Sum of Scrabble values of each letter. So much thanks to @Braegh! (approved by OP in comment)
    My original guess:
    Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)




    Method 2 is:




    Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)




    Method 3 is:




    The sum of values of each letter according to the frequency (descending): etaoi nshrd lcumw fgypb vkjxq z, where e=1, z=26,
    "WELL"=15+1+11+11=38
    THANKS TO @NudgeNudge!!




    Method 4 is:




    the sum of values of each letter on a telephone keypad, like this:
    keypad
    e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39 (approved by OP in comment)




    Method 5 is




    the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)




    And method 6:




    is the sum of the values for each letter according to its position on a QWERTY keyboard, like this:
    qwerty encryption




    PS:




    I really enjoyed this puzzle. Thanks so much, @Dmihawk!







    share|improve this answer














    This is a summary of all answers provided by everyone, I have credited them, if I left anyone out, please state it in the comments. Thanks!



    Partial Answer:



    The phrase is:




    WELL DONE, NOW UPVOTE PUZZLE (which I did), thanks to @DrXorile (approved by OP in comment)




    Method 1 is




    Sum of Scrabble values of each letter. So much thanks to @Braegh! (approved by OP in comment)
    My original guess:
    Ceasar shifting, the number being the rotation number, as all numbers are not larger than 26. 26 means the word is not shifted at all. (I believe that this is wrong...)




    Method 2 is:




    Sum of values in A1Z26 scheme, Thanks to @ImongMama (approved by OP in comment)




    Method 3 is:




    The sum of values of each letter according to the frequency (descending): etaoi nshrd lcumw fgypb vkjxq z, where e=1, z=26,
    "WELL"=15+1+11+11=38
    THANKS TO @NudgeNudge!!




    Method 4 is:




    the sum of values of each letter on a telephone keypad, like this:
    keypad
    e.g. for "DONE" 3+(6+6+6)+(6+6)+(3+3)=39 (approved by OP in comment)




    Method 5 is




    the sum of ASCII values of each letter, since they add up to around 80-90 per letter. (approved by OP in comment)




    And method 6:




    is the sum of the values for each letter according to its position on a QWERTY keyboard, like this:
    qwerty encryption




    PS:




    I really enjoyed this puzzle. Thanks so much, @Dmihawk!








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited yesterday

























    answered Nov 12 at 23:40









    Omega Krypton

    1,141114




    1,141114












    • Good spotting! :)
      – Dmihawk
      Nov 12 at 23:41










    • Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
      – Dmihawk
      2 days ago










    • Method 6? @Dmihawk Thanks!
      – Omega Krypton
      2 days ago












    • Sorry, meant 5!
      – Dmihawk
      2 days ago






    • 2




      For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
      – NudgeNudge
      yesterday


















    • Good spotting! :)
      – Dmihawk
      Nov 12 at 23:41










    • Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
      – Dmihawk
      2 days ago










    • Method 6? @Dmihawk Thanks!
      – Omega Krypton
      2 days ago












    • Sorry, meant 5!
      – Dmihawk
      2 days ago






    • 2




      For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
      – NudgeNudge
      yesterday
















    Good spotting! :)
    – Dmihawk
    Nov 12 at 23:41




    Good spotting! :)
    – Dmihawk
    Nov 12 at 23:41












    Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
    – Dmihawk
    2 days ago




    Method 2 and 6 are correct (I didn't know method 2 had an actual name - so that was cool to learn). For method 1, perhaps consider why one 6-letter word is "worth" more than the other...
    – Dmihawk
    2 days ago












    Method 6? @Dmihawk Thanks!
    – Omega Krypton
    2 days ago






    Method 6? @Dmihawk Thanks!
    – Omega Krypton
    2 days ago














    Sorry, meant 5!
    – Dmihawk
    2 days ago




    Sorry, meant 5!
    – Dmihawk
    2 days ago




    2




    2




    For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
    – NudgeNudge
    yesterday




    For method 3, I believe rot13(gur ahzrevpny inyhr bs gur yrggre vf rdhny gb vgf cbfvgvba ba gur yvfg bs yrggref beqrerq ol eryngvir serdhrapl va Ratyvfu (r svefg, gura g, n, b, v...))
    – NudgeNudge
    yesterday










    up vote
    5
    down vote













    Method 2 is




    Sum of A1Z26 values







    share|improve this answer

























      up vote
      5
      down vote













      Method 2 is




      Sum of A1Z26 values







      share|improve this answer























        up vote
        5
        down vote










        up vote
        5
        down vote









        Method 2 is




        Sum of A1Z26 values







        share|improve this answer












        Method 2 is




        Sum of A1Z26 values








        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 2 days ago









        ImongMama

        50119




        50119






















            up vote
            5
            down vote













            I believe Method 1 is




            the (English) Scrabble value for each word.







            share|improve this answer





















            • Well done! Good find :)
              – Dmihawk
              2 days ago










            • Thank you so much... +1 already
              – Omega Krypton
              yesterday















            up vote
            5
            down vote













            I believe Method 1 is




            the (English) Scrabble value for each word.







            share|improve this answer





















            • Well done! Good find :)
              – Dmihawk
              2 days ago










            • Thank you so much... +1 already
              – Omega Krypton
              yesterday













            up vote
            5
            down vote










            up vote
            5
            down vote









            I believe Method 1 is




            the (English) Scrabble value for each word.







            share|improve this answer












            I believe Method 1 is




            the (English) Scrabble value for each word.








            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 2 days ago









            Braegh

            1563




            1563












            • Well done! Good find :)
              – Dmihawk
              2 days ago










            • Thank you so much... +1 already
              – Omega Krypton
              yesterday


















            • Well done! Good find :)
              – Dmihawk
              2 days ago










            • Thank you so much... +1 already
              – Omega Krypton
              yesterday
















            Well done! Good find :)
            – Dmihawk
            2 days ago




            Well done! Good find :)
            – Dmihawk
            2 days ago












            Thank you so much... +1 already
            – Omega Krypton
            yesterday




            Thank you so much... +1 already
            – Omega Krypton
            yesterday










            up vote
            4
            down vote













            Based on @Omega Krypton's method 5, the phrase is:




            WELL DONE, NOW UPVOTE PUZZLE




            I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...






            share|improve this answer





















            • Nicely done :) now you just need to deduce the other 5 encryption methods!
              – Dmihawk
              Nov 13 at 0:37






            • 1




              I upvoted the puzzle lah :)
              – Omega Krypton
              Nov 13 at 2:57















            up vote
            4
            down vote













            Based on @Omega Krypton's method 5, the phrase is:




            WELL DONE, NOW UPVOTE PUZZLE




            I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...






            share|improve this answer





















            • Nicely done :) now you just need to deduce the other 5 encryption methods!
              – Dmihawk
              Nov 13 at 0:37






            • 1




              I upvoted the puzzle lah :)
              – Omega Krypton
              Nov 13 at 2:57













            up vote
            4
            down vote










            up vote
            4
            down vote









            Based on @Omega Krypton's method 5, the phrase is:




            WELL DONE, NOW UPVOTE PUZZLE




            I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...






            share|improve this answer












            Based on @Omega Krypton's method 5, the phrase is:




            WELL DONE, NOW UPVOTE PUZZLE




            I figured this out by going through all the english words that would fit those sums. The last word stood out, and I got the remaining ones except for the fourth quite quickly. The fourth wasn't in my dictionary, but easy enough to guess and check...







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 13 at 0:36









            Dr Xorile

            10.7k12259




            10.7k12259












            • Nicely done :) now you just need to deduce the other 5 encryption methods!
              – Dmihawk
              Nov 13 at 0:37






            • 1




              I upvoted the puzzle lah :)
              – Omega Krypton
              Nov 13 at 2:57


















            • Nicely done :) now you just need to deduce the other 5 encryption methods!
              – Dmihawk
              Nov 13 at 0:37






            • 1




              I upvoted the puzzle lah :)
              – Omega Krypton
              Nov 13 at 2:57
















            Nicely done :) now you just need to deduce the other 5 encryption methods!
            – Dmihawk
            Nov 13 at 0:37




            Nicely done :) now you just need to deduce the other 5 encryption methods!
            – Dmihawk
            Nov 13 at 0:37




            1




            1




            I upvoted the puzzle lah :)
            – Omega Krypton
            Nov 13 at 2:57




            I upvoted the puzzle lah :)
            – Omega Krypton
            Nov 13 at 2:57


















             

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