Search customer by ID not printing





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$begingroup$


I dont know why my code is not working at all. In my Eclipse there's no errors shown at all.



I want to use the id to print the name of my customers, and that's my goal



Customer custArray = { new Customer("Chen",35), new Customer("You",36) };


public Customer searchCustomerByID(int custID){
for(Customer c:customers){
if(c.getID() == custID)
return c;
}
return null;
}
````









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    0












    $begingroup$


    I dont know why my code is not working at all. In my Eclipse there's no errors shown at all.



    I want to use the id to print the name of my customers, and that's my goal



    Customer custArray = { new Customer("Chen",35), new Customer("You",36) };


    public Customer searchCustomerByID(int custID){
    for(Customer c:customers){
    if(c.getID() == custID)
    return c;
    }
    return null;
    }
    ````









    share|improve this question







    New contributor




    Bravooo121334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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    $endgroup$















      0












      0








      0





      $begingroup$


      I dont know why my code is not working at all. In my Eclipse there's no errors shown at all.



      I want to use the id to print the name of my customers, and that's my goal



      Customer custArray = { new Customer("Chen",35), new Customer("You",36) };


      public Customer searchCustomerByID(int custID){
      for(Customer c:customers){
      if(c.getID() == custID)
      return c;
      }
      return null;
      }
      ````









      share|improve this question







      New contributor




      Bravooo121334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I dont know why my code is not working at all. In my Eclipse there's no errors shown at all.



      I want to use the id to print the name of my customers, and that's my goal



      Customer custArray = { new Customer("Chen",35), new Customer("You",36) };


      public Customer searchCustomerByID(int custID){
      for(Customer c:customers){
      if(c.getID() == custID)
      return c;
      }
      return null;
      }
      ````






      java






      share|improve this question







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      Check out our Code of Conduct.











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      asked 1 hour ago









      Bravooo121334Bravooo121334

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          $begingroup$

          You wrote this:



          for (Customer c : customers)
          {
          if (c.getID == customID) return c;
          }


          The array is called custArray. And the for-each is iterating over an array of Customers cales customers. So, the simple solution is to change customers to custArray! Hope that helps. ;)



          EDIT: this should be on Stack Overflow.






          share|improve this answer








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            1 Answer
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            1 Answer
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            active

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            0












            $begingroup$

            You wrote this:



            for (Customer c : customers)
            {
            if (c.getID == customID) return c;
            }


            The array is called custArray. And the for-each is iterating over an array of Customers cales customers. So, the simple solution is to change customers to custArray! Hope that helps. ;)



            EDIT: this should be on Stack Overflow.






            share|improve this answer








            New contributor




            itzjackyscode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






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              0












              $begingroup$

              You wrote this:



              for (Customer c : customers)
              {
              if (c.getID == customID) return c;
              }


              The array is called custArray. And the for-each is iterating over an array of Customers cales customers. So, the simple solution is to change customers to custArray! Hope that helps. ;)



              EDIT: this should be on Stack Overflow.






              share|improve this answer








              New contributor




              itzjackyscode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.






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                0












                0








                0





                $begingroup$

                You wrote this:



                for (Customer c : customers)
                {
                if (c.getID == customID) return c;
                }


                The array is called custArray. And the for-each is iterating over an array of Customers cales customers. So, the simple solution is to change customers to custArray! Hope that helps. ;)



                EDIT: this should be on Stack Overflow.






                share|improve this answer








                New contributor




                itzjackyscode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                $endgroup$



                You wrote this:



                for (Customer c : customers)
                {
                if (c.getID == customID) return c;
                }


                The array is called custArray. And the for-each is iterating over an array of Customers cales customers. So, the simple solution is to change customers to custArray! Hope that helps. ;)



                EDIT: this should be on Stack Overflow.







                share|improve this answer








                New contributor




                itzjackyscode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                share|improve this answer



                share|improve this answer






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                answered 40 mins ago









                itzjackyscodeitzjackyscode

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                itzjackyscode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                itzjackyscode is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                    Bravooo121334 is a new contributor. Be nice, and check out our Code of Conduct.










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