adding textbox values to sql using winforms
0
$begingroup$
Hi I am having probelms with my sql currently I am trying to pass user input from a textbox to my backend database. this is what I have so far. I am not getting any errors but at the same time when I check my database table it is empty. not sure where I am going wrong.enter code here
conn.Open();
string suggestion = txtSuggestion.Text;
DateTime Date = DateTime.Now;
int Id = 0;
try
{
string txtsql = "INSERT INTO Reps(Id, Date, Suggestion) VALUES(@Id, @Date, @Suggestion)";
SqlCommand cmd = new SqlCommand(txtsql);
Id++;
cmd.Parameters.AddWithValue("@Id", Id);
cmd.Parameters.AddWithValue("@Suggestion", suggestion);
cmd.Parameters.AddWithValue("@Date", Date);
}
catch (SqlException ex)
{
MessageBox.Show("There is an Error" + ex);
}
finally
{
conn.Close();
MessageBox.Show("Thank You your Suggestion has been saved.");
}
c#
asked 10 mins ago
Darren BarrDarren Barr
11
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add a comment |
0
$begingroup$
Hi I am having probelms with my sql currently I am trying to pass user input from a textbox to my backend database. this is what I have so far. I am not getting any errors but at the same time when I check my database table it is empty. not sure where I am going wrong.enter code here
conn.Open();
string suggestion = txtSuggestion.Text;
DateTime Date = DateTime.Now;
int Id = 0;
try
{
string txtsql = "INSERT INTO Reps(Id, Date, Suggestion) VALUES(@Id, @Date, @Suggestion)";
SqlCommand cmd = new SqlCommand(txtsql);
Id++;
cmd.Parameters.AddWithValue("@Id", Id);
cmd.Parameters.AddWithValue("@Suggestion", suggestion);
cmd.Parameters.AddWithValue("@Date", Date);
}
catch (SqlException ex)
{
MessageBox.Show("There is an Error" + ex);
}
finally
{
conn.Close();
MessageBox.Show("Thank You your Suggestion has been saved.");
}
c#
asked 10 mins ago
Darren BarrDarren Barr
11
New contributor
Darren Barr is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
0
0
0
$begingroup$
Hi I am having probelms with my sql currently I am trying to pass user input from a textbox to my backend database. this is what I have so far. I am not getting any errors but at the same time when I check my database table it is empty. not sure where I am going wrong.enter code here
conn.Open();
string suggestion = txtSuggestion.Text;
DateTime Date = DateTime.Now;
int Id = 0;
try
{
string txtsql = "INSERT INTO Reps(Id, Date, Suggestion) VALUES(@Id, @Date, @Suggestion)";
SqlCommand cmd = new SqlCommand(txtsql);
Id++;
cmd.Parameters.AddWithValue("@Id", Id);
cmd.Parameters.AddWithValue("@Suggestion", suggestion);
cmd.Parameters.AddWithValue("@Date", Date);
}
catch (SqlException ex)
{
MessageBox.Show("There is an Error" + ex);
}
finally
{
conn.Close();
MessageBox.Show("Thank You your Suggestion has been saved.");
}
c#
asked 10 mins ago
Darren BarrDarren Barr
11
New contributor
Darren Barr is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Hi I am having probelms with my sql currently I am trying to pass user input from a textbox to my backend database. this is what I have so far. I am not getting any errors but at the same time when I check my database table it is empty. not sure where I am going wrong.enter code here
conn.Open();
string suggestion = txtSuggestion.Text;
DateTime Date = DateTime.Now;
int Id = 0;
try
{
string txtsql = "INSERT INTO Reps(Id, Date, Suggestion) VALUES(@Id, @Date, @Suggestion)";
SqlCommand cmd = new SqlCommand(txtsql);
Id++;
cmd.Parameters.AddWithValue("@Id", Id);
cmd.Parameters.AddWithValue("@Suggestion", suggestion);
cmd.Parameters.AddWithValue("@Date", Date);
}
catch (SqlException ex)
{
MessageBox.Show("There is an Error" + ex);
}
finally
{
conn.Close();
MessageBox.Show("Thank You your Suggestion has been saved.");
}
c#
c#
asked 10 mins ago
Darren BarrDarren Barr
11
New contributor
Darren Barr is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 mins ago
Darren BarrDarren Barr
11
New contributor
Darren Barr is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 mins ago
Darren BarrDarren Barr
11
New contributor
Darren Barr is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 mins ago
Darren BarrDarren Barr
11
asked 10 mins ago
Darren BarrDarren Barr
11
11
New contributor
Darren Barr is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Darren Barr is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Darren Barr is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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